SQL & PL/SQL :: Display The Maximum Sum Of Salary?

Aug 14, 2010

I want to display the maximum sum of salary among sum of salary of each department.

deptno sal
10 1000
10 500
10 100
20 2000
20 200
30 500
30 1500
30 2000
30 200

Sum of salary for each department.
10 1600
20 2200
30 4200

The output should be
30 4200

Because this the highest sum of salary compare to sum of salary of reaming departments.

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SQL & PL/SQL :: Function To View Maximum Salary

Dec 16, 2011

I have to write function that receives department name and an aggregation operation (average, maximum, minimum) and apply the operation on the salary of employees working on the given department and return the result.

here is my select statement:

select distinct d.deptno, d.deptname, max(e.salary)
from employee e join department d
on e.deptno=d.deptno
where d.deptname=upper('finance')
group by d.deptno, d.deptname;
[code]...

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Semantic Technologies :: Maximum Node ID Larger Than Java Maximum Integer Value

Mar 7, 2013

I'm currently doing migration from Oracle 10gR2 RDF to Oracle 11gR2 Semantic Technology.I followed the steps on the documentation and successfully created the network using the following:

-----
EXECUTE SEM_APIS.CREATE_SEM_NETWORK('rdf_tblspace');
CREATE TABLE rdf_network_trace (id NUMBER, triple SDO_RDF_TRIPLE_S);
--Created SEQUENCE andTRIGGER FOR rdf_network_trace id
[code]....

when I looked at my Node Ids, they were like +635762253807433724+, +6118969225776891730+. The problem is, I am not the one who is assigning Node Ids, They were automatically generated when inserting TRIPLE data to the rdf table.

Did I miss something when I created my network?

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PL/SQL :: Finding ID Max (salary)

Oct 31, 2012

Select * from one:

ID SALARY
----------------------
10 1000
20 2000
30 3200

Select * from two:

ID SALARY
----------------------
10     1000
20     2000
40     4000
10     3000
20     4000
30     3000

When i try to find ID,MAX(SALARY) from these two tables, i am getting this output:

Select id,max(salary)
from
(select * from one
union
select * from two)
group by id
order by max(salary) desc;

OUTPUT:

ID MAX(SALARY)
--------------------------------------
20     4000
40     4000
30     3200
10     3000

I want OUTPUT to be like this:

ID MAX(SALARY)
--------------------------------------
20     4000
40     4000

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Find Nth Highest Salary?

Jul 18, 2011

How does the following underlined query works to find the nth highest salary

SELECT DISTINCT(A.SALARY) FROM EMPLOYEE A
WHERE &SALARY = (SELECT COUNT(DISTINCT(B.SALARY)) FROM EMPLOYEE B
WHERE A.SALARY<=B.SALARY);

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SQL & PL/SQL :: Salary Hike Using Cursor

Sep 22, 2011

A.Create object to get the salary hike of an employee on the basis of completion of years in an organization.

Conditions:-
Create two tables with name as "Employee_yourname" and "Employee_Hike_Yourname".
"Employee_yourname" can have columns like EMPID, NAME, SALARY, DATE_OF_JOIN.
"Employee_Hike_Yourname" will have 3 more columns for new salary, Current salary and completed period in organization.
Consider the employees who have completed minimum one year in organization.
Salary hike for employee with tenure >= 1yr and < 2yrs should be 10% of current salary.
If tenure is greater than or equal to two years and less than 3 years then salary hike should be 20% of current salary.
For employees having tenure more than 3 years hike should be 30% % of current salary

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Jun 30, 2010

how to find the nth highest salary

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Apr 29, 2011

i was given a task to find the second highest employee sal from emp table.

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SQL & PL/SQL :: Calling Function Which Calculate Sum Of Salary

May 8, 2010

I created a PROCEDURE in that i am calling function which calculate sum of salary...I just want Output in format for that which function i need to use...?

Actual Output:::

DEPt_Name SALARY
ACCOUNTING 8750
RESEARCH 10875
SALES 11600

I want Output in well alignment column...i WANT Output IN column format but my output in not geting in that format...Is there any function to align output...I want Output in well alignment column

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Jun 16, 2012

I have a created data block using employees table so am trying to validate item salary using max_salary and min_salary from table jobs how to do this kind of validation.

[How can i validate input number into a Field of type char in oracle form?]

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Nov 7, 2012

in this query, i am stuck in this little query but cant get answer lets suppose

select * from emp;

EMPNO ENAME JOB SAL
---------------------- ---------- --------- ----------------------
7788 SCOTT ANALYST 3000
7902 FORD ANALYST 3000
7876 ADAMS CLERK 1100
7934 MILLER CLERK 1300
7900 JAMES CLERK 950

[Code]....

now if i want to see min salary takers group by job then i use

select x.job, min(x.sal), count(*) from emp x group by x.job;

JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 5
CLERK 950 3
PRESIDENT 5000 1
MANAGER 2450 5
Developer 2975 1
ANALYST 3000 2

The above result give me minimum salary but total number of JOB holders, You can see only one SALEMAN getting 1000 but count show total number of SALESMAN. Similarly 3 MANAGERS are getting minimum and same salary but count show total number of MANAGERS.

My question is how can i get number of person on min salary?

Possibly my data should be like as this

JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 1
CLERK 950 1
PRESIDENT 5000 1
MANAGER 2450 3
Developer 2975 1
ANALYST 3000 2

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Jun 18, 2012

I wanted to know the latest salary(last 2 updated records ) getting by emp- id 252 based on below mentioned information

source desti sal emp id MGR
1-Jan 1-Feb 1000 252 venkat
2-Jan 2-Feb 4000 252 venkat
2-Feb 2-Feb 5000 252 venkat

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Aug 21, 2010

I need to obtain the top 2 departments in terms of total salary.

I have the following tables (Dno corresponds to DeptNo). I've found tutorials for obtaining the salaries of the top three employees, and summing the salaries for each dept. is easy, but I can't seem to combine the two.

DNo Fname Salary
2 Tom 10000
3 Mike 20000
2 Harry 30000

DeptNo DeptName
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2 Special
3 Finance

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Nov 26, 2010

To find all the employees whose salaries greater than avg(salary) of the department.

Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote

Its not diplaying all departments

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Aug 30, 2013

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Consider below example:-

Table A Table B
$125 Dollar One Hundred twenty Five only
$45,542 Dollar Forty Five Thousand Five Forty Two Only
$145.56 Dollar One Forty Five and fifty six cents Only
$145,253
$35,256.65
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/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
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p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......

Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.

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SQL & PL/SQL :: Employee Table To Assign Grade For Each Employee Based On His Salary

Feb 9, 2012

based on the following information

grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999

for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:

-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS

vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);

BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
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[code]....

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values : 2 , 4, 5, 1

the output should be field_3 =5

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Aug 10, 2012

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structure_code Attribute_code percentage

160025 2531 30
160025 2536 20
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I could multiply max_size by extent_size and it would give me the max size of temp ever used

SQL> select segment_file, extent_size, max_size from v$sort_segment;

SEGMENT_FILE EXTENT_SIZE MAX_SIZE

0 128 23625
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Oct 25, 2010

Test data for the problem is as follows.

SQL> select * from v$version;

BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for 64-bit Windows: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production

SQL> with t
2 as
3 (
4 select 1 id, 12 compid, 1 rel_type, null enddt from dual union all
5 select 1, 13, 1, to_date('31.12.1993','dd.mm.yyyy') from dual union all
6 select 1, 14, 1, to_date('12.06.1996','dd.mm.yyyy') from dual union all
7 select 1, 15, 1, to_date('23.04.2003','dd.mm.yyyy') from dual union all
[code].......

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Datatype for the tables are :

Id : Number
compid : Number
Rel_Type : Number
enddt : Date

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