Performance Tuning :: How Oracle Optimizer Choose Joins (hash / Merge And Nested Loop Join)
Oct 18, 2012
I want to know how the Oracle optimizer choose joins and apply them while executing the query. So that I will insure about optimizer join before writing any query.
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Mar 27, 2012
Following is the query on TPC-H schema.
explain plan for select
count(*)
from
orders,
lineitem
where
o_orderkey= l_orderkey.
The trace 10053 (as shown below) for this query shows nested loop join with Lineitem as outer table and Orders as inner table. It is effectively join on composite index (pk_lineitem) of Lineitem and unique index(Pk_orderkey) of Orders table. The cost calculation formula as given in the book as "outer table cost + cardinality of outer table * inner table cost " fails here. I am not able to understand this.
BASE STATISTICAL INFORMATION
***********************
Table Stats::
Table: LINEITEM Alias: LINEITEM
#Rows: 6001215 #Blks: 109048 AvgRowLen: 124.00
Column (#1): L_ORDERKEY(NUMBER)
AvgLen: 6.00 NDV: 1500000 Nulls: 0 Density: 6.6667e-07 Min: 1 Max: 6000000
[code]....
how the cost has been calculated. This does not follow the traditional nested loop cost formula as mentioned in the book.
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Oct 14, 2013
I'm looking to see if there is a way (fully expecting it to be an underscore, or two...) to force the optimizer to keep churning until all permutations are exhausted.I'm aware that it, to paraphrase, cuts out when it's spent more time parsing than it would just running it based on it's estimates.
I've got some irritating problems with xml rewrite, xml indexes and access paths/cardinalities etc and I'm really needing the entire thing considered as a one off for debugging this. I've already cranked up the maximum permutations to the max but it's not enough, it shorts out after 5041 permutations (I'd set that to 80000 max).
I know you'd not want to do this in the real world but I cant get the damned thing to run the plan I want in a 10053 so I can see the values it has there. I know I can hint it, but I'm trying to ascertain why it's not even considering it in a "normal" parse.
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Jun 23, 2011
I'm joinging two tables event_types and tmp_acc tables.
event_types contains 2 Billion records
tmp_acc contains 20,000 records.
Resulting rows are about 300,000 records in event_types table end_t and account_obj_id0 are joined indexed
no indexs in tmp_acc.
When I run below query with nexted loop it takes 6 hrs to complete. But when I run with hash join even after 4 days it was still running. what is wrong with hash join here. Why it takes so long. I'm joining only 20000 rows. So I think there should be a way to get result rows quickly.
show parameters hash_area_size
NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
hash_area_size integer 2097152
explain plan for
select --+ parallel(e,6)
[code]....
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Jun 12, 2012
I tried to search on google for "Hash Join" And "Sort Merge". But unfortunatly i am unable to understand that articles. "Hash join" And "Sort Merge".
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Oct 30, 2012
I want to make sure I am describing correctly what happens in a query where there is distributed database access and it is participating in a NESTED LOOPS JOIN. Below is an example query, the query plan output, and the remote SQL information for such a case. Of particular note are line#4 (NESTED LOOPS) and line#11 (REMOTE TABLE_0002).
What I want to know is more detail on how this NESTED LOOPS JOIN handles the remote operation. For example, for each row that comes out of line#5 and is thus going into the NESTED LOOPS JOIN operation @line#4, does the database jump across the network to do the remote loopkup? Thus if there are 1 million rows, does that mean 1 million network hops? Does batchsize play a role? For example, if the database batches in groups of 100 then does that mean 10 thousand network hops?
I think each row that comes out of line#5 means a network hop to the remote database. But I do not know for a fact.I have done some abbreviating in the plan in an attempt to make it fit on the page (line#7 TA = TABLE ACCESS).
SELECT A.POLICY ,
F.MIN_MEMBER_ID,
MIN(A.EFF_DATE) EFF_DATE,
A.EXP_DATE ,
G.DESCRIPTION PROGRAM_NAME,
[code]...
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Mar 16, 2011
What is the difference between Hash join and Nested Loops in pl / sql?
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Jan 22, 2009
how to reduce the cpu cost for a query at query level.
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Nov 2, 2012
I see one of my SQL's which is ran by the user on a 10.2.0.3 database changing its SQL_ID after some runs even if the query is not changed a bit! However the HASH VALUE for this query remains the same.
how a same query can have different SQL_ID's but same HASH_VALUE?
Note: Statistics are not modified on the base tables of this query.
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Nov 18, 2010
Getting an ORA-00060 in our database. This is the alert log:
Wed Nov 10 08:01:54 2010
Global Enqueue Services Deadlock detected. More info in file
/opt/oracle/admin/ngboot/bdump/ngboot1_lmd0_13119.trc.
This is part of the lmd file:
oprocp : (nil)
opid : 0
group lock owner : (nil)
xid : 0000-0000-00000000
dd_time : 0.0 secs
dd_count : 0
timeout : 0.0 secs
[Code] ......
How do I find the SQL causing this? I have the hash value of 3180952482. should I open up en SR as this i logged in an lmd trace?
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Oct 31, 2011
I have two tables with 113M records in DWH_BILL_DET & 103M in prd_rerate_chg_que and Im running following merge query, which is running for 13 hrs to update records, which is quiet longer time.
SQL> explain plan for MERGE /*+ parallel (rq, 16) */
INTO DWH_BILL_DET rq
USING (SELECT rated_que_rowid,
detail_rerate_flag_code,
rerate_sel_key,
[code].....
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Aug 5, 2010
I have to create a hash partition on fact tables.. we can use temp tablespace or permanent tablespace.
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Jul 18, 2012
Query -
SELECT *
FROM sysadm.ps_tmtl_post_vw a
WHERE a.month_prepared_for = 'JUNE,2012'
AND a.ca_status = 'P5 CUST GO AHEAD'
[code]...
When I try for the SQL-Tuning sets its throws error that
ADDITIONAL INFORMATION SECTION
-------------------------------------------------------------------------------
- The optimizer could not merge the view at line ID 2 of the execution plan.
The optimizer cannot merge a view that contains a set operator.
I read earlier forum where it says that optimizer unable to interpret the conditions like order by etc etc.Now there is one view which is getting used in the query when I did select * from vw it took more than 16 hrs to complete. (bad view).
Attached File(s)
exec_plan.txt ( 2.06MB )
Number of downloads: 1
view_def.txt ( 14.12K )
Number of downloads: 2
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Dec 3, 2012
how joins work with in-line views.I have a query and its explain plan as below:
SELECT e.ename,e.deptno,d.dname FROM
dept d,
emp e
WHERE e.deptno=d.deptno
AND e.deptno=20
[code]....
I do not find any difference in both the explain plans. Both are same. In my second query, the filtered rows will be joined to dept table. And hence the baggage will reduce.But how can I verify that in-line view has worked better?
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Apr 6, 2011
mbr has 60,000 rows and member has 60,000 rows approx. two tables have indexes on ssn, and citi_no on them.
PK of mbr : mbr_id
PK of member : mbr_id
other columns are not PK, and have no index on it.
I'm wondering why the statment doesn't use index while ssn and citi_no have index.
MERGE INTO mbr t
USING (SELECT mbr_id,citi_no
FROM member) a
ON (t.ssn = a.citi_no)
WHEN MATCHED THEN
UPDATE SET t.asis_mbr_id = a.mbr_id
where t.ssn not in(select ssn from mbr group by ssn having count(*) > 1)
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Sep 14, 2010
10.2.0.1
I am trying to understand the concept of nested loops.
--------
| 0 | SELECT STATEMENT | | 14 | 364 | 4 (0)| 00
:00:01 |
| 1 | NESTED LOOPS | | 14 | 364 | 4 (0)| 00
:00:01 |
[Code]....
Predicate Information (identified by operation id):
---------------------------------------------------
4 - access("A"."DEPTNO"="B"."DEPTNO")
Nested loop by defintion means,for every row returned by the outer query,the inner query is executed that many times.
In the above example,oracle does a full table scan and returned 14 rows.Now for dept table,it does a index unique scan and applies the predicate a.deptno=b.deptno and returns 1 row.
My question is why it is returning only 1 row? That measn for every 14 rows,this one row is fetched 14 times.
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Nov 1, 2011
Oracle Version: 11.2.0.2.0. I have two explicit cursors and I would like to choose at run time which one to run. Here is a simplified code snippet of what I am doing today:
DECLARE
CURSOR Cursor_A IS
SELECT * FROM EMP_A;
CURSOR Cursor_B IS
SELECT * FROM EMP_B;
RUNA CHAR(1) := 'Y';
[code]....
I want to avoid maintaining the same long list of transformations. I also want to avoid, if possible, an explicit FETCH INTO, because there are hundreds of fields in both tables. I'm looking for something like this (and I know this doesnt work):
DECLARE
CURSOR Cursor_A IS
SELECT * FROM EMP_A;
CURSOR Cursor_B IS
SELECT * FROM EMP_B;
RUNA CHAR(1) := 'Y';
CursorToRun IS REF CURSOR;
[code]....
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Mar 11, 2011
Can this be optimized, in dev and Ist we didn't realize since 1000 rows were there, but in PERF since 2 mil rows are there this is taking a long time,
SET SERVEROUTPUT ON
DECLARE
counter number := 0;
CURSOR insertValues IS select roleid, productcode, functioncode, typecode, restrictiontype, value1 from restrictions where actionmode = 'INSERT';
[code]...
can this be done in a single update since Selects /Updates are happening on same table
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Sep 18, 2012
So usually joining a local table and a remote table (much larger table), the best practice is using a /*+ DRIVING_SITE(remote table) */ hint.
*CASE1:
INSERT INTO another_local_table
SELECT /*+ DRIVING_SITE(remote_table) */
FROM local_table
,remote_table@remotedb
WHERE join condition
*CASE2:
However I saw this particular
FOR x IN Select id From local_table l
LOOP
INSERT INTO another_local_table
[code]...
So far I haven't seen the explain plan of both cases since most of the tables are Global temporary tables. But in terms of the logic of the two cases and the common best practice, logically doesn't CASE1 should have a better performance?
For me, its like taking a trip to a grocery. CASE1 buys all that you need, one time, it will take you a half-day trip perhaps. However CASE2 is like quickly buying a grocery item, one at a time, for several short trips. You'll save on gas on CASE1 right.
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Sep 8, 2009
SQL> select * from v$version;
BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for Solaris: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
5 rows selected.
I have a problem with views and nested selects which I cannot explain. Here is a trimed down version of the research I have done. notice the following:
1) all code is executed from the same user CDRNORMALCODE. this user has all views and procedural code
2) all data is owned by a different user CDRDATA. This user has no views and no code.
My problem is this:
If I reference the table directly with a delete statement that uses a nested select (i.e. IN clause with select), the index I expect and want is used.But if I execute the same delete but reference even the most simple of views (select * from <table>) instead of the table itself, then a full table scan is done of the table.
Here is an execute against the table directly (owned by cdrdata). Notice the reference to the table in the table schema on line 3. Also please notice INDEX RANGE SCAN BSNSS_CLSS_CASE_RULE_FK1 at the bottom of the plan.
SQL> show user
USER is "CDRNORMALCODE"
SQL>
SQL> explain plan for
2 delete
[code]...
OK, here is an update. The views I am useing normally have instead of triggers on them. If I remove the instead of trigger the problem looks like it goes away, when I put the trigger back the problem comes back.But why would an instead-of-trigger change the query plan for a view?
SQL> DELETE FROM PLAN_TABLE;
5 rows deleted.
SQL> explain plan for
2 delete
3 from BSNSS_CLSS_MNR_CASE_RULE_SV
[code]...
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Jul 23, 2013
The full statement is:
SELECT v.key$ FROM VERSION_TABLE v, DOCUMENT_TABLE d, CLASS_TABLE z WHERE
v.documentKey = d.key$ AND
d.classKey = z.key$ AND
z.key$ IN (SELECT zz.key$ FROM CLASS_TABLE zz
START WITH zz.name = 'esDTTemplate'
CONNECT BY PRIOR zz.key$ = zz.parentKey) AND
v.ESGROUP = 'SearchOperatorsMapping' ORDER BY d.name
Now I noticed that the subquery is never used to seed the join: indexes - if any - are used. Otherwise a full table scan is performed.In the example - if ESGROUP is indexed, then it's chosen to start the join evaluation. If not, a full table scan is performed.Is there any way to suggest to the optimizer to use the subquery in case there are no indexes - as a fallback ?
In the above example where VERSION_TABLE contains nearly two million records, the no index solution takes 60 secs. vs. less than 1 sec. in the index case.Wrapping the hierarchical query in a inline view leads to same result.
PS: the execution plan (without index) is:
-------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time
-------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | | | 9 (100)| |
| 1 | SORT ORDER BY | | 1 | 171 | 9 (23)| 00:00:01 |
|* 2 | HASH JOIN SEMI | | 1 | 171 | 8 (13)| 00:00:01 |
[code]...
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Jan 16, 2012
I have to do the optimization of a query that has the following characteristics:
- Takes 3 hours to process
- Performs the inner join with 30 tables
- Produces an output of 280 million records with 450 fields
First of all it is not feasible to make 30 updates (one for each table) to 280 million records.
The best solution that I had found so far was to create 3 temporary tables, where each of them to do the join with 1/3 of the 30 tables, and in the end I make the join between the main table and these three tables temporary.
I know that you will ask (or maybe not) to the query and samples, but it is impossible to create 30 examples.
how to optimize this type of querys that perform the join with multiple tables and produce a large output with (too) many columns.
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Dec 14, 2010
In SQL, almost all the thing which are possible with join is possible with sub-query also and vice-a-versa.
So when should I use sub-query and when should I go for join?
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Apr 10, 2013
I have a select query that was working with no problems. The results are used to insert data into a temp table.
Recently, it would not complete executing. The explain plan shows a cartesian. But, there could be problems with using nested loops on the outer join.
Interestingly, when I copy production code and rename the temp table and rename the view, it works.
CREATE TABLE "CT"
( "TN" VARCHAR2(30) NOT NULL ENABLE,
"COL_NAME" VARCHAR2(30) NOT NULL ENABLE,
"CDE" VARCHAR2(5) NOT NULL ENABLE,
"CDE_DESC" VARCHAR2(80) NOT NULL ENABLE,
[Code]....
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Mar 14, 2012
For a hash join statement, is it beneficial to have the join condition objects in the index as well as the objects in the where clause?
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Nov 14, 2012
The product I work on requires a query to tell us what tables are dependent on certain types.
SELECT dba_tab_cols.owner,
dba_tab_cols.table_name,
dba_tab_cols.data_type_owner,
dba_tab_cols.data_type
FROM dba_tab_cols
JOIN dba_types
ON dba_types.owner = dba_tab_cols.data_type_owner
AND dba_types.type_name = dba_tab_cols.data_type
WHERE (dba_types.owner IN ('SCHEMA1', 'SCHEMA2'......))
I find this query to be pretty slow. I think it is because data_type_owner in dba_tab_cols is not indexed. Adding an index is not an option because users expect our product to read-only.
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Oct 24, 2011
however I was able to identify a poorly performing query that seemed to be maxing out our CPU. I have been trying to understand the Explain Plan. The plan below is from our test system which has considerably less information in the tables than our PROD system.
I can see there are a bunch of table scans at the end which may indicate missing indexes, but I am unclear on whether this is actually a problem as the %CPU seems to be worse for the JOIN near the top of the plan.
-------------------------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time | Inst |IN-OUT|
-------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1870M| 3018G| | 677M (1)|999:59:59 | | |
| 1 | SORT ORDER BY | | 1870M| 3018G| 3567G| 677M (1)|999:59:59 | | |
[code]...
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Sep 12, 2011
Having production system: 11.2.0.1 on Windows Server x64
Test system: 9.2.0.1 on Windows XP
Problem preface: to get all unique CASEID which should be checked up by biometric system.What i should check - all CASEs for different PERSONs having same PHONEs at least among one phone type (1..4).Real table contains little bit more than 10 million records.I made test scripts.
Below the DDL for test table creation:
------------------------------------------
-- Create CASEINFO test table
------------------------------------------
DROP TABLE CASEINFO;
CREATE TABLE CASEINFO
[code]...
Below i've put SQL/DLL to make test data.number of records inserted 2 millions.
PERSON_COUNT := #/8;
------------------------------------------
-- fill CASEINFO with sample data
------------------------------------------
DECLARE
I INTEGER;
[code]...
Below SQL select to check the data in created table.
------------------------------------------
-- Check test data counters
------------------------------------------
SELECT 'TOTAL',count(*) from CASEINFO
UNION ALL
SELECT 'LEGAL',count(*) from CASEINFO where
[code]...
The PROBLEM is that i am experiencing HUGE perfomance problems on both test and production systems with that query:
select distinct b.caseid
from CASEINFO a, CASEINFO b
where (a.person<>b.person) and (a.sex=b.sex) and
(
(a.phone1=b.phone1) or
(a.phone1=b.phone2) or
(a.phone1=b.phone3) or
[code]...
This query takes almost 90 minutes to execute.And i do not know how to avoid this.Full SQL file to make test attached.
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Oct 18, 2010
I am posting the below query:
SELECT PEA.INCURRED_BY_PERSON_ID AS PERSON_ID,
PEA.EXPENDITURE_ENDING_DATE AS WEEK_END_DATE,
CASE
[Code].....
The explain is below:
SELECT STATEMENT ALL_ROWSCost: 48,287 Bytes: 18,428,818 Cardinality: 297,239
3 HASH JOIN Cost: 48,287 Bytes: 18,428,818 Cardinality: 297,239
1 TABLE ACCESS FULL TABLE PA.PA_EXPENDITURES_ALL Cost: 2,964 Bytes: 3,506,094 Cardinality: 194,783
2 TABLE ACCESS FULL TABLE PA.PA_EXPENDITURE_ITEMS_ALL Cost: 43,425 Bytes: 26,637,468 Cardinality: 605,397
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Jul 12, 2012
what is Hash join?how it is different from inner join?what is the sign used for inner join?(eg: like the (+) sign used for outer join)?
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