I need query for below my request...This is our sample text
Original text: ,UNDRLYNG_AST_NM,"NEXTERA ENERGY, INC.",
output Replace text:,UNDRLYNG_AST_NM,"NEXTERA ENERGY~ INC."
i want replace ',' to '~' between the alphabetic or alphabetic with space
I want to replace double space with single space and also remove junk characters from the data. How can I do that?
CREATE TABLE test07013
(
NAME VARCHAR2(50)
);
INSERT INTO VALUES ('WARREN,'); -- REMOVE ","
INSERT INTO VALUES ('CLARK H'); -- REPLACE "DOUBLE SPACE" WITH "SINGLE SPACE"
INSERT INTO VALUES ('BRYAN A.'); -- REMOVE "."
INSERT INTO VALUES ('CARTER JR. ROBERT'); -- REMOVE "."," AND REPLACE "DOUBLE SPACE" WITH "SINGLE SPACE"
TestCase
DROP TABLE test ;
CREATE TABLE test (id NUMBER, cnt_str VARCHAR2(200));
INSERT INTO test (id, cnt_str) VALUES
(1,'AKRN000002,1451-1473,00000A,74,AKRN000002,1475-14791000000A,8010AKRN000002,1481-1492,00000A,9310AKRN000002,1494-1500')
[code]...
The requirement is in each of the string where there is comma after the number and the number is prefixed by "-" character,
the comma after the number should be replaced by '10'.
For example in the second record where ID = 2,
CNT_STR is '00000B,1-251000000D,26-32,ADTW000301,2858-2875'.
In this string -32, should become -3210 and resulting string should be '00000B,1-251000000D,26-3210ADTW000301,2858-2875'
Expected Result.
ID CNT_STR
-------- -------------------------------------
1 AKRN000002,1451-14731000000A,7410AKRN000002,1475-14791000000A,8010AKRN000002,1481-14921000000A,9310AKRN000002,1494-1500
2 00000B,1-251000000D,26-3210ADTW000301,2858-2875
3 AKRN000001,1126-12001000000B,501-525
i have a database column holding first name and last name. I want to find out the special characters and convert it to empty space.
Eg : kishore's 001 ==> kishores 001
: jerryKumar* ==> jerryKumar
I have 70 materialized views where I need to replace the FROM SCHEMA1 TO FROM SCHEMA2...To quickly to do the fix for all the 70 views..
SELECT REPLACE (QUERY, 'schema1', 'schema2' )FROM USER_MVIEWS ;
But It throws me an error that Number cannot be replace.
Just now sysaux resized to 600m from 250m >>
Sysaux Tablespace is running low. WE SET AWR RETENTION TIME=60 DAYS. WE ARE NOT INTEREST TO EXTEND SYSAUX TABLESPACE SIZE.
Usually we take AWR weekly once. Some times we did ADDM report and ASH.
CODEsql>select TABLESPACE_NAME, FILE_NAME, BYTES/(1024*1024), AUTOEXTENSIBLE, MAXBYTES/(1024*1024) from dba_data_files where tablespace_name = 'SYSAUX';
TABLESPACE_NAME FILE_NAME BYTES/(1024*1024) AUT MAXBYTES/(1024*1024)
SYSAUX /u01/app/oracle/oradata/test/sysaux01.dbf 600 YES 32767.9844
CODEsql> @SCRIPT.SQ
TABLESPACE TOTAL_SPACE(MB) USED_SPACE(MB) FREE_SPACE(MB) % Used % Free
SYSAUX 600 248 352 41.33 58.67
1. What's the best SOLUTION ?
2. Can i shrink sysaux tablespace ?
3. I think , The size for all occupants in sysaux tablespace is less than 200 MB => how to find actual content of sysaux tablespace ?
4. What could be the reason for growth? Is there any way to free the space from sysaux table space?
I have a question.
When and Where HASH VALUE for a given SQL statement get generated?
Is it true that the SQL hash is computed on the SQL text only ?
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View 11 Replies View RelatedI see one of my SQL's which is ran by the user on a 10.2.0.3 database changing its SQL_ID after some runs even if the query is not changed a bit! However the HASH VALUE for this query remains the same.
how a same query can have different SQL_ID's but same HASH_VALUE?
Note: Statistics are not modified on the base tables of this query.
I am facing a problem in fetching / updating records from a customer details table having around 20 million records. The table contains around 30 fields with 'MOBILE_NO' as primary key. most of the queries are having 'mobile_no' in where clause .I am planning to hash partition that table using mobile_no column as there is no other column available which can be used for partition.
clarify whether creating hash partition on such key would increase performance of data extraction as I have read on net that hash partitioning is not effective for performance tuning.
I see that one of my queries from an application time is spending most of its time in the hash group by. I'm running Oracle 11g with a quarter rack exadata appliance. Is there a better way to run or design this table? query:
SELECT COUNT(*)
FROM (
SELECT "DDTMDAY", "MRKTNM", "BSMNM", "BSCNM", "CLNM", "CSCDNM", "BTSID", "SECTSEQID", "BNDID", "FAID", SUM("VATTCNT"), SUM("VMBLORGCNT"), SUM("VMBLTERCNT"), SUM("VSILENTRETRYCNT"), SUM("VCUSTBLKCNT"), SUM("VAXSFCNT"), SUM("VCEBLKCNT"), SUM("VWCDBLKCNT"), SUM("VT1BHLBLKCNT"), SUM("VPWRBLKCNT"), SUM("VNONBTSEQBLKCNT"), SUM("VSFULCALLCNT"), SUM("VDRPCALLCNT"),
[code]...
A basic select and group by query I am optimising for my Database course has returned results that indicate it will perform better on a clustered index when returning a smaller number of rows (5% of the largest table) and on a hash clustered index when returning higher volumes (50% and 80%). I understand that it is possible to use more than one index type on a table to improve performance, but I am struggling to understand how I might establish a hash cluster and a cluster on the same table? and then use hints to drive the query down one access path or the other.
Site admin - this site is a very useful resource.
What is the difference between Hash join and Nested Loops in pl / sql?
View 1 Replies View RelatedI tried to search on google for "Hash Join" And "Sort Merge". But unfortunatly i am unable to understand that articles. "Hash join" And "Sort Merge".
View 3 Replies View RelatedI created a single table hash cluster like this :
create tablespace mssm datafile 'c:appmssm01.dbf' size 100m
segment space management manual;
create cluster hash_cluster_4k
( id number(2) )
size 8192 single table hash is id hashkeys 4 tablespace mssm;
-- Created a table in cluster with row size such that only one record fits one block and inserted 5 records each with a distinct key value
CREATE TABLE hash_cluster_tab_8k
( id number(2) ,
txt1 char(2000),
txt2 char(2000),
txt3 char(2000)
)
CLUSTER hash_cluster_8k( id );
[code]....
If I issue the same query after creating unique index on hash_cluster_tab(id), the execution plan shows hash access and single I/O (cr = 1).Does it mean that to have single I/o in a single table hash cluster, we have to create unique index? Won't it create additional overhead of maintaining an index?
What is the second I/O needed for in case unique index is absent?
I have a existing non partition table with more than 100 million records,planning to re design using Hash partition.This table doesn't has any range column to do range partitioning.
Table has 40 columns with a Primary Key on two columns (guest_sales_Id ,Version Flag). guest_sales_Id is unique for entire table but with anopther column version Flag declared as Primary key.(Version Falg will have only two distinct values in entire table)
If i do hash partition,do i need to declare on two columns which are declared ad Primary key ?If i use only guest_sales_id to declare hash prtition any issues ?
I created the 32 hash partition on a fact table. Based on hash parititon technique it should evenly distribute data accross the different partition.But when i analyze the table and check the distribution its not at all even.
P_Name Tabspace num_Rows
SYS_P21TBS_TBS0
SYS_P22TBS_TBS0
SYS_P23TBS_TBS0
[Code]....
note we need to decrypt the data which is encrypted using dbms_crypto.hash algorithm. it is possible to decrypt dbms_crypt.hash
eg
SQL> select DBMS_CRYPTO.hash(utl_raw.cast_to_raw('Foo'), 3) FROM dual;
DBMS_CRYPTO.HASH(UTL_RAW.CAST_TO_RAW('FOO'),3)
--------------------------------------------------------------------------------
201A6B3053CC1422D2C3670B62616221D2290929
Getting an ORA-00060 in our database. This is the alert log:
Wed Nov 10 08:01:54 2010
Global Enqueue Services Deadlock detected. More info in file
/opt/oracle/admin/ngboot/bdump/ngboot1_lmd0_13119.trc.
This is part of the lmd file:
oprocp : (nil)
opid : 0
group lock owner : (nil)
xid : 0000-0000-00000000
dd_time : 0.0 secs
dd_count : 0
timeout : 0.0 secs
[Code] ......
How do I find the SQL causing this? I have the hash value of 3180952482. should I open up en SR as this i logged in an lmd trace?
With this table in local and remote database via a DBLink
CREATE TABLE PICTURES (
ID NUMBER(12),
PICNAME VARCHAR2(20),
PICTURE BLOB
);
How come I can get the hash of the picture column fine like this:
SELECT dbms_crypto.hash@dbLink(PICTURE, 3)from SCHEMA1.PICTURES@dbLink;
but I can't do it in a union with the local database?
SELECT dbms_crypto.hash@dbLink(PICTURE, 3)from SCHEMA1.PICTURES@dbLink
UNION
SELECT dbms_crypto.hash(PICTURE, 3)FROM SCHEMA1.PICTURES;
gives "ORA-06553: PLS-564: lob arguments are not permitted in calls to remote server"
I was reading the documentation for oracle 11gr2, with reference to URL>.....
The following examples show how to correctly choose the cluster key and set the HASH IS, SIZE, and HASHKEYS parameters. For all examples, assume that the data block size is 2K and that on average, 1950 bytes of each block is available data space (block size minus overhead).Note that 34 hash keys are assigned for each data block
how they arrive at 34 hash keys because another portion of the document states
This space determines the maximum number of cluster or hash values stored in a data block. If SIZE is not a divisor of the data block size, then Oracle Database uses the next largest divisor.
if that is the case, then number of hash keys should be 1900/55 = 34.55 which should have rounded up to 35.
At moment we use range-hash partitioning of a large dimension table (dimension model warehouse) table with 2 levels - range partitioned on columns only available at bottom level of hierarchy - date and issue_id.
Result is a partition with null value - assume would get a null partition in large fact table if was partitioned with reference to the large dimension.Large fact table similarly partitioned date range-hash local bitmap indexes
Suggested to use would get automatic partition-wise joins if used reference partitioningWould have thought would get that with range-hash on both dimension.
I have to create a hash partition on fact tables.. we can use temp tablespace or permanent tablespace.
View 10 Replies View RelatedWhile trying partition exchange feature of Oracle with 2 hash partitioned tables, I come to know that I can't directly exchange partitions between 2 partitioned tables
I have two hash partitioned tables , so to move partition data from one table to another will include-
1) Exchange from partitioned table to non-partitioned table.
2) exchange from non-partitioned table to new partitioned table.
But I am not sure in which hash partition my data will go in new partitioned table (data need to be moved has single key value on basis of which tables are partitioned),
When I try to print a decimal value , I get the dot replaced with a comma.
SQL> select 23.45 from dual;
23.45
----------
23,45
Is it because of any particular sqlplus set command or OS issue?
Create table a ( Objectid number, Value varchar2(2000);
/
Insert into a values (12, '2,3,4');
Insert into a values (13, '8,7,4');
Insert into a values (14, '3,8,9');
Insert into a values (15, '6,3,11');
I should get the output as:
ID Value
------ ------
12 2
12 3
12 4
13 8
13 7
13 4
14 3
14 8
14 9
15 6
15 3
15 11
I am trying to insert data into a table which I created but I keep getting the error: missing comma.
INSERT INTO EMPLOYEE_DATA
(EMPLOYEE_ID, FIRST_NAME, LAST_NAME, DEPARTMENT, SALARY_(£), SALARY_PAIDON)
VALUES
('1', 'David', 'Smith', 'IT', '20,000', '3/11/2012')
I want to know how the Oracle optimizer choose joins and apply them while executing the query. So that I will insure about optimizer join before writing any query.
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