how I can create an index dynamically? The DBA wants me to put this code below in the beginning of a PL/SQL package. At first, I tried by just putting the below syntax in the code, but I get an 'Alter' is not a valid identifier.
alter index ZZAP_selected_invoices_n1 rebuild online;
And then once the job completes...
alter index ZZAP_selected_invoices_n1 unusable;
I do below alter command
alter tablespace RCA_MB_IDX add datafile '/gxsdb/database/oradata5/RCA/RCA_REF_MB_IDX_01.dbf ' size 1024M
But there is extra space in the file location '/gxsdb/database/oradata5/RCA/RCA_REF_MB_IDX_01.dbfX'
I mark X for that space ...
The command is commit .
But there is problem when do backup .
can you use alter table command to disable/enable constraints in a form if you can how, if you cant why
View 4 Replies View RelatedI do below alter command alter tablespace RCA_MB_IDX add datafile '/gxsdb/database oradata5/RCA/RCA_REF_MB_IDX_01.dbf ' size 1024M
But there is extra space in the file location '/gxsdb/database/oradata5 RCA/RCA_REF_MB_IDX_01.dbfX' I mark X for that space ...
The command is commit .
But there is problem when do backup ...as the file cannot be find since there is extra space after ".dbf" How can I fall back ?
i need a trigger with alter commands to alter the table structure,it will be captured in a separate meta data table(META)
CREATE OR REPLACE TRIGGER meta_alter AFTER Alter ON SCHEMA
BEGIN
update meta set column_name=:new where table_name=ora_dict_obj_name column_name=:old;
END;
/
Meta table contains Table name and column name..i attached the table data in atext file
How to dynamically execute a select command whether it is retrieved a single record or multiple record in oracle database 10g. i have tried with the command execute immediate but it was not successful.
is it possible can i delete or drop multiple tables in a single drop and delete statement.
alter index test_idx1 shrink space;
I've heard that this statement causes a table lock but cant find any information on this.if it is so, is it a write lock or also a read lock of the table?
SQL> ALTER SESSION SET CURRENT_SCHEMA = CLA_T3;
Session altered.
SQL> select sys_context('USERENV','SESSION_USER') current_user,
2 sys_context('USERENV','SESSION_SCHEMA') current_schema
3 from dual
4 ;
CURRENT_USER
--------------------------------------------------------------------------------
CURRENT_SCHEMA
--------------------------------------------------------------------------------
CSR_ETL
CLA_T3
SQL> set linesize 300;
SQL> /
CURRENT_USER
----------------------------------------------------------------------------------------------------
CURRENT_SCHEMA
----------------------------------------------------------------------------------------------------
CSR_ETL
CLA_T3
SQL> create table cla_t3.test (r number, b char(2));
create table cla_t3.test (r number, b char(2))
*
ERROR at line 1:
ORA-01031: insufficient privileges
SQL> create table test (r number, b char(2));
create table test (r number, b char(2))
*
ERROR at line 1:
ORA-01031: insufficient privileges
After Setting current schema to 'CLA_T3', I am unable to create table in cla_t3 schema.
Can we create non-cluster index on a clustered index?
View 5 Replies View RelatedIn a pl/sql procedure code, I created a normal table (create table) using dynamic sql. Then I used that table in procedure for further processing. But while compiling, it gave error that table does not exist. I can understand that he table is not present in DB, so the error came. But at the same time I need to create a table dynamically, use it and drop it. Does it mean that I need to make every query referencing that table as dynamic ??
View 1 Replies View Related1) how to find a primary key of a table in oracle, for example if I want to drop a index in table , how do I find what is the primary key in a table so that I can issue that command.
P/s: I don't have OEM installed so I must use SQL command
Example of dropping the index
ALTER TABLE table_name
drop CONSTRAINT constraint_name;
For example:
ALTER TABLE supplier
drop CONSTRAINT supplier_pk;
i need to create a replica of an existing table in same schema dynamically so as to reflect the modifications on replica table which has been done on primary table.this table we need to maintain as snapshot,like if a column is added or deleted then it should automatically be added or deleted on the replica table.how should i approach this.
View 4 Replies View RelatedI have created a procedure to build trigger dynamically using Dynamic SQL. Here procedure created successfully, when we execute the procedure to build trigger getting the following error.
Note: We are able to create a Trigger, but it is INVALID. if we get the code of a trigger and execute, trigger created a successfully with Valid Status.
ERROR:
ORA-24344: success with compilation error
ORA-06512: at "APPS.CREATE_TRIGGER", line 28
ORA-06512: at line 2
SQL*Plus internal error state 2087, context 47:0:0
Unsafe to proceed
How to create folder using oracle form. I used HOST command but its not working.
HOST ('md C:Emp_Photo2013');
I am working with forms 6i..Is it possible to create form dynamically at run time..
View 2 Replies View Relatedi want to create a lov and record group dynamically at run time. i have the code in when-form-instance..
Declare
v_lov lov;
rg_id recordgroup;
gc_id groupcolumn;
[Code]....
whether i create first a lov and record group at design time or not? if i create a lov and have the recordgroup column then what is the benefit of dynamically lov.?
how to create link file dynamically in oracle reports 6i
View 3 Replies View RelatedWhat is the difference between alter session and alter system?
View 2 Replies View RelatedI need to load data from a CSV file where one of the CSV values determines how many records should be inserted.
Example of the input data:
KEYWORD;2;REC1_COL1_X,REC1_COL2_X;REC2_COL1_X;REC2_COL2_X
KEYWORD;3;REC1_COL1_Y;REC1_COL2_Y,REC2_COL1_Y;REC2_COL2_Y;REC3_COL1_Y;REC3_COL2_Y
KEYWORD;4;REC1_COL1_Z;REC1_COL2_Z,REC2_COL1_Z;REC2_COL2_Z;REC3_COL1_Z;REC3_COL2_Z,REC4_COL1_Z;REC4_COL2_Z
If the KEYWORD is found, then the next value determines how many value pairs will follow, and therefore how many rows should be created in the affected DB table.
As a result I hope to achieve this:
SELECT Column1, Column2 FROM testTable
REC1_COL1_X,REC1_COL2_X
REC2_COL1_X;REC2_COL2_X
REC1_COL1_Y;REC1_COL2_Y
REC2_COL1_Y;REC2_COL2_Y
REC3_COL1_Y;REC3_COL2_Y
REC1_COL1_Z;REC1_COL2_Z
REC2_COL1_Z;REC2_COL2_Z
REC3_COL1_Z;REC3_COL2_Z
REC4_COL1_Z;REC4_COL2_Z
I learned how to import data using Oracle SQL loader for cases where one input line more or less matches a (new) row in a DB table.
below requirement..
We have certain records like SQL, PL/SQL, Reports, Forms, OAF etc in a table. We wanted to capture rating for each of these criteria. So we want a form to be displayed dynamically..
SQL 1 2 3 4 (1,2,3,4 represent radio buttons)
PL/SQL 1 2 3 4
Reports 1 2 3 4
Forms 1 2 3 4
OAF 1 2 3 4
If we add another row, XMLP in that table additional radio button should be displayed automatically..
I want to creat a table using Execute Immediate that includes tablespace name in the create table command. But I don't know the tablespace name that the client is using. Can I incorporate in a script? If yes, then how?
I have written the following proc. While executing , it gives me the error:
ORA-00959: tablespace 'V_TABLESPACE_NAME' does not exist.
create or replace procedure pr_create_table as
v_tablespace_name varchar2(4000);
begin
select distinct tablespace_name into v_tablespace_name
from user_tables
where table_name like 'ABC%';
[code]....
The way to create a short cut on desktop to have an sql*plus (command line).
i.e. I want to have an short cut on desktop when I click that short cut that would connect me to a specific database with a username and password (which i supply while creating the shortcut-I would provide the database name, username and password)
i want to create a bitmap index,but getting the error shown below..i created primary key on column dname of dept and unique constraint on empno of emp.
SQL> create bitmap index bindx on dept d(d.dname) from emp e,dept d where e.deptno=d.deptno;
create bitmap index bindx on dept d(d.dname) from emp e,dept d where e.deptno=d.deptno
*
ERROR at line 1:
ORA-25954: missing primary key or unique constraint on dimension
How to create index on materialized view which is refreshed daily basis.
View 3 Replies View Relateddifference between the ways we create Reverse Key Index on the table.The two ways are as below:
1) CREATE INDEX <Index_Name> ON <Table_Name>(<Column_Name) REVERSE ;
2) CREATE INDEX <Index_Name> ON<Table_Name>(REVERSE(<Column_Name>)) ;
Which one is the appropraite one.
Are both going to act in the same way.
I created index in both ways one by one on the table.But when I fire the select statement against the same table, The explain plan doesn't show any cost and it shows the full table scan in both ways.The select statement used is as below...I want to compare the column with string RBO(i.e('RBO%') at the start.
SELECT *
FROM <Table_Name>
WHERE REVERSE (<Column_Name>) LIKE '%OBR' ;
The select statement is giving me the correct result. Only the explain plan is showing Full Table Scan.can we use this reverse with IN operator also in the same way by reversing the values.
I use Oracle 10.0.2.0.1.If I create a table with constraint key; after that I create an unique index key, I got an error. Does it mean when I create a table with constraint the unique index are automatically created and I could not create index key as I did as below?
create table test_const(ename varchar2(50) not null,
key_num number not null,
descr varchar2(100),
constraint constraint_test_const unique (ename, key_num));
create unique index test_const_idx on test_const
(
"ENAME","KEY_NUM"
)
tablespace tmp_data;
Error report: SQL Error: ORA-01408: such column list already indexed 01408. 00000 - "such column list already indexed" added [pre] tags by Sriram
I am going through this scenario:
* 35 | ID TABLE ACCESS BY INDEX ROW | S_ORG_EXT | 3064K| 2472M| | 1 (0)| 00:00:01 |
| 36 | INDEX FULL SCAN | S_ORG_EXT_U1 | 14 | | | 1 (0)| 00:00:01 |
Predicate Information (identified by operation id):
---------------------------------------------------
35 - filter("T2"."ACCNT_FLG"<>'N' AND ("T2"."INT_ORG_FLG"<>'Y' OR "T2"."PRTNR_FLG"<>'N'))
This unselective index scan on step 36 of the explain is returning 14 rows but optimizer is selecting 3064 K rows from the table .
I tried creating combined index on all 3 columns mentioned in the predicates for 35th step , but that is not utilized .
how to index this whole expression ::--
(ACCNT_FLG<>'N' AND (INT_ORG_FLG<>'Y' OR PRTNR_FLG<>'N'))
Something like CREATE INDEX XYZ on table((ACCNT_FLG<>'N' AND (INT_ORG_FLG<>'Y' OR PRTNR_FLG<>'N')) compute statistics ;
how to create a primary key with out creating an index?
View 10 Replies View Relatedwe create index on multiple tables in oracle
View 12 Replies View RelatedIs it a possible to create table using clause below together with index ?
create table the_table
as
select col1, col2 from table2
I got procedure which create a table in the schema B. The procedure is called from schema A. But when I write into procedure query for create index
then I got a error:
ORA-01031: insufficient privileges when
...executing
Therefore I think about to create table together with index.
begin
B.proc.cre_table;
end;