SQL & PL/SQL :: Purpose Of Over And Partition By Keywords In Analytical Functions
Jan 3, 2012what is the purpose of over and partition by keywords in analytical functions
View 3 Replieswhat is the purpose of over and partition by keywords in analytical functions
View 3 RepliesIs there any way to apply the restriction on analytical functions, just like WHERE and HAVING .AS we know that we can apply the restriction on table by using WHERE and grouping functions by using HAVING clause .
For Ex: Departments wise count including all employees record :
SQL> select count(*) over(partition by deptno) dept_Count, ce.*
2 from scott.emp ce
3 order by deptno, job;
DEPT_COUNT EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ----- ---------- --------- ----- ----------- --------- --------- ------
3 7934 MILLER CLERK 7782 1/23/1982 1300.00 10
3 7782 CLARK MANAGER 7839 6/9/1981 2450.00 10
3 7839 KING PRESIDENT 11/17/1981 5000.00 10
5 7788 SCOTT ANALYST 7566 4/19/1987 3000.00 20
[code]....
I have simplified this for ease of understanding. I have a Data column and a Month_ID column like this:
Values Month_ID
--------- -------------------------------------------------------
AAA 1
BBB 2
I split this out to values per year like this
Value_2011 Value_2012 Month_ID
-------------------------------------------------------------------------
AAA 1
BBB 2
Now i am trying to get the max(Value_2011) keep (dense_rank Last order by Month_ID) but i get a NULL. I can understand its because the Month_ID accomodates all years but i only need it to look at Month_ID for 2011 and return me the last dense_rank value, how can i achieve this?
I tried a couple of different methods like Last_Value() but i have group by in my original statement and i think analytical functions dont like GROUP by if they are not part of it. How can i achieve this?
I have a table which has the attached data.
Sample data is here
LOGON_DATE NUMBER_OF_LOGINS
11/28/2010 02:00:001
11/28/2010 03:00:001
11/28/2010 04:00:002
11/28/2010 06:00:004
11/28/2010 07:00:002
11/28/2010 08:00:003
11/28/2010 09:00:006
[Code] ........
I am trying to do a report like this.
Date PeakUsersBetween6AMand6PM AVGUsersBetween6AMand6PM PeakUsersBetween6PMand6AM AVGUsersBetween6PMand6AM
Output should be
11/28/2010 25 11 49 27
11/29/2010...
I am using analytical function to do this, It throws an error range cannot be used for dates.
i have employee table i want to update salary with all employee 5 percent
View 4 Replies View RelatedWhat's the meaning of "partition by null" in analytic functions like
select emp_no, dept_nm, count(*) over(partition by null) cnt
from some_table
is it right there is no partition?
i m using oracle 10g forms. in one form i m using post keyword when i use this function then records saved in temporary database but i want to remove one record from this form but it is allrady saved through post.
View 1 Replies View RelatedHow to Check for party names contains standalone four length keywords of consecutive letters(both upper and lower case)
For.e.g. "VMWARE ABCD"
"Jack XWyz jon"
output shoud be: abcd
ABCD,
XWYZ,
like this i want to remove the consecutive characters.
what is the purpose of kernel parameter while creating database.
View 1 Replies View RelatedIf a query can be written using where clause, what is the purpose of using joins over where clause?
View 11 Replies View Relatedi want to run this procedure manually for testing purpose
procedure Reject_Doc(itemtype in varchar2,
itemkey in varchar2,
actid in number,
funcmode in varchar2,
resultout out NOCOPY varchar2 )
what are the possible values for the variables itemtype,itemkey, actid,funcmode?
what the purpose of tnsnames file does? Does it need to be on the client workstation and what should be it's correct location?
View 2 Replies View Relatedi have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedI'm posting below test case in which I'm not able to understand output for LAST_VALUE function. I'm expecting maximum value for the salary in a department. Because I'm partitioning by department and ordering a partition as assending so being last value it should give me maximum value within a partition i.e. department in this case.
CREATE TABLE EMP_MST
(
EMP_ID NUMBER(5),
EMP_NAME VARCHAR2(30),
CONSTRAINT PK_EMP_MST PRIMARY KEY(EMP_ID)
[code]...
I was reading a tutorial for analytical function and i found something like this
sum(princial) keep(dense_rank first order by d_date) over partition by (userid, alias, sec_id, flow, p_date)
How to translate this into simple queries / subquery? i am aware that analytical function are faster but i would like to know how this can translate to using query without analytical function.
Here is the test-table creation script:
CREATE TABLE TEST1 (AGG_DATE DATE, COL1 NUMBER(9), COL2 NUMBER(9), COL3 NUMBER(9));
Here is the test-data population script:
insert into TEST1 (AGG_DATE, COL1, COL2, COL3)
values (to_date('01-01-2012', 'dd-mm-yyyy'), 1, 1, 1);
[code]....
The problem is when I wrote an analytical query, it is giving the BEGIN_DATE and END_DATE by taking all the partition values together and so instead of the values above, it is creating an answer as follows:
Wrong Dataset
BEGIN_DATEEND_DATECOL1COL2COL3
1/1/20121/8/2012111
1/1/20121/8/2012111
1/1/20121/8/2012111
1/1/20121/8/2012111
1/4/20121/11/2012222
1/4/20121/11/2012222
[code]....
Only the last row is correct. What can I do to get the right answer as I know am falling short? Here is my current query:
SELECT MIN(AGG_DATE) OVER(PARTITION BY COL1, COL2, COL3) BEGIN_DATE,
MAX(AGG_DATE) OVER(PARTITION BY COL1, COL2, COL3) END_DATE,
COL1,
COL2,
COL3
FROM TEST1;
I need to calculate the sum of values over a period of exactly one month (including the current row). Now if I use a windowing clause of "range between interval '1' month preceding and current row", the total period length is 1 month plus one day (being the day in the current record).
Basically, I want to sum over a period starting at "add_months(startdate, -1) + 1" up until startdate of each row.
drop table window_tst;
create table window_tst
( id number primary key
[Code]....
So instead of having 01-feb going back to 01-jan, it should only include 02-jan till 01-feb
I could of course recalculate the period length back to a number of days for each row, but that is not really what I would prefer, as it would make the code rather unreadable.
I need to calcaulate the salary avarage for three days prior, leaving the current row. That should happen to every row moving back words.I have given all the details.
create table Employee(
ID VARCHAR2(4 BYTE) NOT NULL,
name varchar(20),
Start_Date DATE,
Salary Number(8,2),
mv_avg number(8,2)
[code]....
I want to use Analytical function instead of group by clause for below query..
select
CASE
WHEN ADMT.SOURCESYSTEM ='CLU'
THEN COUNT(ADMT.TOTAL_COUNT)*5
ELSE COUNT(ADMT.TOTAL_COUNT)
END TOTAL_COUNT
from ESMARTABC.ABC_DRVR_MFAILS_TMP ADMT
group by ADMT.SOURCESYSTEM
can we use distinct keyword with the count and sum analytical functions?
View 5 Replies View RelatedMy table has two date columns EFF_DT which is the start date and TERM_DT is the end date. The EFF_DT of the next record should be the next date of the TERM_DT record.
My table looks like this.
Input Table:
-----------
CK_IDPI_IDEFF_DT TERM_DT
Mem1ABC1-Jan-1331-Mar-13
Mem1ABC1-Apr-1331-May-13
Mem1ABC1-Jun-1330-Sep-13
Mem1ABC15-Oct-1331-Dec-13
Mem1ABC1-Jan-1431-Mar-14
Mem1XYZ1-Apr-1430-Jun-14
Mem1XYZ1-Jul-1431-Dec-14
Expected Output:
----------------
CK_IDPI_IDEFF_DT TERM_DT
Mem1ABC1-Jan-1330-Sep-13
Mem1ABC15-Oct-1331-Mar-14
Mem1XYZ1-Apr-1431-Dec-14
In the fourth record, the effective date should be 1-Oct-13 which is the next date to the last TERM_DT 30-Sep-13.As the is the break in the date, the output should show 15-Oct-13 sa the second start date.
Note: Refer to the PI_ID columns, there is a break in the date for the sale PI_ID 'ABC'.
Here I am trying to generate a pseudo column, so that the table with the pseudo column looks like as shown below. and I can use first_value and LAST_value by partitioning on the pseudo column to get the desired output.
1) CNT_VAL is the pseudo column:
-----------------------------
CK_IDPI_IDEFF_DT TERM_DT CNT_VAL
Mem1ABC1-Jan-1331-Mar-131
Mem1ABC1-Apr-1331-May-131
Mem1ABC1-Jun-1330-Sep-131
[code].....
My Query :
----------
I not getting the desired output here as the value in pseudo column is 3.
select CK_ID, PI_ID,EFF_DT,TERM_DT,
(case
when case_CONT - LAG(case_CONT,1) over (ORDER BY EFF_DT) = 0 then to_char(case_CONT)
when case_CONT - LAG(case_CONT,1) over (ORDER BY EFF_DT) <> 0 then to_char(LAG(case_CONT,1) over (ORDER BY EFF_DT) + 1)
else to_char(nvl(case_CONT,0))
[code].....
Scripts:
--------------------
Create table lead_test(
CK_ID varchar2(10),
PI_IDvarchar2(10),
EFF_DTDate,
TERM_DT date);
[code].....
We've got a query which returns one row, but uses an IN statement. The IN statement links to more than one row in the subquery. When we use a combination of DISTINCT and an ANALYTICAL sum, the sum total is multiplied by the number of rows in the sub query. Remove the DISTINCT and we get a single value.
A simplified example of the problem is below.
I can't see how a query which returns a single row then returns multiple values with the addition of a DISTINCT. Removing the analytical sum also provides a single row, but we need this in the actual query we're running. So it seems to be some combination of DISTINCT, ANALYTICAL SUM and IN query is causing multiple values to be returned.
CREATE TABLE go_test_distinct1
(gtd_value NUMBER);
-- Three identical values
-- To replicate the three identical values returned by
[code].....
how to delete duplicated records from a table without using row_id. I found the duplicated rows from a table using Analytical Function. But i could not use the Analytical function in the where condition.
My table(tab2) Structure is
DEPTNODEPT_NAMEEMPIDSEXID1
107jadf 1F1
40asdf 55
10purchase 2M2
10sales 3M3
30HR 4F4
I found the Duplicate Record by using the query
with a as
(select deptno,dept_name,empid,sex,id1,row_number()over(partition by deptno order by deptno) rnum from tab2)
select * from a where rnum >1
how to delete duplicate record .
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
I am having a table with 5 lakhs transactions. I want to fetch the last balance for a particular date. So i have have returned a query like below.
SELECT curr_balance
FROM transaction_details
WHERE acct_num = '10'
[Code]...
This has to be executed for incrementing of 12 months to find the last balance for each particular month. But this query is having more cpu cost, 12 times it is taking huge time. how to remodify athe above query to get the results in faster way using analytical query. Whether this can be broken into two part in PL/SQL to achive the performance. ?
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....