SQL & PL/SQL :: Salary Hike Using Cursor

Sep 22, 2011

A.Create object to get the salary hike of an employee on the basis of completion of years in an organization.

Conditions:-
Create two tables with name as "Employee_yourname" and "Employee_Hike_Yourname".
"Employee_yourname" can have columns like EMPID, NAME, SALARY, DATE_OF_JOIN.
"Employee_Hike_Yourname" will have 3 more columns for new salary, Current salary and completed period in organization.
Consider the employees who have completed minimum one year in organization.
Salary hike for employee with tenure >= 1yr and < 2yrs should be 10% of current salary.
If tenure is greater than or equal to two years and less than 3 years then salary hike should be 20% of current salary.
For employees having tenure more than 3 years hike should be 30% % of current salary

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PL/SQL :: Finding ID Max (salary)

Oct 31, 2012

Select * from one:

ID SALARY
----------------------
10 1000
20 2000
30 3200

Select * from two:

ID SALARY
----------------------
10     1000
20     2000
40     4000
10     3000
20     4000
30     3000

When i try to find ID,MAX(SALARY) from these two tables, i am getting this output:

Select id,max(salary)
from
(select * from one
union
select * from two)
group by id
order by max(salary) desc;

OUTPUT:

ID MAX(SALARY)
--------------------------------------
20     4000
40     4000
30     3200
10     3000

I want OUTPUT to be like this:

ID MAX(SALARY)
--------------------------------------
20     4000
40     4000

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Jul 18, 2011

How does the following underlined query works to find the nth highest salary

SELECT DISTINCT(A.SALARY) FROM EMPLOYEE A
WHERE &SALARY = (SELECT COUNT(DISTINCT(B.SALARY)) FROM EMPLOYEE B
WHERE A.SALARY<=B.SALARY);

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SQL & PL/SQL :: Display The Maximum Sum Of Salary?

Aug 14, 2010

I want to display the maximum sum of salary among sum of salary of each department.

deptno sal
10 1000
10 500
10 100
20 2000
20 200
30 500
30 1500
30 2000
30 200

Sum of salary for each department.
10 1600
20 2200
30 4200

The output should be
30 4200

Because this the highest sum of salary compare to sum of salary of reaming departments.

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Jun 30, 2010

how to find the nth highest salary

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Apr 29, 2011

i was given a task to find the second highest employee sal from emp table.

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May 8, 2010

I created a PROCEDURE in that i am calling function which calculate sum of salary...I just want Output in format for that which function i need to use...?

Actual Output:::

DEPt_Name SALARY
ACCOUNTING 8750
RESEARCH 10875
SALES 11600

I want Output in well alignment column...i WANT Output IN column format but my output in not geting in that format...Is there any function to align output...I want Output in well alignment column

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Jun 16, 2012

I have a created data block using employees table so am trying to validate item salary using max_salary and min_salary from table jobs how to do this kind of validation.

[How can i validate input number into a Field of type char in oracle form?]

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Dec 16, 2011

I have to write function that receives department name and an aggregation operation (average, maximum, minimum) and apply the operation on the salary of employees working on the given department and return the result.

here is my select statement:

select distinct d.deptno, d.deptname, max(e.salary)
from employee e join department d
on e.deptno=d.deptno
where d.deptname=upper('finance')
group by d.deptno, d.deptname;
[code]...

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Nov 7, 2012

in this query, i am stuck in this little query but cant get answer lets suppose

select * from emp;

EMPNO ENAME JOB SAL
---------------------- ---------- --------- ----------------------
7788 SCOTT ANALYST 3000
7902 FORD ANALYST 3000
7876 ADAMS CLERK 1100
7934 MILLER CLERK 1300
7900 JAMES CLERK 950

[Code]....

now if i want to see min salary takers group by job then i use

select x.job, min(x.sal), count(*) from emp x group by x.job;

JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 5
CLERK 950 3
PRESIDENT 5000 1
MANAGER 2450 5
Developer 2975 1
ANALYST 3000 2

The above result give me minimum salary but total number of JOB holders, You can see only one SALEMAN getting 1000 but count show total number of SALESMAN. Similarly 3 MANAGERS are getting minimum and same salary but count show total number of MANAGERS.

My question is how can i get number of person on min salary?

Possibly my data should be like as this

JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 1
CLERK 950 1
PRESIDENT 5000 1
MANAGER 2450 3
Developer 2975 1
ANALYST 3000 2

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Jun 18, 2012

I wanted to know the latest salary(last 2 updated records ) getting by emp- id 252 based on below mentioned information

source desti sal emp id MGR
1-Jan 1-Feb 1000 252 venkat
2-Jan 2-Feb 4000 252 venkat
2-Feb 2-Feb 5000 252 venkat

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Jul 12, 2012

i have table structure (emp_no, emp_sal,emp_startwork)

i want query to show the monthly salary such as jan month salary Feb month salary

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Dec 21, 2010

write a query to see how many(no) employees getting salary 3000 & what are their names respectively.

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Aug 21, 2010

I need to obtain the top 2 departments in terms of total salary.

I have the following tables (Dno corresponds to DeptNo). I've found tutorials for obtaining the salaries of the top three employees, and summing the salaries for each dept. is easy, but I can't seem to combine the two.

DNo Fname Salary
2 Tom 10000
3 Mike 20000
2 Harry 30000

DeptNo DeptName
1 Administration
2 Special
3 Finance

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Nov 26, 2010

To find all the employees whose salaries greater than avg(salary) of the department.

Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote

Its not diplaying all departments

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Feb 16, 2013

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Aug 30, 2013

How do i check in Table B whether it is converted correctly into words taking input or reference from table A

Consider below example:-

Table A Table B
$125 Dollar One Hundred twenty Five only
$45,542 Dollar Forty Five Thousand Five Forty Two Only
$145.56 Dollar One Forty Five and fifty six cents Only
$145,253
$35,256.65
$560,250.67

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Sep 7, 2007

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Here is the code for a simple program which reproduces the problem:

Each cursor is opened in a PL/SQL package:

CREATE OR REPLACE PACKAGE emp_demo_pkg AS
TYPE emp_cur_type IS REF CURSOR;
PROCEDURE open_cur(curs IN OUT emp_cur_type, dept_num IN NUMBER);
END emp_demo_pkg;

[Code]....

While testing the initialization parameter open_cursors is set to 50.

It's my understanding that Oracle doesn't close the cursors until it needs the space for another cursor, which in my test case seems to happen when I enter a value of 50 or bigger for "number of loops". To see how oracle is reusing the cursors, while the test program is running I run SQL*Plus and query v$sesstat for the session that's running the test with the following sentence:

select name, value
from v$sesstat s, v$statname n
where s.statistic# = n.statistic#
and sid = 7
and name like '%cursor%';

Even before I enter a value for number of loops I can see that the session opened 4 cursors and closed 2 of them:

NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 4
opened cursors current 2

Entering a value of 5 for number of loops yields

NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 11 <----- 7+
opened cursors current 8 <----- 6+

With a value of 30

NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 36 <----- 25+ (apparently, Oracle reused at least 5 cursors)
opened cursors current 33 <----- 25+

With a value of 47

NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 53 <----- 17+
opened cursors current 50 <----- 17+

Now I reached the upper limit set by the initialization parameter open_cursors.

Entering a value of 48, I get the ORA-1000 error.

ORA-01000: maximum open cursors exceeded
ORA-06512: at "SCOTT.EMP_DEMO

Since I open and close the cursor in the same loop iteration, I expect to find in every iterarion 1 explicit cursor and a number of implicit cursors (the PL/SQL call along with the so-called recursive cursors), but I don't expect the sum of all of them to be greater than 50. If my understanding is correct Oracle should be reusing the 50 cursors previously marked as "closeable", not raising the ORA-1000 error.

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Feb 25, 2011

Is it possible to:

-define a cursor with bind variables
-get a cursor record from these cursor
-and pass the bind variable in the OPEN clause

Did'nt succeed as shown in the example.

SET SERVEROUTPUT ON SIZE 900000;
DECLARE
--works fine
CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<3;
--doesn't work
--CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<:1;
crec c1%rowtype;
BEGIN
--works fine
OPEN c1;
--isn't possible ?
--OPEN c1 USING 3;

[Code]....

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Sep 11, 2011

just looking around to use the new feature available in oracle 11g to convert the dbms_sql numeric cursor to reference cursor, how to do it?

parse and execute the sql string first with dbms_sql and then convert it to ref cursor?

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Nov 23, 2011

I want to return ref cursor based on explicit cursors

create table jumbo(id number, name varchar2(20));
insert into jumbo values(1,'jumbo');
create table mumbo(id number, name varchar2(20));
insert into mumbo values(1,'mumbo');
commit;

[Code].....

The above procedure has compilation errors when I am trying to open ref cursor

LINE/COL ERROR
-------- --------------------------------------------------------
20/24 PL/SQL: SQL Statement ignored
20/38 PL/SQL: ORA-00942: table or view does not exist
32/24 PL/SQL: SQL Statement ignored
32/38 PL/SQL: ORA-00942: table or view does not exist
SQL>

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Aug 7, 2013

Can i user exist when cursor will using For Cursor .

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Aug 11, 2013

/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
CREATE PROCEDURE p_get_name (
p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......

Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.

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Feb 9, 2012

based on the following information

grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999

for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:

-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS

vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);

BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
ELSEIF vSAL<= 1201 THEN
[code]....

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Aug 31, 2012

i have a program like this

DECLARE
V_VARIABLE1 VARCHAR2(10);

CURSOR_ABC IS select...............;
BEGIN
OPEN CURSOR_ABC;
LOOP
FETCH CURSOR_ABC INTO V_VARIABLE1;
EXIT WHEN CURSOR_ABC%NOTFOUND;

WHAT IF I WANT TO INSERT ANOTHER SAME KINDA CURSOR LOOP HERE LIKE*

CURSOR_XYZ IS select...............;
BEGIN
OPEN CURSOR_XYZ;
LOOP
FETCH CURSOR_XYZ INTO V_VARIABLE2;
EXIT WHEN CURSOR_XYZ%NOTFOUND;
END LOOP;
CLOSE CURSOR_XYZ;
END LOOP;
CLOSE CURSOR_ABC;

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Oct 14, 2010

We receive hand punches (clock data) every day. Normally a person badges in(hand punch) which creates a row in the clock_tran_processed table. The information from that hand punch is the employee id (emp_id) the date hand punch occurred and a work_summary id (wrks_id). At the end of the day, the employee badges out (hand punch out) and another entry in the clock_tran_processed table is created. The new row will have the emp_id (employee name), date the hand punch occurred and the same work summary id from the morning.

Normally hand punches should occur in pairs. One in, one out... or one in, out for lunch, in for lunch, out for day. I am seeing intervals of three and five. Meaning the employee clocked in twice and out once, or in once and out twice. This shouldn't happen.

I am writing a report that will show number of clocks per for all employees that have three(3) or five(5) clock entries.I wrote a ref cursor that gives all the employees that have a count of 3 or 5 and the employee id (emp_id). I need to pass that employee id to another query that will then get me the dates of the clocks.Here is the ref cursor thus far (I am printing those with a count of 3 and 5).

CODEDECLARE

TYPE ClockTran_Refcur IS REF CURSOR;
ClockTran_cur ClockTran_Refcur;
NumClock_num number :=0;
NumClock_name clock_tran_processed.emp_id%TYPE;
[code]...

How do I pass that variable to the get the clktranpro_time's? I am using "Easy Oracle PL/SQL Programming" but I am not seeing this type of example(pgs 140-148).

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DB Version : 11.1.0.7 OS: AIX

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cursor: pin S wait on X

i am unable to kill these sessions how could i get rid of these sessions

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Apr 10, 2013

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CURSOR c_arch_trk (p_run_date DATE,
p_nbr_days_arch1 NUMBER,
p_nbr_days_arch2 NUMBER )
IS
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