I have a table:
create table employee_function
(
id_emloyee number,
id_function number
);
with clients and their functions.
I want to extract all employes who has 2 functions (ex:id_function = 1 and id_function=2)
I am having a table employees with columns
1.employee_id
2.department_id
3.hire_date
Display department ID, year, and Number of employees joined?
i have employee table i want to update salary with all employee 5 percent
View 4 Replies View RelatedI have Employees and Salary columns in emp table. So i have nearly 200 employees.
I need to show top 10 employees who has maximum salary.
For table employees with
EMPLOYEES
__________________________________________
EMPID NAME MANAGERID
------------------------------------------
34 Amy
17 Ben 34
5 Chris 34
10 Don 5
...
How can we use SQL to get all employees under one manager , either direct or indirect
I only can think the following SQL to get the first direct employee.
select e1.empid
from employees e1, employees e2
where e1.managerid = e2.empid
and e2.empid = '34';
Perhaps we could put it in PL/SQL procedure to do recursive call?
Select top 2 * from employees;
TOP command or function is suitable for oracle 10g SQL
if not then for top analysis what should need to use..is this query work in Oracle SQL 10g?
I borrowed some code fragments from other posts and put together a sql query. I think there is a better method in other posts but I couldn't get them working.
I'm trying to get the count of hired employee(s) using the EMP table. I want from the first hire to the last and ALL in between. If there were no hires in that window, I want 0.
WITH minmax AS
(SELECT MIN(last_day(hiredate)) fmonth, MAX(last_day(hiredate)) lmonth
FROM emp),
cal AS
(SELECT add_months(fmonth, LEVEL - 1) mnth
FROM minmax
CONNECT BY LEVEL <= months_between(lmonth, fmonth) + 1),
vals AS
(SELECT extract(YEAR FROM mnth) YEAR, extract(MONTH FROM mnth) MONTH
FROM cal),
data AS
(SELECT extract(YEAR FROM hiredate) YEAR,
extract(MONTH FROM hiredate) MONTH,
COUNT(*) hired_cnt
[code]...
getting the following kind of output.
I would like to get Each year and the number of employees joined in the corresponding month for jan, feb, mar and april from emp table.
A sample output looks like below.
YEAR JAN FEB MAR APRIL
2000 4 2 1 2
2001 2 1 1 5
2002 2 4 2 6
2004 2 4 1 4
I am trying to update of job_id column of employees table for employee number 205 two times one after another. First time job_id column of employees table for employee number 205 is updated with new job_id. But second time job_id column of employees for employee number 205 table can not be updated. Oracle returns the following errors
HR:orcl > update employees set JOB_ID='AC_MGR' where employee_id=205;
update employees set JOB_ID='AC_MGR' where employee_id=205
*
ERROR at line 1:
ORA-00001: unique constraint (HR.JHIST_EMP_ID_ST_DATE_PK) violated
ORA-06512: at "HR.ADD_JOB_HISTORY", line 10
ORA-06512: at "HR.UPDATE_JOB_HISTORY", line 2
ORA-04088: error during execution of trigger 'HR.UPDATE_JOB_HISTORY'
As there is composite primary key using employee_id and start_date column.how to update same employee job_id twice.AS we can see from job_history table, the record for employee 200 is as follow
EMPLOYEE_ID START_DATE END_DATE JOB_ID DEPARTMENT_ID
----------- ----------- ---------- ---------- -------------
200 17-SEP-1987 17-JUN-1993 AD_ASST 90
200 01-JUL-1994 31-DEC-1998 AC_ACCOUNT 90
So how can i do the same for employee 205 without changing hire_date after first job_id update. Since for every update of job_id fires trigger. To insert row in job_history table employee id and start_date must be unique each time. HERE hire_date of employees table is used as start_date of job_id table. how it was possible for employee id 200 to change job_id twice?
Assign employees to their jobs in consideration the maximum number of employees to each jobs is 5 employee plus each job has own the maximum number of employees
we need the maximum number of employees for each job 5 to be variable when need to change this maximum for certain job , change this number from database (form the from of job ) not form code )
tables
emp
emp_no
name
manager
hiredate
salary
job
job_no
job
you can add tables or attributes to tables to complete you business.
I want TO find out FIRST two employee joined IN A particular department WITH department information.THE relation IS basically FROM THE scott SCHEMA.I tried LIKE AS follows. IS there ANY other way FOR best PERFORMANCE.
SELECT deptno,dname,loc,
Max(Decode(rn, 1, hiredate))hiredate1,
Max(Decode(rn, 1, ename)) employee1,
Max(Decode(rn, 2, hiredate))hiredate2,
Max(Decode(rn, 2, ename)) employee2
FROM (SELECT d.deptno,dname,loc,hiredate,ename,Row_number() over(PARTITION BY e.deptno ORDER BY hiredate) rn
FROM dept d, emp e
WHERE d.deptno = e.deptno(+))
GROUP BY deptno,dname,loc;
Query to find out employees who are all joined before Manager.
For Example the Table may look like.
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E106Manager 11-Oct-08
E107Programmer20-Nov-09
E108Coordinator12-Dec-10
E109DB Admin10-Feb-07
E110DB Analyst10-Aug-05
The out put must be..
EMPIDDesignationDateJoined
E101Programmer10-Jan-04
E102Programmer22-Mar-04
E103Analyst 14-Jan-05
E104Designer20-Dec-06
E105Tester 20-Nov-07
E109DB Admin10-Feb-07
write a query to see how many(no) employees getting salary 3000 & what are their names respectively.
View 2 Replies View RelatedI have to display count of employees that belongs to different categories.
is the situatio There is a category table CATEGORY with three columns (PK,NAME,TREEPOSITION) and we have categories A, B, C these three categories can further have sub-categories so the treeposition for the sub categories will be followed by their root category with _ 'symbol'
Now I have table for the employees with 3 columns (pk,name,category_id), where employees.category_id=category.pk So I want to calculate the number of employees in each category or sub-category.
since the number of categories will be large and each will be having different names so going through names will be bad option left is grouping through the treepostion
the problem is I cant use like using IN for the TREEPOSITION. .
TABLE EMPLOYEES ( PK,NAME,CATEGORY_ID)
TBALE CATEGORIES (PK,NAME,TREEPOSITION)
Get the highly paid two employees from each department with all details?
View 3 Replies View RelatedI want to update the names of employees by concatenating with A for DEPT 20. For that I have written the following PL/SQL block. But instead of one A the ename are concatenating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
BULK COLLECT INTO l_emp_arr
[code].......
I got the following out put.
EMPNOENAME SAL DEPTNO
7566JONESAAAAA200020
7788SCOTTAAAAA300020
7902FORDAAAAA300020
7369SMITHAAAAA800020
7876ADAMSAAAAA 130020
But I want the output like this
EMPNOENAMESAL DEPTNO
7566JONESA200020
7788SCOTTA300020
7902FORDA300020
7369SMITHA800020
7876ADAMSA 130020
Need pl/sql block to fetch all the emails of all the employees from the database and separate them by semicolon....
View 4 Replies View RelatedHow can I create a query to display the total no of employees and, of that total, the number of employees hired in 1995,1996,1997,1998.
I am using Oracle® Database Express Edition 10g Release 2 (10.2)
I want to update the names of employees by concatnating with A for DEPT 20. For that I have writteh the following PL/SQL block. But instead of one A the ename are concatinating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
[Code]...
/I got the following out put.
EMPNO ENAME SAL DEPTNO
7566 JONESAAAAA 2000 20
7788 SCOTTAAAAA 3000 20
7902 FORDAAAAA 3000 20
7369 SMITHAAAAA 8000 20
7876 ADAMSAAAAA 1300 20
But I want the output like this
EMPNO ENAME SAL DEPTNO
7566 JONESA 2000 20
7788 SCOTTA 3000 20
7902 FORDA 3000 20
7369 SMITHA 8000 20
7876 ADAMSA 1300 20
how to achieve this.
I WANT to RETRIEVE all the INFORMATION of DEPT ALONG with TWO EMPLOYEES of each DEPARTMENT.is any OTHER WAY to DO THIS due to performance in Oracle 10g
SELECT *
FROM DEPT D,
(SELECT DEPTNO,
MAX(DECODE(RN,1,ENAME,NULL)) ENAME1,
MAX(DECODE(RN,2,ENAME,NULL)) ENAME2
[code]......
To find all the employees whose salaries greater than avg(salary) of the department.
Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote
Its not diplaying all departments
I used Scott schema.I take 2 blocks ,one block having Deptno,Job and also 1st block is a non database block and Another Block Empno,ename,job,sal,deptno, is a database block,my question is when i enter Deptno,Job then Display Employees Details and also Department name
View 1 Replies View RelatedThere is a attendance table having structure(empid number,signtime datetime)It has data of attendance of employees:
What is the right sql to show employees detail attendance according to the no of days attendance . i.e.(According to the maximum no of attendance first and so on)
suppose: 3 employees abc,bbc,cca abc has 20 days of attendance ,bbc has 21 days,cca has 19 days..The report like this:
bbc 1/5/12 10:30
abc .....
then
cca
according to the no of attendannce
I have two columns Department and EmpName:
Department EmpName
____________________________________
Sales empname1
Sales empname2
Marketing empname3
Development empname4
Now I want to count the number of employees in every department. I want the output to be
Department Total
______________________
Sales 2
Marketing 1
Development 1
I am retrieving names of the department through a subquery
The query I am trying to execute is:
SELECT Department, Employee FROM
( SELECT ...query from other table) AS Department, count( A.EmpName) AS Employee
FROM Employer A, EmployeeInfo B
WHERE (A.EmpID = B.EmpID AND A.EmpCategory like 'Category2')
GROUP BY Department
I know that you cannot group by using aliases and hence a little work around, but still the query isn't working.
I have a table that looks like this...
APPOINTMENT
APPOINTMENT PATIENT DENTIST PROCEDURE AMOUNT
NUMBER NUMBER ID NUMBER DATE BILLED PAYMENT
20000001 3001 27 33100 11-Feb-2000 405.00 405.00
20000005 3988 23 11201 05-Mar-2000 80.00 0.00
[code]...
and i used this to find which dentist had the least appointment
select min(count(dentist_ID)) as "Minimum Number of Appointments" from appointment group by dentist_ID;
and this shows..
Minimum Number of Appointments
------------------------------
2
if there's a way where I can show the dentist's ID that corresponds to this "min number of appointment" i tried doing
select dentist_ID, min(count(dentist_ID)) as "Minimum Number of Appointments" from appointment group by dentist_ID;
but it gives me this error
ERROR at line 1:
ORA-00937: not a single-group group function
I would like to use character functions (LPAD, INSTR, SUBSTR, etc) to accomplish what i feel should be rather easy. I would like to take the following character strings:
'ADAM ST #3 S_109640'
'ALBANY AVE #5 & #6 S_AL5&6'
'ALBIN RD #10A S_123318'
And make them
'ADAM ST'
'ALBANY AVE'
'ALBIN RD'
As you can see, it probably boils down to using SUBSTR, INSTR, RTRIM, and LENGTH??
analytic functions regarding the ORDER BY part =)
SQL> ed
Wrote file afiedt.buf
1 select *
2 from (select deptno, ename, sal
3 ,dense_rank() over (partition by deptno order by sal desc) rank
4 from emp)
[code]...
why is that i just added ename on the ORDER BY part of the DENSE_RANK and then
SQL> ed
Wrote file afiedt.buf
1 select *
2 from (select deptno, ename, sal
3 ,dense_rank() over (partition by deptno order by sal desc, ename) ran
[code]...
ADAMS and WARD we're removed from the result, why is it? did it rank it as UNIQUE per sal and ename?
Trying to understand how Oracle DATE works and how it differs to TO_DATE in the below manner...
SELECT DATE '2012-10-25' FROM DUAL;
SELECT TO_DATE('2012-10-25','YYYY-MM-DD') FROM DUAL;
I've had a look through the Oracle Docs but can't find much on this. Basically I want to know how safe the first option is and if it does the same as the second. Also, where does DATE get the Format String from (NLS setting?). Can it be employed to compare a literal with a date that has a TIME portion set to something other than 12:00:00?
count the no: of emp working under each manager? and instead of manager number display the manager name
View 5 Replies View RelatedAgain i getting confused with conversion function especially Explicit data type conversions. some cases oracle server automatically converts the data to the required type. This is called IMPLICIT CONVERSION. Explicit conversions are done by using the conversion functions.
Oracle Explicit Data Type Conversions are
1 TO_CHAR
2 TO_DATE
3 TO_NUMBER