Server Administration :: Writing Control File
Nov 25, 2011
I was doing some R&D on my test machine trying to understand how controlfile works. I started up my db and then deleted (renamed)the controlfiles at OS level. I was expecting the db to shutdown. But it dint. Moreover when i queried select name from v$controlfile; it was still reflecting the old controlfile names. To check if it was still functioning, i created a new tablespace with one file and it also got created without any error.
What i dint understand is how could the db still be running when the control file was'nt there and new tablespace and datafile get created? As i understand, whenever a new file is created, an entry is made in the control file. But when control file dint exist where was the data about new tablespace and datafile written?
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Jul 12, 2012
I am trying to create a new controlfile. I used "alter database backup controlfile to trace;" and then I copied and pasted the contents of the trace file into the .sql file. My sql script is
CREATE CONTROLFILE SET DATABASE "FIVESTAR" RESETLOGS NOARCHIVELOG
MAXLOGFILES 16
MAXLOGMEMBERS 3
MAXDATAFILES 100
MAXINSTANCES 8
MAXLOGHISTORY 292
[code]....
Actually, the name of my database was 'STAR' and I changed it to "FIVESTAR" int this .sql script. Now when I run this script with SQL> @ <path of my sql script>, it gives me the following errors:
ERROR at line 1:
ORA-01503: CREATE CONTROLFILE failed
ORA-01504: database name 'FIVESTAR' does not match parameter db_name 'STAR'
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Mar 19, 2010
I'm having a problem with SQL loader and the control file. I want to load a delimited file. The script will eventually be automated where the file name is passed in to the script, it's not a static name.
It's a simple SQL loader Unix script that I have created as follows
Unix file called test_load
# Auto Load
#
#
export data_file=/dev/test_$1$2.csv;
export ORACLE_HOME=/u01/oracle/product/10.2.0;
export ORACLE_SID=XXX;
export PATH=$PATH:$ORACLE_HOME/bin;
sqlldr userid=XXX/XXX data=$data_file
control=/dev/cntrl/test.ctl
errors=99999
bad=/dev/bad/test_$1$2_$$.bad
log=/dev/logs/test_$1$2_$$.log
the top of my control file is as follows
load data
truncate
into table test
fields terminated by "|"
when record_type = 'AA'
(
running at the prompt ./test_load myload 20100319
The following error occurs
SQL*Loader-350: Syntax error at line 5.
Expecting "(", found keyword when.
when record_type = 'AA'
^
I believe the format of my control file is correct but for some reason it won't load.
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Jun 13, 2012
I am loading data using sqlldr command in UNIX to an oracle table and want to concatenate timestamp to a file name in the "create_file_name" column in the code below.
I have the below code within the control file..
LOAD DATA
TRUNCATE
INTO TABLE TABLEA
TRAILING NULLCOLS
(
file_type POSITION(1:5) CHAR,
business_date POSITION(16:23) DATE "YYYYMMDD",
create_file_name "FILE_NAME" EXPRESSION "SELECT TO_CHAR(CURRENT_TIMESTAMP(3), 'YYYYMMDDHH24MISS') FROM DUAL")
The load fails with SQL Loader error: "Expecting valid column specification, ",", ")", found keyword EXPRESSION found instead of column. How the timestamp to a filename can be appended?
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Apr 8, 2010
I am using perl script to dynamically generate the control file.If I have data in the control file as well as in the datafile, how would i write the control file in that case. Is the below one correct?
load data
INFILE '*'
INFILE '/export/home/test/test.csv'
INSERT INTO TABLE EMP fields
terminated by "," optionally enclosed by '"'
trailing nullcols
( empno, empname, sal, deptno )
[code]....
Is there any way that if my control file contains half of the data and my data file contains the other half of the data can i club this data into a logical record in the control file to populate the DB?
My exact 2nd requirement is, my DB contains 5 cols and for 1 col the data is common(countryName) which i have to pass to the control file dynamically and the .csv file contains the data for the other four cols. How could i combine these in the ctrl file and populate the DB?
so if the DB contains CountryName, empid, ename, sal and dept..I will get the CountryName to the ctrl file and csv contains the data for empid, ename, sal and dept. How would i combine these data into a logical record and populate the DB?
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Dec 22, 2003
I have a control file like following:
LOAD DATA
INFILE *
INTO TABLE member
REPLACE
FIELDS TERMINATED BY '|' OPTIONALLY ENCLOSED BY '"'
(
control_id,
name,
address
)
problem is that control_id value is not in data file and I have to assign to each row the same value generated from sequence or from unix variable.
For example, after I run sqlldr, I have to have records in the table like following:
control_id name address
---------- ---- -------
1847 Charlie 250 yonge st
1847 Peter 5 Brookbanks dr
1847 Ben 123 King st
.
.
.
How do I do that?
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Oct 8, 2013
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE 11.2.0.3.0 Production
TNS for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
I am trying to write the Turkey character stored in the table in VARCHAR2 to Unix file. But when the text is written to the unix, the characters are coming as junk.
The output of the file it is writing is as below after the execution
Fis Içe Aktarma Olusturuldu Header
Fis Içe Aktarma Olusturuldu
Fiş İçe Aktarma Oluşturuldu
Instead I expect the chararecter to be as "Fiş İçe Aktarma Oluşturuldu Header" which when converted to English will show as "Created Import Plug Header".
DROP TABLE TEST_JUNK_CHAR
/
CREATE TABLE TEST_JUNK_CHAR (primary_description VARCHAR2(400))
/
INSERT INTO TEST_JUNK_CHAR VALUES('Fiş İçe Aktarma Oluşturuldu Header')
[code]....
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Aug 16, 2011
I have a table revenue
create table revenue
(
person varchar2(23),
month varchar2(3),
rev_amt number
)
and i have data in a file like below
Person Jan Feb Mar Apr Mai Jun Jul Aug Sep Oct Nov Dez
--------------------------------------------------------
Schnyder,345,223,122,345,324,244,123,123,345,121,345,197
Weber,234,234,123,457,456,287,234,123,678,656,341,567
Keller,596,276,347,134,743,545,216,456,124,753,346,456
Meyer,987,345,645,567,834,567,789,234,678,973,456,125
Holzer,509,154,876,347,146,788,174,986,568,246,324,987
Müller,456,125,678,235,878,237,567,237,788,237,324,778
Binggeli,487,347,458,347,235,864,689,235,764,964,624,347
Stoller,596,237,976,876,346,567,126,879,125,568,124,753
Marty,094,234,235,763,054,567,237,457,325,753,577,346
Studer,784,567,235,753,124,575,864,235,753,864,634,678
i want to load it into the table in the following way.
Person Month Revenue
-------------------------
Schnyder Jan 345
Schnyder Feb 223
Schnyder Mar 122
Schnyder Apr 345
Schnyder Mai 324
Schnyder Jun 244
Schnyder Jul 123
Schnyder Aug 123
Schnyder Sep 345
Schnyder Oct 121
Schnyder Nov 345
Schnyder Dez 197
........ ... ...
How to write control file to load this data into the above revenue table.
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Jul 13, 2010
I am trying to write data to a network shared folder. When I write to a local file it works perfectly. Below is my procedure.
CREATE OR REPLACE procedure nbpsbp_file as
type r_cursor is ref cursor;
refr r_cursor;
tab_name varchar2(20):= null;
tab_name1 varchar2(20) := null;
tab_name2 varchar2(20) := null;
[code]....
When I execute the above procedure, it gives me the following error
ORA-29283: invalid file operation
ORA-06512: at "SYS.UTL_FILE", line 475
ORA-29283: invalid file operation
ORA-06512: at "NBPSBP_FILE", line 36
ORA-06512: at line 1
I have also set the parameter utl_file_dir = '\10.16.10.225 emp' When I set the utl_file_sir to a local folder, for example, c: emp, and use the same path in UTL_FILE.FOPEN, then it works fine and writes the desired output to text file. But when I give it a network address, it raises the above error.
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Aug 29, 2013
I have to load data file into a table. And the requirement is as below:
Input Data:
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|This is a test
3456|20130823|20130809|Siva 1234
The data should be inserted only in two rows as below:
When Value in first 3 fields is same, 4th field should be appended to the existing value in table.
1234|20130815|20130822|This is a test, this is the the part
3456|20130823|20130809|This is a testThis is a testThis is a testSiva 1234
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