PL/SQL :: Partition By Group?
Sep 14, 2012
below is the create and insert script.
create table sal_group (g_id number(10),sal_rand number(20));
/
INSERT INTO sal_group values(1,5000)
/
INSERT INTO sal_group values(1,2000)
/
INSERT INTO sal_group values(1,4000)
[code]...
/I have tried
SELECT g_id,sal_rand,
case when row_number() over (order by g_id) = count(*) over () then 'yes' else null end as row_check
FROM sal_group output:
G_ID SAL_RAND ROW_CHECK
1 4000
1 2000
[code]....
View 3 Replies
ADVERTISEMENT
Feb 17, 2012
If I run the following query I got 997 records by using GROUP BY.
SELECT c.ins_no, b.pd_date,a.project_id,
a.tech_no
FROM mis.tranche_balance a,
FMSRPT.fund_reporting_period b,
ods.proj_info_lookup c,
ods.institution d
WHERE a.su_date = b.pd_date
AND a.project_id = c.project_id
AND c.ins_no = d.ins_no
AND d.sif_code LIKE 'P%'
AND d.sif_code <> 'P-DA'
AND a.date_stamp >='01-JAN-2011'
AND pd_date='31-MAR-2011'
GROUP BY c.ins_no,
b.pd_date,
a.project_id,
a.tech_no;
I want to show the extra columns a.date_stamp and a.su_date in the out put so that I have used PARTITION BY in the second query but I got 1079 records.
SELECT c.ins_no, b.pd_date,a.date_stamp,a.su_date, a.project_id,
a.tech_no,
COUNT(*) OVER(PARTITION BY c.ins_no,
b.pd_date,
a.project_id,
a.tech_no)c
[code]....
why I got 1079 records.how to show the two extra columns in the out put whcich are not used in GROUP BY clause.
View 8 Replies
View Related
May 28, 2010
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies
View Related
Nov 1, 2013
I'm trying to group sets of data based on time separations between records and then count how many records are in each group.
In the example below, I want to return the count for each group of data, so Group 1=5, Group 2=5 and Group 3=5
SELECT AREA_ID AS "AREA ID",
LOC_ID AS "LOCATION ID",
TEST_DATE AS "DATE",
TEST_TIME AS "TIME"
FROM MON_TEST_MASTER
WHERE AREA_ID =89
AND LOC_ID ='3015'
AND TEST_DATE ='10/19/1994';
[code]....
Group 1 = 8:00:22 to 8:41:22
Group 2 = 11:35:47 to 11:35:47
Group 3 = 15:13:46 to 15:13:46
Keep in mind the times will always change, and sometime go over the one hour mark, but no group will have more then a one hour separation between records.
View 4 Replies
View Related
Mar 17, 2011
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies
View Related
Jun 26, 2010
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
View 3 Replies
View Related
Apr 3, 2013
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
View 2 Replies
View Related
Jun 23, 2011
I read that rownum is applied after the selection is made and before "order by". So, in order to get the sum of salaries for all employees in all departments with a row number starting from 1, i wrote :
select ROWNUM,department_id,sum(salary) from employees group by department_id
If i remove rownum, it gives the correct output. Why can't rownum be used here ?
View 16 Replies
View Related
Jan 2, 2013
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
View 8 Replies
View Related
Sep 22, 2011
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
View 2 Replies
View Related
Jun 14, 2011
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
View 15 Replies
View Related
Mar 3, 2011
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies
View Related
Jul 10, 2012
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
View 2 Replies
View Related
Apr 12, 2010
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
View 3 Replies
View Related
Mar 28, 2013
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
View 4 Replies
View Related
May 17, 2011
Refer to the txt file to create table and insert data.
I executed the following query-
SELECT priority, detail, COUNT(1) FROM TEST GROUP BY priority, detail
and got the following result-
PRIORITYDETAIL COUNT(1)
StandardPatch 27
StandardInitial TSS 1
StandardInitial development 10
StandardProduction deployment5
High PriorPatch 1
Now I want that Initial TSS and Initial development should be combined as Initial together and I should get the result as follows:
PRIORITYDETAIL COUNT(1)
StandardPatch 27
StandardInitial 11
StandardProduction deployment5
High PriorPatch 1
View 3 Replies
View Related
Jun 8, 2011
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies
View Related
Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
View 11 Replies
View Related
Jul 17, 2010
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
View 8 Replies
View Related
May 5, 2011
I am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
View 4 Replies
View Related
Feb 21, 2013
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
View 5 Replies
View Related
Jun 19, 2012
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies
View Related
May 9, 2011
Is there any way to add one disk group space to another disk group. Because One of my disk group is full i want to add space in to that group.
View 1 Replies
View Related
Mar 23, 2013
I'm using this code, and it performs fine, but I'm wondering if there is a more elegant way to do it--maybe with "ROLLBACK". Basically (as you can see) I need to get a normal count for each group but also for each group take a percentage of the total count (so all groups pct adds up to 100 (oh yeah, don't test for zero below, but just a test... )
select
c.Event,
c.code,
count(1) as calls,
total.total_count,
count(1) / total.total_count * 100 as pct_of_total
from
table1 c
[Code]....
[Edit MC: add code tags, do it yourself next time]
View 4 Replies
View Related
Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
View 2 Replies
View Related
Oct 10, 2011
CREATE TABLE TEMP_GP_SEQ
(
COL1 NUMBER,
COL2 NUMBER,
COL3 NUMBER,
COL4 NUMBER,
COL5 NUMBER,
COL6 NUMBER,
COL7 CHAR (25)
);
[Code]...
I need to update the TEMP_GP_SEQ table and on the COLUMN COL7 based on the grouping range mentioned above using the sequence created. But the sequence should not be incremented for each and every record, it should be incremented only for change of groups. For example
SELECT *
FROM TEMP_GP_SEQ;
COL1 COL2 COL3 COL4 COL5 COL6 COL7
110100
110101
12101001
[Code]...
After update it should look like
SELECT *
FROM TEMP_GP_SEQ;
COL1 COL2 COL3 COL4 COL5 COL6 COL7
110100
110101
12101001M2
[Code]...
Actually the group by fetched two rows with a total record count of 4 (2 records in both the rows). SO the COL7 is updated for these four rows with M as a prefixed word and the number followed after M is from the sequence. Here the number is changing (sequence is incrementing) only when there is a change in grouping criteria and it remains the same throughout a group.
View 19 Replies
View Related
Jan 22, 2008
how to logically connect two tables. Here is an example of what I'm trying to do:
HOSTS TABLE CPU TABLE
----------- ---------
ID HOST ID CPU
01 host1 01 proc01
02 host2 01 proc02
03 host3 02 proc01
02 proc02
02 proc03
02 proc04
03 proc01
Based on the above, I can see that 'host1' has 2 CPUs, 'host2' has 4 CPUs, and 'host3' has 1 CPU. What I'd like to do is create a query that would output:
HOST CPU
----------
host1 2
host2 4
host3 1
I'm looping through the hosts and passing the them into another query as bind variables. That's slow and cannot be the best way to do this. I'm aware that I need to using a GROUP BY HAVING COUNT, but that doesn't seem to be working. It tends to return the total count of all CPUs rather than CPUs per host.
View 2 Replies
View Related
Jun 19, 2013
Give me some examples of creating grouped in VPD .
Group policy example for
1) Grouped policy on same table for different columns
2) Grouped policy on two different table for different columns
View 1 Replies
View Related
Sep 5, 2012
I have a query that extracts the row with a max(record_date) within a group.
select ssn, fund, type_indicator, annuitant, cur_year, record_date, guarantee
from LC_MORTALITY
where (ssn, fund, type_indicator, annuitant, cur_year, record_date) in
(select ssn, fund, type_indicator, annuitant, cur_year, max(record_date)
from LC_MORTALITY
group by ssn, fund, type_indicator, annuitant, cur_year);
the table has index that matches the group by clause exactly.
create index IDX_LC_MORTALITY_sftayd on LC_MORTALITY
(SSN,
FUND,
TYPE_INDICATOR,
ANNUITANT,
cur_year,
record_date
However, the plan ignores the index
---------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1963K| 241M| | 1375K (4)| 05:21:04 |
|* 1 | HASH JOIN RIGHT SEMI| | 1963K| 241M| 9701M| 1375K (4)| 05:21:04 |
| 2 | VIEW | VW_NSO_1 | 145M| 8038M| | 241K (12)| 00:56:22 |
| 3 | HASH GROUP BY | | 145M| 8038M| | 241K (12)| 00:56:22 |
| 4 | TABLE ACCESS FULL| LC_MORTALITY | 145M| 8038M| | 219K (3)| 00:51:13 |
| 5 | TABLE ACCESS FULL | LC_MORTALITY | 145M| 9840M| | 222K (5)| 00:51:49 |
---------------------------------------------------------------------------------------------
[code]...
It uses the index but still shows "table access full" in one place. Why is there still a full access?Can I do anything to optimize further?
View 9 Replies
View Related
Sep 8, 2011
My requirement is Data from a TableA has to be provided as an overall view
TABLEA
ID ENTITY REQ_FLG PAR_FLG EXT_FLG
CONV_1 ACCNT Y Y Y
CONV_1 PROD Y Y N
CONV_1 ADDR Y N N
CONV_2 DID Y N N
CONV_2 ORDER Y N N
Required to show the data in report as
ID Expand View_Report Populate ENTITY QRY_STATUS
CONV_1 Expand Report Populate
ACCNT Y Y Y
PROD Y Y Y
ADDR Y N N
CONV_2 Expand Report Populate
DID Y N N
ORDER Y N N
Where "Expand", "Report", "Populate" are provided as Hard coded values in query.
Sample Query.
SELECT ID
,'Expand' AS EXPAND
,'Report' AS VIEW_REPORT
, 'Populate / Reset' AS POP
, DECODE(MN_TBL.ENTITY,NULL,NULL,ENTITY) AS ENTITY
, REQ_FLG || ' ' || PAR_FLG || ' ' || EXT_FLG AS QRY_STATUS
FROM TABLEA
GROUP BY GROUPING SETS
((ID), (ENTITY, REQ_FLG , PAR_FLG , EXT_FLG ))
ORDER BY CONVERSION_ID, ENTITY
Above query works fine, where single ID is present
ID Expand View_Report Populate ENTITY QRY_STATUS
CONV_1 Expand Report Populate
ACCNT Y Y Y
PROD Y Y Y
ADDR Y N N
But when more than one ID is present the entire thing collapses
View 5 Replies
View Related