SQL & PL/SQL :: Replacing Vowels In A String?

Apr 13, 2013

I am looking to replace the vowels in a string, and get rid of the empty spaces afterwards.

Our Lab Book suggested that we use the REPLACE function, but I have only been able to get it to work using the TRANSLATE function.

Also, I can`t figure out how to get the empty spaces out of the string when output, I tried to use the TRIM command unsuccessfully.

1) Is it possible to use REPLACE instead of TRANSLATE to replace the vowels?

2) How would i get rid of the empty spaces when the vowels have been replaced?

CREATE OR REPLACE PROCEDURE replacingvowels (vowels IN VARCHAR2, var IN VARCHAR2)
IS
vowelreplace VARCHAR2(50);
BEGIN

[code]....

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Jun 22, 2010

I am facing a simple problem, but could not resolve as yet, i want to replace two string 'M/S' and ' " ' with null, i know this command SELECT REPLACE(' " M/S Private linker " ','M/S',NULL) FROM dual Which command i should use

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Jun 17, 2010

i want to replace 4 digit number in a given string with the same number incremented by 10000.

That mean in the given sting 1201 should be replace by 11201 (Icremented BY 10000).

Input String:

<query><matchAll>true</matchAll><row><columnId>1201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>1212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>1224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

Required output :

<query><matchAll>true</matchAll><row><columnId>11201</columnId><dataType>31</dataType><op>Like</op><val>North America - Houston</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Agreement Date Mismatch</val></row><row><columnId>11212</columnId><dataType>31</dataType><op>!=</op><val>Facility Type Mismatch</val></row><row><columnId>11224</columnId><dataType>31</dataType><op>Like</op><val>y</val></row></query>

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Dec 14, 2010

I am reading Section 4-8 (page 42/216) in the Oracle Database 2-day Developer Guide from here:

[Code]....

It reads:

Suppose that you want to select every employee whose last name has a double vowel(two adjacent occurrences of the same vowel).

Example 4.9 shows how you can do this.

The regular expression ([AEIOU]) represents any vowel. The metacharacter 1 represents the first (and in this case, only) regular expression. The third function parameter, 'i', specifies that the match is case-insensitive.

Example 4.9 Selecting All Employees Whose Last Names Have Double Vowels

SELECT FIRST_NAME, LAST_NAME
FROM EMPLOYEES
WHERE REGEXP_LIKE(LAST_NAME, '([AEIOU])1', 'i');

Result is similar to:

FIRST_NAME LAST_NAME
-------------------- -------------------------
Harrison Bloom
Lex De Haan
Kevin Feeney
Ki Gee
Nancy Greenberg
Danielle Greene
Alexander Khoo
David Lee

8 rows selected.

I don't understand how [AEIOU])1 would find a double vowel(two adjacent occurrences of the same vowel).

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Jul 26, 2011

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following is my trial:

create table abc
(
pk_id number(4) primary key,
abc_name varchar2(10),
fk_id number(4)
);

create table xyz
(
x_id1 number(4),
x_id2 number(4),
x_name varchar2(10)
);

commit;
insert all
into abc values (10,'ab1',1)
into abc values (11,'ab2',2)
into abc values (12,'ab3',5)
into abc values (13,'ab4',7)
into abc values (14,'ab5',9)
into xyz values (1,1,'d1')
into xyz values (2,2,'d2')
into xyz values (5,3,'d3')
into xyz values (7,4,'d4')
into xyz values (9,5,'d5')
select * from dual;
commit;

--this following select returns 5 rows

select * from abc, xyz where abc.fk_id = xyz.x_id1;

-- the following update only updates 3 rows and sets the other 2
-- to null!

update abc set fk_id = (select x_id2 from xyz where xyz.x_id1 = abc.fk_id);
commit;

select * from abc;

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May 21, 2013

I am doing some ETL that I need to run "faster". The function in which I am interested removes low ascii code characters from a string. Please see the timing below and the definitions of the of the functions below those. I am selecting just the first 100K rows for testing and timing purposes only. In production, we are doing millions of records several times a day, thus the desire for "faster". Selecting with no functions is very fast, 0.2 seconds. We would really really want to convert at least 100K rows per second.

The best I can do is get it down to around five seconds using clear_nonlegal. That is, ironically, the one that I thought would be the slowest. It's making thirty-one calls to REPLACE. I would have guessed that the other two would be much faster. I am guessing that REPLACE is just much better optimized than TRANSLATE and, of course, my homegrown PL/SQL, which isn't optimized at all.

So, my question is thisif there is a way I can optimize my custom function, or maybe know of a better already optimized standard SQL and/or Oracle function that would do the job? I am thinking about trying to use a Java stored procedure, but I have never done that before, I am not currently set up for it, if it would be any faster anyway. Is Java faster with string manipulation the PL/SQL? I am thinking it would be really fast to call a C method,

Connected to Oracle Database 11g Enterprise Edition Release 11.2.0.3.0
Connected as aggs@AGGSTEST

SQL> set timing on
SQL> SELECT COUNT(*)
2 FROM (SELECT DISTINCT keyword_dest_url
3 FROM se_keywords sek

[code]...

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Nov 15, 2012

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ORA-39083 some
ORA-39151 lots
ORA-39082 lots
ORA-39111 lots
ORA-39112 lots

I can see that I can use REUSE_DATAFILES & TABLE_EXISTS_ACTION to overwrite tables by default, but is there a recognised way of replacing the entire DB with the impdp? Do I just create the instance, (with the init file) and not build/init the tables, or what? I'll experiment, but I'm just interested if there is a DBA best practice for this sort of thing.

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May 16, 2013

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Connected to Oracle Database 11g Enterprise Edition Release 11.2.0.3.0
Connected as aggs@AGGSTEST

SQL>
SQL> SELECT str,
2 e9,
3 REPLACE(str, '%E9', e9) replace,
4 regexp_replace(str, '%E9', e9) regexp_replace,
5 utl_url.unescape(str, 'UTF8') utl_url,
6 ascii(e9) ascii
7 FROM (SELECT 'Soir%E9e' str,
8 chr(to_number('E9', 'xx')) e9
9 FROM dual);

STR E9 REPLACE REGEXP_REPLACE UTL_URL ASCII
-------- --- ------- -------------- ------- -----
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iu.mfg_prod_cd, iu.mfg_prod_seq_no, ccequip.fk_mkt_cd,
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----------------------------
Apex 4.2
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
CORE 11.2.0.1.0 Production
TNS for Linux: Version 11.2.0.1.0 - Production
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[code].......

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12/4/10 0:00 NULL
12/5/10 0:00 NULL
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12/4/10 0:00 100033868
12/5/10 0:00 100033868
12/6/10 0:00 100033868

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[Code]...

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