SQL & PL/SQL :: Exchange A Partition - ORA-14096?
May 9, 2013
I am trying to exchange a partition and I am seeing an ORA-14096. I've done this several time before with other tables without problem. I am pretty sure my columns and index really does match.
Connected to Oracle Database 11g Enterprise Edition Release 11.2.0.3.0
SQL> ALTER TABLE se_keywords EXCHANGE PARTITION p_user_1068 WITH TABLE se_keywords_1068 INCLUDING INDEXES WITHOUT VALIDATION;
ALTER TABLE se_keywords EXCHANGE PARTITION p_user_1068 WITH TABLE se_keywords_1068 INCLUDING INDEXES WITHOUT VALIDATION
ORA-14096: tables in ALTER TABLE EXCHANGE PARTITION must have the same number of columns
SQL> SELECT COUNT(*) cnt
2 FROM all_tab_columns a
3 FULL OUTER JOIN all_tab_columns b ON a.column_name = b.column_name
4 AND b.owner = USER
[code]...
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Jul 30, 2012
I ran exchange partition from non-partitioned table to a partitioned table with the following params: WITHOUT VALIDATION UPDATE GLOBAL INDEXES since we have a GLOBAL index( the GLOBAL is a must). After the exchange , if I'm running a simple query on the first column of the PK the plan is very bad and the EM Adviser advices me to build an index based on that column. I'm using 11.2.0.2
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Nov 7, 2011
I exchange a partition with into a normal table with UPDATE INDEXES,but i found the index of both table are marked UNUSABLE?
SQL> Create Table tb_hxl_list_part
2 (
3 statedate Number,
4 provcode Number
5 )
6 Partition By List(provcode)
7 (
8 Partition p_1 Values(1)
9 );
Table created.
SQL> Create Unique Index idx_tb_hxl_list_part On tb_hxl_list_part(provcode) Local;
Index created.
SQL> Insert Into tb_hxl_list_part Values(20111101,1);
1 row created.
SQL> commit;
Commit complete.
SQL> Select status From dba_ind_partitions aa
2 Where aa.index_name = 'IDX_TB_HXL_LIST_PART';
STATUS
--------
USABLE
SQL> Create Table tb_hxl_list_part_bak
2 (
3 statedate Number,
4 provcode Number
5 );
Table created.
SQL> Create Unique Index idx_hxl_list_part_bak On tb_hxl_list_part_bak(provcode);
Index created.
SQL> Select status From dba_indexes bb
2 Where bb.index_name = 'IDX_HXL_LIST_PART_BAK';
STATUS
--------
VALID
SQL> Alter Table tb_hxl_list_part
2 Exchange Partition p_1
3 With Table TB_HXL_LIST_PART_bak UPDATE Indexes;
Table altered.
SQL> Select status From dba_ind_partitions aa
2 Where aa.index_name = 'IDX_TB_HXL_LIST_PART';
STATUS
--------
UNUSABLE
SQL> Select status From dba_indexes bb
2 Where bb.index_name = 'IDX_HXL_LIST_PART_BAK';
STATUS
--------
UNUSABLE
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Aug 17, 2012
I used the Exchange Partition feature to swap segments between 2 tables- one Partitioned, and one Non-Partitioned. The exchange went well. However, all the data in the partitioned table has gone to the partition which stores the maxbound values.
/** actual table names changed due to client confidentiality issues */
-- Drop the 2 intermediate tables if they already exist
drop table ordered_inv_bkp cascade constraints ;
drop table ordered_inv_t cascade constraints ;
/**
1st create a Non-Partitioned Table from ORDERED_INV and then add the primary key and unique index(s):
*/
create table ordered_inv_bkp as select * from ordered_inv ;
alter table ordered_inv_bkp add constraint ordinvb_pk primary key (ordinv_id) ;
--
create unique index ordinv_scinv_uix on ordered_inv_bkp(
SCP_ID ASC,
[code]....
-- Next, we have to create a partitioned table ORDERED_INV_T with a similar
-- structure as ORDERED_INV.
-- This is a bit tricky, and involves a pl/sql code
declare
l_dt_start DATE;
l_ptn VARCHAR2(50);
cnt PLS_INTEGER;
l_cnt_initial PLS_INTEGER;
ts_name VARCHAR2(50);
l_sql VARCHAR2(10000);
ts_indx VARCHAR2(100);
[code]....
-- Add section to set default values for the intermediate table OL_ORDERED_INV_T
FOR crec_cols IN (
SELECT u.column_name ,u.nullable, u.data_default,u.table_name
FROM USER_TAB_COLUMNS u WHERE
u.table_name ='ORDERED_INV' AND
u.data_default IS NOT NULL )
LOOP
[code]....
-- Next, use exchange partition for actual swipe
-- Between ordered_inv_t and ordered_inv_bkp
-- Analyze both tables : ordered_inv_t and ordered_inv_bkp
BEGIN
DBMS_STATS.GATHER_TABLE_STATS(OWNNAME => 'HENRY220', TABNAME => 'ORDERED_INV_T');
DBMS_STATS.GATHER_TABLE_STATS(OWNNAME => 'HENRY220', TABNAME =>'ORDERED_INV_BKP');
END;
/
SET TIMING ON;
[code]....
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Mar 13, 2012
While trying partition exchange feature of Oracle with 2 hash partitioned tables, I come to know that I can't directly exchange partitions between 2 partitioned tables
I have two hash partitioned tables , so to move partition data from one table to another will include-
1) Exchange from partitioned table to non-partitioned table.
2) exchange from non-partitioned table to new partitioned table.
But I am not sure in which hash partition my data will go in new partitioned table (data need to be moved has single key value on basis of which tables are partitioned),
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May 28, 2010
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
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Aug 8, 2012
My company already work with Oracle 10g, I developed an application using this database and asp.NET. It allows the management of BD and exploitation of these data by clients via ASP pages.
Now I must use Microsoft Exchange (especially the calendar) to retrieve data from the Oracle database and embed links to setup my ASP pages to the calendar.
Being new to Exchange, my questions are:
- It can be done?
- Should I use a particular driver?
- Some idea ?
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Jul 8, 2011
I am trying to xcom the file from Linux server location to Windows server location through shell script. When i execute my DBMS_SCHEDULER to trigger the shell script i am getting the below mentioned error.
Error report:
ORA-27369: job of type EXECUTABLE failed with exit Exchange full
ORA-06512: at "SYS.DBMS_ISCHED", line 150
ORA-06512: at "SYS.DBMS_SCHEDULER", line 441
ORA-06512: at "CUSTDOMAIN.TSC_041_REPORT_PRC", line 50
[code]....
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Mar 17, 2011
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
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Jun 26, 2010
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
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Apr 3, 2013
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
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Nov 26, 2012
We have a table with interval partition. This table is accessed very frequently. We are suppose to exchange partitions between this actual table from it's corresponding staging table.
In order to keep the newly created partitions empty, is there a way to restrict other applications from using it before we push data from staging table to it's actual table.
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Jan 2, 2013
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
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Sep 22, 2011
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
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Jun 14, 2011
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
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Mar 3, 2011
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
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Jul 10, 2012
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
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Apr 12, 2010
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
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Mar 28, 2013
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
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Jun 8, 2011
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
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Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
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Jul 17, 2010
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
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May 5, 2011
I am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
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Feb 21, 2013
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
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Jun 19, 2012
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
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Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
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Nov 27, 2012
I have a table
CREATE TABLE TEST_TABLE
(
DSET_COB_DATE DATE,
[Code]....
This table is being loaded daily with lots of data. relation between DSET_COB_DT to DSET_UID is 1 to many. meaning, for a given date DSET_COB_DT = NOV 27,2012 there will be many DSET_UID=1,2,3,4
DSET_COB_DATE DSET_UID COLUMNA COLUMNB
NOV-27-2012 1 AB CD
NOV-27-2012 2 BC DC
NOV-27-2012 3 CB DA
NOV-27-2012 4 BZ CE
I have the above rows in the table such that all above rows are in one partition for nov-27-2012 and each row is in it's own sub-partition.
In order to gather statistics at the sub-partition level as soon as sub-partition is loaded with the data ( i will come to know when the sub-paritition is loaded with data for the day by some other means.) , i need to know the sub-partition name.
how to know what is the sub-parition name when all i know is DSET_COB_DT=NOV-27-2012 and DSET_UID=1.
when i know the sub-partition name, i can pass the sub-partition name to Gather Statistics procedure.
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Jan 10, 2012
I am a new Oracle DBA that has been tasked with creating some single node databases for our programmers to connect to. I have never built a database, only upgraded. I will be using a Dell 610 with 10.2.0.4 software. I have been reading the install guides but cannot find a definitive answer for how to create the raw partitions. I have a SAN that I can utilize and my current db is set up with RAID 6 like so:
Disk 2 300 GB 1 Extended 300 GB and 5 logical, 100MB, 30 MB, 100 GB, 100 GB, 100 GB
Disk 3 100GB 1 Extended 100 GB and 3 logical 100 MB, 30 MB, 100 GB
why the old DBA partitioned this way? I am not good with storage and know that I need to understand before I build new databases so I do not duplicate something that is wrong. I was reading articles that recommend SAME but would not know how to do that on the SAN.
I will be using data pump to export the database and import to the new server. I was looking at using transportable tablespaces to do this. Would you recommend that from the cluster to the standalone?
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Oct 3, 2013
I want to change the partition name for my existing max value partition. I tried searching in forums but couldn't get the info.
For Example: I have partition PART_30001230, i want to change this to part_maxvalue
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Dec 5, 2011
In my prod table few partition need to be added.
I tried below both syntax, but I am getting error
1)
Alter table STS.DNA_ACCESSION add PARTITION DNA_ACC_P143 VALUES LESS THAN (286000000);
ORA-14074: partition bound must collate higher than that of the last partition
2)
ALTER TABLE STS_RO.DNA_ACCESSION
SPLIT PARTITION DNA_ACC_P999 AT VALUES LESS THAN (286000000)
INTO (PARTITION DNA_ACC_P143,
[Code]....
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