My Table structure
column1 varchar(10)
column2 Date
Column3 varcahr(2)
Column4 varcahr(2)
By Data file
asds 12/12/2001asas
textsd asds
asds 12/12/2001asas
ramkiy asds
I still want to insert row 2 and row 4 into table by defaulting the date. how can I handle this in control file?
The following control file updates multiple rows in database table.
LOAD DATA
INFILE *
replace
INTO TABLE temp_tab
FIELDS TERMINATED BY ","
(Data LOBFILE(CONSTANT cadd_pass.xml) terminated by eof
There are 21 lines in the xml. So 21 rows are updated in table.update only one row?
how to create control file and how to load the data through command window in our database using sql * loader.i am having structure in my database and .csv file in my desktop.
View 20 Replies View RelatedI have a table revenue
create table revenue
(
person varchar2(23),
month varchar2(3),
rev_amt number
)
and i have data in a file like below
Person Jan Feb Mar Apr Mai Jun Jul Aug Sep Oct Nov Dez
--------------------------------------------------------
Schnyder,345,223,122,345,324,244,123,123,345,121,345,197
Weber,234,234,123,457,456,287,234,123,678,656,341,567
Keller,596,276,347,134,743,545,216,456,124,753,346,456
Meyer,987,345,645,567,834,567,789,234,678,973,456,125
Holzer,509,154,876,347,146,788,174,986,568,246,324,987
Müller,456,125,678,235,878,237,567,237,788,237,324,778
Binggeli,487,347,458,347,235,864,689,235,764,964,624,347
Stoller,596,237,976,876,346,567,126,879,125,568,124,753
Marty,094,234,235,763,054,567,237,457,325,753,577,346
Studer,784,567,235,753,124,575,864,235,753,864,634,678
i want to load it into the table in the following way.
Person Month Revenue
-------------------------
Schnyder Jan 345
Schnyder Feb 223
Schnyder Mar 122
Schnyder Apr 345
Schnyder Mai 324
Schnyder Jun 244
Schnyder Jul 123
Schnyder Aug 123
Schnyder Sep 345
Schnyder Oct 121
Schnyder Nov 345
Schnyder Dez 197
........ ... ...
How to write control file to load this data into the above revenue table.
what i miss to load date and time from text file to oracle table through sqlloader
this is my data in this path (c:externalmy_data.txt)
7369,SMITH,17-NOV-81,09:14:04,CLERK,20
7499,ALLEN,01-MAY-81,17:06:08,SALESMAN,30
7521,WARD,09-JUN-81,17:06:30,SALESMAN,30
7566,JONES,02-APR-81,09:24:10,MANAGER,20
7654,MARTIN,28-SEP-81,17:24:10,SALESMAN,30
my table in database emp2
create table emp2 (empno number,
ename varchar2(20),
hiredate date,
etime date,
ejob varchar2(20),
deptno number);
the control file code in this path (c:externalctrl.ctl)
load data
infile 'C:externalmy_data.txt'
into table emp2
fields terminated by ','
(empno, ename, hiredate, etime, ejob, deptno)
this is the error :
C:>sqlldr scott/tiger control=C:externalctrl.ctl
SQL*Loader: Release 10.2.0.1.0 - Production on Mon May 31 09:45:10 2010
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Commit point reached - logical record count 5
C:>
Is it possible to use where clause to discard one of the item which is not able to fit into column because of the length constraint.
Example:
1.Remove first digit from the item_ID where ITEM_ID IN (12345)
2.Do not load data WHERE ITEM_ID IN (12345)
I'm having a problem with SQL loader and the control file. I want to load a delimited file. The script will eventually be automated where the file name is passed in to the script, it's not a static name.
It's a simple SQL loader Unix script that I have created as follows
Unix file called test_load
# Auto Load
#
#
export data_file=/dev/test_$1$2.csv;
export ORACLE_HOME=/u01/oracle/product/10.2.0;
export ORACLE_SID=XXX;
export PATH=$PATH:$ORACLE_HOME/bin;
sqlldr userid=XXX/XXX data=$data_file
control=/dev/cntrl/test.ctl
errors=99999
bad=/dev/bad/test_$1$2_$$.bad
log=/dev/logs/test_$1$2_$$.log
the top of my control file is as follows
load data
truncate
into table test
fields terminated by "|"
when record_type = 'AA'
(
running at the prompt ./test_load myload 20100319
The following error occurs
SQL*Loader-350: Syntax error at line 5.
Expecting "(", found keyword when.
when record_type = 'AA'
^
I believe the format of my control file is correct but for some reason it won't load.
I have a csv file extracted from mainframe which has to be loaded into oracle using sqlldr utility.The numbers are in the format +0000003333, -0000003232.44 etc
I have to convert it to 3333 and -3232.44 and insert into the table.
I have used syntax like
Load file....append into table (t_num expression "to_number(':tnum,'99999.999')")
This gives me an invalid number error.
The reason "why sql loader's CONTROL FILE is not working, if that location has space in between"
E.g. - C:practice for sqlloadercontrol1.ctl
But it works if we remove the space in between the path as below:
E.g. - C:practice_for_sqlloadercontrol1.ctl
I tried a lot to load data to table from excel(.csv) using sql*loader the oracle version of sql*loader doesn't support the control file created using notepad(.ctl).Though i given a filename with extension as .ctl it seems as a .txt file. Is there any alternate way to create it?
View 3 Replies View Relatedwe are using sqlldr to load data into table.we have data in a csv file as below
"TXN_DATE","TXN_HOUR","VID","HID"
"2010-05-18 20:00:00.0","20","184","212"
"2010-05-18 21:00:00.0","21","184","212"
"2010-05-19 17:00:00.0","17","184","212"
I just want to insert only date without timestamp from the first field TXN_DATE. i.e., i just want 2010-05-18 in my table column.
my table desc is
Name Null? Type
----------------------------------------- -------- ---------
SEQID NUMBER(5)
TXN_DATE NOT NULL DATE
TXN_HOUR NOT NULL NUMBER(2)
VID NOT NULL NUMBER(5)
HID NOT NULL NUMBER(5)
i tried many combination but i couldn't achieve. right now i am able to get only the complete date with timestamp using the following control file.
APPEND INTO PERF_STATS
FIELDS TERMINATED BY ',' optionally ENCLOSED BY '"'
TRAILING NULLCOLS
[Code].....
I am trying to insert rows in two tables using sql loader.
I have two tables in database as
SQL> desc name
Name Null? Type
---------------------- -------- ------------
ID NUMBER
NAME VARCHAR2(20)
BD DATE
SQL> desc name3
Name Null? Type
--------------------- ----------- -------------
ID NUMBER
NAME VARCHAR2(20)
BD DATE
I created controlfiles as
[oracle@DBTEST sqldri]$ cat datafile.ctl
options (direct=true)
load data
INFILE *
into table name truncate
when id='1'
[code]....
when i run sql loader as
[oracle@DBTEST sqldri]$ sqlldr hr/hr control=/u01/sqldri/datafile.ctl
SQL*Loader: Release 10.2.0.1.0 - Production on Tue Aug 7 23:30:07 2012
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Load completed - logical record count 2.
no rows is inserted..the log file contain entries as
[oracle@DBTEST sqldri]$ cat datafile.log
SQL*Loader: Release 10.2.0.1.0 - Production on Tue Aug 7 23:30:07 2012
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Control File: /u01/sqldri/datafile.ctl
Data File: /u01/sqldri/datafile.ctl
Bad File: /u01/sqldri/datafile.bad
[code]....
I am loading data using sqlldr command in UNIX to an oracle table and want to concatenate timestamp to a file name in the "create_file_name" column in the code below.
I have the below code within the control file..
LOAD DATA
TRUNCATE
INTO TABLE TABLEA
TRAILING NULLCOLS
(
file_type POSITION(1:5) CHAR,
business_date POSITION(16:23) DATE "YYYYMMDD",
create_file_name "FILE_NAME" EXPRESSION "SELECT TO_CHAR(CURRENT_TIMESTAMP(3), 'YYYYMMDDHH24MISS') FROM DUAL")
The load fails with SQL Loader error: "Expecting valid column specification, ",", ")", found keyword EXPRESSION found instead of column. How the timestamp to a filename can be appended?
I am using perl script to dynamically generate the control file.If I have data in the control file as well as in the datafile, how would i write the control file in that case. Is the below one correct?
load data
INFILE '*'
INFILE '/export/home/test/test.csv'
INSERT INTO TABLE EMP fields
terminated by "," optionally enclosed by '"'
trailing nullcols
( empno, empname, sal, deptno )
[code]....
Is there any way that if my control file contains half of the data and my data file contains the other half of the data can i club this data into a logical record in the control file to populate the DB?
My exact 2nd requirement is, my DB contains 5 cols and for 1 col the data is common(countryName) which i have to pass to the control file dynamically and the .csv file contains the data for the other four cols. How could i combine these in the ctrl file and populate the DB?
so if the DB contains CountryName, empid, ename, sal and dept..I will get the CountryName to the ctrl file and csv contains the data for empid, ename, sal and dept. How would i combine these data into a logical record and populate the DB?
I am trying to generate dynamic control file, as the files I want to upload are coming from different source and their name is constantly changing but following a fix pattern and naming convention.
I am able to generate dynamic control file through SQL. But while calling from BATCH file, i am unable to sent the file name as parameter.
All the examples i have searched are for UNIX, how to do it with BATCH File in WINDOWS.
I have a control file like following:
LOAD DATA
INFILE *
INTO TABLE member
REPLACE
FIELDS TERMINATED BY '|' OPTIONALLY ENCLOSED BY '"'
(
control_id,
name,
address
)
problem is that control_id value is not in data file and I have to assign to each row the same value generated from sequence or from unix variable.
For example, after I run sqlldr, I have to have records in the table like following:
control_id name address
---------- ---- -------
1847 Charlie 250 yonge st
1847 Peter 5 Brookbanks dr
1847 Ben 123 King st
.
.
.
How do I do that?
My oracle table having 2 fields.
filed1 VARCHAR(500)
field2 NUMBER.
i load data to this table from a file using sqlldr.
what is the proper data type should i use in control-file for both the fields.? i dont mention any datatye in ctl file which is working fine with given dataset.
I have to load data file into a table. And the requirement is as below:
Input Data:
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|Siva 1234
The data should be inserted only in two rows as below:
When Value in first 3 fields is same, 4th field should be appended to the existing value in table.
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a testThis is a testThis is a testSiva 1234
I have another interesting SQL Loader issue. I have created 2 prior topics RE: "Trapping SQL Loader summary counts" and "Using Sql Loader issue". This new issue is along the same lines, but unfortunately the same input csv file has a date field that is has a different input format..
The 10G Oracle Table looks like...
---------------------------
CREATE TABLE PTLIVE.MODULE_CSV_LOADS
( MODULE_ID NUMBER (20),
MODULE_TAGNUMBER VARCHAR2(100),
MODULE_SERIAL_NUMBER NUMBER (20,0),
[code]...
My initial control file looks like...
-----------------
OPTIONS (SKIP=1)
load data
infile 'J:GrowerRound_ModulesCrop2011ProcessedBatch_2011Jul12_081326_746563.csv'
BADFILE 'J:GrowerRound_ModulesCrop2011LogsBatch_2011Jul12_081326_746563.bad'
[code]...
The input csv data file (for this example) contains 3 records. The first is a heading record that is skipped. The 2nd record
is correct and the field entitled "GMT Date" contains a value of
"16/05/2011". The 3rd record, however, has a date of "2011/5/18", which get rejected by the above control file, as the output SQL Loader log indicates...
Record 2: Rejected - Error on table PTLIVE.MODULE_CSV_LOADS, column DATEPICKED.
ORA-01861: literal does not match format string
Now we will be receiving literally hundreds of these csv files and in testing I have found that when I open the csv file (the default is Excel), and Excel must alter its display, as all date appear 100% okay. However, upon opening the csv file with Wordpad, I discovered the dates in the same file had these 2 different formats. So the control file was attempting to concat the input csv file "GMT Date" in one format with the input "GMT_TIME" to load the output value into the Oracle table column
"DATEPICKED" ... but different date formats cause some records to be rejected.
It would be super if SQl Loader could use a IF clause or an OR clause to execute loading the date in one or more input formats. We only expect the 2 foramts DD/MM/YYYY or YYYY/MM/DD....however, there could be 6 different combinations in theory.
I thought about writing a Function or Procedure to analyst the input date and output a standard one to load into the Oracle column
I want to know how to add date/time in export dump file in Linux using parfile script. I keep getting an error "contain an invalid substitution variables"
my parfile is:
Dumpfile = Daily_Full_%U_`date "+%Y%m%d%H%S"`.dmp or
Dumpfile = Daily_Full_%U_`%date%`.dmp
l am loading data i.e text file of huge size into oracle 9i db using sqlldr through command prompt, but my table contains already some data so while loading it shows error as
SQL*Loader-601: For INSERT option, table must be empty.
i cant truncate my table since present data is important.
I am using OWB to load a table which write sql loader command. When running the load i am getting below error.
SQL*Loader-643: error executing INSERT statement for table "STG_EWORK"."STG_ISF_LUCC"
I am unable to guess which privileges is missing.
My control file as below
OPTIONS (SKIP=2,BINDSIZE=50000,ERRORS=0,ROWS=200,READSIZE=65536)
LOAD DATA
CHARACTERSET WE8MSWIN1252
INFILE '\devora003.dev.tfl.localPDWPDW_SourceISF_LUCC_Loadfile.csv'
CONCATENATE 1
INTO TABLE "STG_EWORK"."STG_ISF_LUCC"
[code]....
how to insert data in oracle table without writing insert statement in oracle 9i or above. i am not going to write insert all, merge, sqlloder and import data.
View 2 Replies View Relatedis it possible to import only one or two table from a schema export file or from a full database export file.
View 2 Replies View RelatedBelow is the external table definition and the content of csv file, why the first record fails ?
0546-0*LB-CRP*16*"Tech", ZAO*29-DEC-2009*29-DEC-2010***A051453*RU*29-DEC-2009*0***21-MAY-2010*21-MAY-2010 --FAILED
0546-0*LB-CRP*16*ID"Tech", ZAO*29-DEC-2009*29-DEC-2010***A051453*RU*29-DEC-2009*0***21-MAY-2010*21-MAY-2010 -- SUCCESS
0546-0*LB-CRP*16*"Tech, ZAO"*29-DEC-2009*29-DEC-2010***A051453*RU*29-DEC-2009*0***21-MAY-2010*21-MAY-2010 -- SUCCESS
[code]....
I am having query regarding sql loader. my data file is comm(,) seperated and I want to load the whole file in oracle table 'bill_temp' except 1st column data of data file.
e.g.
File name: bill_file.dat
fields seperated by comma ','
values are like
emp_id,emp_name,emp_sal,join_date
oracle table bill_temp having the below column:
emp_name,emp_sal,join_date
Here I want load the emp_name,emp_sal and join_date into oracle table bill_temp.
emp_id should not get loaded into table.
Is there any way to skip the loading of particular column data from data file into table?
I have a text file called ReturnedFile.txt. This is a comma separated text file that contains records for two fields.... Envelope and Date Returned.
At the same time, I have a table in Oracle called Manifest. This table contains the following fields:
Envelope
DateSentOut
DateReturned
I need to write something that imports the ReturnedFile.txt into a temporary Oracle table named UploadTemp, and then compares the data in the Envelope field from UploadTemp with the Envelope field in Manifest. If it's a match, then the DateReturned field in Manifest needs updated with the DateReturned field in UploadTemp.
I've done this with SQL Server no problem, but I've been trying for two days to make this work with Oracle and I can't figure it out. I've been trying to use SQL*Loader, but I can't even get it to run properly on my machine.
I did create a Control file, saved as RetFile.ctl. Below is the contents of the CTL file:
LOAD DATA
INFILE 'C:OracleTestReturnedFile.txt'
APPEND
INTO TABLE UploadTemp
FIELDS TERMINATED BY "'"
(
ENVELOPE,
DATERETURNED
)
If I could get SQL*Loader running, below is the code I came up with to import the text file and then to do the compare to the Manifest table and update as appropriate:
sqlldr UserJoe/Password123 CONTROL=C:OracleTestRetFile.ctl LOG=RetFile.log BAD=RetFile.bad
update Manifest m set m.DateReturned =
(select t.DateReturned
from UploadTemp t
where m.Envelope = t.Envelope
*)
That's all I got. As I said, I can't find a way to test it and I have no idea if it's even close.
My requirement is to to truncate the table and load it with the data present in file. In the control file, I used the "TRUNCATE" command as well.In case, if the file has some invalid data and sqlldr fails, my existing data will be lost. Is there any option in which the sqlldr does not TRUNCATE the table in case of a failure.
View 6 Replies View RelatedI have dump file of 17 GB,which i want to import in my database db1 in user amol ;so i created new user under db1 as below ,before this i have created tablespace so that i can import my data only to that tablespace only. My steps are as below.
CREATE TABLESPACE ptaxold1 DATAFILE '/home/oracle/oracle/product/10.2.0/oradata/cvsdbm/ptaxold1.dbf' SIZE 6024M AUTOEXTEND ON;
create user amol identified by amol default tablespace ptaxold1 temporary tablespace tem; imp amol/amol then i mentioned my dump file but after importing it does not show any table under user amol.
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)