There is a customer_account table. It is partitioned by Range. In one of the partition, the range value is given wrongly, and irrelevant data sits in that partition.
How can i modify the range partition value and re-arrange the data ?
I have created the following partition. but i want to alter in future . how to alter the reference partition. is it avilable in reference partition.
CREATE TABLE EMD_FILE_LOAD_DETAILS_PR
(
FILE_REFERENCE_ID ,
FILE_NAME ,
FILE_TYPE ,
FILE_GROUP_NAME ,
[Code]...
We have a large customer table so first thought was to partition.Also we see two union alls in the plan - can we introduce parallelism? Below is the plan - have attached a text file if difficult to read
SELECT V_IDENTIFIER_LOOKUP.UID_V_IDENTIFIER_LOOKUP AS "UID",
V_IDENTIFIER_LOOKUP.ABA, V_IDENTIFIER_LOOKUP.ADDRESS1,
V_IDENTIFIER_LOOKUP.ADDRESS2, V_IDENTIFIER_LOOKUP.ADDRESS3,
V_IDENTIFIER_LOOKUP.ADDRESS4, V_IDENTIFIER_LOOKUP.ALIAS,
V_IDENTIFIER_LOOKUP.CITY, V_IDENTIFIER_LOOKUP.COUNTRYCODE,
V_IDENTIFIER_LOOKUP.CUST_CODE, V_IDENTIFIER_LOOKUP.CUST_NAME,
V_IDENTIFIER_LOOKUP.HEAD_OFFICE_IN,
V_IDENTIFIER_LOOKUP.IDENTIFIER,
V_IDENTIFIER_LOOKUP.IDENTIFIER_TYPE,
[code]...
We have some tables in our database in which for loading data we have the setup in place to do Exchange partition after data load into staging. Today we did changes to column length to one pair of main and staging table. Post that Exchange partition stop working.
View 1 Replies View Relatedi have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedI Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
is there any way we can find out which row is updated in oracle table if we don't have any date/time column in table.
let say.
Create table T1 (ename varchar2(200), age number);
insert into T1 values ('A',20);
insert into T1 values ('B',30);
insert into T1 values ('C',40);
insert into T1 values ('D',50);
commit;
update t1 set age=50 where ename='A'
commit;
looking some oracle query which identify which record is update in table in given time period.
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies View RelatedI have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
Moidfy trigger into procedure
I am quite a beginner One of trigerred jobs is freezing and I have to reproduce the issue. Thing is about extracion and export data from one table to another (from Rating to Xtexport_table_1).
I want to build query which will fill xtexport_table_1 with values, partialy declared and partialy fetched from Rating tabble.
I figured out that that I have to get rid of all condition statements(IF, WHEN etc ), and just declare variables for some columns and then use a SELECT statement to fetch data.
create or replace
TRIGGER TRG_RATING_EXP_DLS
BEFORE DELETE OR UPDATE OR INSERT
OF RATING_ID,EXTERNAL_ID_1,DN_RATING_ATTRIBUTE_ID,ALI GNMENT_ID,TEAM_ID,CUSTOMER_ID,AFFILIATION_ID,PRODU CT_ID,PERIOD_ID,VALUE_MIN,VALUE_MAX,TENANT_ID,USER _ACCOUNT_ID
ON RATING
REFERENCING OLD AS OLD NEW AS NEW
FOR EACH ROW
DECLARE
[Code]...
-------------------
Don't play what's there, play what's not there
i have one table emp in this table already data exist now i have to modity this existing column data so how can i do this
example:existing emp table
emp_no ename
1 dk patel
2 sk patel
3 jk patel
now i want to change this ename column data i want output like this below table
emp_no ename
1 dk
2 sk
3 jk
how can i do this.
We have table with number as datatype which starts with number 10 like 1056723. Here we need to update the first 2 digits which is 10 to 04.Digit 10 will be always constant across all the data.
select * from temp;
id
----------
1056723
After update, it should be
id
----------
0456723
What function in pl/sql should be used for achieve the desired results.
I have a table containing BLOB column which stores scanned images. Due to an application error, few extra data was padded with BLOB data and now we want to remove it.
The table count will be near to 10 million rows.
We need to remove data from 161byte to 167byte of the blob data. I tried to do with DBMS_LOB.ERASE.But it will create blank spaces for the removed data. Here we need to reduce the size of BLOB data by 6 bytes by removing data from 161bytes to 167 bytes.
I need to know how to modify the spfile - I know how to create it from scratch (from pfile to spfile), but need to modify an existing spfile.
View 3 Replies View RelatedWe are running an Oracle 10g server.
We are adding support for barcode scanner in one part of our information system. So that the mechanics can add parts to an work orders bill of material themselves using barcode scanner to scan the part and enter the qty.
I can via SQL add a part to the bill of materials and reserve the part. But then the part needs to be issued to make it disappear from the stock.
I have found a table that contains information about the part and the bill of material, it has a column named "QTY ISSUED" I have tried via an update command to set the qty issued = 1 for the reserved part. The table is updated, and via SQL everything looks fine, but the part doesn't disappear from the stock. So my guess is that there is a trigger or function somewhere that I need for this.
can i modify oracle data dictionary
View 6 Replies View RelatedI have a database in which a user xxxx is assigned a password 'bbbbb'.I want to change the password to the one which was used before which was 'aaaaa'.But when I change the password it was saying "Password cannot be Reused".So I checked in user profile and found out that password_reuse_time=unlimited and password_reuse_max=5.
So what I did was change the password 6 times to something else(Since it is 5) and then tried changing it to 'aaaaa' but still it is saying "Old password cannot be reused".
I am working on Oracle reports 6i. Just for R&D purpose I have opened REP file in notepad. In the notepad file I could find the queries which are there in the data model.
I did a small addition to the query and saved it in the same location. I tried to open the modified REP file from RWRUN60, but it is throwing me error saying "REP-0110- Unable to open file".
Original Query in data model:
SELECT empno, sal, job, hiredate
FROM emp;
Modified Query:
SELECT empno, sal, job, hiredate
FROM emp
WHERE deptno in (10,30);
is there a way to modify supertypes without dropping / recreating its subtypes?
View 6 Replies View RelatedI am using 'Novell Sentinel Log Manager' to collect/fetch logs from my Oracle 11g R2.To enable auditing, first I did following:
login as sys, then
SQL> create user testuser identified by "testuser";
SQL> grant connect to testuser
SQL> grant dba to sharf
SQL> grant CREATE SESSION to testuser;
SQL> grant select on v_$session to testuser;
SQL> grant select on v_$version to testuser;
SQL> grant select on SYS.DBA_AUDIT_TRAIL to testuser;
SQL> grant select_catalog_role to testuser;
SQL> grant select any dictionary to testuser;
Now logon/logof of user 'testuser' are logged , as well as if testuser drops a table or creates a table, its also logged . but when 'testuser' insert a new record, this information does not logged ;( while I need to know exactly what was added SQL> insert into emp (empid, name, salary) values (10002, 'Ron', 6000)
likewise if 'testuser' modify/update an existing record it also does not logged.
SQL> update emp set salary=700 where empid=10001;
which sql statements I have to execute to start auditing 'insert' and 'update', so that I know what was added/inserted and exactly what was updated/ changed/modify by user 'testuser'.
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View RelatedI have created a job using DBMS_SCHEDULER with named schedule.
After i have modified the schedule using the below queries,
exec dbms_scheduler.disable( 'JOB1' );
exec dbms_scheduler.set_attribute_null('JOB1','schedule_name');
exec DBMS_SCHEDULER.SET_ATTRIBUTE( name => 'JOB1', attribute => 'repeat_interval', value => 'freq=WEEKLY;BYDAY=SUN,WED,FRI;BYHOUR=05');
exec dbms_scheduler.enable( 'JOB1' );
I am using the client system to change the setting and the time zone differs from that of production. Even though the job is scheduled to run at 5 AM it show the start date as 6:30 PM which is the client system time.
I have made an application in forms 6i. Now i want if user can update, or modify the data it will required automatic authentication. Administrator will gives his password then the updation will continue otherwise rollback the transaction.
View 1 Replies View Related