SQL & PL/SQL :: Passing Partition Name In A Cursor
Aug 8, 2012
I am running below cursor but getting error like
ORA-06550: line 10, column 38:
PL/SQL: ORA-00971: missing SET keyword
ORA-06550: line 10, column 1:
PL/SQL: SQL Statement ignored
Seems it's not able to identify R.PARTITION_NAME in update statement. Are you aware whether we can partition name like this if we need to update based on partition names in a cursor.
My cursor code is:
DECLARE
CURSOR C_PARTITION IS
SELECT PARTITION_NAME, PARTITION_POSITION FROM ALL_TAB_PARTITIONS
WHERE OWNER = 'FACTS'
AND TABLE_NAME = 'TABLEA'
[code].....
We receive hand punches (clock data) every day. Normally a person badges in(hand punch) which creates a row in the clock_tran_processed table. The information from that hand punch is the employee id (emp_id) the date hand punch occurred and a work_summary id (wrks_id). At the end of the day, the employee badges out (hand punch out) and another entry in the clock_tran_processed table is created. The new row will have the emp_id (employee name), date the hand punch occurred and the same work summary id from the morning.
Normally hand punches should occur in pairs. One in, one out... or one in, out for lunch, in for lunch, out for day. I am seeing intervals of three and five. Meaning the employee clocked in twice and out once, or in once and out twice. This shouldn't happen.
I am writing a report that will show number of clocks per for all employees that have three(3) or five(5) clock entries.I wrote a ref cursor that gives all the employees that have a count of 3 or 5 and the employee id (emp_id). I need to pass that employee id to another query that will then get me the dates of the clocks.Here is the ref cursor thus far (I am printing those with a count of 3 and 5).
CODEDECLARE
TYPE ClockTran_Refcur IS REF CURSOR; ClockTran_cur ClockTran_Refcur; NumClock_num number :=0; NumClock_name clock_tran_processed.emp_id%TYPE; [code]...
How do I pass that variable to the get the clktranpro_time's? I am using "Easy Oracle PL/SQL Programming" but I am not seeing this type of example(pgs 140-148).
I would like to know whether a value obtained from one cursor can be passed to the other cursor as a parameter and by passing it i want to retrieve a list of records and print only the records obtained from the second cursor where the value is passed.
I have a table Student with two columns Rno and Name and i write following PL-Sql, it is working fine, my question is that how can i pass the parameter to cursor in the following query, e.g. if i pass the roll no. 501 then it should display only the particular Name.
declare ��� cursor st_name is ����������� select rno,name from student; ����������� studentnm st_name%ROWTYPE; begin �� open st_name;
I am strugling hard to pass a cursor to my function as in parameter.here is my code
Function migrate_audits (sys_audit_ids SYS_REFCURSOR ) return number; Function migrate_audits (sys_audit_ids in sys_refcursor ) return number is v_return number; v_sys_audit_id number; begin LOOP FETCH sys_audit_ids INTO v_sys_audit_id; [code]....
passing cursor to a function is not possible in oracle? what other option I have to pass collection to the function ?
i trying to pass the char varible to the cursor but it is not taking ,,, if i hardcode the values to the cursor it is taking
here is the detailed program ... why this is not taking and tell me how to pass the values through it..
declare v_name char(6) ; cursor c1(c_name char) is select name, parent,child,status from relation start with name='%' connect by prior parent=child union
in below program,i have to pass column name to cursor at runtime..but this giving error.
DECLARE TYPE EmpCurTyp IS REF CURSOR; v_emp_cursor EmpCurTyp; emp_record hr.employees%rowtYPE; v_stmt_str VARCHAR2(200); colname varchar2(10):='Last_name'; BEGIN
[code]....
dbms_output.put_line(emp_record); * ERROR at line 13: ORA-06550: line 13, column 1: PLS-00306: wrong number or types of arguments in call to 'PUT_LINE' ORA-06550: line 13, column 1: PL/SQL: Statement ignored
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test ( test_id VARCHAR2(10 ) , test_TYPE VARCHAR2(5) , CREATE_DATE date ) partition by hash (test_id, test_type) Partitions 3 SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
Activity Structure ACTIVITY_TYPE CHAR (1) NOT NULL, ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL, ACTIVITY_ON VARCHAR2 (30) NOT NULL, REFERENCE_NO VARCHAR2 (19), CHILD_REFERENCE_NO VARCHAR2 (19), USER_ID VARCHAR2 (30) DEFAULT user NOT NULL, TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1( ACTIVITY_TYPE CHAR (1) NOT NULL, ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL, ACTIVITY_ON VARCHAR2 (30) NOT NULL, REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE, ACTIVITY_DATE, ACTIVITY_ON, REFERENCE_NO, CHILD_REFERENCE_NO,
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal; insert into tbl_temp select * from tbl_mittal * ERROR at line 1: ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
I'm dealing with an ORA-1000 error in a Pro*C application where all the cursors are correctly closed (or so it seems to me).
Here is the code for a simple program which reproduces the problem:
Each cursor is opened in a PL/SQL package:
CREATE OR REPLACE PACKAGE emp_demo_pkg AS TYPE emp_cur_type IS REF CURSOR; PROCEDURE open_cur(curs IN OUT emp_cur_type, dept_num IN NUMBER); END emp_demo_pkg;
[Code]....
While testing the initialization parameter open_cursors is set to 50.
It's my understanding that Oracle doesn't close the cursors until it needs the space for another cursor, which in my test case seems to happen when I enter a value of 50 or bigger for "number of loops". To see how oracle is reusing the cursors, while the test program is running I run SQL*Plus and query v$sesstat for the session that's running the test with the following sentence:
select name, value from v$sesstat s, v$statname n where s.statistic# = n.statistic# and sid = 7 and name like '%cursor%';
Even before I enter a value for number of loops I can see that the session opened 4 cursors and closed 2 of them:
NAME VALUE ---------------------------------------------------------------- ---------- opened cursors cumulative 4 opened cursors current 2
Entering a value of 5 for number of loops yields
NAME VALUE ---------------------------------------------------------------- ---------- opened cursors cumulative 11 <----- 7+ opened cursors current 8 <----- 6+
With a value of 30
NAME VALUE ---------------------------------------------------------------- ---------- opened cursors cumulative 36 <----- 25+ (apparently, Oracle reused at least 5 cursors) opened cursors current 33 <----- 25+
With a value of 47
NAME VALUE ---------------------------------------------------------------- ---------- opened cursors cumulative 53 <----- 17+ opened cursors current 50 <----- 17+
Now I reached the upper limit set by the initialization parameter open_cursors.
Entering a value of 48, I get the ORA-1000 error.
ORA-01000: maximum open cursors exceeded ORA-06512: at "SCOTT.EMP_DEMO
Since I open and close the cursor in the same loop iteration, I expect to find in every iterarion 1 explicit cursor and a number of implicit cursors (the PL/SQL call along with the so-called recursive cursors), but I don't expect the sum of all of them to be greater than 50. If my understanding is correct Oracle should be reusing the 50 cursors previously marked as "closeable", not raising the ORA-1000 error.
-define a cursor with bind variables -get a cursor record from these cursor -and pass the bind variable in the OPEN clause
Did'nt succeed as shown in the example.
SET SERVEROUTPUT ON SIZE 900000; DECLARE --works fine CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<3; --doesn't work --CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<:1; crec c1%rowtype; BEGIN --works fine OPEN c1; --isn't possible ? --OPEN c1 USING 3;
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
