Get Sub-partition Name?
Nov 27, 2012
I have a table
CREATE TABLE TEST_TABLE
(
DSET_COB_DATE DATE,
[Code]....
This table is being loaded daily with lots of data. relation between DSET_COB_DT to DSET_UID is 1 to many. meaning, for a given date DSET_COB_DT = NOV 27,2012 there will be many DSET_UID=1,2,3,4
DSET_COB_DATE DSET_UID COLUMNA COLUMNB
NOV-27-2012 1 AB CD
NOV-27-2012 2 BC DC
NOV-27-2012 3 CB DA
NOV-27-2012 4 BZ CE
I have the above rows in the table such that all above rows are in one partition for nov-27-2012 and each row is in it's own sub-partition.
In order to gather statistics at the sub-partition level as soon as sub-partition is loaded with the data ( i will come to know when the sub-paritition is loaded with data for the day by some other means.) , i need to know the sub-partition name.
how to know what is the sub-parition name when all i know is DSET_COB_DT=NOV-27-2012 and DSET_UID=1.
when i know the sub-partition name, i can pass the sub-partition name to Gather Statistics procedure.
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May 28, 2010
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
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Mar 17, 2011
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
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Jun 26, 2010
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
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Apr 3, 2013
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
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Jan 2, 2013
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
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Sep 22, 2011
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
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Jun 14, 2011
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
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Mar 3, 2011
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
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Jul 10, 2012
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
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Apr 12, 2010
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
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Mar 28, 2013
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
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Jun 8, 2011
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
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Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
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Jul 17, 2010
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
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May 5, 2011
I am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
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Feb 21, 2013
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
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Jun 19, 2012
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
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Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
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Jan 10, 2012
I am a new Oracle DBA that has been tasked with creating some single node databases for our programmers to connect to. I have never built a database, only upgraded. I will be using a Dell 610 with 10.2.0.4 software. I have been reading the install guides but cannot find a definitive answer for how to create the raw partitions. I have a SAN that I can utilize and my current db is set up with RAID 6 like so:
Disk 2 300 GB 1 Extended 300 GB and 5 logical, 100MB, 30 MB, 100 GB, 100 GB, 100 GB
Disk 3 100GB 1 Extended 100 GB and 3 logical 100 MB, 30 MB, 100 GB
why the old DBA partitioned this way? I am not good with storage and know that I need to understand before I build new databases so I do not duplicate something that is wrong. I was reading articles that recommend SAME but would not know how to do that on the SAN.
I will be using data pump to export the database and import to the new server. I was looking at using transportable tablespaces to do this. Would you recommend that from the cluster to the standalone?
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Oct 3, 2013
I want to change the partition name for my existing max value partition. I tried searching in forums but couldn't get the info.
For Example: I have partition PART_30001230, i want to change this to part_maxvalue
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Dec 5, 2011
In my prod table few partition need to be added.
I tried below both syntax, but I am getting error
1)
Alter table STS.DNA_ACCESSION add PARTITION DNA_ACC_P143 VALUES LESS THAN (286000000);
ORA-14074: partition bound must collate higher than that of the last partition
2)
ALTER TABLE STS_RO.DNA_ACCESSION
SPLIT PARTITION DNA_ACC_P999 AT VALUES LESS THAN (286000000)
INTO (PARTITION DNA_ACC_P143,
[Code]....
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Nov 16, 2011
There is a customer_account table. It is partitioned by Range. In one of the partition, the range value is given wrongly, and irrelevant data sits in that partition.
How can i modify the range partition value and re-arrange the data ?
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Dec 18, 2012
I have a question related to partitions and dividing into subpartitions on the existing table.Situation is as follows:
1. we have an inventory table with a list partition on one column sales_desk_id.
2. This table contains millions of records. Due to concurrency and due to high amount of data inserts, now there is a need to make sub partitions based on sale_date.
Question: is there any way to make the subpartitions without dropping the tables?
BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
CORE 11.1.0.7.0 Production
TNS for IBM/AIX RISC System/6000: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - Production
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Jul 7, 2012
Do i have to create indexes again if i drop a partition on a table?
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Sep 14, 2012
below is the create and insert script.
create table sal_group (g_id number(10),sal_rand number(20));
/
INSERT INTO sal_group values(1,5000)
/
INSERT INTO sal_group values(1,2000)
/
INSERT INTO sal_group values(1,4000)
[code]...
/I have tried
SELECT g_id,sal_rand,
case when row_number() over (order by g_id) = count(*) over () then 'yes' else null end as row_check
FROM sal_group output:
G_ID SAL_RAND ROW_CHECK
1 4000
1 2000
[code]....
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Aug 27, 2012
How to do the partition on sql result result using query.
sample
BPREF_NO BILL_MONTt AVG_IND partition
Q12345 1/31/2009 2 part1
Q12345 2/28/2009 2 part1
Q12345 3/31/2009 2 part1
Q12345 4/30/2009 2 part1
Q12345 5/31/2009 2 part1
Q12345 6/30/2009 1 part1
Q12345 7/31/2009 2 part1
Q12345 9/30/2009 1 part2
Q12345 10/31/2009 2 part2
Q12345 11/30/2009 2 part2
Q12345 1/31/2010 1 part3
Q12345 2/28/2010 2 part3
Q12345 3/31/2010 2 part3
Q12345 11/30/2011 2 part4
Q12345 2/29/2012 2 part5
Q12345 3/31/2012 2 part5
Q12345 4/30/2012 2 part5
Q12345 5/31/2012 2 part5
Q12345 7/31/2012 2 part6
i want to create the partition column using query based on below logic
if bill_month is sequence then we have to create a partition and if any breaks comes we have to introduce the new partition.
just for example....
from 31-jan-2009 to 31-jul-2009 is called part1
from 30-aug-2009 to 30-nov-2009 is called part2
like wise...
is it possible to make the partition by query itself.
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Apr 19, 2012
we have our production database running on 11.2.0.2. I have a user table which has partitions. i would like to drop the partition and seeing weird issue:
The command to drop the partition i have is:
alter table SA.accounts drop partition dec_20111203 update global indexes;
Say after 10 minutes, the session is terminated and we are seeing the following: ORA-00028. We don't have a process that kills the session so we are trying to find the root cause why the session is being killed. what might be going on? also as an alternative - i was looking to do the following and want to know - if this works or not:
ALTER TABLE sa.accounts TRUNCATE PARTITION dec_20111203;
Then try to do the drop partition again.
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Jul 30, 2012
I ran exchange partition from non-partitioned table to a partitioned table with the following params: WITHOUT VALIDATION UPDATE GLOBAL INDEXES since we have a GLOBAL index( the GLOBAL is a must). After the exchange , if I'm running a simple query on the first column of the PK the plan is very bad and the EM Adviser advices me to build an index based on that column. I'm using 11.2.0.2
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Oct 24, 2011
how to partition and index my table for a special problem.
The table:
CREATE TABLE TEST (
ID NUMBER PRIMARY KEY,
U_VALUE NUMBER NOT NULL, -- Ranges from 0 - 30.000.000
O_VALUE NUMBER NOT NULL, -- Ranges from U_VALUE - 30.000.000
CREATE_TS TIMESTAMP DEFAULT SYSTIMESTAMP NOT NULL,
UPDATE_TS TIMESTAMP NOT NULL,
ITEM_TYPE NUMBER NOT NULL --<< Only 4 different values >>
);
As you can see, U_VALUE is ALWAYS lower than O_VALUE.I need to have the CREATE_TS in either main- or subpartition do drop the partitions after some time so i don,t have to use DELETE statements. The table has 360 millions rows.
The application has only 8 query which will always use a WHERE clause like this:
SELECT * FROM TEST
WHERE U_VALUE <= :1 AND O_VALUE => :2 AND ITEM_TYPE = :3
1. Is there any good technique how to create a good index for the queries (application will execute 120 queries per second)?
2. how to partition this table?
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