Performance Tuning :: Nested Select / Instead Of Trigger And Views - No Index Used?
Sep 8, 2009
SQL> select * from v$version;
BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for Solaris: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
5 rows selected.
I have a problem with views and nested selects which I cannot explain. Here is a trimed down version of the research I have done. notice the following:
1) all code is executed from the same user CDRNORMALCODE. this user has all views and procedural code
2) all data is owned by a different user CDRDATA. This user has no views and no code.
My problem is this:
If I reference the table directly with a delete statement that uses a nested select (i.e. IN clause with select), the index I expect and want is used.But if I execute the same delete but reference even the most simple of views (select * from <table>) instead of the table itself, then a full table scan is done of the table.
Here is an execute against the table directly (owned by cdrdata). Notice the reference to the table in the table schema on line 3. Also please notice INDEX RANGE SCAN BSNSS_CLSS_CASE_RULE_FK1 at the bottom of the plan.
SQL> show user
USER is "CDRNORMALCODE"
SQL>
SQL> explain plan for
2 delete
[code]...
OK, here is an update. The views I am useing normally have instead of triggers on them. If I remove the instead of trigger the problem looks like it goes away, when I put the trigger back the problem comes back.But why would an instead-of-trigger change the query plan for a view?
SQL> DELETE FROM PLAN_TABLE;
5 rows deleted.
SQL> explain plan for
2 delete
3 from BSNSS_CLSS_MNR_CASE_RULE_SV
[code]...
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Feb 18, 2011
I have created table with nested table:
CODECREATE OR REPLACE TYPE ADDR_T AS OBJECT (
ADDR1 VARCHAR2 (50),
ADDR2 VARCHAR2 (50)
);
CREATE OR REPLACE TYPE t_ADDr AS TABLE OF ADDR_T;
[code]....
I have added some records and created index on ID column. I want to get result of CODEselect id, p.addr1,p.addr2 from nested_table n,table(n.COL1) p where id=1
Explain plan for that is:
CODESELECT STATEMENT ALL_ROWSCost: 8 Bytes: 231 Cardinality: 3
4 HASH JOIN Cost: 8 Bytes: 231 Cardinality: 3
2 TABLE ACCESS BY INDEX ROWID TABLE SYS.NESTED_TABLE Cost: 2 Bytes: 13 Cardinality: 1
1 INDEX RANGE SCAN INDEX SYS.FDSFAS Cost: 1 Cardinality: 1
3 TABLE ACCESS FULL TABLE (NESTED) SYS.COL1_TAB Cost: 5 Bytes: 163,840 Cardinality: 2,560
How to avoid full table scan on nested table? Cardinality is sum of all records in nested column in all rows in main table, why?
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Sep 14, 2010
10.2.0.1
I am trying to understand the concept of nested loops.
--------
| 0 | SELECT STATEMENT | | 14 | 364 | 4 (0)| 00
:00:01 |
| 1 | NESTED LOOPS | | 14 | 364 | 4 (0)| 00
:00:01 |
[Code]....
Predicate Information (identified by operation id):
---------------------------------------------------
4 - access("A"."DEPTNO"="B"."DEPTNO")
Nested loop by defintion means,for every row returned by the outer query,the inner query is executed that many times.
In the above example,oracle does a full table scan and returned 14 rows.Now for dept table,it does a index unique scan and applies the predicate a.deptno=b.deptno and returns 1 row.
My question is why it is returning only 1 row? That measn for every 14 rows,this one row is fetched 14 times.
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Jun 28, 2011
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
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Jan 28, 2011
We are using the below query to create a Materialized View but it has been running since 3 hours. It is an Oracle 9i database running in HP-UX.The quey is as follows,
(SELECT
/*+ use_nl(A) parallel (A,4)*/
A.ICD_CODE AS ICD_CODE,
A.ICD_DESC AS ICD_DESC,
A.PROC_GROUP as PROC_GROUP,
B.COMPL_ICD_CODE AS COMPL_ICD_CODE,
B.COMPL_GRP_TXT AS COMPL_GRP_TXT,
C.PROC_TYPE AS PROC_TYPE ,
[code]....
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Nov 19, 2010
I have a query which had a join:
a.c1=b.c1 and a.c2=@var
where @var is user supplied input at runtime...We had a index on a.c2 . The CBO would use this index to generate an opitimised query plan.We found some records from table "b" were dropping due to inner join. So we made a change in join. It'd be like
a.c1(+)=b.c1 and nvl(a.c2,@var)=@var
This query is no longer using the index, instead its doing a full table scan causing the query to slowdown.I have tried creating index on nvl(a.c2,'31-dec-9999')
But the CBO won't use it.Anyway to create index on this col so that full table scan can be avoided?
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Aug 9, 2013
How to force an index if the table not using the index?
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Dec 3, 2012
how joins work with in-line views.I have a query and its explain plan as below:
SELECT e.ename,e.deptno,d.dname FROM
dept d,
emp e
WHERE e.deptno=d.deptno
AND e.deptno=20
[code]....
I do not find any difference in both the explain plans. Both are same. In my second query, the filtered rows will be joined to dept table. And hence the baggage will reduce.But how can I verify that in-line view has worked better?
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Oct 30, 2012
I want to make sure I am describing correctly what happens in a query where there is distributed database access and it is participating in a NESTED LOOPS JOIN. Below is an example query, the query plan output, and the remote SQL information for such a case. Of particular note are line#4 (NESTED LOOPS) and line#11 (REMOTE TABLE_0002).
What I want to know is more detail on how this NESTED LOOPS JOIN handles the remote operation. For example, for each row that comes out of line#5 and is thus going into the NESTED LOOPS JOIN operation @line#4, does the database jump across the network to do the remote loopkup? Thus if there are 1 million rows, does that mean 1 million network hops? Does batchsize play a role? For example, if the database batches in groups of 100 then does that mean 10 thousand network hops?
I think each row that comes out of line#5 means a network hop to the remote database. But I do not know for a fact.I have done some abbreviating in the plan in an attempt to make it fit on the page (line#7 TA = TABLE ACCESS).
SELECT A.POLICY ,
F.MIN_MEMBER_ID,
MIN(A.EFF_DATE) EFF_DATE,
A.EXP_DATE ,
G.DESCRIPTION PROGRAM_NAME,
[code]...
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Mar 27, 2012
Following is the query on TPC-H schema.
explain plan for select
count(*)
from
orders,
lineitem
where
o_orderkey= l_orderkey.
The trace 10053 (as shown below) for this query shows nested loop join with Lineitem as outer table and Orders as inner table. It is effectively join on composite index (pk_lineitem) of Lineitem and unique index(Pk_orderkey) of Orders table. The cost calculation formula as given in the book as "outer table cost + cardinality of outer table * inner table cost " fails here. I am not able to understand this.
BASE STATISTICAL INFORMATION
***********************
Table Stats::
Table: LINEITEM Alias: LINEITEM
#Rows: 6001215 #Blks: 109048 AvgRowLen: 124.00
Column (#1): L_ORDERKEY(NUMBER)
AvgLen: 6.00 NDV: 1500000 Nulls: 0 Density: 6.6667e-07 Min: 1 Max: 6000000
[code]....
how the cost has been calculated. This does not follow the traditional nested loop cost formula as mentioned in the book.
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Sep 30, 2010
How the length of column width effects index performance?
For example if i had IOT table emp_iot with columns:
(id number,
job varchar2(20),
time date,
plan number)
Table key consist of(id, job, time)
Column JOB has fixed list of distinct values ('ANALYST', 'NIGHT_WORKED', etc...).
What performance increase i could expect if in column "job" i would store not names but concrete numbers identifying job names.
For e.g. i would store "1" instead 'ANALYST' and "2" instead 'NIGHT_WORKED'.
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Jun 23, 2011
I'm joinging two tables event_types and tmp_acc tables.
event_types contains 2 Billion records
tmp_acc contains 20,000 records.
Resulting rows are about 300,000 records in event_types table end_t and account_obj_id0 are joined indexed
no indexs in tmp_acc.
When I run below query with nexted loop it takes 6 hrs to complete. But when I run with hash join even after 4 days it was still running. what is wrong with hash join here. Why it takes so long. I'm joining only 20000 rows. So I think there should be a way to get result rows quickly.
show parameters hash_area_size
NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
hash_area_size integer 2097152
explain plan for
select --+ parallel(e,6)
[code]....
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Oct 18, 2012
I want to know how the Oracle optimizer choose joins and apply them while executing the query. So that I will insure about optimizer join before writing any query.
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Jun 6, 2013
We have a DELETE statement when coming from application is not using index but when run from Toad or SQLplus as same user uses index. Explain plan also shows using index.I did a query on v$sql below is the output of the query( I have attached the same as a txt file). All the stats are up to date and confirmed from the developer the variable B1 is using the same datatype as column MAXMKY.
SQL_TEXTSQL_ID DISK_READSOPTIMIZER_HASH_VALUE
DELETE LOTA WHERE MAXMKY=:B1 2g2prrp3z56ah19,099,1891,846,735,884
DELETE LOTA WHERE MAXMKY=:B1 2g2prrp3z56ah0 1,846,735,884
OPTIMIZER_COST HASH_VALUEPLAN_HASH_VALUE MODULEPARSING_SCHEMA_NAME
[code].....
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Nov 6, 2010
I am working on a query for a feedback response system which is going to be targeted at the common case when the user only want the most recent 10-20 rows in the feedback table. My though is to create an index on the date column, do a sort in an inner query and rownum <= in an outer query. This works as I expect when I am only querying the main table (lookup by index with a stop key), but when I start joining the main table to attribute tables I end up with a full table scan of the main table with the stop key applied after all the joins are completed, the index is nowhere to be found.
CREATE TABLE attr1_tbl(attr1_id NUMBER NOT NULL, attr1 VARCHAR2(10) NOT NULL,
CONSTRAINT attr1_pk PRIMARY KEY (attr1_id));
CREATE TABLE attr2_tbl(attr2_id NUMBER NOT NULL, attr2 VARCHAR2(10) NOT NULL,
CONSTRAINT attr2_pk PRIMARY KEY (attr2_id));
CREATE TABLE attr3_tbl(attr3_id NUMBER NOT NULL, attr3 VARCHAR2(10) NOT NULL,
CONSTRAINT attr3_pk PRIMARY KEY (attr3_id));
[code]....
One thing I noticed was that when no data is selected from the attribute tables, even if they are joined in the query, the CBO throws them out of the plan and only accesses the main table. With the foreign keys this makes sense and really just disqualified my first thought that maybe I was missing a foreign key or not null constraint somewhere.
I also added the cardinality hint to overcome the chance that in my test case there was so little data that index access is not worth it.
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Mar 30, 2013
I am going through this scenario:
* 35 | ID TABLE ACCESS BY INDEX ROW | S_ORG_EXT | 3064K| 2472M| | 1 (0)| 00:00:01 |
| 36 | INDEX FULL SCAN | S_ORG_EXT_U1 | 14 | | | 1 (0)| 00:00:01 |
Predicate Information (identified by operation id):
---------------------------------------------------
35 - filter("T2"."ACCNT_FLG"<>'N' AND ("T2"."INT_ORG_FLG"<>'Y' OR "T2"."PRTNR_FLG"<>'N'))
This unselective index scan on step 36 of the explain is returning 14 rows but optimizer is selecting 3064 K rows from the table .
I tried creating combined index on all 3 columns mentioned in the predicates for 35th step , but that is not utilized .
how to index this whole expression ::--
(ACCNT_FLG<>'N' AND (INT_ORG_FLG<>'Y' OR PRTNR_FLG<>'N'))
Something like CREATE INDEX XYZ on table((ACCNT_FLG<>'N' AND (INT_ORG_FLG<>'Y' OR PRTNR_FLG<>'N')) compute statistics ;
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Aug 9, 2010
is there any way to reduce the index creation time.
in my case one index creation took 5 minute and there are 5 indexes , so it took 25 minutes.
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Jan 18, 2012
I have the following problem. When I used in the IN-Statement fixed values e.q. 197321,197322,197323 ..., the index i_tab2_index works fine (index range scan).
But when I used in the IN-Statement an Sub-Select, the index i_tab2_index doesn't work (fast full scan)!My scale indices and used Selects:
CREATE INDEX i_tab1_index ON tab1 ( datum, flag_inst );
CREATE INDEX i_tab2_index ON tab2 ( tab2Idx, kontro );
SELECT count(epidx) as rowAnz
FROM tab2
WHERE tab2Idx IN ( SELECT tab1IDX FROM tab1
WHERE datum BETWEEN '20120117' AND '20120117'
AND flag_inst = '1' )
AND kontro = '9876521'
[code]...
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Aug 26, 2010
get all the unused index in the system , if i put this query in batch job and execute it every night upto one months and store its data in a table and after one months i can get all the used indexes and left would be our unused indexes.
select
distinct p.object_name c1
from
dba_hist_sql_plan p,
dba_hist_sqlstat s
[Code]....
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Oct 17, 2012
I have a table whose size is 2.3 GB and there are two indexes on it. One index is based on a Date column whose size is 900 MB, and the Other index consists of 5 columns including the date column, and the size is almost 2GB. But when i query the table using the Date column, it is doing a range scan on the second index which is almost the same size as the table. why is it not using the first index? What steps should i take so that it uses the First index without passing hints.
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Jan 10, 2011
What is the difference between index rebuild and index rebuild online.
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Apr 6, 2011
mbr has 60,000 rows and member has 60,000 rows approx. two tables have indexes on ssn, and citi_no on them.
PK of mbr : mbr_id
PK of member : mbr_id
other columns are not PK, and have no index on it.
I'm wondering why the statment doesn't use index while ssn and citi_no have index.
MERGE INTO mbr t
USING (SELECT mbr_id,citi_no
FROM member) a
ON (t.ssn = a.citi_no)
WHEN MATCHED THEN
UPDATE SET t.asis_mbr_id = a.mbr_id
where t.ssn not in(select ssn from mbr group by ssn having count(*) > 1)
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Jul 22, 2010
I have to create indexes on foreign key columns ,now if composite index is already there with foreign key column then that will work or i will have to create a single column index.
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Dec 15, 2010
I am just curious to know what is clustering factor in index and How is it impartant in a sql tuning perspective ?
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Oct 3, 2011
i am trying to find the index want to rebuild or not for that i have analyzed that index after that i don't know how to calculate the ration could any one steps to do calculate the following ratio
Run the ANALYZE INDEX command on the index to validate its structure and then calculate the ratio of LF_BLK_LEN/LF_BLK_LEN+BR_BLK_LEN and if it isn?t near 1.0 (i.e. greater than 0.7 or so) then the index should be rebuilt. Or if the ratio BR_BLK_LEN/ LF_BLK_LEN+BR_BLK_LEN is nearing 0.3.
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Mar 14, 2012
For a hash join statement, is it beneficial to have the join condition objects in the index as well as the objects in the where clause?
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Aug 5, 2010
I have the following query:
Select
tag0.TAG_VALUE pid, tag1.TAG_VALUE, tag2.TAG_VALUE From TAGGER.TAGGABLE_RESOURCE r
, TAGGER.TAG tag0
, TAGGER.TAG tag1
, TAGGER.TAG tag2
where 1=1
[code]....
This runs in about 400ms. Now I replace this:
ANDtag0.TAG_TYPE in (4602, 5228)
ANDtag1.TAG_TYPE in (4612, 5225)
ANDtag2.TAG_TYPE in (4613, 5226)
with this:
ANDtag0.TAG_TYPE in (select COLUMN_VALUE from ( select * from table( TAGGER.GET_IDS_OF_SIMILAR_TAG_TYPES('Patient ID') ) x1 ))
ANDtag1.TAG_TYPE in (select COLUMN_VALUE from ( select * from table( TAGGER.GET_IDS_OF_SIMILAR_TAG_TYPES('Patients Sex') )x2 ))
ANDtag2.TAG_TYPE in (select COLUMN_VALUE from ( select * from table( TAGGER.GET_IDS_OF_SIMILAR_TAG_TYPES('Patients Birth Date') ) x3 ))
So instead of hard coding the IDs there is a function that looks them up. The function itself is reporting that it runs in 0ms. But when I run the new query:
Select
tag0.TAG_VALUE pid, tag1.TAG_VALUE, tag2.TAG_VALUE From TAGGER.TAGGABLE_RESOURCE r
, TAGGER.TAG tag0
, TAGGER.TAG tag1
, TAGGER.TAG tag2
where 1=1
[code]....
it takes around 6s to run. I have looked at the explain plans it it seems as though the function based approach is triggering a full table scan of 'TAG'.
I have tried it with query hints to use index, but it doesn't change the execution plan, or the query time.
The explain plan for the quick query is:
PLAN_TABLE_OUTPUT
---------------------------------------------------------------------------------------------------
Plan hash value: 1031492929
---------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
[code]....
And the slow one is:
PLAN_TABLE_OUTPUT
----------------------------------------------------------------------------------------------------
Plan hash value: 2741657371
----------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes |Te
----------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 20M| 1602M|
[code]....
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Dec 2, 2010
I have a table "NEWS_COMMENT" like this:
Name Type
------- --------------
ID NUMBER(8)
USERID NUMBER(8)
SORT_TEXT VARCHAR2(100)
TEXT VARCHAR2(1000)
DATE DATE
VALID VARCHAR2(1)
CODNEW NUMBER(10)
The table has a normal index for the userid column.
There is a query that looks for the differents CODNEW for a USERID but allways the CODNEW has to be greater than 2248833
select codnew from news-comment where userid=2914655 and valid='N' and codnew>2248833
I have created a new index for this kind of querys
create index coment_new_IDX on news_comment
(CASE WHEN codnew >2248833 and valid='N' THEN userid ELSE NULL END )
but oracle doesn't use it. I have used a hint to force it but doesn't run.
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Apr 7, 2011
Here, let me explain:
I have create a table with 8 million records and 2 different indexes using 2 different columns (columns name NUM1 & NUM2) on that table. First indexed column (NUM1) values have many different values (1,2,3... etc).
Second indexed column (NUM2) values have only 2 different values.
7999999 records values is same("A") and remaining one record values is different("B").
Query1:
select * from tbl where num1=val
Query2:
select * from tbl where num2='B'
I have compare explain plan both queries, but Query2 doesn't use predefined index. Why Oracle don't use my redefined index at column NUM2?
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Dec 6, 2011
I have column containing three values:-N,E,Y.I want to get results with only E and Y values.Is it it possible to create index which would not look for N values.
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