i need to multiply with previous row value?
my table have about to 100 columns and lakhs of rows
Ex:
date adj
------ -----
8/21/2012 1
1/1/2012 1
12/1/2011 0.5
8/1/2011 0.5
[code]....
My requirement is multiply the existing adj by adj
adj value coming as 0.5
present year always 1
Ex:
date adj
------ -----
8/21/2012 1
1/1/2012 1
.
.
12/1/2011 0.5
8/1/2011 0.5
[code]....
I have the task that I have to determine the number of parts that need to be produced based on the number of products sold for the day (each product consists of many parts).
I am using SQL 11g Express.
The report would look something like this:
{OrderDate PartID PartDesc NumOfParts(Total for that day)
10-24-2011 2001 12" X 12" Solid Shelf 108
10-24-2011 2003 12" X 24" Solid Shelf 32
10-24-2011 3001 96" Side Panel 50
[code].......
My issue is, I can't get the equation right to produce the total number of parts. I think I need to multiply ProductPart.NumOfParts by SUM(CustOrder.Qty) Group by CustOrder.SKU.
Below I have what the calculations should look like
SKU PartID Total Parts Needed by SKU
DVCK1212 1001 42 (7 orders * 6 shelves)
DVCK1812 1002 0 (NONE)
DVCK2412 1003 42 (7 orders * 6 shelves)
DVCK3012 1004 78 (13 orders * 6 shelves)
[code].......
Here's my script:
/**PRODUCT**/
CREATE table Product
(
SKU VARCHAR2(10) NOT NULL,
ProdDesc VARCHAR2(50) NOT NULL,
Price NUMBER(5,2),
PRIMARY KEY(SKU)
);
[code].......
Query 1
SELECT ProductPart.NumOfParts
FROM ProductPart,
( SELECT CustOrder.SKU,
sum(CustOrder.qty) cust_qty_sum
FROM CustOrder
[code].......
Result: I am only getting a total of 2 parts
Query 2
SELECT ProductPart.Qty,
ProductPart.PartID,
ProductPart.PartDesc
(SELECT COUNT(CustOrder.SKU)
FROM CustOrder
GROUP BY CustomerOrder.SKU)TotalProducts,
[code].......
ORA-00936: missing expression
Query 3
SELECT Part.PartDesc.
ProductPart.NumOfParts
FROM ProductPart, Part
( SELECT CustOrder.SKU,
sum(CustOrder.qty) cust_qty_sum
FROM CustOrder
[code].......
ORA-00933: SQL command not properly ended
Query 4
SELECT o.OrderDate AS "Date Ordered",
o.OrderDate + 5 AS "Date Due",
pp.PartID AS "Part No.",
pp.NumOfParts * COUNT(o.SKU) AS "Qty"
FROM CustOrder o
[code].......
ORA-00934: group function is not allowed here
I am writing a query and I am trying to multiply some of the columns with *1.50 and 0.75.
The columns I am trying to multiply are coke_rebate.volumecsd and coke_rebate.volumencb. I am getting an error in oracle sql command from web "ORA-00937: not a single-group group function"
Here is the code I am writing:
SELECT CUSTOMERS.CUSTID,
CUSTOMERS.MEMBERID,
CUSTOMERS.BNAME,
COKE_REBATE.COKEID,
SUM(COKE_REBATE.VOLUMECSD*1.50) "TOTALCSD",
[code]........
Have 2 small tasks for regexp..where we need to extract numbers from the text & multiply & get the result.
Input field varchar2 : 5x a day x 10 days
Output : 5 * 10 = 50
Select regexp_replace('5x a day x 10 days', '[^[:digit:]]' from dual;
The code extracts numbers ..but doesn't multiply & give the result.Have one more scenario as well.
Input field varchar2 : take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days
Output : 2 * 800 * 4 * 6 * 10 = 384000
Select regexp_replace('take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days', '[^[:digit:]]' from dual;
For the above code, if it's hours ..we need to convert into day by multiplying with the required factor to make it a day.
how to create a function that will multiply the number when the number has more than 3 decimal point.
Example.
123.012 - multiply by 10
123.0123 - multiply by 100
123.01234 - miltiply by 1000
Column A is the result of the number being multiplied according to decimal point.
Column B contains the multiplier used in column A.
1) First Problem:
Difference in hours is supposed to be 35 but it comes as 34.When i manually find the difference in days and multiply by 24 it comes as 34.999999999 and floor converts it as 34.. But when i execute the difference between dates alone and convert to 24 it shows as 35. So when i apply floor to this, it should be 35 instead of 34 right?
SQL> select (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss'))
3 from dual
4 ;
[code].....
1) Second Problem:
For the following query, difference of the dates in minutes is 2100.. so mod(2100,60) should give 0 but it's giving 60.. Separately if if put mod(2100,60) it is giving as 0 only.
SQL> SELECT MOD(((to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
2 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440),
3 60) AS duration,
4 (to_date('2011-05-03 09:00:00', 'yyyy-mm-dd hh24:mi:ss') -
5 to_date('2011-05-01 22:00:00', 'yyyy-mm-dd hh24:mi:ss')) * 1440 as diffinmin
[code]....
The main condition in SQL is like this.
SELECT TO_DATE (TO_CHAR (doc_date, 'MON-YY'), 'MON-YY') "INV_MTH",
SUM (inv_amt) INV_TOTAL
FROM table_x
WHERE doc_date BETWEEN TRUNC (SYSDATE, 'YYYY')
AND LAST_DAY (
ADD_MONTHS (TRUNC (SYSDATE, 'YYYY'), 11)
);
My Output from if run in JAN as of now 16 Jan.
INV_MTHINV_TOTAL
Jan-136260830.42
I want an sql until previous day of that month for example 15 Jan and another sql until day before previous day of that month for example 14 Jan.
How to get the previous value of row with calling function to add value in SELECT statement for the row value.
Consider the example Table A1 having column a with values 1,NULL,NULL,NULL
SELECT CASE WHEN a IS NULL THEN (prev_row_value+function_return_Value) ELSE a END as A from A1
And my result-set should be like
a
----------------------
1
1+(Return Value Of Function)
Prev_Row_Value+(Return Value Of Function)
Prev_Row_Value+(Return Value Of Function)
Below is sample code but doesn't fulfill my criteria
[code]....
Output is
A A2
---------------------------
1 1
3
3
3
i want to know the all scn number's that are generated yesterday or in any previous day? how can i achieve it?
View 5 Replies View RelatedIs it possible for me as a DBA to find IP address of the client who ran a specific transaction or query in past?
Oracle server version I'm using is 11g.
i have tablestructure like this
empno ename sal
1 sam 1000
2 tom 2000
3 ric 3000
4 mac 4000
5 doy 5000
i want TO WRITE SELECT QRY WHICH WILL GO like this
empno ename sal prevemp prevename presale
1 sam 1000 0 0 0
2 tom 2000 1 sam 1000
3 ric 3000 2 tom 2000
4 mac 4000 3 ric 3000
5 doy 5000 4 mac 4000
means when each current row executes it shld show details from previous row also means when details of tom is executing it also shows sam details
Is it possible to get cumulative sum of the same column? I am trying to get a value for COL6... it is dependent on the values of previous row
COL6 Formula:
IF COL2 = 'A' THEN
IF 100 - [SUM_COL6] > COL5 THEN
COL5
ELSE
(TRUNC(100 - [SUM_COL6] / COL4) )* COL4
END IF
[code]....
I need to get data from a table in which dates is equal from previous month. The dates in this table has a formula DD-MMM-YY (CRE_DTTM is the name for date column).
I've already achieve getting data from the previous month by using this formula:
(to_char(CRE_DTTM,'MON')) = UPPER(to_char(add_months(trunc(sysdate,'MONTH'),-1), 'Mon'))
My problem now is what if the current month is for example JAN 2011.. I need to get the data from DEC 2010. How can I query the previous year in this case?
CREATE TABLE F_TIME( PERIOD_ID NUMBER, PERIOD_NAME VARCHAR2(30 CHAR), PERIOD_YEAR NUMBER, PERIOD_TYPE VARCHAR2(30 CHAR), CREATION_DATE DATE, UPDATE_DATE DATE, UPDATE_BY NUMBER); SET DEFINE OFF;Insert into F_TIME (PERIOD_ID, PERIOD_NAME, PERIOD_YEAR, PERIOD_TYPE, CREATION_DATE, UPDATE_DATE) Values (16, 'Q4', 2012, 'q', TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'));Insert into F_TIME
[code]...
if i pass 30 then it will return period id=16 data
We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
CODEemp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
Primary key - emp_id, effective_date..This table is yearly partitioned...I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
CODEWITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]....
For emp_id 1, if we ran this query for 10/31/2011, then it has to compare the 10/31 salary with 10/29 and do the same until the salary mismatches. In this case, salary salary mismatch occurs on 10/20, so the stale salary period is from 10/31 to 10/21 which is 7 days.Below query will give that result:
CODE
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]...
I take a select into a cursor and process it record by record.I have to do sum based on a column and display row by row by using dbms_output.put_line .... So the sum has to happen based on a column. Based on the column value i need to display the cumulative sum as well.
Example:-
col1 col2 amount
DL AADD 25
DL BBCC 10
DL BBRR 15
Sum value for DL ----- 50
TX ADED 20
TX EDWW 60
Sum value for TX ----- 80
All the above data should be displayed using DBMS_OUTPUT.PUT_LINE in a pl/sql code. I use cursor to take the values from the table but the problem i face is .... I am not able to display the sum based in the col1 values.
Since i use the cursor .. i took the col1 values in to a variable and checked every time
old_variable = new_variable
if yes then continue the sum
else
display the sum value.
once i get the above check satisfied i am loosing a new col1 row in the check. The next loop only run for the new col1 values -1( which is used in the check loop).So is there any better way to get the solution or is there a facility to store the previous loop values in a cursor ? so that i dont have to loose that one row of data.
I am not able to come up with proper loop so which can identify that the col1 has changed and you have to display the sum value.
How to achieve "Prev_Value" column as shown below without using ORACLE analytic functions
I have records stored in table for various categories and based on ID / Name / Office / Product / Category combination I want to achieve previous value column through efficient SQL query
Test Scripts as below
CREATE TABLE TEST_Prev
(
ID1 NUMBER(3),
Name1 VARCHAR2(10),
OFFICE VARCHAR2(20),
PRODUCT VARCHAR2(20),
Overall VARCHAR2(20),
DATE1 DATE,
VALUE1 NUMBER(1)
);
commit;
[code]......
Expected output as in attached sheet.
What command can be used to take the previous day upto mid night?
For example
TO_DATE('18-MAR-13 23:59:59', 'dd-mon-yy hh24:mi:ss')
Instead of me entering the date any way to take the previous day till mid-night.
I dont think sysdate-1 will work for me because if I enter sysdate-1 it will take from now -1 that means 18-mar-13 15.45.45 but I want till the previous date until mid-night.
I am trying to set the min date if there is no gap between dates.compare previous date2 value with current date1,if they are same then my new date will be min(date1).
source data
date1 iddate2 new_date
1/2/20111234/2/2011
4/2/20111237/2/2011
7/2/201112310/2/2011
10/2/20111231/2/2012
1/2/20121234/2/2012
4/2/20121237/2/2012
12/17/20121233/17/2013
3/17/20131236/17/2013
and I am expecting the out put like this
date1 id date2 new_date
1/2/20111234/2/20111/2/2011
4/2/20111237/2/20111/2/2011
7/2/201112310/2/20111/2/2011
10/2/20111231/2/20121/2/2011
1/2/20121234/2/20121/2/2011
4/2/20121237/2/20121/2/2011
12/17/20121233/17/201312/17/2012
3/17/20131236/17/201312/17/2012
how to achieve this with SQL
i am looking for a SQL query by which i can extract data between 25th of previous month till today .
i tried the below code but no luck
SELECT TO_CHAR(SYSDATE, 'YYMM'), TO_CHAR(SYSDATE, 'YYMM') -1, TO_CHAR(SYSDATE, 'YYMM') -2, TO_CHAR(SYSDATE, 'YYMM') -3
FROM DUAL
I'm making a menu in my form, wherein it has FILE, TRANSACTION and REPORT. Under FILE it has BACK, and LOGOUT. In my back menu item, i want to go back to the previous block or previous module. I used previous_block but it's not working in some of my blocks.
View 8 Replies View RelatedI have a tar.gz file when i issue command like this to untar,
mysql@test ~]$ tar xfvz mysql-advanced-5.5.17-linux2.6-x86_64.tar.gz
output:
mysql-advanced-5.5.17-linux2.6-x86_64/bin/mysql2mysql
mysql-advanced-5.5.17-linux2.6-x86_64/bin/mysqlslap
tar: skipping to next header
tar: Archive contains obsolescent base-64 headers incomplete literal tree
gzip: stdin: invalid compressed data--format violated
tar: Child returned status 1
tar: Error exit delayed from previous errors
But when i check i found the file like below,
mysql@test ~]$ ls
mysql-advanced-5.5.17-linux2.6-x86_64
This means its completly untar the file?Why that error is showing?
I have a stat table that got info like login_date,user_id etc.For a specific user, i have a requirement based on the no of days difference between the current login date and last login date.
For example, Tom logged in on June 4th 2013. His previous login was May 31. So no_of_days_difference is 5 days.How to programmatically get this for each user inside a pl-sql sub block.
I need to have a function which will round to previous quarter
For ex :
if the value is 1.95 it should give 1.75
if the value is 1.60 it should give 1.50
I've overwritten my PL/SQL function and it's not working now. Is there a way to recover the previous version of this function?
View 6 Replies View RelatedI need to update the current column with sum of the previous column values. Following are the creation scripts
DROP TABLE TEST_LOG;
CREATE TABLE TEST_LOG
(
[Code]....
Above query is working fine to retrieve the previous column values.But when we are updating the SUM_PRE_COLS column with those values it's not working fine.
I tried by using the following query
UPDATE TEST_LOG T SET SUM_PRE_COLS =
( SELECT LAG(T2.KEY0, 1, 0) OVER(ORDER BY T2.KEY0) + LAG(T2.KEY1, 1, 0) OVER(ORDER BY T2.KEY0)
FROM TEST_LOG T2 WHERE T2.ROWID= T.ROWID);
Is there a way of selecting the value of a previous column in a case statement, without having to duplicate. E.g.
SELECT prod_id as Product,
Some complex calculation... as Total,
CASE
[Code]....
I do not want to re-write the same calculation in the else statement but just want it to be be the value of Total column.
I overwritten the package and want to get the previous version.
Is there a way I can get it using FLASHBACK or any other feature?
My user_recyclebin is showing only tables.
SELECT object_name, original_name, TYPE
FROM user_recyclebin;
How do you repeat the same values to the next record from the previous record to reduce the user entry in d2k ??
View 1 Replies View Relatedcreate table a(sourcerow number(2), test_level number(2), dpn varchar2(1), qty number(5)); T
he insert scripts are as follows:
insert into a values(1,3,'Y',5); insert into a values(2,2,'Y',4); insert into a values(3,3,'N',3); insert into a values(4,4,'Y',3); insert into a values(5,1,'N',6); insert into a values(6,2,'N',5); insert into a values(7,2,'Y',4); insert into a values(8,3,'N',2); insert into a values(9,4,'Y',2); insert into a values(10,1,'Y',3); . SQL>select * from v$version; Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
My logic should have the output as follows without 5th column: sourcerowleveldpnqtyremark13Y522Y4This row in main table shouldn't be displayed in the query result as it has
dpn='N'44Y3*3=9In this row qty=9 will bedisplayed.
It will compare the value of level column with its previous row level col,if it is the parent of the current(ex.current is 4 and previous is 3 parent of 4),then it will check the dpn of previous row ,if dpn='N' then qty of parent will be multiplied with qty of current row and displayed under qty column.this row will not be displayed as dpn='N'this row will not be displayed as dpn='N'72Y4*6=24in its previous row level value is same so it will check the previous to previous row where level is 1(parent of current row) and dpn='N' ,then it will multiply the qty of that row with current row and display the value in qty column.this row will not be displayed as dpn='N'94Y2*2=4In this row qty=4 will be displayed.It will compare the value of level column with its previous row level col,if it is the parent of the current(ex.current is 4 and previous is 3 parent of 4),then it will check the dpn of previous row ,if dpn='N' then qty of parent will be multiplied with qty of current row and displayed under qty column.101Y3It will not check for the previous rows as level 1 doesn't have any parent.