SQL & PL/SQL :: Vertical Partitioning In Oracle
Mar 19, 2013Explain me steps to do vertical partitioning in oracle .
View 3 RepliesExplain me steps to do vertical partitioning in oracle .
View 3 RepliesI have two graph pj item in oracle block one is pie chart and other is vertical bar graph... there is color display in bottom of pie graph which is red=50,yellow-30 and orange=20 ..and in vertical bar red=50,but orange=30 and yellow is 20 ..means orange and yellow is interchange in bar graph..how i can same the both graph value..
the graph is populate through cursor and graph properties is setting through set_custom_propert();
an existing normal table be converted to a partitioned table without recreating the table or truncating/reloaded data?
View 4 Replies View RelatedEnvironment
I have a database 10.2.0.4 running on 64bit Solaris 5.10 SPARC.
Question:
CREATE TABLE SYSTEM.BIG_TABLE1
(
ID NUMBER(10),
LOOKUP_ID NUMBER(10),
DATA VARCHAR2(50 BYTE)
)
[code].......
When I query dba_tab_partitions. I get this result
select table_name, partition_name, high_value, high_value_length from dba_tab_partitions where table_name = 'BIG_TABLE1' ;
table_name partition_name high_value HIGH_VALUE_LENGTH
------------- -------------- ---------- -----------------
BIG_TABLE1 BIG_TABLE_2003 1000000000 10
BIG_TABLE1 BIG_TABLE_2004 5000000000 10
BIG_TABLE1 BIG_TABLE_2005 MAXVALUE 8
3 rows selected.
Now my question is why do I see max_value_lengh=8 when my column value is 10. I don't get any error. But I do like to understand it.
I have a table which if approc 5GB in size.I am trying to create a partition table from it. I created the new table,but when i am creating local indexes, i am getting an error when i create a unique key. I ll post the creation scripts:
CREATE TABLE A_PT_ORDREG
(
BUS_UNIT VARCHAR2(5) NOT NULL,
ORDER_NO VARCHAR2(15) NOT NULL,
PT_CODE VARCHAR2(15) NOT NULL,
REG_NO VARCHAR2(15) NOT NULL,
AS_APPLICATION VARCHAR2(5) NOT NULL,
[code].....
THE INDEX:
CREATE UNIQUE INDEX PK_A_PT_ORDREG ON A_PT_ORDREG (BUS_UNIT, ORDER_NO, SEQ_NO) local;
I am getting the following error:
ORA-14039: partitioning columns must form a subset of key columns of a UNIQUE index
I want to install the partitioning option in my oracle database. I have the license. When i run the installer and select the partitioning option, the installation begins from beginning overwriting my old setup files. How can i avoid this and only install partitioning.
View 2 Replies View RelatedI have problem to transfer data in non partitioning table to partitioning table.
I have non partitioning table and i create new table partitioning that have same column and type like in non partitioning. So how can i transfer data from table in non partitioning to table in partitioning?
how can i set the alignment of the text field in report 6i.
View 10 Replies View RelatedI need to build a query on making a vertical records to horizontal records. I did read somewhere saying that we can use decode function. But im still trying to understand how decode function can make a vertical records to horizontal records.
View 4 Replies View RelatedI have a table like the
WEEK STORE SALES
1 A 12
2 A 18
3 A 20
4 A 25
I need a query to build out put like
store week1 week2 week3 week4
A 12 18 20 25
Refresh my memory if there's a way to display vertical text on buttons in forms?
e.g. v
e
r
t
i
c
a
l
i have output query in 1 row, for example
Id Name Salary
100 John 2000
i need to output the same query in vertical way like:
100
John
2000
i need to create a form with 15 col and 10 records in tabular format to display records from the table....i done it with vertical scroll bar ..bt.i need both horizontal and vertical scroll bar for that tabular.
View 2 Replies View RelatedWhen I first access the form and query for records, it works as per the expectation and with scroll bar to scroll up and down. But when I do "View>Record>Last", it reaches to last record, but not able to use the scroll bar to scroll the records up(I am on last record, so can't do downward scrolling).
The scroll bar is displaying in Full, no room to scroll up down.It happens only when I do "View>Record>Last".
I would like to format my output for the select query.
Example:
SQL>select empno, ename from emp;
empnoename
1987766Jack Blake
187765Greg Ni
But I would like to get the output in the below format
EMPNO:.................1987766
ENAME:.................Jack Blake
EMPNO:.................187765
ENAME:.................Greg Ni
I will need printing the column name. I would like to know how do we address the column name to print.
How to create horizontal and vertical scrollbar at a time while design mode??
View 2 Replies View RelatedVertical scrollbar not showing all the records when I scroll down.
Using Oracle forms 10g , operating system windows.
I have two fields with number of items dispayed = 15.
I have a vertical scroll bar with them. There are 34 records in the table but the scrollbar only shows 15 records.
Here's my table:
SQL> desc stg_query_overflow
Name Null? Type
----------------------------------------- -------- ----------------------------
HOSTNAME VARCHAR2(50)
NPSID NUMBER
NPSINSTANCEID NUMBER
OPID NUMBER
[code]....
Here's my controlfile:
load data
infile '/u01/tony/server_name/query_overflow.dat'
badfile '/opt/oracle/tony/sql_dir/bad/server_name_query_overflow.bad'
discardfile '/opt/oracle/tony/sql_dir/discard/server_name_query_overflow.dsc'
append
into table stg_query_overflow
[code]....
Here's a sample of data that I can't load into the table via sqlldr:
echo
echo ***** Creating view: "pul_promotion_response"
CREATE or replace VIEW "pul_promotion_response"
(
"promo_rsp_id",
"promo_hist_dtl_id",
"indiv_id",
[code]....
Here's the error(s) I receive in my log file:
Record 272: Rejected - Error on table STG_QUERY_OVERFLOW, column NPSID.
ORA-01722: invalid number
Record 273: Rejected - Error on table STG_QUERY_OVERFLOW, column NPSID.
ORA-01722: invalid number
As you can see, sqlldr is interpreting this vertical sql code as the npsid column, when in fact it is the querytext column. How can I insert each record when some of my data is in this vertical format?
I was keen on creating left side vertical menus instead of using a tab for every page to organize my application better. An example is
[URL].......
I tried creating a list and attaching it to a page. Did not work. Still investigating this. Specifically, what list option that person is using. Not sure, if its really a list or maybe the vertical navigation bar?
I've a 6 column report where col5 is set to expand vertically (based upon comments) and works wonderfully. Col6 is a single character column, therefore does not expand so the report looks rather messy.
I would like col6 to expand in accordance to col5. Is it possible?
I've edited the XML on the Chart Attributes page but I don't find atrtributes to rotate the y-axis title (<text>TITLE</text>) nor the letters themselves in the title. What I'd like is something very close to
T
I
T
L
E
But what I get is a horizontal title rotated -90 degrees. I've looked at lots of Anychart documentation but don't find anything that seems to fit with the XML already given on the Chart Attributes page. I've seen the "rotate" attribute but I don't know where it would go and even then, I'm sure it only rotates the title as a unit and not the individual letters.
Apex 4.2.0.00.27Firefox 22.0, IE 8 Just started using the Enkitec Navbar, and we have noticed that when a page is rendered a vertical list always appears momentarily before being replaced with the Navbar list. It happens on all applications we have installed it on, and every time a page is refreshed.
View 13 Replies View RelatedI want to practice partitioning, I have schema which has sales table but that is already partitioned. I want to know if there are some schema available for download which has non partitioned tables and records more than 10000.
View 8 Replies View RelatedThere is a very large fact table that is range partitioned by a column DATE_KEY of type NUMBER(38), such that every hour is a different partition. There is a bitmap index BX$FACT#DATE_KEY on field DATE_KEY, which also is a foreign key referencing DATE_DIM (DATE_KEY). There is a different DATE_KEY for every hour, generated as YYYYMMDDHH24.
When I run
"SELECT * FROM FACT WHERE DATE_KEY >= 2012031207 AND DATE_KEY < 2012031208"
to get all the records for 7 am on March 12th, partition pruning kicks in and sees that only one partition is used. The CBO then decides to do a full scan of the partition. This behavior is correct/desired.
If, however, I run
"SELECT * FROM FACT WHERE DATE_KEY = 2012031207 AND DATE_KEY < 2012031209"
to get all the records for 7 and 8 am, Oracle knows that it will have to scan two partitions. The CBO then decides that using the BX$FACT#DATE_KEY must be a good idea and, instead of doing a full scan of the partitions, does access by local index rowid, which is many times slower.
I think I understand the cause - when more than a single partition is involved, Oracle has to use the global index stats (instead of the local ones, like in the first scenario) and the CBO decides to use it because that the selectivity for the global index is great, when in fact the query will return all the rows for that particular partition (no selectivity).
How to get the CBO to choose a full scan in the second scenario as well? I need to support ad-hoc queries generated by a BI tool, so I cannot add hints to the queries. I also can't get rid of the index on DATE_KEY, because in real life the predicates are on fields of the date dimension, not directly on the key, so I need to join on it.
How to partition a table which is already having data.I have a STUDENT table along with following fields which is having million of rows.
studentid name class Gender
Now I want to partition this table based on gender MALE and FEMALE.
I have a partitioned table with 1 lakh records
if i disable the partition feature im my database will it affect my table data.
how should i do to make horizontal partitioning?
View 18 Replies View Relatedwe apply partitioning concept on a table which don't have any primary key ?
I just want to add one more field as primary key with some sequence generated values while partitioning ? Is it possible ?
Oracle 10.2.0.4
I partitioned a source table of around 100 million rows (62GB) in DEV server. The target database was created new. It was range partioned on a date column as follows:
PARTITION BY RANGE (ENTRY_DATE_TIME)
(
PARTITION ppre2012 values less than (TO_DATE('01/01/2012','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
PARTITION p2012 values less than (TO_DATE('01/01/2013','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
PARTITION p2013 values less than (TO_DATE('01/01/2014','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
PARTITION p2014 values less than (MAXVALUE) TABLESPACE WST_LRG_D
)
That is yearly basis. Anything before 2012 went to ppre2012, then p2012, p2013 and so forth. There is 20 million rows in p2012. and around 75 million rows in ppre2012. We needed both the source (un-partitioned) and target (partitioned) tables in DEv for comparision. The queries are normally on the current year partition. Just to state taht I am a developer and don't have full visibility to the production instance.
Now that our tests are complete, we would like to promote this in production. Obviously in production we would not not need both source and target tables. In all probability this will be performed over a weekend window. Therefore I would like to suggest the following .
1) use expdp to export source table
2) drop the source table
3) create a new source table "partitioned" with no indexes
4) use impdp to get data back into table
5) create global index (it is a unique index to enforce uniquness) and the rest of indexes as local
6) perform dbms_stats.gather_table_stats(user,'SOURCE', cascade=>true). This takes around 2 hours in dev
My point is that whether importing 100 million rows will not cause issues with undo segments. Can we import data say first to the current partition p2012 (20 million rows) first.
If a Interval Partitioning can be created on a table for every fortnight ? db version is 11g.
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