Performance Tuning :: How To Reduce Cost Of Query

Mar 21, 2013

I have Following wjich takes some minutes to executes i want to be tune so this query Executes fast.

Query :

SELECT a.CHDR_EXCH_CD ,TMHR_EXCH_TM_CD,'S' Sec_type,
round(SUM (Decode(csdt_Depo_Typ,'I',(Cal_Scheme_Rate(csdt_rsm_code,TO_DATE(:P_DT_FR,'DD-MM-RR'),csdt_stsc_cd,csdt_scp_qty)*csdt_scp_qty)-
(Cal_Scheme_Rate(csdt_rsm_code,TO_DATE(:P_DT_FR,'DD-MM-

[Code]...

Explain Plan Result :

Plan
SELECT STATEMENT ALL_ROWS
Cost: 1,669 Bytes: 67 Cardinality: 1
15 HASH GROUP BY
Bytes: 67 Cardinality: 1
14 CONCATENATION

[Code].....

After i see result , no 4 in explain plan result gives TABLE ACCESS FULL . i want to be indexing on that how to do this..

This table MG_COLL_SCP_DTL have index like this

CREATE UNIQUE INDEX CSDT_PK ON MG_COLL_SCP_DTL
(CSDT_CHDR_TRANS_NUM, CSDT_PROD_TYP, CSDT_TRAN_SR_NO, CSDT_CHDR_CDTL_COLL_TYP, CSDT_CHDR_CDTL_COLL_TYP_CD,
CSDT_STSC_CD, CSDT_CHDR_CLNT_CD, CSDT_CHDR_CLNT_TM_CD)

[Code]....

How to Reduce cost ???

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Jun 16, 2010

I have a question about database fragmentation.I know that fragmentation can reduce performance in query times. The blocks are distributed in many extents and scans process takes a long time. Oracle engine have to locate the address of the next extent..

I want to know if there is any system view in which you can check if your table or index has high fragmentation. If it's needed I will have to re-create, move or rebulid the table or index, but before I want to know if the degree of fragmentation is high.

Any useful script or query to do this, any interesting oracle system view?

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Sep 1, 2010

For an query, cost was 16Lakhs and was taking 30min, I brought down the cost to 1.5lakhs, but still it is taking 30min.

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Jul 23, 2010

I am facing one performance issue, in which the query cost is very low compare to cpu cost and as a result the cpu always show the high graph.I am also attaching the gv$sql and gv$sql_plan data of this query.

This is the query:

SELECT PTLS.ITEMTYPE , PTLS.ITEMID , PTLS.STAGEID, TS.USERID, SUM(PREVIOUSHOURS) AS PREVIOUSHOURS, MIN(STARTDATE) AS STARTDATE, MAX(STARTDATE) AS ENDDATE FROM PROJECTTIMELOGSSTAGE PTLS, PROJECTTIMESHEETITEM PTSI, TIMESHEET TS WHERE PTLS.PROJECTID = :B2 AND TS.TIMESHEETID = PTSI.TIMESHEETID AND TS.USERID = :B1 AND PTSI.TIMESHEETID = PTLS.TIMESHEETID AND PTSI.ITEMTYPE = PTLS.ITEMTYPE AND PTSI.ITEMID = PTLS.ITEMID AND (PTSI.ISPWFITEM = 'N' OR PTSI.ISPWFITEM IS NULL) AND PTLS.ITEMTYPE NOT IN ('OtherTsk','NewTsk','Loc','Glb') AND (PTLS.ITEMTYPE, PTLS.ITEMID ) IN (SELECT ITEMTYPE, ITEMID FROM PROJECTTIMELOGSSTAGE PTLS1 WHERE PTLS1.PROJECTID = :B2 AND PTLS1.TIMESHEETID = :B3 ) GROUP BY PTLS.ITEMTYPE, PTLS.ITEMID, PTLS.STAGEID, TS.USERID

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Aug 4, 2010

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Mar 27, 2012

Following is the query on TPC-H schema.

explain plan for select
count(*)
from
orders,
lineitem
where
o_orderkey= l_orderkey.

The trace 10053 (as shown below) for this query shows nested loop join with Lineitem as outer table and Orders as inner table. It is effectively join on composite index (pk_lineitem) of Lineitem and unique index(Pk_orderkey) of Orders table. The cost calculation formula as given in the book as "outer table cost + cardinality of outer table * inner table cost " fails here. I am not able to understand this.

BASE STATISTICAL INFORMATION
***********************
Table Stats::
Table: LINEITEM Alias: LINEITEM
#Rows: 6001215 #Blks: 109048 AvgRowLen: 124.00
Column (#1): L_ORDERKEY(NUMBER)
AvgLen: 6.00 NDV: 1500000 Nulls: 0 Density: 6.6667e-07 Min: 1 Max: 6000000
[code]....

how the cost has been calculated. This does not follow the traditional nested loop cost formula as mentioned in the book.

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Jun 7, 2012

how to reduce the clustering_factor's value which appears in the user_indexes view?

in my table ,its clustering factor's value is so high:

SQL> SELECT UI.clustering_factor,UI.num_rows,UI.index_type,UI.distinct_keys FROM USER_INDEXES UI WHERE UI.table_name = 'TAWB_AWB';

CLUSTERING_FACTOR NUM_ROWS INDEX_TYPE DISTINCT_KEYS
----------------- ---------- --------------------------- -------------
83609 187603 NORMAL 187603

and its block numbers is 5063

SQL> SELECT COUNT(DISTINCT DBMS_ROWID.rowid_block_number(ROWID)) BLOCK_NUM FROM TAWB_AWB A;
BLOCK_NUM
----------
5063

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Performance Tuning :: How To Reduce Consistent Gets Of SQL

Jun 27, 2011

How can I reduce the consistent gets of the sql:

select b.OFFER_ID,
b.OFFER_CODE,
b.OFFER_NAME,
b.OFFER_COMMENTS,
b.BAND_ID,
b.CAN_BE_BUY_ALONE,
b.PRICING_PLAN_ID,
b.PRIORITY,
b.STATE,
[code]...

I have already added the indexes for the outer sql to reduce the cost from 374 to 150. But the the consistent gets seems not reduce that much. I notice that the function will cost 6 consistents gets per execution. It seems it not very high. But if this function goes with the sql, it will cost a very high consistent gets, if I remove this function, the sql only cost 1903 consistents gets.

So what I am thinking there should be two ways to reduce the consistent gets..The first one is reduce the recursive call of the sql. The second is reduce the consistent gets of the function. (but it seems that the consistent gets in this function is very low, only 6.)

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May 24, 2012

After ran db health check, my database report gives the following details

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Aug 17, 2010

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For example, I have the following simple query:

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Questions: With respect to the above query,
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Jun 21, 2011

I use oracle 11g r2

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create table table_t
(Record_no number,
t_no number,
position SDO_GEOMETRY
, occupation_time number);

and inserted many values (examples below )

INSERT INTO tra VALUES
(2,
20503,
SDO_GEOMETRY
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NULL,
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NULL,
NULL),
23037
)
/

and( position) indexed as Rtree spatial index

now when i run spatial query such as

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i tried set autotrace on

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Jun 24, 2011

Below query is taking a long time...

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/

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Dec 14, 2010

In SQL, almost all the thing which are possible with join is possible with sub-query also and vice-a-versa.

So when should I use sub-query and when should I go for join?

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Sep 2, 2010

I am using oracle 10g, i want to know the cost of query. In the explain plan and by auto trace am able to get some query cost, but i dont know how to calculate the query cost.

How i will know the query is costly and take more time..? But i know about the hash table and nested tables in the explain plan.
Other than this how to calculate the query cost..?

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Jan 13, 2009

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---------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost |
----------------------------------------------------------------
| 0 | SELECT STATEMENT | | 178K| 6609K| 129K|
| 1 | TABLE ACCESS FULL| BHI_TRACKING | 178K| 6609K| 129K|
----------------------------------------------------------------

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Dec 26, 2011

I am executing the query below:

INSERT INTO temp_vendor(vendor_record_seq_no,checksum,rownumber,transaction_type,iu_flag)
SELECT /*+ USE_NL ( vd1 ,vd2 ,vd3 ) leading ( vd1 ,vd2 ,vd3 , tvd) */ vd1.vendor_record_seq_no, tvr.checksum, tvr.rownumber, tvr.transaction_type, 'U'
FROM vendor_data vd1,
vendor_data vd2,
vendor_data vd3,
(SELECT rownumber,

[code]....

It is taking different approaches (execution plans) while executing for same set of parameters. Due to which sometimes it executes successfully, but sometimes it fills all TEMP space and get failed. I am pasting both the execution plan (different from expalin plan) below:

I. Successfull Execution Plan:

------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
------------------------------------------------------------------------------------------------------------------------
| 0 | INSERT STATEMENT | | | | 65612 (100)| | | |
|* 1 | HASH JOIN | | 1 | 6121 | 65612 (1)| 00:13:08 | | |

[code]....

II. Failed with TEMP space Execution Plan:

--------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
--------------------------------------------------------------------------------------------------------------------------
| 0 | INSERT STATEMENT | | | | 1967 (100)| | | |
|* 1 | FILTER | | | | | | | |
| 2 | SORT GROUP BY | | 1 | 8233 | 1967 (3)| 00:00:24 | | |
|* 3 | HASH JOIN | | 1 | 8233 | 1966 (3)| 00:00:24 | | |

[code]....

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Jun 25, 2010

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Nov 27, 2012

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This is cause by an sql , which's sql_id is know to me: 4zty77fkf907j when I run

select * from GV$SQL_PLAN_STATISTICS where SQL_ID = '4zty77fkf907j'

I get that the plan hash value is 3405747833.

I ran SELECT Q.PARSING_SCHEMA_NAME

,Q.SQL_ID,ROUND(Q.ELAPSED_TIME / Q.EXECUTIONS)/1000000 AS AVG_USECS
,Q.CHILD_NUMBER
,Q.HASH_VALUE
,Q.PLAN_HASH_VALUE
,'''' || REPLACE(Q.SQL_FULLTEXT

[code]....

and seen that the result was 2 rows(for 2 RAC nodes), with a figure of hundreds of seconds of execution, meaning - bad plan.

when I run

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Query:

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Aug 17, 2012

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Below is the sql and corresponding explain plan in Prod and SIT respectively.

Query:
SELECT seq,CCN,ProcessorPart,root_item,comp_path,Item,comp_item,comp_item_type,
lag(comp_item_type,1,'PART') over(PARTITION BY seq ORDER BY lvl)Nxt_comp_item_type,lvl,bom_qty,
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WHEN 0 THEN 0 ELSE 1 END * EXP (SUM (LN (nullif(abs(bom_qty),0))) OVER (PARTITION BY seq ORDER BY lvl))) Ulti_qty,
'AMER'

[code]...

The tables referred in above query is small tables containing arnd 10k records.The above tables are partitioned on Region and not indexed.

Explain Plan in Prod: COST CARDINALITY BYTES

SELECT STATEMENT, GOAL = ALL_ROWS165173613539322883634804
SORT UNIQUE236360
UNION-ALL
PARTITION LIST SINGLE117240

[code]...

Explain Plan in SIT: COST CARDINALITY BYTES

SELECT STATEMENT, GOAL = ALL_ROWS3211689
SORT UNIQUE347240
UNION-ALL
PARTITION LIST SINGLE172120

[code]...

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Sep 23, 2010

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Feb 21, 2013

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P104-Nov-1204-Nov-12D
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Below is the code which I have written which considers the rundate as Input parameter.

-- To get the Items disabled for Input date
with Itemdisabled as
(
select item,stddate maxcycledate
from Item_tbl
where rundate = stddate

[code]....

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