SQL & PL/SQL :: Regular Expression To Find Commits In All Oracle Source?

Oct 14, 2013

I would like to write a select that would return all places in DB that are commiting transaction.

E.g. package for testing:

CREATE OR REPLACE PACKAGE test.TEST_COMMIT AS
PROCEDURE THE_ONLY_COMMIT_IN_DB ;
END TEST_COMMIT;--not a match
CREATE OR REPLACE PACKAGE BODY test.TEST_COMMIT AS

[code]....

The select should return 4 rows with --ok.

SELECT *
FROM ALL_SOURCE ASO
WHERE
REGEXP_LIKE(ASO.TEXT,'commit(s*);','i' )
AND name = 'TEST_COMMIT'

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Apr 13, 2013

What is the use of Regular Expression?

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Jan 21, 2011

I have a following table,

CREATE TABLE checkdata
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);
INSERT
INTO checkdata VALUES
[code]......

I need output as ,
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How do i use Substr and Regular expression here ?

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Sample Data:

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Expected Output:

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'DFFFF' D
FROM DUAL;  

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Nov 8, 2012

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select count(*) from dual where regexp_like('one plus one is two', '(^|s)one|three', 'i');

Currently this gives a count of 1. But needs to give a count of 0 when the regexp is fixed.

search words : one two

one is less than two -> match
two is greater than one -> match
onetwo is union of two numbers -> match
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Can we use regular expression to eliminate all characters other than -

A to Z
0 to 9
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Example

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Expected result - TEST@#_~12311HELLO

how we can use regular expression to achieve this result.

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I think the same logic will be implemented by regular expression also . How to write the equivalent logic by using regular expressions

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(
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TRANS_IDENTIFIER VARCHAR2(250)
) ;
insert into REG_EXP_TEST
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Examples of right or wrong
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654321HD - wrong value
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The pattern has to be as i mentioned above (6 number, 2 letters, 1 number) otherwise its wrong. My pattern does not cover all cases.

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<Attributes>
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[code]....

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*********************************************
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A B
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ERROR at line 1:
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