I can not run the control file treace file,why?
[oracle@hxl oradata_bak]$ more run_sql.sql
CREATE CONTROLFILE REUSE DATABASE "ORACL" RESETLOGS ARCHIVELOG
MAXLOGFILES 16
MAXLOGMEMBERS 3
MAXDATAFILES 100
[code]...
I am trying to create a new controlfile. I used "alter database backup controlfile to trace;" and then I copied and pasted the contents of the trace file into the .sql file. My sql script is
CREATE CONTROLFILE SET DATABASE "FIVESTAR" RESETLOGS NOARCHIVELOG
MAXLOGFILES 16
MAXLOGMEMBERS 3
MAXDATAFILES 100
MAXINSTANCES 8
MAXLOGHISTORY 292
[code]....
Actually, the name of my database was 'STAR' and I changed it to "FIVESTAR" int this .sql script. Now when I run this script with SQL> @ <path of my sql script>, it gives me the following errors:
ERROR at line 1:
ORA-01503: CREATE CONTROLFILE failed
ORA-01504: database name 'FIVESTAR' does not match parameter db_name 'STAR'
I was doing some R&D on my test machine trying to understand how controlfile works. I started up my db and then deleted (renamed)the controlfiles at OS level. I was expecting the db to shutdown. But it dint. Moreover when i queried select name from v$controlfile; it was still reflecting the old controlfile names. To check if it was still functioning, i created a new tablespace with one file and it also got created without any error.
What i dint understand is how could the db still be running when the control file was'nt there and new tablespace and datafile get created? As i understand, whenever a new file is created, an entry is made in the control file. But when control file dint exist where was the data about new tablespace and datafile written?
I am not able to create control file from scrip . it showing following error
ORA-01081: cannot start already-running ORACLE - shut it down first
CHARACTER SET WE8ISO8859P1
*
ERROR at line 19:
ORA-02236: invalid file name
SQL> select checkpoint_change#,controlfile_change# from v$database;
CHECKPOINT_CHANGE# CONTROLFILE_CHANGE#
------------------ -------------------
203454 204955
what's the difference between checkpoint_change# and controlfile_change#.
what's the checkpoint_change# use for ? does it use for recover ?
what's the controlfile_change# use for ?
when the controlfile_change# will be increase ?
SQL> select controlfile_sequence# from v$database;
CONTROLFILE_SEQUENCE#
---------------------
293
Qs.) what is controlfile_sequence# ?
What's the maximum size of the control file in one database ?
i calculated it according to the following steps:
SQL>SELECT (BLOCK_SIZE/1024/1024)*20000 MB FROM V$CONTROLFILE WHERE ROWNUM = 1;
MB
------
312.5
The maximum number of the data block in one control file is 20000.
1)How a single control file is enough to have all the transaction's SCN no for older transactions.
Eg - A transaction has the SCN 01 and after a month the new transaction's SCN is 502. Is the control file holding all those (01 to 502) SCN in it or just will have the latest SCN no (ie - 502).
SQL> select block_size from v$controlfile;
BLOCK_SIZE
----------
16384
SQL> show parameter db_block_size;
NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
db_block_size integer 8192
the 2 can have difference block size?
I am using oracle 10g R2. Some how control file is corrupted and database is not open. and there is no backup of control file. Now i need to open the database without recreating the database.
View 5 Replies View Relatedi missed a tablespace that includes more than 20,000 indexes for reason. there is nothing to do with it without recreate these indexes.i could find these index's ddl createment from "dbms_metadata.get_ddl" packages.
but the DDL createment like this:
CREATE UNIQUE INDEX "AMV"."SYS_IL0000241510C00002$$" ON "AMV"."DR$AMV_C_CHANNELS_DESC_CTX$R" (
PCTFREE 10 INITRANS 2 MAXTRANS 255 COMPUTE STATISTICS
STORAGE(INITIAL 524288 NEXT 524288 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT)
TABLESPACE "APPS_TS_TX_IDX"
PARALLEL (DEGREE 0 INSTANCES 0)
PCTFREE 10 INITRANS 2 MAXTRANS 255 COMPUTE STATISTICS
*ERROR at line 2: ORA-00936: missing expression
note: this tablespace is in ORACLE EBS R11 name "APPS_TS_TX_IDX" how to recreate LOBINDEX?
recreate paramater file if you lost init.ora or spfile.ora
STEPS
SQL> startup
ORA-01078: failure in processing system parameters
LRM-00109: could not open parameter file 'D:ORACLEORA92DATABASEINITGPT2.ORA'
How to resolve ORA-01078 with LRM-00109 error?
For resolving these error, you should need to replace init.ora or spfile if you have backup of same files. If you don't have backup then go to alert.log and copy all parameters in one file and save as "init.ora". Modify same init.ora with some parameters which need single quotation mark " ' " like background_dump_dest,controlfiles,db_name and "dispatchers ......)". Connect as sysdba in SQL*Plus and execute command "create spfile from pfile=" or startup pfile or startup.
I cannot start our Enterprise Manager services for our newly created db. I'm encountering this error:
"$ emctl start dbconsole
Unable to locate file /appl1/home/oracle/10.2/xxx-dbs_abcd/sysman/config/emd.properties : No such file or directory"
I've been executing this command for a no. of times at the ORACLE_HOME directory:
$ ./emca -config dbcontrol db -repos create
.. but still I cannot start EMCTL dbconsole.
Is it possible to use where clause to discard one of the item which is not able to fit into column because of the length constraint.
Example:
1.Remove first digit from the item_ID where ITEM_ID IN (12345)
2.Do not load data WHERE ITEM_ID IN (12345)
I'm having a problem with SQL loader and the control file. I want to load a delimited file. The script will eventually be automated where the file name is passed in to the script, it's not a static name.
It's a simple SQL loader Unix script that I have created as follows
Unix file called test_load
# Auto Load
#
#
export data_file=/dev/test_$1$2.csv;
export ORACLE_HOME=/u01/oracle/product/10.2.0;
export ORACLE_SID=XXX;
export PATH=$PATH:$ORACLE_HOME/bin;
sqlldr userid=XXX/XXX data=$data_file
control=/dev/cntrl/test.ctl
errors=99999
bad=/dev/bad/test_$1$2_$$.bad
log=/dev/logs/test_$1$2_$$.log
the top of my control file is as follows
load data
truncate
into table test
fields terminated by "|"
when record_type = 'AA'
(
running at the prompt ./test_load myload 20100319
The following error occurs
SQL*Loader-350: Syntax error at line 5.
Expecting "(", found keyword when.
when record_type = 'AA'
^
I believe the format of my control file is correct but for some reason it won't load.
I have a csv file extracted from mainframe which has to be loaded into oracle using sqlldr utility.The numbers are in the format +0000003333, -0000003232.44 etc
I have to convert it to 3333 and -3232.44 and insert into the table.
I have used syntax like
Load file....append into table (t_num expression "to_number(':tnum,'99999.999')")
This gives me an invalid number error.
The reason "why sql loader's CONTROL FILE is not working, if that location has space in between"
E.g. - C:practice for sqlloadercontrol1.ctl
But it works if we remove the space in between the path as below:
E.g. - C:practice_for_sqlloadercontrol1.ctl
I tried a lot to load data to table from excel(.csv) using sql*loader the oracle version of sql*loader doesn't support the control file created using notepad(.ctl).Though i given a filename with extension as .ctl it seems as a .txt file. Is there any alternate way to create it?
View 3 Replies View RelatedI am loading data using sqlldr command in UNIX to an oracle table and want to concatenate timestamp to a file name in the "create_file_name" column in the code below.
I have the below code within the control file..
LOAD DATA
TRUNCATE
INTO TABLE TABLEA
TRAILING NULLCOLS
(
file_type POSITION(1:5) CHAR,
business_date POSITION(16:23) DATE "YYYYMMDD",
create_file_name "FILE_NAME" EXPRESSION "SELECT TO_CHAR(CURRENT_TIMESTAMP(3), 'YYYYMMDDHH24MISS') FROM DUAL")
The load fails with SQL Loader error: "Expecting valid column specification, ",", ")", found keyword EXPRESSION found instead of column. How the timestamp to a filename can be appended?
I am using perl script to dynamically generate the control file.If I have data in the control file as well as in the datafile, how would i write the control file in that case. Is the below one correct?
load data
INFILE '*'
INFILE '/export/home/test/test.csv'
INSERT INTO TABLE EMP fields
terminated by "," optionally enclosed by '"'
trailing nullcols
( empno, empname, sal, deptno )
[code]....
Is there any way that if my control file contains half of the data and my data file contains the other half of the data can i club this data into a logical record in the control file to populate the DB?
My exact 2nd requirement is, my DB contains 5 cols and for 1 col the data is common(countryName) which i have to pass to the control file dynamically and the .csv file contains the data for the other four cols. How could i combine these in the ctrl file and populate the DB?
so if the DB contains CountryName, empid, ename, sal and dept..I will get the CountryName to the ctrl file and csv contains the data for empid, ename, sal and dept. How would i combine these data into a logical record and populate the DB?
I am trying to generate dynamic control file, as the files I want to upload are coming from different source and their name is constantly changing but following a fix pattern and naming convention.
I am able to generate dynamic control file through SQL. But while calling from BATCH file, i am unable to sent the file name as parameter.
All the examples i have searched are for UNIX, how to do it with BATCH File in WINDOWS.
I have a control file like following:
LOAD DATA
INFILE *
INTO TABLE member
REPLACE
FIELDS TERMINATED BY '|' OPTIONALLY ENCLOSED BY '"'
(
control_id,
name,
address
)
problem is that control_id value is not in data file and I have to assign to each row the same value generated from sequence or from unix variable.
For example, after I run sqlldr, I have to have records in the table like following:
control_id name address
---------- ---- -------
1847 Charlie 250 yonge st
1847 Peter 5 Brookbanks dr
1847 Ben 123 King st
.
.
.
How do I do that?
how to create control file and how to load the data through command window in our database using sql * loader.i am having structure in my database and .csv file in my desktop.
View 20 Replies View RelatedMy oracle table having 2 fields.
filed1 VARCHAR(500)
field2 NUMBER.
i load data to this table from a file using sqlldr.
what is the proper data type should i use in control-file for both the fields.? i dont mention any datatye in ctl file which is working fine with given dataset.
The following control file updates multiple rows in database table.
LOAD DATA
INFILE *
replace
INTO TABLE temp_tab
FIELDS TERMINATED BY ","
(Data LOBFILE(CONSTANT cadd_pass.xml) terminated by eof
There are 21 lines in the xml. So 21 rows are updated in table.update only one row?
My Table structure
column1 varchar(10)
column2 Date
Column3 varcahr(2)
Column4 varcahr(2)
By Data file
asds 12/12/2001asas
textsd asds
asds 12/12/2001asas
ramkiy asds
I still want to insert row 2 and row 4 into table by defaulting the date. how can I handle this in control file?
I have a table revenue
create table revenue
(
person varchar2(23),
month varchar2(3),
rev_amt number
)
and i have data in a file like below
Person Jan Feb Mar Apr Mai Jun Jul Aug Sep Oct Nov Dez
--------------------------------------------------------
Schnyder,345,223,122,345,324,244,123,123,345,121,345,197
Weber,234,234,123,457,456,287,234,123,678,656,341,567
Keller,596,276,347,134,743,545,216,456,124,753,346,456
Meyer,987,345,645,567,834,567,789,234,678,973,456,125
Holzer,509,154,876,347,146,788,174,986,568,246,324,987
Müller,456,125,678,235,878,237,567,237,788,237,324,778
Binggeli,487,347,458,347,235,864,689,235,764,964,624,347
Stoller,596,237,976,876,346,567,126,879,125,568,124,753
Marty,094,234,235,763,054,567,237,457,325,753,577,346
Studer,784,567,235,753,124,575,864,235,753,864,634,678
i want to load it into the table in the following way.
Person Month Revenue
-------------------------
Schnyder Jan 345
Schnyder Feb 223
Schnyder Mar 122
Schnyder Apr 345
Schnyder Mai 324
Schnyder Jun 244
Schnyder Jul 123
Schnyder Aug 123
Schnyder Sep 345
Schnyder Oct 121
Schnyder Nov 345
Schnyder Dez 197
........ ... ...
How to write control file to load this data into the above revenue table.
i have two tablespaces dictionary managed (SYSTEM,APPLSYSX) i tried to change to locally cause it will cause problem in future when trying to run OATM migration.i did it successfully on APPLSYSX,when i did it on system upon oracle procedure.i have to change all tablespaces to read only when i did that with tablespace APPLSYSD(alter tablespace APPLSYSD read only) i received errors
SQL> alter tablespace APPLSYSD READ ONLY;
alter tablespace APPLSYSD READ ONLY
*
ERROR at line 1:
ORA-01230: cannot make read only - file 636 is offline
ORA-01111: name for data file 636 is unknown - rename to correct file
ORA-01110: data file 636: '/vol5u/oracle/prddb/9.2.0/dbs/MISSING00636'
i have not this file on the OS
I have to load data file into a table. And the requirement is as below:
Input Data:
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|Siva 1234
The data should be inserted only in two rows as below:
When Value in first 3 fields is same, 4th field should be appended to the existing value in table.
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a testThis is a testThis is a testSiva 1234
is there any way you can get the name of the file loading the table in a control file? i have a table with a column called source_file, and need to populate it during the load.
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