SQL & PL/SQL :: Hierarchical Retrieving With Cycles

Sep 29, 2011

first of all sample data;

create table test_circular_data(c1 varchar2(10),c2 varchar2(10));
insert into test_circular_data values ('c1','l2');
insert into test_circular_data values ('c1','l3');
insert into test_circular_data values ('c3','l3');
insert into test_circular_data values ('c4','l3');

commit;

There is a circular relation between columns c1 and c2, so what I'm trying to retrieve is something like that :

c1--> l2 --> l3 --> c3 --> c4

The steps to get that result is :

1.- c1 related to l2 : c1-->l2
2.- c1 related to l3 : c1-->l2-->l3
3.- l3 in the list and related to c3 : c1-->l2-->l3-->c3
4.- l3 in the list and related to c4 : c1-->l2-->l3-->c3-->c4

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SQL & PL/SQL :: Hierarchical And With Clause

Jul 31, 2013

>select level ,empno,ename,mgr
from emp
connect by prior empno=mgr
start with mgr is null;

Output:-
>
LEVEL EMPNO ENAME MGR
----- ---------- ---------- ----------
1 7839 KING
2 7566 JONES 7839
3 7788 SCOTT 7566
4 7876 ADAMS 7788
3 7902 FORD 7566
2 7698 BLAKE 7839
3 7499 ALLEN 7698
3 7521 WARD 7698
3 7654 MARTIN 7698
3 7844 TURNER 7698
3 7900 JAMES 7698

LEVEL EMPNO ENAME MGR
----- ---------- ---------- ----------
2 7782 CLARK 7839
3 7934 MILLER 7782

Note:- I got only this that this query is alternative of self join and it is giving manager name along with mgr id for each employee but when it gives output i couldn't able to understand how to identify who is manager of whom. Tell and explain with clause in oracle , i only know it is alternative of inline view but i want to know how does it work and how to use 'WITH' in oracle query if possible.

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Jan 27, 2009

I'm trying to get different level using hierarchical query in sql.my table is

item_id child_item_id
------------------------------
p21 p25
p21 p22
p22 p23
p22 p24
p25 p27
p25 p26
p27 p28
p27 p29
p30 p31
p30 p32

I want to display result with respective levels.
for example p21 ,p30 are coming under first level .
p22,p25 ,P31,P32are 2nd level.
p23,p24,p26,p27 are 3rd level
p28,p29 are FOURTH level item_id's.

Already I 'VE tried using CONNECT BY PRIOR clause.BUT STILL I COULDN'T GET THE RESULT.

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Apr 22, 2010

I have a hierarchical data structure where a child can have many parents, and a parent can have many childs.See the attached file hierarchy_iliustration.jpg. This example has 4 hierarchy levels, in real problem there can be unlimited number of levels.I want to write a SQL query that lists all indirectly dependent child nodes for a given parent node.

Test structure for example attached:

CREATE TABLE TEST.NODE_T
(
ID NUMBER PRIMARY KEY,
TEXTAS VARCHAR2(254)
);

[code]....

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Dec 24, 2012

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SELECT 1,
level,
job
,
'',
ename
FROM emp
START WITH mgr IS NULL
CONNECT BY PRIOR empno = mgr
order by level

i want to show job wise employees ...

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SQL & PL/SQL :: Update Hierarchical Relation

Nov 13, 2011

I have a table which contains the connectivity details. It is telecom data. The table contains the relation between the point features(Ex: Terminal) and linear features(Ex: Cable)

Below is some sample data

drop table connectivity ;
create table connectivity
(
ftr_no number(5),
ftr_id number(5),

[Code]...

-- 2nd linear ftr

insert into connectivity values (30,10359,33, 9655, 2,NULL,NULL);
insert into connectivity values (30,10359,33, 9656, 1,NULL,NULL);
insert into connectivity values (30,10359,30, 10359,3,NULL,NULL);

[Code]...

In the connectivity table PARENT_FTR_NO and PARENT_FTR_ID needs to be updated based on these conditions.

1. Correspponding to each feature there are 3 entries in this table.

2. Each feature(Point orLinear) has 2 sides INcoming and OUTgoing

3. The possible values for the RELATION column are 1, 2 and 3 where

-> 1 indicates feature conncted at the OUTgoing end
->2 indicates features connected at the INcoming end
->3 indicates self connected

4. Always a linear feature is the parent of a point feature which are connected to the OUTgoing end of the linear feature (i.e where RELATION = 1)

There is another table which contains FEATURE_NO and FEATURE_TYPE.

create table ftr_catgry
(
ftr_no number(5),
ftr_type char(1)
);

[Code]...

FTR_NO F
---------- -
33 P
31 L
30 L

Where
'L' represents linear feature
'P' represents point feature

The relation should be updated as

Step 1. Start with a linear feature, for example FTR_NO = 31

SQL> select * from connectivity where ftr_no = 31 and ftr_id = 10354 and relation = 1;

FTR_NO FTR_ID CONNECTED_FTR_NO CONNECTED_FTR_ID RELATION PARENT_FTR_NO PARENT_FTR_ID
---------- ---------- ---------------- ---------------- ---------- ------------- -------------
31 10354 33 9651 1

The feature connected to the OUTend of the 10354 i 9651 with FTR_NO = 33 and it is a point feature so the parent for 9651 is 10354

Step 2.

SQL> select * from connectivity where ftr_no = 33 and ftr_id = 9651 and relation = 1;

FTR_NO FTR_ID CONNECTED_FTR_NO CONNECTED_FTR_ID RELATION PARENT_FTR_NO PARENT_FTR_ID
---------- ---------- ---------------- ---------------- ---------- ------------- -------------
33 9651 33 9652 1

9652 is connected to 9651 at the OUTend, since 9651 is point feature so the parent of 9651 which is a linear feature is also the parent for 9652

Likewise the all relations have to be updated

Expected result after update

SQL> select * from connectivity;

FTR_NO FTR_ID CONNECTED_FTR_NO CONNECTED_FTR_ID RELATION PARENT_FTR_NO PARENT_FTR_ID
---------- ---------- ---------------- ---------------- ---------- ------------- -------------
31 10354 33 9650 2
31 10354 33 9651 13110354
31 10354 33 10354 3
33 9651 31 10354 2
33 9651 33 9652 13110354
33 9651 33 9651 3
33 9652 33 9651 2

[Code]...

24 rows selected.

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Oct 20, 2010

Any links on hierarchical retrieval concepts?

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Aug 27, 2013

I have a table (Parent - Child).There is a requirement to maintain this table, thats the hierarchy of the oraganisation.So, every quater they will be updating the table. They will be importing the data through an excel and in that excel there are 3 action items,

=> Insert, Update and Delete (logical delete). 
CREATE TABLE PARENT_CHILD_TBL   ( "ID" VARCHAR2(6 BYTE) NOT NULL ENABLE, "ID_DESC" VARCHAR2(200 BYTE), "ID_LEVEL" VARCHAR2(200 BYTE), "PARENT_ID" VARCHAR2(200 BYTE)   )  

For Update:What all validation can come for an updation of an hierarchical data in general.Like = how to derive the level value at database side when the id is updated to some other level.= How to maintain the relation. A -> B -> D ( A is the grand parent here).A -> Ceg: if B is updated as parent node of A, then we should throw error (cyclic data). Any more validations for hierarchical data

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Apr 12, 2008

I have a problem with my Oracle 9i SQL Query and I'm struggling to get it done.

I have three tables namely Student, Lease and Room and want to retrieve data from these three tables.

I want the Student name, the Lease details and the Room No from these tables.

The problem with my SQL query is that I get all the information from the tables except from the Room table, where in the column it show Room_No but the values are not displayed, the query is given below.

SELECT STUDENT.STU_FNAME, STUDENT.STU_LNAME, LEASE.LSE_NO, LEASE.LSE_DURATION, LEASE.LSE_STARTS, LEASE.LSE_ENDS, ROOM.ROOM_NO

FROM STUDENT

LEFT OUTER JOIN LEASE ON LEASE.STU_ID = STUDENT.STU_ID
LEFT OUTER JOIN ROOM ON ROOM.PLACE_NO = LEASE.PLACE_NO;

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Dec 14, 2011

I have this SQL that returns the correct amount of rows which should be 2:

Select Distinct A.File_Name, A.File_Desc, A.file_location,
A.location_date, A.downloaded_date, A.downloaded_id, A.file_size,
A.days_to_request, B.File_Name, B.Act_Date, B.date_loaded
from SDT_LOG A Inner Join ACTIVITY_LOG B
On A.file_name = B.file_name
and A.downloaded_date = B.date_loaded

I need to add another field in the Select query which is B.Act_Code. When I do, I get 2 extra rows. I do not know how to make these rows distinct.

The A table's structure is along with sample data for 1st record:

CODE                                   Example of
Name               Type            1st record.            
----               -------         --------------
FILE_NAME          VARCHAR2(50)    STLMK.txt
FILE_DESC          VARCHAR2(50)    NON-RESIDENT
FILE_LOCATION      VARCHAR2(50)    L:\NonResFiles
YEAR               NUMBER(4)       2008
LOCATION_DATE      DATE            10/10/2007
DOWNLOADED_DATE    DATE         09/04/2008 9:17:00 AM
DOWNLOADED_ID      VARCHAR2(50)    Cindy
FILE_SIZE          CHAR(10)        16212
DAYS_TO_REQUEST    NUMBER(3)       60

The B table's structure is along with sample data for 1st record:

CODE                                Example of
Name               Type         1st record
----               ------       -----------
FILE_NAME          VARCHAR2(50) STLMK.txt
ACT_CODE           CHAR(2)      D
ACT_DATE           DATE         10/10/2007
ACTIVITY_ID        VARCHAR2(50) downloaded on
DATE_LOADED        DATE      09/04/2008 9:17:00 AM

The second record of activity would all be the same except Cindy would be "Jason", act_code would be an "S", activity_id would be "sent on" and then of course the dates would be changed to whenever the new information was saved within the system.

I am getting something like this (shortened of course):

CODEFile_name       Downloaded_ID      Act_Code

STLMK.txt          Cindy               D
STLMK.txt          Cindy               S
STLMK.txt          Jason               D
STLMK.txt          Jason               S

There should only be one row for Cindy with a D act_code and one row for Jason with an S act_code. For some reason, Cindy and Jason each get a row with the different act_code. I'm retrieving 4 rows instead of two when I use B.Act_Code in the SQL statement.

Cindy should have the D Act_Code because she downloaded that file name and Jason should have the S because he sent that file to someone else. Every time a file's activity changes, it is entered into the system so we can keep track of where the files are.

Cindy should have the D Act_Code because she downloaded that file name and Jason should have the S because he sent that file to someone else. Every time a file's activity changes, it is entered into the system so we can keep track of where the files are.

Also, I get the 2 extra rows when I add activity_id field to the select.

I use Oracle 10.

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Dec 20, 2012

i have created two data blocks

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I have a Button in the first data block. So in the WHEN BUTTON PRESSED trigger i wrote SELECT INTO clause which is raising "exact fetch returns more than requested number of rows".Then i used a cursor in the WHEN-BUTTON-PRESSED trigger in the first block to fetch row by row and assign it to the items in second block. But i am able to retrieve only one record in the second block.

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Dec 2, 2010

My table XXX has following records with data

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A1 2 A N
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A2 3 A N
A3 100 A Y

The Select Query should be..All the records should be considered and if the (amount is greater than 50 and approve_flag is N )then except that records all records should be considered.The output should be 3 rows; 2nd row (B1) should not come. writing a select statement for the above conditions.

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Mar 21, 2013

i have requirement, that is to retrieve the data from pl/sql table.

SQL> select * from emp;

EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- --------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17-DEC-80 800 20
7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30
7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30
7566 JONES MANAGER 7839 02-APR-81 2975 20
7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30
[code]....

PL/SQL procedure successfully completed.now i want receive the data from particular x record to y record

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SQL & PL/SQL :: Retrieving Extra Rows

Dec 14, 2011

I have this SQL that returns the correct amount of rows which should be 2:

Select Distinct A.File_Name, A.File_Desc, A.file_location,
A.location_date, A.downloaded_date, A.downloaded_id, A.file_size,
A.days_to_request, B.File_Name, B.Act_Date, B.date_loaded
from SDT_LOG A Inner Join ACTIVITY_LOG B
On A.file_name = B.file_name
and A.downloaded_date = B.date_loaded

I need to add another field in the Select query which is B.Act_Code. When I do, I get 2 extra rows. I do not know how to make these rows distinct.

The A table's structure is along with sample data for 1st record:
Example of
Name Type 1st record.
---- ------- --------------
FILE_NAME VARCHAR2(50) STLMK.txt
FILE_DESC VARCHAR2(50) NON-RESIDENT
FILE_LOCATION VARCHAR2(50) L:NonResFiles
YEAR NUMBER(4) 2008
LOCATION_DATE DATE 10/10/2007
DOWNLOADED_DATE DATE 09/04/2008 9:17:00 AM
DOWNLOADED_ID VARCHAR2(50) Cindy
FILE_SIZE CHAR(10) 16212
DAYS_TO_REQUEST NUMBER(3) 60

The B table's structure is along with sample data for 1st record:
Example of
Name Type 1st record
---- ------ -----------
FILE_NAME VARCHAR2(50) STLMK.txt
ACT_CODE CHAR(2) D
ACT_DATE DATE 10/10/2007
ACTIVITY_ID VARCHAR2(50) downloaded on
DATE_LOADED DATE 09/04/2008 9:17:00 AM

The second record of activity would all be the same except Cindy would be "Jason", act_code would be an "S", activity_id would be "sent on" and then of course the dates would be changed to whenever the new information was saved within the system.

I am getting something like this (shortened of course):

File_name Downloaded_ID Act_Code

STLMK.txt Cindy D
STLMK.txt Cindy S
STLMK.txt Jason D
STLMK.txt Jason S

There should only be one row for Cindy with a D act_code and one row for Jason with an S act_code. For some reason, Cindy and Jason each get a row with the different act_code. I'm retrieving 4 rows instead of two when I use B.Act_Code in the SQL statement.

Cindy should have the D Act_Code because she downloaded that file name and Jason should have the S because he sent that file to someone else. Every time a file's activity changes, it is entered into the system so we can keep track of where the files are. Cindy should have the D Act_Code because she downloaded that file name and Jason should have the S because he sent that file to someone else. Every time a file's activity changes, it is entered into the system so we can keep track of where the files are.

Also, I get the 2 extra rows when I add activity_id field to the select.I use Oracle 10.

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Nov 3, 2011

I have one table when I am querying like below

select * from timeoffreqitem
where timeoffreqitemid=134

getting data like below

134 144 07-OCT-11 13-OCT-11 134

I need to see this result as below.

134 144 07-OCT-11 13-OCT-11 134
134 144 08-OCT-11 13-OCT-11 134
134 144 09-OCT-11 13-OCT-11 134
134 144 10-OCT-11 13-OCT-11 134
134 144 11-OCT-11 13-OCT-11 134
134 144 12-OCT-11 13-OCT-11 134
134 144 13-OCT-11 13-OCT-11 134

I am looking at multilple optons.

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Sep 6, 2012

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Mar 27, 2010

I want to retrieve the data from ex.tables. How to get this.

table1:

Account_No, Account_sub_No
1234 1
1234 2
1234 3
2345 4
2345 5
2345 6
2345 7
2345 8
................
Account_no is the primary key

table2:

Account_sub_No, Description
1 Hello
2 Hi
3 No.1
4 great
5 people
.................
8 world
..........................
Account_sub_No is primary key.

Out put:

I want the data like Account_no who is having more than 3 Account_sub_no values.

But in my case need to join these two tables with other tables. join field is Account_no from table1. there are no other fields to join.

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Mar 7, 2013

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Is the above approach is correct? Is there any difference between trunc(sysdate)-180 and trunc(sysdate-180) ?

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Sep 24, 2012

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FROM employees
START WITH manager_id IS NULL
CONNECT BY PRIOR employee_id = manager_id
GROUP BY level

This returns 4 levels. I'm wanting to add up the number of siblings under the level 2 instead of listing them all.

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Aug 19, 2013

I want Hierarchical Query..I have Table of chart of account

CREATE TABLE COA
(
ACCOUNT_CODE CHAR(19),
ACCOUNT_TITLE VARCHAR2(70),
ACC_TYPE Char(1),
PARENT_CODE CHAR(19)
)
[code]....

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Nov 10, 2011

Look into the below table:

TABLE :- EMPLOYEE
________________________
| ID | SUPERVISOR |
|_______________________|
| A101 | B102 |
|________|______________|
| | |
| B102 | C104 |
|________|______________|
| | |
| C104 | D108 |
|________|______________|
| | |
| D108 | E104 |
|________|______________|

Here B102 is supervisor of A101 and C104 is supervisor of B102 and so on. I want to get this data into new table in below format

TABLE :- Hierarchy
________________________________________________________________
| ID |SUPERVISOR_1 |SUPERVISOR_2 |SUPERVISOR_3 |SUPERVISOR_4|
|______________________|_____________|_____________|____________|
| A101 | B102 | C104 | D108 | E104 |
|________|_____________|_____________|_____________|____________|
| | | | | |
| B102 | C104 | D108 | E104 | NULL |
|________|_____________|_____________|_____________|____________|
| | | | | |
| C104 | D108 | E104 | NULL | NULL |
|________|_____________|_____________|_____________|____________|
| | | | | |
| D108 | E104 | NULL | NULL | NULL |
|________|_____________|_____________|_____________|____________|
| | |
| E104 | NULL | NULL NULL NULL
|________|_____________|_____________|_____________|____________|

I want to insert 1st two rows into Hierarchy table, then I would like to update Supervisor_2 to Supervisor_4. Here I don't want to use 'CONNECT BY PRIOR', as it take more time to execute (there are millions of records).SQL code for same.

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Mar 5, 2010

i'm trying to display the heirarichal relationship between the tables (parents-child-subchild).

[b]table structure[/b]
DEPT
|PK-DEPT_ID
|
EMP
|pk-EMP_ID

[code]....

Expected output

table_name path
DEPT DEPT
EMP DEPT/EMP
EMP_AUTHORIZATION DEPT/EMP/EMP_AUTHORIZATION
EMP_AUTHRIZATION_CARD DEPT/EMP/EMP_AUTHORIZATION/EMP_AUTHRIZATION_CARD
EMP_AUTHRIZATION_DUP DEPT/EMP/EMP_AUTHORIZATION/EMP_AUTHRIZATION_CARD/EMP_AUTHRIZATION_DUP

but by using below query i am getting complete heirarichy.

SELECT LEVEL,
Table_Name,
Constraint_Name,
R_Constraint_Name ,
SYS_CONNECT_BY_PATH(Table_Name, '/') Path

[code]....

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Mar 5, 2010

i'm trying to display the hierarchical relationship between the tables (parents-child-subchild).

[b]table structure[/b]
DEPT
|PK-DEPT_ID
|
EMP
|pk-EMP_ID
|fK emp_DEPT_fK((FK column is dept_id references dept table dept_id column))

[code]....

but by using below query i am not getting complete heirarichy.

SELECT LEVEL,
Table_Name,
Constraint_Name,
R_Constraint_Name ,
SYS_CONNECT_BY_PATH(Table_Name, '/') Path

[code]....

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Nov 7, 2011

I have a table with 4 columns. The data is stored in an hierarchical format where L1 being the parent and L4 being the lowest child.

L1 L2 L3 L4
1 11 111 1111
2 21 211 2111
2 22 222 2222

[code]...

So each Level(L1 ..L4) has zero or many child levels which further has more levels.With out using PL/SQL how can we write a Select query to give me a distinct of all children, all the way to the lowest level (L4).Example: give me all the children where L1 = 3.Result: 31, 32, 33, 311, 322, 333, 3111, 3222, 3333Is it possible to write such a query or am I asking too much logic out of a select and should go with PL/SQL.

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Apr 24, 2010

Below query. Below is the DDL , DML and expected output.

create table tab_1 (col1 varchar2(10), col2 varchar2(10));
select * from tab_1

Output of query
col1 col2
12
23
34

[code]...

The above query is not giving below expected output.

Output:
4 4/3/2/1
3 3/2/1
7 7/6/5
8 8/7/6/5
11 11/10/9

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Nov 30, 2010

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Mar 12, 2008

I have a table of N records with: Name SeqNo ID Col4 ... ColX

where Name and ID are non-unique, and SeqNo is a monotonic non-consecutive sequence 0 .. N that is unique within ID..I'd like to generate the following 'groups': For each record where SeqNo = 0, sorted by Name, create the 'group where ID is the same, ordered by SeqNo irrespective of the

values of any of the other columns. For instance, if the table contained:

NameSeqNoIDCol4 ... ColX
RPL2975...
TLM0444...
AAB2801...
AZZ0801...
ABA3444...
KTT4975...
ABA1801...
YHG0975...
DEF1444...

I'd like to generate:

NameSeqNoIDCol4 ... ColX
AZZ0801...
ABA1801...
AAB2801...
TLM0444...
DEF1444...
ABA3444...
YHG0975...
RPL2975...
KTT4975...

I got my desired results by brute-forcing via four sub-queries:

Sub-query 1 - Generate the sorted Names with SeqNo = 0
Sub-query 2 - Expand above with the additional columns,
maintaining original order
Sub-query 3 - For each of the records from sub-query 2,
generate the 'dependents' having the same ID
and SeqNo != 0
Sub-query 4 - Expand above with the additional columns,
maintaining original order of sub-query 1
Main query - Create UNION of 2 and 4, sorting by original
order and SeqNo

if there were not a simpler approach - after all, this must be a fairly common issue when generating BOMs.

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Apr 2, 2010

I want to retrieve the data based on the count.

Sample data
AccountSubAccountDate
11.12-Mar-10
11.23-Mar-10
11.34-Mar-10
11.42-Mar-10
11.56-Mar-10
21.67-Mar-10
21.78-Mar-10
21.82-Mar-10
3210-Mar-10
32.111-Mar-10
32.22-Mar-10
32.313-Mar-10
32.414-Mar-10
32.52-Mar-10
42.616-Mar-10
42.717-Mar-10

What i want is I want the data which account is having more than 5 subaccounts within the last one month. Also need data with other date criteria like last 100 days if more than10 sub accounts. need single query.

Output is :

3210-Mar-10
32.111-Mar-10
32.22-Mar-10
32.313-Mar-10
32.414-Mar-10
32.52-Mar-10

Having more than 8lacks in my database. i wrote the query but it is taking much time and didnt give the data even after 14 hours.

My query is :
select * from table a where account in
(select account from table b where b.subaccount=a.subaccount
and b.date>=sysdate-35
group by b.account having count(b.subaccount)>5)
union
select * from table a where account in
(select account from table b where b.subaccount=a.subaccount
and b.date>=sysdate-100
group by b.account having count(b.subaccount)>10)

how to retrieve the Subaccounts which satisfies my requirements.

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SQL & PL/SQL :: Retrieving Column Names And Storing Them

Apr 2, 2010

I'm writing a procedure that takes a table name as a parameter and I would like to print out the column name with the supporting row entry for each row. I know the logic I'd like to use, but how do you query the metadata to return the column names and store them.

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Forms :: Retrieving The Data According To Where Clause?

Jul 30, 2010

I want if the user write for example in text box 'AM TK' the query display the resualt which has am alone tk alone, and that has both. I know that i should use the Like with % but i do not know how to write it in the set property. I have wrote

set_block_property('Employee_Other',default_where,'Upper(name) like '''||UPPER(:key_search.person_name)||'''') ;

This will bring the resualt just if the user write am tk. How i can modify it to return value as i explained above.

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