PL/SQL :: Finding ID Max (salary)
Oct 31, 2012
Select * from one:
ID SALARY
----------------------
10 1000
20 2000
30 3200
Select * from two:
ID SALARY
----------------------
10 1000
20 2000
40 4000
10 3000
20 4000
30 3000
When i try to find ID,MAX(SALARY) from these two tables, i am getting this output:
Select id,max(salary)
from
(select * from one
union
select * from two)
group by id
order by max(salary) desc;
OUTPUT:
ID MAX(SALARY)
--------------------------------------
20 4000
40 4000
30 3200
10 3000
I want OUTPUT to be like this:
ID MAX(SALARY)
--------------------------------------
20 4000
40 4000
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Jul 18, 2011
How does the following underlined query works to find the nth highest salary
SELECT DISTINCT(A.SALARY) FROM EMPLOYEE A
WHERE &SALARY = (SELECT COUNT(DISTINCT(B.SALARY)) FROM EMPLOYEE B
WHERE A.SALARY<=B.SALARY);
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Sep 22, 2011
A.Create object to get the salary hike of an employee on the basis of completion of years in an organization.
Conditions:-
Create two tables with name as "Employee_yourname" and "Employee_Hike_Yourname".
"Employee_yourname" can have columns like EMPID, NAME, SALARY, DATE_OF_JOIN.
"Employee_Hike_Yourname" will have 3 more columns for new salary, Current salary and completed period in organization.
Consider the employees who have completed minimum one year in organization.
Salary hike for employee with tenure >= 1yr and < 2yrs should be 10% of current salary.
If tenure is greater than or equal to two years and less than 3 years then salary hike should be 20% of current salary.
For employees having tenure more than 3 years hike should be 30% % of current salary
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Aug 14, 2010
I want to display the maximum sum of salary among sum of salary of each department.
deptno sal
10 1000
10 500
10 100
20 2000
20 200
30 500
30 1500
30 2000
30 200
Sum of salary for each department.
10 1600
20 2200
30 4200
The output should be
30 4200
Because this the highest sum of salary compare to sum of salary of reaming departments.
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Jun 30, 2010
how to find the nth highest salary
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Apr 29, 2011
i was given a task to find the second highest employee sal from emp table.
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May 8, 2010
I created a PROCEDURE in that i am calling function which calculate sum of salary...I just want Output in format for that which function i need to use...?
Actual Output:::
DEPt_Name SALARY
ACCOUNTING 8750
RESEARCH 10875
SALES 11600
I want Output in well alignment column...i WANT Output IN column format but my output in not geting in that format...Is there any function to align output...I want Output in well alignment column
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Jun 16, 2012
I have a created data block using employees table so am trying to validate item salary using max_salary and min_salary from table jobs how to do this kind of validation.
[How can i validate input number into a Field of type char in oracle form?]
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Dec 16, 2011
I have to write function that receives department name and an aggregation operation (average, maximum, minimum) and apply the operation on the salary of employees working on the given department and return the result.
here is my select statement:
select distinct d.deptno, d.deptname, max(e.salary)
from employee e join department d
on e.deptno=d.deptno
where d.deptname=upper('finance')
group by d.deptno, d.deptname;
[code]...
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Nov 7, 2012
in this query, i am stuck in this little query but cant get answer lets suppose
select * from emp;
EMPNO ENAME JOB SAL
---------------------- ---------- --------- ----------------------
7788 SCOTT ANALYST 3000
7902 FORD ANALYST 3000
7876 ADAMS CLERK 1100
7934 MILLER CLERK 1300
7900 JAMES CLERK 950
[Code]....
now if i want to see min salary takers group by job then i use
select x.job, min(x.sal), count(*) from emp x group by x.job;
JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 5
CLERK 950 3
PRESIDENT 5000 1
MANAGER 2450 5
Developer 2975 1
ANALYST 3000 2
The above result give me minimum salary but total number of JOB holders, You can see only one SALEMAN getting 1000 but count show total number of SALESMAN. Similarly 3 MANAGERS are getting minimum and same salary but count show total number of MANAGERS.
My question is how can i get number of person on min salary?
Possibly my data should be like as this
JOB MIN(X.SAL) COUNT(*)
--------- ---------------------- ----------------------
CLERK1 800 1
SALESMAN 1000 1
CLERK 950 1
PRESIDENT 5000 1
MANAGER 2450 3
Developer 2975 1
ANALYST 3000 2
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Jun 18, 2012
I wanted to know the latest salary(last 2 updated records ) getting by emp- id 252 based on below mentioned information
source desti sal emp id MGR
1-Jan 1-Feb 1000 252 venkat
2-Jan 2-Feb 4000 252 venkat
2-Feb 2-Feb 5000 252 venkat
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Jul 12, 2012
i have table structure (emp_no, emp_sal,emp_startwork)
i want query to show the monthly salary such as jan month salary Feb month salary
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Dec 21, 2010
write a query to see how many(no) employees getting salary 3000 & what are their names respectively.
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Aug 21, 2010
I need to obtain the top 2 departments in terms of total salary.
I have the following tables (Dno corresponds to DeptNo). I've found tutorials for obtaining the salaries of the top three employees, and summing the salaries for each dept. is easy, but I can't seem to combine the two.
DNo Fname Salary
2 Tom 10000
3 Mike 20000
2 Harry 30000
DeptNo DeptName
1 Administration
2 Special
3 Finance
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Nov 26, 2010
To find all the employees whose salaries greater than avg(salary) of the department.
Quote
select empname,salary,deptid from salaries t1 where
salary > (select avg(salary) from salaries t2 where t1.deptid = t2.deptid);
Unquote
Its not diplaying all departments
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Feb 16, 2013
i have employee table i want to update salary with all employee 5 percent
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Aug 30, 2013
How do i check in Table B whether it is converted correctly into words taking input or reference from table A
Consider below example:-
Table A Table B
$125 Dollar One Hundred twenty Five only
$45,542 Dollar Forty Five Thousand Five Forty Two Only
$145.56 Dollar One Forty Five and fifty six cents Only
$145,253
$35,256.65
$560,250.67
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Aug 11, 2013
/* Formatted on 2013/08/11 18:46 (Formatter Plus v4.8.8) */
CREATE PROCEDURE p_get_name (
p_empno IN OUT NUMBER,
p_name OUT VARCHAR2,
p_err OUT NUMBER
[code].......
Note:- I want to print ename and salary of emp using empno as a input but i dont want to declare extra variable for salary , i want to print salary using empno but when i execute this procedure. It gives value of empno in salary. Don't Know Why , how can i print salary of emp using empno as input without declaring extra variable for salary.
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Feb 9, 2012
based on the following information
grade lowsal highsal
------ ----- ------
1 700 1200
2 1201 1400
3 1401 2000
4 2001 3000
5 3001 9999
for the employee table to assign grade for each employee based on his salary the following plsql procedure is giving error:
-----------------------------------------------------------
CREATE OR REPLACE PROCEDURE GRADE(EID IN NUMBER,BONUS OUT NUMBER) IS
vGRADE NUMBER(8,2);
vSAL NUMBER(8,2);
BEGIN
vGRADE=1
SELECT SAL INTO vSAL FROM EMP WHERE EMPNO=EMPID;
IF vSAL<= 700 THEN
vGRADE:=1;
ELSEIF vSAL<= 1201 THEN
[code]....
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Jun 19, 2013
I have the following query where i need to find the max value[code] with t as
( select 'L1' R_nm ,'Data' R_Data , 'Obj' R_Obj , 'Wd' r_prec , '2' val
from dual union all select 'L1' , 'Data', 'Obj' , 'No', '4'
from dualunion all select 'L2' , 'Data', 'Obj' , 'No', '4' from dual )
select t.*, max(val) over(partition by r_nm,r_data,r_obj) rk from t[/code]
My expected output should be
[code]
r_nm r_data r_obj r_prec val rkL1 Data Obj Wd 2 1L1 Data Obj No 4 2L2 Data Obj Yes 1 1
[/code]
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Dec 4, 2011
I'm not really sure why oracle is not finding my Foreing Key, I'm creating an easy set of table for a company and I'm declaring all Primary keys and foreing keys as necessary and this is my
CREATE TABLE Items
(ItemID NUMBER(5) NOT NULL,
Description VARCHAR2(30),
ListPrice NUMBER(9,2) NOT NULL,
QtyOnHand Number(5),
ReorderPoint NUMBER(3),
ReorderQty NUMBER(3),
OnBackOrder Number(3),
CONSTRAINT ItemsPK
[Code] ............
There's three sets of inserts the first two successfully inserts the data NO problem but when i try to insert the data on SupplierItems comes as:
ERROR at line 1:
ORA-02291: integrity constraint (jcarter.SUPPLIERITEMSFK2) violated - parent key not found
I looked on the forum and it appears this happens when someone is doing a Insert ALL but this is not my case..
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Jun 23, 2008
What i have is table with:
mission_id, mission_type_id, security_level and code_name.
What i have to do is get the 10 most recent missions and change their security level to the highest one in their mission_type_id but ONLY if code_name length is >7
So far I have this, the problem is that the oracle moans about the order and wants me to close the bracket before the order
sql
UPDATE missions m
SET m.security_level = (
SELECT max(m2.security_level)
FROM missions m2
WHERE m2.mission_type_id = m.mission_type_id
AND length(m2.code_name) > 7
)
WHERE m.mission_ID IN (
Select m3.mission_id
From missions m3
ORDER BY m3.mission_id desc)
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Dec 23, 2011
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Oct 4, 2007
Whats the command to show the name of the primary key in a table using oracle sql plus?
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Nov 3, 2008
I have read and used the AWR script (mentioned in the page Finding unused index for finding unused customised (Z) indexes in our SAP system using oracle 10.2.0.2 as the SAP database.
But this returns no rows. Is there any precondition? I want to know how much / many times the indexes are used...We are smelling that lot of unused index are there in the database.
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May 30, 2011
How to find the list of tables which has permission select only and tables which has both read and write access permission for a particular user.
I'm using ORACLE database.
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Nov 22, 2011
finding the difference between IN and EXIST.
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Feb 7, 2012
I want to track the session id that has been initiated by a particular job (I have job ids with me). Which dictionary views I can get this result.
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Nov 1, 2011
@test.sql
accept 1 num prompt 'enter begin value '
accept 2 num prompt 'enter end value '
Need to display all values between the above given inputs.
No tables involved.
Need SQL level solution in version 8i.
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May 20, 2010
i have table with name, count, flag with dublicate records
example
with swayam name , counts are 3, 4
with ramana name, counts are 5,5
with reddy name, counts are 1,2,3
i want to update the flag
if count are same then update one of record (flag='A') and other should be flag='R'
if count are different then update the max count (flag='A') and other should be reject remaing (flag='R'). use below quires
CREATE TABLE TEST_DUB ( NAME VARCHAR2(99), V_COUNT NUMBER, FLAG VARCHAR2(1));
Insert into TEST_DUB (NAME, V_COUNT)
Values
('SWAYAM', 3);
Insert into TEST_DUB
(NAME, V_COUNT)
Values
[Code]....
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