how to create control file and how to load the data through command window in our database using sql * loader.i am having structure in my database and .csv file in my desktop.
View 20 RepliesI tried a lot to load data to table from excel(.csv) using sql*loader the oracle version of sql*loader doesn't support the control file created using notepad(.ctl).Though i given a filename with extension as .ctl it seems as a .txt file. Is there any alternate way to create it?
View 3 Replies View RelatedMy Table structure
column1 varchar(10)
column2 Date
Column3 varcahr(2)
Column4 varcahr(2)
By Data file
asds 12/12/2001asas
textsd asds
asds 12/12/2001asas
ramkiy asds
I still want to insert row 2 and row 4 into table by defaulting the date. how can I handle this in control file?
I am using perl script to dynamically generate the control file.If I have data in the control file as well as in the datafile, how would i write the control file in that case. Is the below one correct?
load data
INFILE '*'
INFILE '/export/home/test/test.csv'
INSERT INTO TABLE EMP fields
terminated by "," optionally enclosed by '"'
trailing nullcols
( empno, empname, sal, deptno )
[code]....
Is there any way that if my control file contains half of the data and my data file contains the other half of the data can i club this data into a logical record in the control file to populate the DB?
My exact 2nd requirement is, my DB contains 5 cols and for 1 col the data is common(countryName) which i have to pass to the control file dynamically and the .csv file contains the data for the other four cols. How could i combine these in the ctrl file and populate the DB?
so if the DB contains CountryName, empid, ename, sal and dept..I will get the CountryName to the ctrl file and csv contains the data for empid, ename, sal and dept. How would i combine these data into a logical record and populate the DB?
What is difference when you issue a create controlfile with "standby" keyword on the primary database
ALTER DATABASE CREATE STANDBY CONTROLFILE AS '/path/db_stby.ctl';
vs. creating a control using
ALTER DATABASE BACKUP CONTROLFILE to '/path/db_control.ctl';
what does ORACLE put into the standby control that is "extra"? ie. what is the difference between a standby control file and a normal control file?
My oracle table having 2 fields.
filed1 VARCHAR(500)
field2 NUMBER.
i load data to this table from a file using sqlldr.
what is the proper data type should i use in control-file for both the fields.? i dont mention any datatye in ctl file which is working fine with given dataset.
The following control file updates multiple rows in database table.
LOAD DATA
INFILE *
replace
INTO TABLE temp_tab
FIELDS TERMINATED BY ","
(Data LOBFILE(CONSTANT cadd_pass.xml) terminated by eof
There are 21 lines in the xml. So 21 rows are updated in table.update only one row?
I have a table revenue
create table revenue
(
person varchar2(23),
month varchar2(3),
rev_amt number
)
and i have data in a file like below
Person Jan Feb Mar Apr Mai Jun Jul Aug Sep Oct Nov Dez
--------------------------------------------------------
Schnyder,345,223,122,345,324,244,123,123,345,121,345,197
Weber,234,234,123,457,456,287,234,123,678,656,341,567
Keller,596,276,347,134,743,545,216,456,124,753,346,456
Meyer,987,345,645,567,834,567,789,234,678,973,456,125
Holzer,509,154,876,347,146,788,174,986,568,246,324,987
Müller,456,125,678,235,878,237,567,237,788,237,324,778
Binggeli,487,347,458,347,235,864,689,235,764,964,624,347
Stoller,596,237,976,876,346,567,126,879,125,568,124,753
Marty,094,234,235,763,054,567,237,457,325,753,577,346
Studer,784,567,235,753,124,575,864,235,753,864,634,678
i want to load it into the table in the following way.
Person Month Revenue
-------------------------
Schnyder Jan 345
Schnyder Feb 223
Schnyder Mar 122
Schnyder Apr 345
Schnyder Mai 324
Schnyder Jun 244
Schnyder Jul 123
Schnyder Aug 123
Schnyder Sep 345
Schnyder Oct 121
Schnyder Nov 345
Schnyder Dez 197
........ ... ...
How to write control file to load this data into the above revenue table.
Is it possible to use where clause to discard one of the item which is not able to fit into column because of the length constraint.
Example:
1.Remove first digit from the item_ID where ITEM_ID IN (12345)
2.Do not load data WHERE ITEM_ID IN (12345)
I'm having a problem with SQL loader and the control file. I want to load a delimited file. The script will eventually be automated where the file name is passed in to the script, it's not a static name.
It's a simple SQL loader Unix script that I have created as follows
Unix file called test_load
# Auto Load
#
#
export data_file=/dev/test_$1$2.csv;
export ORACLE_HOME=/u01/oracle/product/10.2.0;
export ORACLE_SID=XXX;
export PATH=$PATH:$ORACLE_HOME/bin;
sqlldr userid=XXX/XXX data=$data_file
control=/dev/cntrl/test.ctl
errors=99999
bad=/dev/bad/test_$1$2_$$.bad
log=/dev/logs/test_$1$2_$$.log
the top of my control file is as follows
load data
truncate
into table test
fields terminated by "|"
when record_type = 'AA'
(
running at the prompt ./test_load myload 20100319
The following error occurs
SQL*Loader-350: Syntax error at line 5.
Expecting "(", found keyword when.
when record_type = 'AA'
^
I believe the format of my control file is correct but for some reason it won't load.
I am trying to create a new controlfile. I used "alter database backup controlfile to trace;" and then I copied and pasted the contents of the trace file into the .sql file. My sql script is
CREATE CONTROLFILE SET DATABASE "FIVESTAR" RESETLOGS NOARCHIVELOG
MAXLOGFILES 16
MAXLOGMEMBERS 3
MAXDATAFILES 100
MAXINSTANCES 8
MAXLOGHISTORY 292
[code]....
Actually, the name of my database was 'STAR' and I changed it to "FIVESTAR" int this .sql script. Now when I run this script with SQL> @ <path of my sql script>, it gives me the following errors:
ERROR at line 1:
ORA-01503: CREATE CONTROLFILE failed
ORA-01504: database name 'FIVESTAR' does not match parameter db_name 'STAR'
I have a csv file extracted from mainframe which has to be loaded into oracle using sqlldr utility.The numbers are in the format +0000003333, -0000003232.44 etc
I have to convert it to 3333 and -3232.44 and insert into the table.
I have used syntax like
Load file....append into table (t_num expression "to_number(':tnum,'99999.999')")
This gives me an invalid number error.
The reason "why sql loader's CONTROL FILE is not working, if that location has space in between"
E.g. - C:practice for sqlloadercontrol1.ctl
But it works if we remove the space in between the path as below:
E.g. - C:practice_for_sqlloadercontrol1.ctl
I am not able to create control file from scrip . it showing following error
ORA-01081: cannot start already-running ORACLE - shut it down first
CHARACTER SET WE8ISO8859P1
*
ERROR at line 19:
ORA-02236: invalid file name
I am loading data using sqlldr command in UNIX to an oracle table and want to concatenate timestamp to a file name in the "create_file_name" column in the code below.
I have the below code within the control file..
LOAD DATA
TRUNCATE
INTO TABLE TABLEA
TRAILING NULLCOLS
(
file_type POSITION(1:5) CHAR,
business_date POSITION(16:23) DATE "YYYYMMDD",
create_file_name "FILE_NAME" EXPRESSION "SELECT TO_CHAR(CURRENT_TIMESTAMP(3), 'YYYYMMDDHH24MISS') FROM DUAL")
The load fails with SQL Loader error: "Expecting valid column specification, ",", ")", found keyword EXPRESSION found instead of column. How the timestamp to a filename can be appended?
how to insert data in oracle table without writing insert statement in oracle 9i or above. i am not going to write insert all, merge, sqlloder and import data.
View 2 Replies View RelatedI am trying to generate dynamic control file, as the files I want to upload are coming from different source and their name is constantly changing but following a fix pattern and naming convention.
I am able to generate dynamic control file through SQL. But while calling from BATCH file, i am unable to sent the file name as parameter.
All the examples i have searched are for UNIX, how to do it with BATCH File in WINDOWS.
I have a control file like following:
LOAD DATA
INFILE *
INTO TABLE member
REPLACE
FIELDS TERMINATED BY '|' OPTIONALLY ENCLOSED BY '"'
(
control_id,
name,
address
)
problem is that control_id value is not in data file and I have to assign to each row the same value generated from sequence or from unix variable.
For example, after I run sqlldr, I have to have records in the table like following:
control_id name address
---------- ---- -------
1847 Charlie 250 yonge st
1847 Peter 5 Brookbanks dr
1847 Ben 123 King st
.
.
.
How do I do that?
I have one .mdb (Microsoft Access Database) file and it has some tables in it. I had load it once using toad. But now i have to load it frequently into the database. Is it possible using external table, so i can access that tables using "select" statement.
View 6 Replies View RelatedAre there any GUI based tools that can auto generate a CTL file based off a CSV input? I'd love something like this since I have quite a few SQL*LDR projects coming up!
View 2 Replies View RelatedSQL> select block_size from v$controlfile;
BLOCK_SIZE
----------
16384
SQL> show parameter db_block_size;
NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
db_block_size integer 8192
the 2 can have difference block size?
I am using oracle 10g R2. Some how control file is corrupted and database is not open. and there is no backup of control file. Now i need to open the database without recreating the database.
View 5 Replies View RelatedBy mistakenly Oradata file has been deleted and there is I have not any backup when we Startup the database then we get an Error as
ORA-00205: error in identifying control file, check alert log for more info
Now I want to create controlfile as
Microsoft Windows [Version 6.1.7600]
Copyright © 2009 Microsoft Corporation. All rights reserved.
C:\Users\SARASWATIMAA>SQLPLUS
SQL*Plus: Release 10.2.0.1.0 - Production on Sun Apr 8 23:15:09 2012
Copyright © 1982, 2005, Oracle. All rights reserved.
Enter user-name: SYS AS SYSDBA
Enter password:
[code]...
where is My Mistake in Creating Cotrolfile..I want to know that in which condition we use "SET" or "REUSE" in Create Controlfile.
How to execute the SQLLDR, where Data File Reside in another Server?
View 1 Replies View RelatedI am trying to import .dmp file to my database
I am trying to run the imp command from dos prompt.
Here is the error I got .
C:Documents and SettingssairammMy Documentsartmsexp_AUDT2_04292012>imp
sairamm/mypassword@aws fromuser=AUDT2 toUSER=SAIRAMM file=exp_AUDT2_04292012.dmp
log=imp_AUDT2_04292012.log BUFFE
R=10000000 GRANTS=y
Import: Release 9.2.0.1.0 - Production on Mon Apr 30 14:23:29 2012
Copyright (c) 1982, 2002, Oracle Corporation. All rights reserved.
Connected to: Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production With the Partitioning, Oracle Label Security, OLAP, Data Mining,Oracle Database Vault and Real Application Testing option
IMP-00010: not a valid export file, header failed verification
IMP-00000: Import terminated unsuccessfully
I want to load data from LST file. The data format and control file is given below. It is loading the 1st line only. it is not loading the other lines. pls let me know what needs to be added in the control file to load this data?
Table Scan: |14-DEC-11 09:54 |xest | 16| 0|SYSTEM |ws_email|declare v_lst_suc da|14-DEC-11 08:32:39| 716444|XEST_USER
XEST_USER.X| | | | | |er.exe |te; v_nxt_sch date; | | |
EST_PING_RCV| | | | | | |cur_time varchar2(30| | |
D: 28609 out| | | | | | |); begin --select| | |
of 28609 Bl| | | | | | | last_date, next_dat| | |
ocks done | | | | | | |e into v_lst_suc, v_| | |
[code]....
I want to import 1 .dmp file into oracle database. I dont know what exactly what that .dmp file contains e.g i dont know the Users inside the dump.While importing it gives me the error.
1. Do i need to create those users first and then import if yes then how would i know how many users are inside that dump.
2. Currently the objects are created in SYSTEM user by default. I want to import those objects in the MACL user which i created. How can i do it?
IMP-00003: ORACLE error 1917 encountered
ORA-01917: user or role 'MALCCOMAN' does not exist
IMP-00017: following statement failed with ORACLE error 1917:
[Code]....
I have a data in text file which has around 7 laks lines. I need to import those data into a table in oracle then do some process.
Since this job is done by end user, i have created a form with the following process.
Create a single text file from multiple flat files in client system. Run the application from the application server [ which is unix based ] once the text file is uploaded to the server, read the text file line by line and insert into the table.
The above process works perfectly in test eniviroment which I have as stand alone system. When I move this to application server and execute it, the session got killed after an hour and I got network inturpted error.
I would like to know is there any other method instead of reading line by line and insert into a table. I do not want to use the tools like sql Loader etc since I do not want my user to do lot of things.
I have to load data file into a table. And the requirement is as below:
Input Data:
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|Siva 1234
The data should be inserted only in two rows as below:
When Value in first 3 fields is same, 4th field should be appended to the existing value in table.
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a testThis is a testThis is a testSiva 1234
I want to create binary copy of control file every time I do backup. I am using sql "alter database backup controlfile to ''+FRADG/TESTDB/controlfile/controlfile.ctl'' "; in my rman backup script. If I run it second time I got errors as it does does not allow to overwrite existing one.
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