SQL & PL/SQL :: Alter Partition Key Column?
Sep 13, 2012I have a partition table which is partition on date_loaded column, can i alter the partition key column to orig_date_loaded column
View 9 RepliesI have a partition table which is partition on date_loaded column, can i alter the partition key column to orig_date_loaded column
View 9 RepliesWe have some tables in our database in which for loading data we have the setup in place to do Exchange partition after data load into staging. Today we did changes to column length to one pair of main and staging table. Post that Exchange partition stop working.
View 1 Replies View Relatedwrite ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
I have created the following partition. but i want to alter in future . how to alter the reference partition. is it avilable in reference partition.
CREATE TABLE EMD_FILE_LOAD_DETAILS_PR
(
FILE_REFERENCE_ID ,
FILE_NAME ,
FILE_TYPE ,
FILE_GROUP_NAME ,
[Code]...
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies View Relatedi have a database in which some tables. Now i want to alter column by using this query.
ALTER TABLE SALE_INVO_DETAIL_COPY
MODIFY ("QTY" number(5,2))
this column properties is QTY NUMBER(5)
now i want to convert it into QTY NUMBER (5,2)
I have a table with usernames and passwords. The passwords are stored in plaintext. I would like to issue an ALTER command on the password field to store a hash instead, and then repopulate those fields with an encrypted version of the plaintext passwords that were there before.
I would prefer to do this in a procedure, as I am going to perform it in a test environment first, then eventually in the production environment.
I have a table PR in that some data is there for instance, My Mr_NO was Char(11) I modify MR_No to Char(13)My Table Structure now is:
MR_No Char(13),
Mr_Date Date
My Previous data is MR_NO=APN00209085
I want to add two 00 after alter the table I want my result data like APN0000209085.I am updating through this command
update PR set Substr(MR_No,4,2)='00'
ERROR at line 1: ORA-00927: missing equal sign
Result I want is APN0000209085
I need to Modify the column(MSGID) data type from RAW to BLOB for a Queue Table, I'm getting the following error.
BANNER
---------------
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
PL/SQL Release 11.2.0.2.0 - Production
CORE11.2.0.2.0Production
YUV >
YUV > DESC PDA_REPORT_MESSAGE_QTAB
Name Null?Type
----------------------------------------------------- -------- ------------------------------------
Q_NAME VARCHAR2(30)
MSGID NOT NULL RAW(16)
YUV >
YUV >
YUV > ALTER TABLE PDA_REPORT_MESSAGE_QTAB MODIFY (MSGID BLOB);
ALTER TABLE PDA_REPORT_MESSAGE_QTAB MODIFY (MSGID BLOB)
*
ERROR at line 1:
ORA-22858: invalid alteration of datatype
YUV >
YUV >
YUV >
YUV >
YUV > ALTER TABLE PDA_REPORT_MESSAGE_QTAB ADD (MSGID_NEW BLOB);
ALTER TABLE PDA_REPORT_MESSAGE_QTAB ADD (MSGID_NEW BLOB)
*
ERROR at line 1:
ORA-24005: Inappropriate utilities used to perform DDL on AQ table PDADBA.PDA_REPORT_MESSAGE_QTAB
YUV >
I am using 11.2.0.3.0 version of oracle.
Now we are supposed to apply column level TDE to some of our table in database. Now it will be a 'ALTER' on the columns. it involves 4 big tables out of which 3 tables having size ~30GB(one is partitioned table) and another one ~800GB(Not partitioned) Now the concern is, what will be the efficient/safest way to apply TDE on columns, below are the two options with us. (NOTE - We do have downtime window during DB maintenance but looking at the size of the table, i suspect it might take lot.)
1. Directly apply 'ALTER' on the columns. (Note- i was testing on my local, it took 3hrs for a 30GB table to ALTER the column to TDE)
2. Use Table Redefinition for Altering the column. (Creating interim table with column as TDE and then Redefining whole table).
What is the difference between alter session and alter system?
View 2 Replies View RelatedI have a table which has two partitions (by range): first_half and second_half based on a column "INSERT_DAY".
I need to add sub partitions "SUCCESS" and "NONSUCCESS" based on the values of another column "STATUS" (subpartition by list) i.e. I need to transform my range partition to composite (range-list) partition. I do not wish to drop existing tables or partitions. What is the ALTER query for this?
i have in tb1 data like and i need the latest status changed date : when date on which the status of the task changes.for the data below for taskno :
1 i need to get the o/p : 1/2/2013and for taskno :
2 I need the o/p 1/4/2013 taskno :
upd_dateold_status new_status11/1/2013openWIP11/2/2013WIPClosed11/3/2013closed closed21/1/2013openWIP21/2/2013WIPmore_info_needed21/3/2013more_info_neededWIP21/4/2013WIPclosed im writing the query as below select taskno, max(upd_date) MAX_UPD_DATE from (select taskno, upd_date, old_status, new_status, rank from (select taskno, upd_date, old_status, new_status, rank() over (partition by taskno, old_status, new_status order by upd_date asc) as rankfrom tb1)where rank = 1and old_status <> new_status)group by taskno;
IS there any more efficient way to write this query as the clause "old_status <> new_status" is taking a toll on the performance
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedI Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
How can we partition a table based on date if it does not have a date column.
Actually I have to compare two tables on daily basis and fetch few rows from those two tables and enter it to a third table.But both these tables does not have a date column.
I am confused if i need to alter those tables and add date column or if there is some way in which i can compare the data from the two tables for that particular day only and not the whole table data.
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies View RelatedI have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View RelatedI think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
View 8 Replies View RelatedI am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
I have issue of TABLESPACES on test instance. Tablespace files are TEMP1,TEMP2 and APPS_UNDOTS1. Initially TEMP1 and TEMP2 were of 4 GB but now the have grown to 32 GB each respectively. Resulting an occupied space of 64 GB on test server. I want to reuse that space on test instance as those tablespaces never crosses used space of 1%. Reason of this problem was my DBA set AUTOEXTEND as ON for tablespaces.
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