Get Left Chars Of A Field?
Oct 15, 2008
I have many different file names within my table and I want to remove the .TXT extension from each one. I want to try this SQL but being a newbie in Oracle, I don't know how to say "Left" characters. "Left" is an invalid identifier.
Update TableName
Set File_Name = Left(File_Name, Len(File_Name)-4)
Where File_Name LIKE '%.TXT'
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May 27, 2013
I have already done auto increment by making sequence and trigger. but now the problem is when i am trying to retrieve data from that table it returns all data perfectly but the primary key that is my auto increment value shows blank.I am facing this problem with join query, there 4 table left joined in my query. But when I remove join from my query then it shows that value.
But i need that value in my join query.So, what is the problem and what can I do?And other thing is when I apply this query in Oracle SQL Developer, it works perfect.
My Query:
return $this->db->query("select * from TBL_EMPLOYEE_BASIC left join TBL_EMPLOYEE_DETAILS on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_DETAILS.EMPL_ID left join TBL_EMPLOYEE_EDUCATION on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_EDUCATION.EMPL_ID left join TBL_EMPLOYEE_EXPERIENCE on TBL_EMPLOYEE_BASIC.EMPL_ID = TBL_EMPLOYEE_EXPERIENCE.EMPL_ID where
[code]...
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Aug 25, 2013
We have to get some data from U98 (saixdbU98) in UTF-8 format in Excel sheet.We are having queries ready for this. These queries bring data which have Japanese characters.But when we run the Select queries then in the result Japanese chars are garbled. It comes in ????.
let us know what process we have to follow to get the result in UTF-8 format in Excel sheet.here is the code
set sqlblanklines on;
SET DEFINE OFF;
set linesize 1000
set long 1000000
[code]....
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Jan 3, 2012
I'm sending Emoji's in by Email body, but its not being rendering properly.
Is there any way to encode Emoji chars like --> 😪
[URL]........
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Dec 5, 2011
I'm using utl_encode.mimeheader_encode to encode the subject line for non ascii chars, but its encoding only first 75 chars, is there any other way to encode subject.
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Apr 9, 2013
Can we use regular expression to eliminate all characters other than -
A to Z
0 to 9
Special characters like - &,%,~,@,#,$,^,*,_,+,=,,/,<,>
Example
String - TEST@#_~````}{!!!12311HELLO
Expected result - TEST@#_~12311HELLO
how we can use regular expression to achieve this result.
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Mar 6, 2011
How can I do this ?
is there an rpad that works for multiple chars?
select RPAD('test',10, 'X') from dual;
I want to be able to do something like
select RPAD('test',6, '%20') from dual;
which should return test%20%20
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Aug 25, 2013
We have to get some data from U98 (saixdbU98) in UTF-8 format in Excel sheet.We are having queries ready for this. These queries bring data which have Japanese characters.
But when we run the Select queries through pbrun (Power Broker) then in result Japanese chars are garbled. It comes in what process we have to follow to get the result in UTF-8 format in Excel sheet.
here is the code
--
set sqlblanklines on;
SET DEFINE OFF;
set linesize 1000
set long 1000000
set pages 50000
[code]...
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Sep 30, 2011
Creating a table
CREATE TABLE NEW_DATA
(INK_DATE DATE,
INV_ID NUMBER,
CUST_ID NUMBER,
AMOUNT NUMBER)
Loading data into the table with
LOAD DATA
CHARACTERSET WE8MSWIN1252
INFILE 'input/NEW_DATA.dat' "str '
'"
BADFILE 'log/NEW_DATA.bad'
DISCARDFILE 'log/NEW_DATA.dsc'
TRUNCATE INTO TABLE NEW_DATA
FIELDS TERMINATED BY '|'
(INK_DATE date "YYYY-MM-DD",
INV_ID,
CUST_ID,
AMOUNT)
My problem is that there are some rows (about 1%) where the columns INV_ID, CUST_ID, AMOUNT are containing non numeric characters and they end up in the BAD-file as errors.
Is there a way to make them end up in the discard file instead so I don't end up with errors but discards?Or even better load then into another table looking like this
(INK_DATE DATE,
INV_ID varchar2,
CUST_ID varchar2,
AMOUNT varchar2)
Do I need to have a WHEN-clause?
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Jun 23, 2011
i tried to apply a sql case statement in sql loader control file in " " the load succeed with 258 chars case or decode statement but when i add more cases it return sql loader 350 token longer than max
LOAD DATA
INFILE 'F:Vouvou20110613_102_951454.unl'
BADFILE 'F:Vouvou.pad'
DISCARDFILE 'F:Vouvou.dic'
replace
INTO TABLE vou_test_2
FIELDS TERMINATED BY '|'
TRAILING NULLCOLS
[code].......
the above one succeed when i edit the case statement as follow
ACCOUNT_2001 "CASE WHEN:ACCOUNTTYPE1='2001'THEN :REWARDAMOUNT1 WHEN :ACCOUNTTYPE2='2001' THEN :REWARDAMOUNT2
WHEN :ACCOUNTTYPE3='2001' THEN :REWARDAMOUNT3
WHEN :ACCOUNTTYPE4='2001' THEN :REWARDAMOUNT4
WHEN :ACCOUNTTYPE5='2001' THEN :REWARDAMOUNT5
WHEN :ACCOUNTTYPE6='2001' THEN :REWARDAMOUNT6
WHEN :ACCOUNTTYPE7='2001' THEN :REWARDAMOUNT7
WHEN :ACCOUNTTYPE8='2001' THEN :REWARDAMOUNT8
WHEN :ACCOUNTTYPE9='2001' THEN :REWARDAMOUNT9
WHEN :ACCOUNTTYPE10='2001' THEN :REWARDAMOUNT10 END"
i got the Error sql loader 350 token longer than max allowable length of 258 chars .
note : i cant modify the table structure to shorten the column names .
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Apr 9, 2013
I am creating a query where I am trying to take phone call lengths and put them into buckets of length ranges 0:00 - 0:59, 1:00 - 1:59 etc. Even if there are no calls in the call table I need to return the range with a zero (hence the left join and nvl). When I do this the left join acts like an equal join, I suspect there is some reason left joins only work if there is an equal condition in the join (instead of >= and < that I use, or similarly I could use BETWEEN). I also have a question about performance (below).
The create table script for the lookup is like this:
CREATE TABLE DURATION_RANGES
(
RANGE_TEXT varchar2(20),
RANGE_LBOUND decimal(22),
RANGE_UBOUND decimal(22)
)
Sample inserts are:
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',0,59);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('01:00 - 01:59',60,119);
etc.
The query is:
select
r.range_text as duration_range,
nvl(count(*),0) as calls,
nvl(SUM(call_duration),0) as total_duration
from
[code]...
As I say, it is not returning all ranges in the duration_ranges table, so acting like an inner join. I realize one solution would be to populate duration ranges with every value possible (instead of ranges) so join is an equal join, but that would make the duration_range table larger.
My questions:
1. Is it possible to get the left join to work with the duration range values as they currently are?
2. Even if 1 is possible, would it be better performance to have exact values (but a larger lookup table) and do an equals join instead of >=, < or BETWEEN? Performance now is not bad.
What I mean is (with only one time value and not lbound and ubound:
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',0);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',1);
INSERT INTO DURATION_RANGES (RANGE_TEXT,RANGE_LBOUND,RANGE_UBOUND) VALUES ('00:00 - 00:59',2);
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Nov 29, 2011
Using Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
Here's a simplified version of the query I am having problems with:
SELECT
assoc.association_id
FROM mentor_initiative mi
LEFT JOIN program assoc_prog ON assoc_prog.program_id = -1
LEFT JOIN mentor_association assoc ON assoc.mentor_initiative_id = mi.mentor_initiative_id AND
NVL(assoc_prog.program_id, -1) = NVL(assoc.program_id, -1)
Note that there is no program with program id -1. So the assoc_prog left join will come up with nothing. I was thinking that since assoc_prog.program_id will be null, the second assoc left join would pick the row where assoc.program_id is null. However, the second left join doesn't join to any row.
In this query, it does join to an assoc row (I changed assoc_prog.program_id to NULL)
SELECT
assoc.association_id
FROM mentor_initiative mi
LEFT JOIN program assoc_prog ON assoc_prog.program_id = -1
LEFT JOIN mentor_association assoc ON assoc.mentor_initiative_id = mi.mentor_initiative_id AND NVL(NULL, -1) = NVL(assoc.program_id, -1)
I was thinking it would join to an assoc row in the first query though. How can I change the first query to have the desired effect of left joining to a row where assoc.program_id is null if assoc_prog.program_id is null?
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Jun 11, 2013
I am observing some skewed results for Left outer join where the main table has NULL in the field we are joining against with another table.
Just wondering if there are some tricks to get over it. I am currently using NVL(tab1.col1,'X') = NVL(tab2.col3,'X') and am just wondering if there is a better way to handle this.
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Apr 23, 2010
Even though i am using COL1 CHAR(500) NULLIF COL1=BLANKS, then also i am getting same error for those columns.
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Sep 15, 2009
i have downloaded ireports latest version (3.6.0) for working with jasper reports (3.5.2) and creating reports;How can I change the orientation of a 4 columns report in order to generate the columns starting from the right side.I need to generate a multiple columns report in arabic and it should be done from right to left.
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Dec 22, 2006
Is there is an equivalent to the 'LEFT' Function of SQLServer in Oracle9i?
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Apr 1, 2011
I am using forms 6i and oracle 10g. i want to display a char from database. that means a database string 'Bangladesh' is display from by one char to one char.
and display view right to left first display "B" then "BA" then 'BAN' etc.
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Mar 11, 2010
Is there any way to align the output data of sql plus.
for eg., if i give "select custname, custid, custage from cust;" the ouput am getting is,
custname custid custage
aaa 1 23
bbbbb 2 22
cccc 3 45
dddddddd 4 21
but i need to left align the custid and custage.
my output should look like,
custname custid custage
aaa 1 23
bbbbb 2 22
cccc 3 45
dddddddd 4 21
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Oct 13, 2010
I have two tables employee_master and employee_time. There could be situation that record from employee_master does not exist in employee_time.
create table employee_master(employee_id number, employee_name varchar2(100));
insert into employee_master values(1, 'employee 1');
insert into employee_master values(2, 'employee 2');
insert into employee_master values (3, 'employee 3');
create table employee_time(employee_id number, project_id number, project_type varchar2(20), time_date date, hours number)
insert into employee_time values(1, 100, 'Billable', '01-Oct-2010', 10);
insert into employee_time values(1, 200, 'Billable', '02-Oct-2010', 9);
insert into employee_time values(1, 210, 'Non Billable', '03-Oct-2010', 10);
insert into employee_time values(2, 100, 'Billable', '01-Oct-2010', 10);
insert into employee_time values(2, 200, 'Billable', '02-Oct-2010', 9);
The requirement is to show all the employees from employee_master and with total billable hours and non billable hours, if not exist, show zero.The output will be:
Employee_ID Employee_Name Total_Billable_Hours Total_Non_Billable
1 Employee1 19 10
2 Employee2 19 0
3 Employee3 0 0
The question is to write a Left outer join query or to write a PL/SQL function which can return total rows if Employee_ID is supplied to it as a parameter
Query 1:
Select Employee_ID, Employee_name, sum(Billable), sum(Non_Billable)
From
(
Select a.Employee_ID, a.employee_name,
decode(b.project_type, 'Billable', hours, 0) as Billable,
decode(b.project_type, 'Non Billable', Hours, 0) as Non_Billable
from employee_master a
left outer join employee_time b on a.Employee_ID=b.Employee_ID
)
Group by Employee_ID, Employee_Name
Query 2:
Select Employee_ID, Employee_Name, func_billable(Employee_ID) as Billable, func_non_billable(Employee_ID) as Non_Billable
From Employee_Master
Which query is good from the performance perspective? In real situation the employee_time is a very huge table.
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Jan 20, 2011
joining this query instead of using the left join. Reason is want to show the score column in a different place and also do not want to show the second IPS column that is used in the joined query.
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
select * from
(
select i.ips,
p.project_name,
p.project_segment,p.location,p.project_exec_model,
p.project_exec_model||' - '||p.project_config pmodel,
one.score schedule,two.score cost,three.score execution,four.score commercial,
nvl(one.score,0)+nvl(two.score,0)+nvl(three.score,0)+nvl(four.score,0) as total,
[code]....
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Sep 21, 2012
I have the following query but it is taking too much time because of the LEFT OUTER JOIN on HST table which is a huge table , is there an alternative to LEFT OUTER JOIN that can be used to optimize the code:
SELECT HST.COMP_CODE,
HST.BRANCH_CODE,
HST.CURRENCY_CODE,
HST.GL_CODE,
HST.CIF_SUB_NO,
HST.SL_NO,
SUM(CV_AMOUNT) CV_AMOUNT,
[code].....
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Feb 16, 2013
Is there any possibility of creating a selection interface similar to our report or forms wizard where user can select single fields or multiple fields together and when he clicks on the arrow those fields data to be inserted into another table.Please refer attachment.
--this is the main table
create table batch_item (batch_no varchar2(12),item_batch varchar2(12),total_batch_qty number);
insert into batch_item ('0001','a',300);
insert into batch_item ('0002','b',200);
insert into batch_item ('0003','a',102);
--after inserting the data i should be able to move this data to corresponding batches by manually selection and pushing them to a batch.create table ct_item (item varchar2(12),item_nm varchar2(20),item_qty number);
insert into om_item values ('a','alpha',2);
insert into om_item values ('b','beta',3);
insert into om_item values ('c','gama',4);
--left side is om_item and right will have batch items where batch qty will be accumulated upon choose arrows.
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Jul 13, 2011
t1
col1 col2 col3
1 10 100
2 20 200
3 30 300
How to calculate sum of left diagonal of table t1
1,20,300=321
Give me the query
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Nov 22, 2010
i am trying to left join a selection of two or more tables. what i have found, and solved part of my problem, is that oracle left joins only the last table in the select statement ...
i.e : select * from A, B left join C on C.id = A.id wouldn't work because left join applies to B and not A.
but as my queries grow i need to make something as follows :
select * from A, B
left join C on (C.ID_A = A.ID and C.ID_B = B.ID)
[... evantually more left joins as the preceding one may go here]
this query works for DB2 but Oracle claims that "A"."ID" is an invalid identifier, while the B.ID is recognized since it's the last table stated before the "LEFT JOIN" keyword.
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Jun 17, 2010
I have the following 2 SQLs ; one return 1 row, another one is no row returned.
select v.value
from v$parameter v
where v.name = 'cpu_count';
return value "1"
select o.value
from v$osstat o
where o.stat_name = 'NUM_CPU_CORES';
No row returned.
combine the above two in to 1 SQL, and return 1 , null or 1, 1. I assume we can get it with left join for the condition "o.stat_name (+) = 'NUM_CPU_CORES'" , but no row returned for the following SQL. How could we get the result for 1, null for this case?
select v.value, o.value -- or NVL(o.value, 1)
from v$parameter v, v$osstat o
where v.name = 'cpu_count'
and o.stat_name (+) = 'NUM_CPU_CORES';
no row returned
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Feb 5, 2012
I am trying to develop an application of cars. The car have marques example :
TOYOTA,HUNDAI,CHEVROLET
each mark have families example: TOYOTA have Hilux, yaris corola, CHEVROLET have opra,...etc. Each family have a lot of models example: hilux have h2kn-clim,.. etc. And finally there are some options witch are generally in all cars example Radio-k7,air-conditioner ... etc.
option 1..n-----------------1..n model the relation call(opt_mod)
i did develop the block of marques (master) and the block of families (detail) in a form 1. i did develop the bock of models(master) in form 2 and the is no problem. but i want to add to form 2 the block of (opt_mod) but the user did tell me that he want to to see all options with check boxes .
As a solution of this problem i want to build a block on LEFT JOIN between table :option and table :opt_mod
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Apr 14, 2010
how to assign the values by taking the values on LEFT HAND SIDE DYNAMICALLY.
Say if I have a,b,c,d in an array then I need to take variables from the array and assign some values to it. Like a=1;b=2;c=3;d=4;
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Jul 27, 2012
What is the fundamental difference between MINUS keyword and LEFT outer join in Oracle.
I can achieve same results using either one of them.
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Jul 20, 2011
We just upgraded to 11g and have run into incorrect results for some of our LEFT JOINs. If the table, view, subquery, or WITH clause that is being LEFT JOINed to contains any constants, the results are not correct.
For example, a test (nonsensical) view such as the following is created:
create or replace view fyvtst1 as
select spriden_pidm as fyvtst1_pidm,
'Sch' as fyvtst1_test
from spriden
where spriden_last_name like 'Sch%' ;
When I run the following query, I get correct results; that is, only those with "Sch" starting their last name are listed.
select spriden_pidm, spriden_last_name, fyvtst1_pidm, fyvtst1_test
from spriden
join fyvtst1 on fyvtst1_pidm = spriden_pidm ;
However, when I change the JOIN to a LEFT JOIN, the last column contains "Sch" for all rows, instead of NULL:
select spriden_pidm, spriden_last_name, fyvtst1_pidm, fyvtst1_test
from spriden
left join fyvtst1 on fyvtst1_pidm = spriden_pidm ;
We've discovered other quirky things related to this. A WITH clause with similar logic as the above view, when LEFT JOINed to a table will also cause the constant to appear in each row, instead of NULL (and only the value where there is a join). But when additional columns are added to the WITH, it behaves correctly.
This is easy enough to rewrite - but we have WITHs and views containing constants in numerous places, and cannot hope to track down every single one successfully before the incorrect results are used.
Finally, the NO_QUERY_TRANSFORMATION hint will force the query to work correctly. Unfortunately, it has a huge negative performance impact (one query ran for an hour, vs. 1 second in 10g).
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Nov 7, 2011
I am trying to understand "ordered" hint. I want to use it in my sql where I am using some left outer joins. I believe if I use this ordered hint it will be much faster.
But the problem is I am not able to understand the concept of this hint. As i did alot of search on this eveyone says it will be , even I got some similar references where it worked But I am getting contradicting explanation for on this.
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