I WANT to RETRIEVE all the INFORMATION of DEPT ALONG with TWO EMPLOYEES of each DEPARTMENT.is any OTHER WAY to DO THIS due to performance in Oracle 10g
SELECT *
FROM DEPT D,
(SELECT DEPTNO,
MAX(DECODE(RN,1,ENAME,NULL)) ENAME1,
MAX(DECODE(RN,2,ENAME,NULL)) ENAME2
[code]......
How to select Name and Department name from dept and emp table using parametrized cursor . Provide only Cursor declaration part.
View 12 Replies View RelatedI want TO find out FIRST two employee joined IN A particular department WITH department information.THE relation IS basically FROM THE scott SCHEMA.I tried LIKE AS follows. IS there ANY other way FOR best PERFORMANCE.
SELECT deptno,dname,loc,
Max(Decode(rn, 1, hiredate))hiredate1,
Max(Decode(rn, 1, ename)) employee1,
Max(Decode(rn, 2, hiredate))hiredate2,
Max(Decode(rn, 2, ename)) employee2
FROM (SELECT d.deptno,dname,loc,hiredate,ename,Row_number() over(PARTITION BY e.deptno ORDER BY hiredate) rn
FROM dept d, emp e
WHERE d.deptno = e.deptno(+))
GROUP BY deptno,dname,loc;
I want to update the names of employees by concatenating with A for DEPT 20. For that I have written the following PL/SQL block. But instead of one A the ename are concatenating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
BULK COLLECT INTO l_emp_arr
[code].......
I got the following out put.
EMPNOENAME SAL DEPTNO
7566JONESAAAAA200020
7788SCOTTAAAAA300020
7902FORDAAAAA300020
7369SMITHAAAAA800020
7876ADAMSAAAAA 130020
But I want the output like this
EMPNOENAMESAL DEPTNO
7566JONESA200020
7788SCOTTA300020
7902FORDA300020
7369SMITHA800020
7876ADAMSA 130020
I want to update the names of employees by concatnating with A for DEPT 20. For that I have writteh the following PL/SQL block. But instead of one A the ename are concatinating with five AAAAA s.
DECLARE
TYPE lt_emp_arr IS TABLE OF t_emp.deptno%TYPE;
l_emp_arr lt_emp_arr;
BEGIN
SELECT deptno
[Code]...
/I got the following out put.
EMPNO ENAME SAL DEPTNO
7566 JONESAAAAA 2000 20
7788 SCOTTAAAAA 3000 20
7902 FORDAAAAA 3000 20
7369 SMITHAAAAA 8000 20
7876 ADAMSAAAAA 1300 20
But I want the output like this
EMPNO ENAME SAL DEPTNO
7566 JONESA 2000 20
7788 SCOTTA 3000 20
7902 FORDA 3000 20
7369 SMITHA 8000 20
7876 ADAMSA 1300 20
how to achieve this.
Get the highly paid two employees from each department with all details?
View 3 Replies View RelatedTo find all the employees whose salaries greater than avg(salary) of the department.
Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote
Its not diplaying all departments
I used Scott schema.I take 2 blocks ,one block having Deptno,Job and also 1st block is a non database block and Another Block Empno,ename,job,sal,deptno, is a database block,my question is when i enter Deptno,Job then Display Employees Details and also Department name
View 1 Replies View RelatedI have two columns Department and EmpName:
Department EmpName
____________________________________
Sales empname1
Sales empname2
Marketing empname3
Development empname4
Now I want to count the number of employees in every department. I want the output to be
Department Total
______________________
Sales 2
Marketing 1
Development 1
I am retrieving names of the department through a subquery
The query I am trying to execute is:
SELECT Department, Employee FROM
( SELECT ...query from other table) AS Department, count( A.EmpName) AS Employee
FROM Employer A, EmployeeInfo B
WHERE (A.EmpID = B.EmpID AND A.EmpCategory like 'Category2')
GROUP BY Department
I know that you cannot group by using aliases and hence a little work around, but still the query isn't working.
How can i retrieve which tables have composite primary keys, and only one of the primary key columns is a foreign key to another table?
Like:
CREATE TABLE club (
clubId NUMBER,
name VARCHAR(20) NOT NULL,
PRIMARY KEY (ClubId)
);
CREATE TABLE team (
teamid NUMBER(10),
clubid NUMBER(10),
teamname VARCHAR(10) NOT NULL,
PRIMARY KEY (teamid, clubid),
FOREIGN KEY (clubid) REFERENCES club (clubid));So in this case, the team table
I am trying to get information about the columns of tables in Oracle databases. In MySQL, show columns provides good deal of information.But in Oracle, we do not have such equivalent call."describe" shows only the primary key.
But it does not show whether any column has unique constraint or an index.
I created a column in a table with unique constraint (but not a primary key), but it was not listed with CONSTRAINT_TYPE = 'U' in dba_constraints view, but was listed with CONSTRAINT_TYPE = 'C' - Check constraint.
how i cant get the private package procedures(the procedures that are defined only in the pcakage body) information?Specially the name and arguments??
Every simple Oracle client presents this type of information, so I think there is a way to get it?
UDI-31626: operation generated ORACLE error 31626
ORA-31626: job does not exist
ORA-39086: cannot retrieve job information
ORA-06512: at "SYS.DBMS_DATAPUMP", line 3326
ORA-06512: at "SYS.DBMS_DATAPUMP", line 4551
ORA-06512: at line 1
I would like to retrieve only the latest repair information based on the latest date regardless of the other information, so I would like to query only items 3 and 5 in the following example.
drop table a;
create table a(
seq number,
custom_id number,
repair_id number,
repair_date date);
[code]........
What is the structure and the values of the default EMP and DEPT table in oracle 9i....i accidentally dropped those 2 tables .... and i don't remember the structure of it.
View -1 Replies View RelatedIn dept table there is deptno=10,20,30,40
in emp table there is deptno=10,20,30
i want to find the deptno which present in dept table but not
present in emp table.
table was defined as below & indexes are also created on name /dept columns, data is also available :
create table test (
name varchar2(10),
version NUMBER(12),
dept varchar2(10)
[code].....
Now the requirement is that the parition keys has to be changed to 'dept' from the existing 'version' . How to accomplish this without any implication on the indexes and other constraints.
1) First Table
Id , Name , Eff_date
10 I1 15-APR-2013
20 I2 30-APR-2013
30 I3 26-May-2013
20 I4 10-SEP-2013
40 I5 10-sep-2013
40 I6 10-Oct-2013
2) Second Table
Eff date Rate
15-APR-2013 900
30-APR-2013 500
16-Sep-2013 400
05-Oct-2013 200
Q. How to get department wise effective rate?
how to show total number of department with their department name assign to employee table.
View 2 Replies View RelatedI have employee interface table something like this.
emp_idemp_name Job_title supervisor_name
1AJ Engineer BJ
2CK Analyst ND
3BJ Manager TR
5TR VP IT JD
6ND S Manager MD
7MD VP Telecom SK
8SK VP Eng JR
I want to idenitfy the VP for each employee. The logic I have to apply is check for hte supervisor of each employee to see if the supervisor has designation starting with 'VP'. If no, I have check the supervisor of the supervisor and so on. I tried using a recursive query using connect_by_root but in the above example for employee ND it lists the VP as both MD and SK. I need it to show on MD who is the lower in the hierarchy.
I am a Java person but since my app uses the Oracle DB I am to do this task.
I am trying to track an employee's department changes by adding a Department change counter which is set to 1 whenever the department changes otherwise it is set to a 0. How can I accomplish this update of the counter? Below is the table creation sql and sample data for insert.
CREATE TABLE EMPL_DEPT
(EMPLID VARCHAR2(11) NOT NULL,
EFFDT DATE,
EFFSEQ SMALLINT NOT NULL,
EMPL_RCD SMALLINT NOT NULL,
DEPT_ID VARCHAR2(12) NOT NULL,
[code]..........
i have 3 tables
table employee
employee_no
employee_name
table manager
manager_id
manager_name
table department
dept_id
dept_name
how can show on the tree all manager with employee with department
example
manager ali
employee Mohamed
department marketing
I have to write function that receives department name and an aggregation operation (average, maximum, minimum) and apply the operation on the salary of employees working on the given department and return the result.
here is my select statement:
select distinct d.deptno, d.deptname, max(e.salary)
from employee e join department d
on e.deptno=d.deptno
where d.deptname=upper('finance')
group by d.deptno, d.deptname;
[code]...
Using the HR schema, I'm trying to write a query which will display the names and salaries of those employees who earn the highest salaries in their respective departments.
I wrote the query:
SELECT first_name, last_name, salary
FROM employees
WHERE salary =
(SELECT department_id, MAX(salary) FROM employees GROUP BY department_id);
However, this query does not execute correctly but I'm not sure why?
I have Employees and Salary columns in emp table. So i have nearly 200 employees.
I need to show top 10 employees who has maximum salary.
I would like to create a hierarchical tree with Department number as a node and all the employees (only employee names) under that department as shown below:
[-]Department - 10
KING
JAMES
-----
[-]Department - 20
MARY
|
|
and so on...
I have created a hierarchical tree 'HT_DEPTNO' under block 'BL_EMP'. I also created a Record Group 'RG_HTREE' with query as shown below:
SELECT 1, LEVEL, E.ENAME, D.DEPTNO||' - '||D.DNAME DEPARTMENT, D.DEPTNO
FROM EMP E, DEPT D
WHERE E.DEPTNO = D.DEPTNO
START WITH E.DEPTNO = 10
CONNECT BY PRIOR E.EMPNO=E.MGR
I am attaching the form for your reference.
For table employees with
EMPLOYEES
__________________________________________
EMPID NAME MANAGERID
------------------------------------------
34 Amy
17 Ben 34
5 Chris 34
10 Don 5
...
How can we use SQL to get all employees under one manager , either direct or indirect
I only can think the following SQL to get the first direct employee.
select e1.empid
from employees e1, employees e2
where e1.managerid = e2.empid
and e2.empid = '34';
Perhaps we could put it in PL/SQL procedure to do recursive call?
I have a table:
create table employee_function
(
id_emloyee number,
id_function number
);
with clients and their functions.
I want to extract all employes who has 2 functions (ex:id_function = 1 and id_function=2)
Select top 2 * from employees;
TOP command or function is suitable for oracle 10g SQL
if not then for top analysis what should need to use..is this query work in Oracle SQL 10g?
I borrowed some code fragments from other posts and put together a sql query. I think there is a better method in other posts but I couldn't get them working.
I'm trying to get the count of hired employee(s) using the EMP table. I want from the first hire to the last and ALL in between. If there were no hires in that window, I want 0.
WITH minmax AS
(SELECT MIN(last_day(hiredate)) fmonth, MAX(last_day(hiredate)) lmonth
FROM emp),
cal AS
(SELECT add_months(fmonth, LEVEL - 1) mnth
FROM minmax
CONNECT BY LEVEL <= months_between(lmonth, fmonth) + 1),
vals AS
(SELECT extract(YEAR FROM mnth) YEAR, extract(MONTH FROM mnth) MONTH
FROM cal),
data AS
(SELECT extract(YEAR FROM hiredate) YEAR,
extract(MONTH FROM hiredate) MONTH,
COUNT(*) hired_cnt
[code]...
