I want to use multiple partitions in from clause of SQL statement. select c1 from tab1 partition (part1,part2); However getting below error message.
ORA-00933: SQL command not properly ended00933. 00000 - "SQL command not properly ended"
*Cause:
*Action:Error at Line: 3 Column: 43 Above query is sample query.
Real query is big and hence i cant write using UNION ALL to access multiple partitions.
I need to find all the partition names below or equal given value.
select
partition_name
from
user_tab_partitions
where
table_name = 'RB' and
HIGH_VALUE <= 1234
Above Query is giving error "ORA-00997: illegal use of LONG datatype"
Any other alternative ? (I know its because of LONG Datatype of HIGH_VALUE ) ...
i have in tb1 data like and i need the latest status changed date : when date on which the status of the task changes.for the data below for taskno :
1 i need to get the o/p : 1/2/2013and for taskno :
2 I need the o/p 1/4/2013 taskno :
upd_dateold_status new_status11/1/2013openWIP11/2/2013WIPClosed11/3/2013closed closed21/1/2013openWIP21/2/2013WIPmore_info_needed21/3/2013more_info_neededWIP21/4/2013WIPclosed im writing the query as below select taskno, max(upd_date) MAX_UPD_DATE from (select taskno, upd_date, old_status, new_status, rank from (select taskno, upd_date, old_status, new_status, rank() over (partition by taskno, old_status, new_status order by upd_date asc) as rankfrom tb1)where rank = 1and old_status <> new_status)group by taskno;
IS there any more efficient way to write this query as the clause "old_status <> new_status" is taking a toll on the performance
I am using the below code to update specific sub-partition data using oracle merge statements.
I am getting the sub-partition name and passing this as a string to the sub-partition clause.
The Merge statement is failing stating that the specified sub-partition does not exist. But the sub-partition do exists for the table.
We are using Oracle 11gr2 database.
Below is the code which I am using to populate the data.
declare
ln_min_batchkey PLS_INTEGER;
ln_max_batchkey PLS_INTEGER;
lv_partition_name VARCHAR2 (32767);
lv_subpartition_name VARCHAR2 (32767);
begin
[code]....
I have a table with around 80 columns. All i need is to select first 40 columns.
Is there any way to select first 40 columns without giving all the 40 Column Names in select clause.
select * from nrc_trans_descr where type_id_nrc=60013 -- it has 18 columns and i have hard coded 60013 for simplification here.60013 is derived from 3 other table Output is ( it can have many rows too.typically for each type_id_nrc there is one row ).
TYPE_ID_NRC TRIGGER_STATUS INSTALLMENT_TYPE_ID_NRC
---------------------------------------------------------------------
60013 0 61013
i have to pass TYPE_ID_NRC and INSTALLMENT_TYPE_ID_NRC to restriction_id column in a different table. currently i am doing like this
select * FROM DISCOUNT_RESTRICTIONS WHERE discount_id in (12085,12086)
and (restricted_id in ( select type_id_nrc from nrc_trans_descr where type_id_nrc=60013)
or restricted_id in ( select installment_type_id_nrc from nrc_trans_descr where type_id_nrc=60013));
am using ORACLE 10GR2(solution for 11gr2 is welcome too)
I need to build a SQL statement dynamically such that the WHERE clause looks/works as follows: WHERE x LIKE '%1%' OR x LIKE '%2%' OR x LIKE '%3%' .
View 2 Replies View RelatedI have a view that contain multiple tables with ( UNION all ) clause , is there any way that if i query from this view I can explicitly specify the table that i need the data from ?
Let say i have view that contain salaries of 2011
Create view sals_2011 as select * from sals_jan2011 union all sals_feb2011 ..... union all select * from sals_dec2011.
if i issued select * from sals_2011 where emp_id >500 and date < 01-feb-2011 the explain plan show me that full tables and indexes are in processing, while i know that i need only to scan sal_jan2011, and of course it is taking much longer time than selecting from the original table only.
I am using oracle RAC 11g R2
I have a function that returns the total sum of an account. From reports I call the function passing the account code. The function sums the values for that specific account code and returns the value. In my function I have the following code :
where account_code = P_CODE.
Eg. The value of :P_CODE is 'CS'.
I now want to pass multiple account codes ('CS','TV',LJ') to the function. How do I change the IN clause in the function to accommodate multiple values.
I have tried using the instr function, but it does not work. eg. AND instr(o.ACCOUNT_CODES,','||P_CODE||',') > 0
Can i partition by list on multiple columns? i am trying the following code, and it is returning an error. Is there a way round this?
CREATE TABLE
(...)
PARTITION BY LIST (col1)
SUBPARTITION BY LIST (col2)
SUBPARTITION TEMPLATE (
SUBPARTITION DETAIL VALUES ('DETAIL')
SUBPARTITION ROLLUP VALUES ('ROLLUP'))
(
PARTITION RT VALUES('RT')
)
I have Leave Balances In such Format
EMP_COD CategoryJON_DTE LEV_BAL
3900000385101/02/200760
3900002678107/01/200840
Now I want to Separate it into Three and Two Partitions Year Wise.
Like this
3900000385101/02/200720 2012
3900000385101/02/200720 2011
3900000385101/02/200720 2010
3900002678107/01/200820 2012
3900002678107/01/200820 2011
I have a scenario where the requirement is to create a "SEQ NO". Based on the 'Tasks' & it's creation date. Where there are multiple 'tasks' for a single SR.
The following example will make it clear
SR TASK Created on SEQ NO
11009 2345 14/10/1988 12:15:17 1
11009 2346 14/10/1988 12:15:57 2
11234 - - -
If there is a SR which has no task then the SEQ NO should be 0. And the seq no should be in the order of the created on field & if 2 tasks are created at the same time i.e suppose 2345 & 2346 have the same time stamp then the SEQ no should be 1,2 respectively n not both as 1.
I am trying to use model clause to get comma separate single row for multiple rows. My scenario is like this:
SQL> desc test1
Name Null? Type
----------------------------------------------------- -------- ------------------------------------
ID NUMBER
VALUE CHAR(6)
SQL> select * from test1 order by id;
ID VALUE
---------- ------
1 Value1
2 Value2
3 Value3
4 Value4
5 Value4
6
7 value5
8
The query that I have is:
SQL> with t as
2 ( select distinct substr(value,2) value
3 from test1
4 model
5 ignore nav
6 dimension by (id)
7 measures (cast(value as varchar2(100)) value)
8 rules
9 ( value[any] order by id = value[cv()-1] || ',' || value[cv()]
10 )
11 )
12 select max(value) oneline
13 from t;
ONELINE
---------------------------------------------------------------------------------------------------
Value1,Value2,Value3,Value4,Value4,,value5,
what I want is : null value should not come and duplicate value should not come (Value4 in output above)
I have 20 tables. In all 20 tables, some of column names are same and some are different. I need to find all column names in all 20 tables that have same names.
create table t1 (
col1 varchar2(10),
col2 varchar2(10));
create table t2 (
col1 varchar2(10),
col3 varchar2(10));
create table t3 (
col1 varchar2(10));
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedI Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies View RelatedI have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies View RelatedI have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View Relatedcan we use something like this
"select ... order by emp from emp"
what is to be done? so that this qurey runs. no co-related subquery to be used.
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
View 8 Replies View RelatedI am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020