Retrieve Auto Increment Field Value With Left Join?
May 27, 2013
I have already done auto increment by making sequence and trigger. but now the problem is when i am trying to retrieve data from that table it returns all data perfectly but the primary key that is my auto increment value shows blank.I am facing this problem with join query, there 4 table left joined in my query. But when I remove join from my query then it shows that value.
But i need that value in my join query.So, what is the problem and what can I do?And other thing is when I apply this query in Oracle SQL Developer, it works perfect.
My Query:
return $this->db->query("select * from TBL_EMPLOYEE_BASIC left join TBL_EMPLOYEE_DETAILS on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_DETAILS.EMPL_ID left join TBL_EMPLOYEE_EDUCATION on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_EDUCATION.EMPL_ID left join TBL_EMPLOYEE_EXPERIENCE on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_EXPERIENCE.EMPL_ID where
[code]...
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Aug 11, 2010
I have a table abc with name and phone_number columns in it,and this table contains 100 records. Now I want to add a column say ID as primary key for this and it should be auto incremented and should have primary key for the first 100 records as well.
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Jun 16, 2010
Step1
CREATE TABLE test
(id NUMBER PRIMARY KEY,
name VARCHAR2(30));
Step2
CREATE SEQUENCE test_sequence
START WITH 1
INCREMENT BY 1;
Method1 Follow Step1 and Step2 and create a Trigger as below :
CREATE OR REPLACE TRIGGER test_trigger
BEFORE INSERT
ON test
REFERENCING NEW AS NEW
FOR EACH ROW
BEGIN
SELECT test_sequence.nextval INTO :NEW.ID FROM dual;
END;
/
Method 2 Follow Step1 and Step2 and directly have an insert statement as below:
INSERT INTO test (id, name) VALUES (test_sequence.nextval , 'Jon343');
Method 1, the Trigger is not getting created, however by following Method 2, I am able to generate auto-increment number.
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Jun 16, 2010
which method is more efficient in terms of performance to generate an auto increment number in oracle.
Step1
CREATE TABLE test
(id NUMBER PRIMARY KEY,
name VARCHAR2(30));
Step2
CREATE SEQUENCE test_sequence
START WITH 1
INCREMENT BY 1;
[code]....
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Nov 26, 2012
I am switching database from access to oracle 11g. I have create all the required tables, but I am stuck at one point. The previous person who created access database had auto increment with SG0101, SG0102,........ In oracle I know we can auto increment primary keys but only with the numbers not with characters.
So I have customerid which is a primary key and it automatically increments the number, but I have one more column with memberid where I am inserting all the ids that start with SG0101 bla bla.....
I already have 800 member ID's that start with SG, but that value doesnt automatically increment because I dont have any sequence or trigger to do that.
So how do I create a sequence and trigger that will automatically start value with SG and keeps auto incrementing?
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Mar 14, 2005
I'm trying to create a sequence for a primary key to simply auto-increment by the default of 1. I have a sql script written to generate mt tables, and I'm not sure how to modify the script to include the sequence. I also just want the sequence for a specific column, ie, PK, not the PK in all tables.
Here's a snippet from my script:
create table image
(
image_id int NOT NULL,
source_id int NOT NULL,
CONSTRAINT image_id_pk PRIMARY KEY (image_id),
CONSTRAINT fk_source_id FOREIGN KEY (source_id) REFERENCES source(source_id)
);
Would I add the create sequence statement right after the create table, and if so, how do I apply the sequence to only 1 table and a single column?
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Apr 18, 2011
Srl no - Srl no w.r. to the date of transaction.i.e will be incremented for every day and should again reset for the next day-Length -4 Purpose code -Purpose code of the transaction.
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Feb 1, 2013
I have three tables.
One for projects, one for volunteers, and a bridge entity for the many to many relationship between the Project and Volunteer.
In Project table, I have a field called, Volunteers_currently_signed_up, which means the number of volunteers currently signed up to participate in a project.
When I add an entry to my bridge entity which is composed of Volunteer_ID and Project_ID, I want the Volunteers_currently_signed_up to increment by 1, where the Project_ID in the bridge entity corresponds to that in Project.
I have very very little PL/SQL, and this is my amateur attempt so far:
CREATE OR REPLACE trigger "BI_Volunteers_currently_signed_up"
BEFORE INSERT OR UPDATE ON Volunteers_in_project
for each row
WHERE Volunteers_in_project.Project_ID=Project.Project_ID;
begin
Project.Volunteers_currently_signed_up += 1;
end;
/
write a trigger that achieves the above
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Apr 9, 2013
I am creating a query where I am trying to take phone call lengths and put them into buckets of length ranges 0:00 - 0:59, 1:00 - 1:59 etc. Even if there are no calls in the call table I need to return the range with a zero (hence the left join and nvl). When I do this the left join acts like an equal join, I suspect there is some reason left joins only work if there is an equal condition in the join (instead of >= and < that I use, or similarly I could use BETWEEN). I also have a question about performance (below).
The create table script for the lookup is like this:
CREATE TABLE DURATION_RANGES
(
RANGE_TEXT varchar2(20),
RANGE_LBOUND decimal(22),
RANGE_UBOUND decimal(22)
)
Sample inserts are:
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',0,59);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('01:00 - 01:59',60,119);
etc.
The query is:
select
r.range_text as duration_range,
nvl(count(*),0) as calls,
nvl(SUM(call_duration),0) as total_duration
from
[code]...
As I say, it is not returning all ranges in the duration_ranges table, so acting like an inner join. I realize one solution would be to populate duration ranges with every value possible (instead of ranges) so join is an equal join, but that would make the duration_range table larger.
My questions:
1. Is it possible to get the left join to work with the duration range values as they currently are?
2. Even if 1 is possible, would it be better performance to have exact values (but a larger lookup table) and do an equals join instead of >=, < or BETWEEN? Performance now is not bad.
What I mean is (with only one time value and not lbound and ubound:
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',0);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',1);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',2);
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Nov 29, 2011
Using Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
Here's a simplified version of the query I am having problems with:
SELECT
assoc.association_id
FROM mentor_initiative mi
LEFT JOIN program assoc_prog ON assoc_prog.program_id = -1
LEFT JOIN mentor_association assoc ON assoc.mentor_initiative_id = mi.mentor_initiative_id AND
NVL(assoc_prog.program_id, -1) = NVL(assoc.program_id, -1)
Note that there is no program with program id -1. So the assoc_prog left join will come up with nothing. I was thinking that since assoc_prog.program_id will be null, the second assoc left join would pick the row where assoc.program_id is null. However, the second left join doesn't join to any row.
In this query, it does join to an assoc row (I changed assoc_prog.program_id to NULL)
SELECT
assoc.association_id
FROM mentor_initiative mi
LEFT JOIN program assoc_prog ON assoc_prog.program_id = -1
LEFT JOIN mentor_association assoc ON assoc.mentor_initiative_id = mi.mentor_initiative_id AND NVL(NULL, -1) = NVL(assoc.program_id, -1)
I was thinking it would join to an assoc row in the first query though. How can I change the first query to have the desired effect of left joining to a row where assoc.program_id is null if assoc_prog.program_id is null?
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Oct 13, 2010
I have two tables employee_master and employee_time. There could be situation that record from employee_master does not exist in employee_time.
create table employee_master(employee_id number, employee_name varchar2(100));
insert into employee_master values(1, 'employee 1');
insert into employee_master values(2, 'employee 2');
insert into employee_master values (3, 'employee 3');
create table employee_time(employee_id number, project_id number, project_type varchar2(20), time_date date, hours number)
insert into employee_time values(1, 100, 'Billable', '01-Oct-2010', 10);
insert into employee_time values(1, 200, 'Billable', '02-Oct-2010', 9);
insert into employee_time values(1, 210, 'Non Billable', '03-Oct-2010', 10);
insert into employee_time values(2, 100, 'Billable', '01-Oct-2010', 10);
insert into employee_time values(2, 200, 'Billable', '02-Oct-2010', 9);
The requirement is to show all the employees from employee_master and with total billable hours and non billable hours, if not exist, show zero.The output will be:
Employee_ID Employee_Name Total_Billable_Hours Total_Non_Billable
1 Employee1 19 10
2 Employee2 19 0
3 Employee3 0 0
The question is to write a Left outer join query or to write a PL/SQL function which can return total rows if Employee_ID is supplied to it as a parameter
Query 1:
Select Employee_ID, Employee_name, sum(Billable), sum(Non_Billable)
From
(
Select a.Employee_ID, a.employee_name,
decode(b.project_type, 'Billable', hours, 0) as Billable,
decode(b.project_type, 'Non Billable', Hours, 0) as Non_Billable
from employee_master a
left outer join employee_time b on a.Employee_ID=b.Employee_ID
)
Group by Employee_ID, Employee_Name
Query 2:
Select Employee_ID, Employee_Name, func_billable(Employee_ID) as Billable, func_non_billable(Employee_ID) as Non_Billable
From Employee_Master
Which query is good from the performance perspective? In real situation the employee_time is a very huge table.
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Jan 20, 2011
joining this query instead of using the left join. Reason is want to show the score column in a different place and also do not want to show the second IPS column that is used in the joined query.
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
select * from
(
select i.ips,
p.project_name,
p.project_segment,p.location,p.project_exec_model,
p.project_exec_model||' - '||p.project_config pmodel,
one.score schedule,two.score cost,three.score execution,four.score commercial,
nvl(one.score,0)+nvl(two.score,0)+nvl(three.score,0)+nvl(four.score,0) as total,
[code]....
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Sep 21, 2012
I have the following query but it is taking too much time because of the LEFT OUTER JOIN on HST table which is a huge table , is there an alternative to LEFT OUTER JOIN that can be used to optimize the code:
SELECT HST.COMP_CODE,
HST.BRANCH_CODE,
HST.CURRENCY_CODE,
HST.GL_CODE,
HST.CIF_SUB_NO,
HST.SL_NO,
SUM(CV_AMOUNT) CV_AMOUNT,
[code].....
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Jun 17, 2010
I have the following 2 SQLs ; one return 1 row, another one is no row returned.
select v.value
from v$parameter v
where v.name = 'cpu_count';
return value "1"
select o.value
from v$osstat o
where o.stat_name = 'NUM_CPU_CORES';
No row returned.
combine the above two in to 1 SQL, and return 1 , null or 1, 1. I assume we can get it with left join for the condition "o.stat_name (+) = 'NUM_CPU_CORES'" , but no row returned for the following SQL. How could we get the result for 1, null for this case?
select v.value, o.value -- or NVL(o.value, 1)
from v$parameter v, v$osstat o
where v.name = 'cpu_count'
and o.stat_name (+) = 'NUM_CPU_CORES';
no row returned
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Feb 5, 2012
I am trying to develop an application of cars. The car have marques example :
TOYOTA,HUNDAI,CHEVROLET
each mark have families example: TOYOTA have Hilux, yaris corola, CHEVROLET have opra,...etc. Each family have a lot of models example: hilux have h2kn-clim,.. etc. And finally there are some options witch are generally in all cars example Radio-k7,air-conditioner ... etc.
option 1..n-----------------1..n model the relation call(opt_mod)
i did develop the block of marques (master) and the block of families (detail) in a form 1. i did develop the bock of models(master) in form 2 and the is no problem. but i want to add to form 2 the block of (opt_mod) but the user did tell me that he want to to see all options with check boxes .
As a solution of this problem i want to build a block on LEFT JOIN between table :option and table :opt_mod
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Jul 27, 2012
What is the fundamental difference between MINUS keyword and LEFT outer join in Oracle.
I can achieve same results using either one of them.
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Jul 20, 2011
We just upgraded to 11g and have run into incorrect results for some of our LEFT JOINs. If the table, view, subquery, or WITH clause that is being LEFT JOINed to contains any constants, the results are not correct.
For example, a test (nonsensical) view such as the following is created:
create or replace view fyvtst1 as
select spriden_pidm as fyvtst1_pidm,
'Sch' as fyvtst1_test
from spriden
where spriden_last_name like 'Sch%' ;
When I run the following query, I get correct results; that is, only those with "Sch" starting their last name are listed.
select spriden_pidm, spriden_last_name, fyvtst1_pidm, fyvtst1_test
from spriden
join fyvtst1 on fyvtst1_pidm = spriden_pidm ;
However, when I change the JOIN to a LEFT JOIN, the last column contains "Sch" for all rows, instead of NULL:
select spriden_pidm, spriden_last_name, fyvtst1_pidm, fyvtst1_test
from spriden
left join fyvtst1 on fyvtst1_pidm = spriden_pidm ;
We've discovered other quirky things related to this. A WITH clause with similar logic as the above view, when LEFT JOINed to a table will also cause the constant to appear in each row, instead of NULL (and only the value where there is a join). But when additional columns are added to the WITH, it behaves correctly.
This is easy enough to rewrite - but we have WITHs and views containing constants in numerous places, and cannot hope to track down every single one successfully before the incorrect results are used.
Finally, the NO_QUERY_TRANSFORMATION hint will force the query to work correctly. Unfortunately, it has a huge negative performance impact (one query ran for an hour, vs. 1 second in 10g).
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Oct 16, 2012
I am using left outer join to fetch PRSN_KEY .I need to find null values in B.PRSN_KEY. I am using below query but its giving me 0 count.
select count(*) from (
Select A.PRSN_KEY AS AKEY,B.PRSN_KEY AS BKEY from CD03955P.H_CM_EEST_EEOR A LEFT JOIN CD03955P.H_CM_EEST_EEOR B
ON
A.PRSN_KEY =B.PRSN_KEY
where
A.CAT_ID=111
AND
A.DATA_SOURCE='PEN_CO'
AND
B.CAT_ID = 1 and B.DATA_SOURCE ='PEN_EEST'
AND B.CAT_CD IN ('ACTIVE','LOA','LOAWP','LOAMLP','LOAMLN')
AND B.EFBEGDT < A.EFBEGDT
)
where BKEY IS NULL
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Oct 16, 2012
What I am trying to do is get my report to list every room in the table even if there is nothing scheduled in the room for the selected date. I add a command to the report to force the left outer join but I keep running into errors. This is how I have it worded:
SELECT
"ROOM"."ROOM_ID",
"PATIENT_CARE_EVENT"."OR_NUM"
FROM
"ROOM"."ROOM" LEFT OUTER JOIN "PATIENT_CARE_EVENT"."PATIENT_CARE_EVENT"
ON "PATIENT_CARE_EVENT"."OR_NUM"="ROOM"."ROOM_ID" AND "PATIENT_CARE_EVENT"."PROCEDURE_DATE_DT" IN {?Start Date} TO {?End Date}
Someone else suggested that I change the IN/TO wording in the last line to BETWEEN/AND. When I do that it gives me an error stating that the table or view does not exist.
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Oct 15, 2008
I have many different file names within my table and I want to remove the .TXT extension from each one. I want to try this SQL but being a newbie in Oracle, I don't know how to say "Left" characters. "Left" is an invalid identifier.
Update TableName
Set File_Name = Left(File_Name, Len(File_Name)-4)
Where File_Name LIKE '%.TXT'
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Aug 14, 2009
i want to know the difference between Left outer join Vs. Right outer join? Its like which join is safer to use or is there any recommendations to use any join?
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Mar 22, 2012
these are the sample data :
CREATE OR REPLACE TYPE CourseList AS TABLE OF VARCHAR2(64);
CREATE TABLE department (
courses CourseList)
NESTED TABLE courses STORE AS courses_tab;
INSERT INTO department (courses)VALUES (CourseList('1','2','3'));
[code]....
The query returns the correct data, CourseList that are not subset of any other CourseList of the table.
I am trying to convert this not exists in a left outer join query to check if the performance is better, but I don't know how to do it.
I was making some variations of this code :
select d1.courses c_1, d2.courses c_2
from department d1,department d2
where d1.courses<>d2.courses(+);
but it is now working.
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Dec 2, 2010
the following statement gives each customer owns how many promotions.
Q:) how do i retrieve a customer who has max. promotions?
SELECT C.CUSTOMER_ID,COUNT(P.PROMOTION_ID)
FROM PROMOTIONS P,CUSTOMERS C
WHERE C.CUSTOMER_ID = P.CUSTOMER_ID
GROUP BY C.CUSTOMER_ID
=====================================================
CUSTOMER_ID COUNT(P.PROMOTION_ID)
-------------------------------------
001 | 5
002 | 8
003 | 4
004 | 6
005 | 5
006 | 3
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Aug 6, 2012
In my project, the below function retrieve output very slowly. Is there any alternative code to replace this function with join
CREATE OR REPLACE FUNCTION f_johnson (i_case_id number,i_seq_num argus_app.case_reference.seq_num%type) RETURN VARCHAR2 AS
c_ref VARCHAR2(32500) := null ;
CURSOR c_refer IS
[code]...
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Jul 13, 2011
I am having a problem with auto populating different fields based on inventory no. field.. This is a bug giving to me to work on and i not able to figure out how to populate the other fields.
How to set any triggers for the items to auto populate and i am suppose to finish this work today.
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Jun 8, 2011
I am using LOV on some field to retrieve data, but sometimes it does not retrieve anything cause of unavailability of date its fine but i want to put N/A in that field when such condition is occurring .
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Mar 17, 2010
i have a doubt in building a query.
I have a table with fields
job_no activity Date
101 anchorage 20/01/2010
102 berthing 25/01/2010
103 sailing 29/01/2010
If i want to know the status of the ship on the date '22/01/2010' It has to show as 'anchorage', becoz on '25/01/2010' only it came to berthing from anchorage. How to write a query to achieve this.
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Aug 5, 2011
I have encountered a weird (or maybe not weird at all but unexplainable from my point of view) behavior from Oracle. I have simplified the example as much as possible
This query returns 2 rows as expected:
with edited as
(select F101, e_id from (select 'Test' F101, -1 e_id from dual
union all select 'Test1' F101, -2 e_id from dual) input_clob),
distinct_intermediate_edited as
[code]...
But this one (with only one row in input_clob) returns one row (as expected) but with null on e_id (why?):
with edited as
(select F101, e_id from (select 'Test' F101, -1 e_id from dual) input_clob),
distinct_intermediate_edited as
(select e.f101, e.e_id
from edited e
[code]...
If I change the join condition with and nvl(e.E_id,0) = nvl(e_id,0) both cases work as I expect (e_id = -1 for second query) but I simply want an explication for this behavior.
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Oct 18, 2010
I am posting the below query:
SELECT PEA.INCURRED_BY_PERSON_ID AS PERSON_ID,
PEA.EXPENDITURE_ENDING_DATE AS WEEK_END_DATE,
CASE
[Code].....
The explain is below:
SELECT STATEMENT ALL_ROWSCost: 48,287 Bytes: 18,428,818 Cardinality: 297,239
3 HASH JOIN Cost: 48,287 Bytes: 18,428,818 Cardinality: 297,239
1 TABLE ACCESS FULL TABLE PA.PA_EXPENDITURES_ALL Cost: 2,964 Bytes: 3,506,094 Cardinality: 194,783
2 TABLE ACCESS FULL TABLE PA.PA_EXPENDITURE_ITEMS_ALL Cost: 43,425 Bytes: 26,637,468 Cardinality: 605,397
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Sep 1, 2012
I am trying to create a table that will increment my ID by one using the following commands:
/*Creates the log needed to increment ID*/
create sequence seq_log;
CREATE TABLE MESSAGE_LOG_TABLE
(
IDNUMBER(10)NOT NULLPRIMARY KEY,
[code]...
When I run the above my create sequence completes successfully but I get a ORA-00955: name is already used by an existing object error message on the create table. I have dropped all tables and sequences before running my command but I still get the same error message.
After it bombs out it appears that SQL+ want's more information for it begins to give me line numbers as if it is looking for a ";" to end the above command. I have to exit SQL+ and log back in to continue working.
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