Finding 10 Most Recent Missions
Jun 23, 2008
What i have is table with:
mission_id, mission_type_id, security_level and code_name.
What i have to do is get the 10 most recent missions and change their security level to the highest one in their mission_type_id but ONLY if code_name length is >7
So far I have this, the problem is that the oracle moans about the order and wants me to close the bracket before the order
sql
UPDATE missions m
SET m.security_level = (
SELECT max(m2.security_level)
FROM missions m2
WHERE m2.mission_type_id = m.mission_type_id
AND length(m2.code_name) > 7
)
WHERE m.mission_ID IN (
Select m3.mission_id
From missions m3
ORDER BY m3.mission_id desc)
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Jan 22, 2009
i have to display the 10 most costly missions. but if the 11th record has the same cost then it needs to display 11 records instead of 10. how can i do this?
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Jan 22, 2009
My solution to the following question update 10 rows. It should update only 6 records. Create a copy of the missions table called AM_X_442_2. For missions on this table that meet the following criteria:
1. within the 10 most recent missions
2. length of the first word of the mission code_name exceeds 7 characters
Change the security level to the highest security level found in missions of the same type.
UPDATE
AM_X_442_2 am
SET
am.SECURITY_LEVEL =
(
SELECT
MAX(amx.SECURITY_LEVEL)
FROM
AM_X_442_2 am
INNER JOIN
AM_X_442_2 amx
[code]....
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Jan 25, 2009
I am trying to update the security_level of a mission to the highest security level of missions of the same type.
Attributes of the missions table:
mission_id, code_name, mission_type_id, mission_date, security_level
The following is an intermediate output.
MISSION_ID MISSION_TYPE_ID SECURITY_LEVEL
318 3 6
329 3 2
286 5 6
521 5 3
281 6 4
396 7 3
331 8 4
14 9 4
230 9 0
486 10 2
The maximum output for each mission_type_id
MAX_LEVEL TYPE
6 3
6 5
4 6
3 7
4 8
4 9
2 10
According to this 3 records (329,521 and 230) should update.
But my code returns an error.
ERROR at line 4:
cannot update (......"SECURITY_LEVEL") to NULL
this is my code
UPDATE
AM_X_442_2 amx
SET
Amx.SECURITY_LEVEL =
(
select
max_level
[code].........
I have intended the query to make it legible but it removes all spaces.
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Sep 7, 2007
Have a table like this:
ID1ID2DATEID2Value
1121/1/20066
1241/1/2006400
1246/1/2006410
1366/1/2006100
2121/1/20077
2246/1/2007350
2247/1/2007360
I need to return 1 row for each ID1 value - and only the ID2 value of 24 and only the most recently dated record for the multiple ID2 values - query would return:
1246/1/2006410
2247/1/2007360
I have worked and worked on this and I am still stumped (part of the problem may be I am also trying to make this work in Crystal Reports but that is for another day). I need to make this work in Oracle first.
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May 26, 2011
I have one table,in that table have number of rows. I want to select recent row updated details.
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Jul 5, 2012
Below given is the sample data
SELECT *
FROM
(
SELECT 1 ORDR_ID, TO_DATE('01-JAN-2012', 'DD-MON-YYYY') INWD_DATE, 5 SIZE_, 'APD' Colr_CD FROM DUAL UNION ALL
SELECT 1 ORDR_ID, TO_DATE('15-JAN-2012', 'DD-MON-YYYY') INWD_DATE, NULL SIZE_, 'KPD' Colr_CD FROM DUAL UNION ALL
SELECT 1 ORDR_ID, TO_DATE('16-JAN-2012', 'DD-MON-YYYY') INWD_DATE, NULL SIZE_, 'ALD' Colr_CD FROM DUAL UNION ALL
SELECT 2 ORDR_ID, TO_DATE('02-JAN-2012', 'DD-MON-YYYY') INWD_DATE, 9 SIZE_, 'APD' Colr_CD FROM DUAL UNION ALL
SELECT 2 ORDR_ID, TO_DATE('05-JAN-2012', 'DD-MON-YYYY') INWD_DATE, 10 SIZE_, '' Colr_CD FROM DUAL UNION ALL
[code]....
Where every first row is the initial entry for an order and following rows are the changes done to the order with modification date
And the expected output is
ORDR_ID Start_date End_date SIZE_ COLR_CD
1 01-01-12 01/15/2012 5 APD
1 01/15/2012 01/16/2012 5 KPD
1 01/16/2012 00-01-00 5 ALD
2 01-02-12 01-05-12 9 APD
2 01-05-12 01-06-12 10 APD
[code]....
I cam use a select statement within select, but wanted to write an efficient SQL...
I'm using
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0
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May 9, 2013
I encountered error ORA-00338 while performing incomplete database recovery:
ORA-00283: recovery session canceled due to errors
ORA-00338: log 3 of thread 1 is more recent than control file
ORA-00312: online log 3 thread 1: '+DG_REDO/dbase/onlinelog/group_3.267.814820795'
Recovery Manager complete.
I performed this recovery on oracle 10g, ASM database.
1. What are possible causes behind this error ORA-00338 ?
2. This error occurs at the start of media recovery, while RMAN is applying archived logs. So does RMAN apply "online REDO" logs after applying "archived" logs required for recovery or before them ?
3. How does rman come to know that online log 3 is more recent than control file ? How can I get scn of online log & control file in my environment ?
Following are few details related to checkpoint scn/change# info. I found in my environment..Before recovery:
view
v$datafile: 642935
v$datafile_header: 642935
v$database: 642935
v$log: 640956
After unsuccessful recovery (ORA 338 :( )
v$datafile: 640917
v$datafile_header: 640056
v$database: 640906
v$log: 640906
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Jul 29, 2013
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The table has fields like:
category - string,
item - string,
creation_date - string ('YYYYMMDDHHMI'),
complete_flag - boolean,
etc.
Each category does not have the same amount of records with the same creation_date so I do not want to filter by creation_date. Is there a way to accomplish this?
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Nov 18, 2011
I have a sub query (already dervived from several other tables) that has a list of children in with the date they started their course (tableofchildren). Child IDs may be duplicated in this query but each record will have unique start dates per child ID.
I have a second sub query which lists workers involved with the children in the first query (tableofworkers). A worker may be responsible for more than one child but has the unique child in the record to identify involvement with the child.
I need to join these queries together to return the child's record with the WorkerName and the AllocatedStartDate of the worker who was most recently involved with the child prior to the date (EnteredCourseDate) the child started their course (OutputWanted) - the worker associated with the child when they started their course.
A couple of points - I need to deploy this into another reporting application that doesn't support cursors etc or the 'With' operator. Also, I tend to join tables/queries in the Where clause so if it's possible that way that would be great.
OC.
create table tableofchildren
(ChildID varchar(20),
ChildName varchar (50),
[Code].....
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May 6, 2013
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The weird thing which I have noticed is that. I tried backing up Yesterday's Control file. So, I would say that the backup pieces it should pick should be from yesterday. however, the backup pieces are getting restored from last week's backup.
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Jun 19, 2013
I have the following query where i need to find the max value[code] with t as
( select 'L1' R_nm ,'Data' R_Data , 'Obj' R_Obj , 'Wd' r_prec , '2' val
from dual union all select 'L1' , 'Data', 'Obj' , 'No', '4'
from dualunion all select 'L2' , 'Data', 'Obj' , 'No', '4' from dual )
select t.*, max(val) over(partition by r_nm,r_data,r_obj) rk from t[/code]
My expected output should be
[code]
r_nm r_data r_obj r_prec val rkL1 Data Obj Wd 2 1L1 Data Obj No 4 2L2 Data Obj Yes 1 1
[/code]
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Dec 4, 2011
I'm not really sure why oracle is not finding my Foreing Key, I'm creating an easy set of table for a company and I'm declaring all Primary keys and foreing keys as necessary and this is my
CREATE TABLE Items
(ItemID NUMBER(5) NOT NULL,
Description VARCHAR2(30),
ListPrice NUMBER(9,2) NOT NULL,
QtyOnHand Number(5),
ReorderPoint NUMBER(3),
ReorderQty NUMBER(3),
OnBackOrder Number(3),
CONSTRAINT ItemsPK
[Code] ............
There's three sets of inserts the first two successfully inserts the data NO problem but when i try to insert the data on SupplierItems comes as:
ERROR at line 1:
ORA-02291: integrity constraint (jcarter.SUPPLIERITEMSFK2) violated - parent key not found
I looked on the forum and it appears this happens when someone is doing a Insert ALL but this is not my case..
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Oct 31, 2012
Select * from one:
ID SALARY
----------------------
10 1000
20 2000
30 3200
Select * from two:
ID SALARY
----------------------
10 1000
20 2000
40 4000
10 3000
20 4000
30 3000
When i try to find ID,MAX(SALARY) from these two tables, i am getting this output:
Select id,max(salary)
from
(select * from one
union
select * from two)
group by id
order by max(salary) desc;
OUTPUT:
ID MAX(SALARY)
--------------------------------------
20 4000
40 4000
30 3200
10 3000
I want OUTPUT to be like this:
ID MAX(SALARY)
--------------------------------------
20 4000
40 4000
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@test.sql
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May 20, 2010
i have table with name, count, flag with dublicate records
example
with swayam name , counts are 3, 4
with ramana name, counts are 5,5
with reddy name, counts are 1,2,3
i want to update the flag
if count are same then update one of record (flag='A') and other should be flag='R'
if count are different then update the max count (flag='A') and other should be reject remaing (flag='R'). use below quires
CREATE TABLE TEST_DUB ( NAME VARCHAR2(99), V_COUNT NUMBER, FLAG VARCHAR2(1));
Insert into TEST_DUB (NAME, V_COUNT)
Values
('SWAYAM', 3);
Insert into TEST_DUB
(NAME, V_COUNT)
Values
[Code]....
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Aug 1, 2012
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Jan 12, 2012
Version : Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
I have a source which is of datatype RAW(1). Basic requirement is to convert it into binary, and then lookup the value of the 4th and 6th bit. Is this possible using simple SQL ?
Eg.
DataBinary
----- -------
EF1110 1111
From this binary output, i need to find the value of 4th and 5th bit.
So if the 4th bit is 1, I need to perform some operations if 0 then some other.
Create table test_hex_to_bin (col1 raw(1));
INSERT into test_hex_to_bin values ('99');
INSERT into test_hex_to_bin values ('EF');
INSERT into test_hex_to_bin values ('AB');
Basically the output should read as
Bit_number Value
----------------
4 1
5 0
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Dec 14, 2010
I am reading Section 4-8 (page 42/216) in the Oracle Database 2-day Developer Guide from here:
[Code]....
It reads:
Suppose that you want to select every employee whose last name has a double vowel(two adjacent occurrences of the same vowel).
Example 4.9 shows how you can do this.
The regular expression ([AEIOU]) represents any vowel. The metacharacter 1 represents the first (and in this case, only) regular expression. The third function parameter, 'i', specifies that the match is case-insensitive.
Example 4.9 Selecting All Employees Whose Last Names Have Double Vowels
SELECT FIRST_NAME, LAST_NAME
FROM EMPLOYEES
WHERE REGEXP_LIKE(LAST_NAME, '([AEIOU])1', 'i');
Result is similar to:
FIRST_NAME LAST_NAME
-------------------- -------------------------
Harrison Bloom
Lex De Haan
Kevin Feeney
Ki Gee
Nancy Greenberg
Danielle Greene
Alexander Khoo
David Lee
8 rows selected.
I don't understand how [AEIOU])1 would find a double vowel(two adjacent occurrences of the same vowel).
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