SQL & PL/SQL :: Multiply Rows From Different Tables?
Oct 27, 2011
I have the task that I have to determine the number of parts that need to be produced based on the number of products sold for the day (each product consists of many parts).
I am using SQL 11g Express.
The report would look something like this:
{OrderDate PartID PartDesc NumOfParts(Total for that day)
10-24-2011 2001 12" X 12" Solid Shelf 108
10-24-2011 2003 12" X 24" Solid Shelf 32
10-24-2011 3001 96" Side Panel 50
[code].......
My issue is, I can't get the equation right to produce the total number of parts. I think I need to multiply ProductPart.NumOfParts by SUM(CustOrder.Qty) Group by CustOrder.SKU.
Below I have what the calculations should look like
I am writing a query and I am trying to multiply some of the columns with *1.50 and 0.75.
The columns I am trying to multiply are coke_rebate.volumecsd and coke_rebate.volumencb. I am getting an error in oracle sql command from web "ORA-00937: not a single-group group function"
Have 2 small tasks for regexp..where we need to extract numbers from the text & multiply & get the result.
Input field varchar2 : 5x a day x 10 days Output : 5 * 10 = 50 Select regexp_replace('5x a day x 10 days', '[^[:digit:]]' from dual;
The code extracts numbers ..but doesn't multiply & give the result.Have one more scenario as well.
Input field varchar2 : take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days Output : 2 * 800 * 4 * 6 * 10 = 384000 Select regexp_replace('take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days', '[^[:digit:]]' from dual;
For the above code, if it's hours ..we need to convert into day by multiplying with the required factor to make it a day.
Difference in hours is supposed to be 35 but it comes as 34.When i manually find the difference in days and multiply by 24 it comes as 34.999999999 and floor converts it as 34.. But when i execute the difference between dates alone and convert to 24 it shows as 35. So when i apply floor to this, it should be 35 instead of 34 right?
For the following query, difference of the dates in minutes is 2100.. so mod(2100,60) should give 0 but it's giving 60.. Separately if if put mod(2100,60) it is giving as 0 only.
I am using the SQL-Developer to access and manipulate a database. I am not very sure about the format of the database (I'm new to databases), but I had to setup the TNS-folder.
Anyway, I guess the problem is the same for any database.
I am having a table with the BOM (bill of material) positions of certain articles and I want to change the BOM quantities of some of the articles. What happens is that I can only change some of the rows. For other rows I get the message like (it is in German, so I try to translate it):
"data was commited in another/the same session already. row cannot be updated"
This error message looks like there is somebody else locked on the database and manipulating it, correct? Is that possible to see somewhere which processes/people are currently accessing to the database?
I saw that there is one process/another database, which is having the authorization to access to the database. But where can I check if this process is accessing to the database?
BTW: I used to do this process before, and it worked. I had been able to manipulate arbitrary entries on the database. I guess that the process or the person, mentioned above, hasn't been accessing to the database at that time.
i work on oracle 8i with around 950 tables in my database. when i export or import it gives me the no of rows exported / imported from each table. is it possible to take a print out of the no of rows in each table through a single query .
select count(*) from each table takes a long time , since there are 950 tables.
We have two tables, TableA and TableB that contain list of accounts and balances.The requirement is to compare the balances of accounts in both the tables, and if there is a difference, then record that difference with account number in another table.
Both TableA and TableB contain more than 10 million rows.What is the best way to do this task in PL/SQL? A join on TableA and TableB to know the differences has become very slow due to large volume.
Here the SUB1 and SUB2 are "tables" and are similar in their structure. The "Main_Table" will be update dynamically and the no of rows in this table will vary.
Now my question , i need to create a view which will have all the rows from these tables ,in the current case it is something like
create or replace view sample as select * from SUB1 union all select * from SUB2
How can this be achived. I tried as shown below:
spool file_to_exe.sql select 'select * from ' || AA ||' union all ' from Main_table; spool off
i will end up in a union all "extra" , if i do like this.
DECLARE L_DE_TGUP_ID BBP_ALLOC.DATA_ELEMENT.DATA_ELEMENT_ID%TYPE; L_ZERO_EXP EXCEPTION; L_DATA NUMBER; BEGIN SELECT DATA_ELEMENT_ID INTO L_DE_TGUP_ID FROM BBP_ALLOC.DATA_ELEMENT WHERE DATA_ELEMENT_CD = 'TGUP'; SELECT DECODE(UPPER('0.0028'),'',0,'0',0,'NULL',0) INTO L_DATA FROM DUAL; [code]......
Here the relationship between the source and target tables is one to one. but still i am getting "unable to get the stable set of rows from the source tables" error. Source query retrieves only 2 rows which are distinct. but still getting this error.
A block shouldn't have rows from multiple tables... Is that true? I read in one of the OTN thread (i don't exactly remember the thread name) that a block can have data from multiple tables. If it doesn't have, what's the table directory in block signifies?
create a procedure or cursor to allocate extents to all tables with zero rows for all the user in the database.I have used the below query to check table with zero rows and no extents allocated.
select onwer,table_name,initial_extent from dba_tables where initial_extent is null order by owner; I generated the query to allocate extents by using concatenation in the above query. select 'ALTER TABLE '||table_name|| ' ALLOCATE EXTENT; ' from dba_tables where initial_extent is null order by owner;
now I want the extent allocation for such table auutomatically for aal the tables with zero rows.
I am trying to insert rows in two tables using sql loader.
I have two tables in database as
SQL> desc name Name Null? Type ---------------------- -------- ------------ ID NUMBER NAME VARCHAR2(20) BD DATE
SQL> desc name3 Name Null? Type --------------------- ----------- ------------- ID NUMBER NAME VARCHAR2(20) BD DATE
I created controlfiles as
[oracle@DBTEST sqldri]$ cat datafile.ctl options (direct=true) load data INFILE * into table name truncate when id='1'
[code]....
when i run sql loader as
[oracle@DBTEST sqldri]$ sqlldr hr/hr control=/u01/sqldri/datafile.ctl SQL*Loader: Release 10.2.0.1.0 - Production on Tue Aug 7 23:30:07 2012 Copyright (c) 1982, 2005, Oracle. All rights reserved. Load completed - logical record count 2.
no rows is inserted..the log file contain entries as
[oracle@DBTEST sqldri]$ cat datafile.log SQL*Loader: Release 10.2.0.1.0 - Production on Tue Aug 7 23:30:07 2012 Copyright (c) 1982, 2005, Oracle. All rights reserved. Control File: /u01/sqldri/datafile.ctl Data File: /u01/sqldri/datafile.ctl Bad File: /u01/sqldri/datafile.bad
problem on oracle 11gR2 where i have to import data from a source database to an existing table without truncate or drop the target table in the target database.
we have found something called table_exist_action=append in impdp.
I have to cleanup data from our tables (Production Environment) that contain millions of rows. The question is apart from the solution of the partitioned tables what alternative recommended solution suggests Oracle?
To delete these tables by using a cursor PL/SQL block or to import all the database and in the tables that we want to remove the old rows to use the QUERY option of the data pump utility.
I have used both ways and i have to admit that datapump solution is much much faster than the deletion that suffers from I/O disk.The question again is which method from these two is more reliable and less risky for the health of the database.
I came across an implementation where data from DB2 tables are moved to Oracle tables, for BI solutioning, using some oracle procedures called from MS SQL DTS packages which are scheduled jobs.Just being curious, can this be done using OWB or ODI rather than the above detour. I suppose there are some changes being done in those procedures before the data is being loaded into Oracle tables, can't this be done using OWB/ODI? Can it be scheduled too as jobs using OWB/ODI?
In our schema we have corresponding audit tables for most of the production tables
Ex Table name Audit Table EMP EMP_AU DEPT DEPT_AU
Audit tables will have all the columns of production table along with audit columns AUDIT_DATE , AUDIT_OPERATION There are few production tables which are not having audit tables.I need to write a script to identify
1) Production tables where corresponding audit table is missing
2) Where there is column difference (In case any column missing in audit table) between Production table and Audit table
drop table test / create table test ( lib varchar2(100) ) / insert into test values ('111/aaa/bbb/ccc'); insert into test values ('222/aaa/bbb/ccc'); insert into test values ('333+444/aaa/bbb/ccc'); insert into test values ('333/aaa/bbb/ccc'); insert into test values ('222+333+444/aaa/bbb/ccc'); insert into test values ('222+333+444+555/aaa/bbb/ccc');
I need to transpose the following table columns to rows and rows to columns...Im not quite sure how to acheive this...I have the following table with fixed number of columns and dynamic number of rows based on date filter in query
MONTH_YEAR RMS RMS_OCC TTL_RMS --------------------------------------- SEPTEMBER 200917790017790 OCTOBER 2009183831278818347 NOVEMBER 2009177901460517762
and I need to display this as
COL1 SEPTEMBER 2009 OCTOBER 2009 NOVEMBER 2009 -------------------------------------------------------------- RMS 17790 18383 17790 RMS_OCC 0 12788 14605 TTL_RMS 17790 18347 17762