SQL & PL/SQL :: Display Count Of Employees That Belongs To Different Categories?
Sep 21, 2010
I have to display count of employees that belongs to different categories.
is the situatio There is a category table CATEGORY with three columns (PK,NAME,TREEPOSITION) and we have categories A, B, C these three categories can further have sub-categories so the treeposition for the sub categories will be followed by their root category with _ 'symbol'
Now I have table for the employees with 3 columns (pk,name,category_id), where employees.category_id=category.pk So I want to calculate the number of employees in each category or sub-category.
since the number of categories will be large and each will be having different names so going through names will be bad option left is grouping through the treepostion
the problem is I cant use like using IN for the TREEPOSITION. .
TABLE EMPLOYEES ( PK,NAME,CATEGORY_ID)
TBALE CATEGORIES (PK,NAME,TREEPOSITION)
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Sep 11, 2012
I borrowed some code fragments from other posts and put together a sql query. I think there is a better method in other posts but I couldn't get them working.
I'm trying to get the count of hired employee(s) using the EMP table. I want from the first hire to the last and ALL in between. If there were no hires in that window, I want 0.
WITH minmax AS
(SELECT MIN(last_day(hiredate)) fmonth, MAX(last_day(hiredate)) lmonth
FROM emp),
cal AS
(SELECT add_months(fmonth, LEVEL - 1) mnth
FROM minmax
CONNECT BY LEVEL <= months_between(lmonth, fmonth) + 1),
vals AS
(SELECT extract(YEAR FROM mnth) YEAR, extract(MONTH FROM mnth) MONTH
FROM cal),
data AS
(SELECT extract(YEAR FROM hiredate) YEAR,
extract(MONTH FROM hiredate) MONTH,
COUNT(*) hired_cnt
[code]...
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Oct 31, 2012
I have two columns Department and EmpName:
Department EmpName
____________________________________
Sales empname1
Sales empname2
Marketing empname3
Development empname4
Now I want to count the number of employees in every department. I want the output to be
Department Total
______________________
Sales 2
Marketing 1
Development 1
I am retrieving names of the department through a subquery
The query I am trying to execute is:
SELECT Department, Employee FROM
( SELECT ...query from other table) AS Department, count( A.EmpName) AS Employee
FROM Employer A, EmployeeInfo B
WHERE (A.EmpID = B.EmpID AND A.EmpCategory like 'Category2')
GROUP BY Department
I know that you cannot group by using aliases and hence a little work around, but still the query isn't working.
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Aug 22, 2012
How can I create a query to display the total no of employees and, of that total, the number of employees hired in 1995,1996,1997,1998.
I am using Oracle® Database Express Edition 10g Release 2 (10.2)
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Mar 28, 2013
I used Scott schema.I take 2 blocks ,one block having Deptno,Job and also 1st block is a non database block and Another Block Empno,ename,job,sal,deptno, is a database block,my question is when i enter Deptno,Job then Display Employees Details and also Department name
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Nov 1, 2012
I need a query to display the office and count(*)
where rownum > 6 i.e
here is the data
office
------
hq
hq
hq
hq
hq
hq1
hq1
[code]....
I need a query to display the top 3 counts and the 4 row should be sum of count of other offices.
my result should look like this
office count(*)
--------- --------
hq 5
hq1 4
hq2 3
other 10
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Mar 6, 2013
My problem is i need to display the status and the record count in separate rows.How can i do it
Example
SELECT 'A' STAT, COUNT(A) CNT,'B' STAT, COUNT(B) CNT,'C' STAT, COUNT(C) CNT
FROM TAB1;
OUTPUT SHUD BE LIKE
STAT COUNT
A A_cnt
B B_CNT
C C_CNT
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Oct 11, 2012
A datafile was deleted from a partitioned table which has 31 partitions , that datafile contains data from day 25 to day 31 st I am not having a backups of this database. but I have all the dumps of that table what is the solution to get those 6 partitions data back.
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Nov 8, 2012
Our application has a homepage that displays results of several SQL statements that are defined as reports. One report in particular should only display a custom message when Count of Invoices having a particular status > 0, and not the actual invoice count itself.
I have gotten the layout to not display the count but I need to be able to display a custom message that says "Problem Invoices exist. Please see Invoices Report for more information." I've looked over the Report Attributes definition page but I cannot find how to display this custom message.
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Jul 22, 2013
I have flash backed by primary database to an older SCN, from then on I am receiving the following errors on my standby database when I do media recovery :
ERROR at line 1:ORA-00283: recovery session canceled due to errorsORA-19909: datafile 1 belongs to an orphan incarnation
ORA-01110: data file 1:
'/u01/app/sbydb11g/system01.dbf' PRIMARY DATABASE RMAN> list incarnation; List of Database IncarnationsDB Key Inc Key DB Name DB ID STATUS Reset SCN Reset Time------- ------- -------- ---------------- --- ---------- ----------1 1 ORCL 1343967574 PARENT 1 13-AUG-092 2 ORCL 1343967574 PARENT 754488 23-MAY-133 3 ORCL 1343967574 PARENT 1713927 14-JUN-134
[code]...
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Oct 9, 2007
I have around 1 million users in my table. I currently have their birth date in the table and for reporting purposes i want to put them into three different columns.
For example, For User A, DOB is 01/01/2005,
User B, DOB is 01/01/2002,
user C,DOB is 01/01/1998.
user D, DOB is 01/01/1990
I want a view like below.
Cat1. Cat2. Cat3. User
"0-10" '0-5' '0-2' 'USER A'
"0-10" '0-5' '3-5' 'USER B'
"0-10" '6-10' '8-10' 'USER C'
"11-20" '16-20' '16-17' 'USER D'
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Nov 29, 2010
I need to display dynamically a bunch of categories and I need the SQL algorithm to determine their size and names.
So, I have a table with one column and a variable number of records and I need to display them in GUI in pages, displaying also the page name which should be something like short name for first item to short name of last item in category.
Maximum items per page in 10 but I don't want to simply display blocks of 10 records. If the name of the 8th item starts with B and the name of the 9th item starts with C I want the first page to contain only the first 8 records. Minimum accepted items per page is 8, maximum is 10. The split should be based on the first 2 characters. Page name should be something like: first 4 chars of first item in category - first 4 chars of the last item in category.
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Nov 29, 2010
I need to display dynamically a bunch of categories and I need the SQL algorithm to determine their size and names.
So, I have a table with one column and a variable number of records and I need to display them in GUI in pages, displaying also the page name which should be something like short name for first item to short name of last item in category.
Maximum items per page in 10 but I don't want to simply display blocks of 10 records. If the name of the 8th item starts with B and the name of the 9th item starts with C I want the first page to contain only the first 8 records. Minimum accepted items per page is 8, maximum is 10. The split should be based on the first 2 characters. Page name should be something like: first 4 chars of first item in category - first 4 chars of the last item in category.
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Jun 17, 2011
I have Employees and Salary columns in emp table. So i have nearly 200 employees.
I need to show top 10 employees who has maximum salary.
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Sep 27, 2010
For table employees with
EMPLOYEES
__________________________________________
EMPID NAME MANAGERID
------------------------------------------
34 Amy
17 Ben 34
5 Chris 34
10 Don 5
...
How can we use SQL to get all employees under one manager , either direct or indirect
I only can think the following SQL to get the first direct employee.
select e1.empid
from employees e1, employees e2
where e1.managerid = e2.empid
and e2.empid = '34';
Perhaps we could put it in PL/SQL procedure to do recursive call?
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Feb 24, 2013
I have a table:
create table employee_function
(
id_emloyee number,
id_function number
);
with clients and their functions.
I want to extract all employes who has 2 functions (ex:id_function = 1 and id_function=2)
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Apr 28, 2010
Select top 2 * from employees;
TOP command or function is suitable for oracle 10g SQL
if not then for top analysis what should need to use..is this query work in Oracle SQL 10g?
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Jan 28, 2011
getting the following kind of output.
I would like to get Each year and the number of employees joined in the corresponding month for jan, feb, mar and april from emp table.
A sample output looks like below.
YEAR JAN FEB MAR APRIL
2000 4 2 1 2
2001 2 1 1 5
2002 2 4 2 6
2004 2 4 1 4
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Jan 8, 2012
I am trying to update of job_id column of employees table for employee number 205 two times one after another. First time job_id column of employees table for employee number 205 is updated with new job_id. But second time job_id column of employees for employee number 205 table can not be updated. Oracle returns the following errors
HR:orcl > update employees set JOB_ID='AC_MGR' where employee_id=205;
update employees set JOB_ID='AC_MGR' where employee_id=205
*
ERROR at line 1:
ORA-00001: unique constraint (HR.JHIST_EMP_ID_ST_DATE_PK) violated
ORA-06512: at "HR.ADD_JOB_HISTORY", line 10
ORA-06512: at "HR.UPDATE_JOB_HISTORY", line 2
ORA-04088: error during execution of trigger 'HR.UPDATE_JOB_HISTORY'
As there is composite primary key using employee_id and start_date column.how to update same employee job_id twice.AS we can see from job_history table, the record for employee 200 is as follow
EMPLOYEE_ID START_DATE END_DATE JOB_ID DEPARTMENT_ID
----------- ----------- ---------- ---------- -------------
200 17-SEP-1987 17-JUN-1993 AD_ASST 90
200 01-JUL-1994 31-DEC-1998 AC_ACCOUNT 90
So how can i do the same for employee 205 without changing hire_date after first job_id update. Since for every update of job_id fires trigger. To insert row in job_history table employee id and start_date must be unique each time. HERE hire_date of employees table is used as start_date of job_id table. how it was possible for employee id 200 to change job_id twice?
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Oct 12, 2011
Assign employees to their jobs in consideration the maximum number of employees to each jobs is 5 employee plus each job has own the maximum number of employees
we need the maximum number of employees for each job 5 to be variable when need to change this maximum for certain job , change this number from database (form the from of job ) not form code )
tables
emp
emp_no
name
manager
hiredate
salary
job
job_no
job
you can add tables or attributes to tables to complete you business.
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Jul 24, 2013
I want TO find out FIRST two employee joined IN A particular department WITH department information.THE relation IS basically FROM THE scott SCHEMA.I tried LIKE AS follows. IS there ANY other way FOR best PERFORMANCE.
SELECT deptno,dname,loc,
Max(Decode(rn, 1, hiredate))hiredate1,
Max(Decode(rn, 1, ename)) employee1,
Max(Decode(rn, 2, hiredate))hiredate2,
Max(Decode(rn, 2, ename)) employee2
FROM (SELECT d.deptno,dname,loc,hiredate,ename,Row_number() over(PARTITION BY e.deptno ORDER BY hiredate) rn
FROM dept d, emp e
WHERE d.deptno = e.deptno(+))
GROUP BY deptno,dname,loc;
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Jun 27, 2011
Query to find out employees who are all joined before Manager.
For Example the Table may look like.
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E106Manager 11-Oct-08
E107Programmer20-Nov-09
E108Coordinator12-Dec-10
E109DB Admin10-Feb-07
E110DB Analyst10-Aug-05
The out put must be..
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E109DB Admin10-Feb-07
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Aug 21, 2013
I am having a table employees with columns
1.employee_id
2.department_id
3.hire_date
Display department ID, year, and Number of employees joined?
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Dec 21, 2010
write a query to see how many(no) employees getting salary 3000 & what are their names respectively.
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Mar 4, 2013
Get the highly paid two employees from each department with all details?
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Aug 21, 2012
I want to update the names of employees by concatenating with A for DEPT 20. For that I have written the following PL/SQL block. But instead of one A the ename are concatenating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
BULK COLLECT INTO l_emp_arr
[code].......
I got the following out put.
EMPNOENAME SAL DEPTNO
7566JONESAAAAA200020
7788SCOTTAAAAA300020
7902FORDAAAAA300020
7369SMITHAAAAA800020
7876ADAMSAAAAA 130020
But I want the output like this
EMPNOENAMESAL DEPTNO
7566JONESA200020
7788SCOTTA300020
7902FORDA300020
7369SMITHA800020
7876ADAMSA 130020
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Aug 17, 2010
Need pl/sql block to fetch all the emails of all the employees from the database and separate them by semicolon....
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Aug 21, 2012
I want to update the names of employees by concatnating with A for DEPT 20. For that I have writteh the following PL/SQL block. But instead of one A the ename are concatinating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
[Code]...
/I got the following out put.
EMPNO ENAME SAL DEPTNO
7566 JONESAAAAA 2000 20
7788 SCOTTAAAAA 3000 20
7902 FORDAAAAA 3000 20
7369 SMITHAAAAA 8000 20
7876 ADAMSAAAAA 1300 20
But I want the output like this
EMPNO ENAME SAL DEPTNO
7566 JONESA 2000 20
7788 SCOTTA 3000 20
7902 FORDA 3000 20
7369 SMITHA 8000 20
7876 ADAMSA 1300 20
how to achieve this.
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Jan 21, 2013
I WANT to RETRIEVE all the INFORMATION of DEPT ALONG with TWO EMPLOYEES of each DEPARTMENT.is any OTHER WAY to DO THIS due to performance in Oracle 10g
SELECT *
FROM DEPT D,
(SELECT DEPTNO,
MAX(DECODE(RN,1,ENAME,NULL)) ENAME1,
MAX(DECODE(RN,2,ENAME,NULL)) ENAME2
[code]......
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Nov 26, 2010
To find all the employees whose salaries greater than avg(salary) of the department.
Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote
Its not diplaying all departments
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