SQL & PL/SQL :: Passing Partition Name In A Cursor
Aug 8, 2012
I am running below cursor but getting error like
ORA-06550: line 10, column 38:
PL/SQL: ORA-00971: missing SET keyword
ORA-06550: line 10, column 1:
PL/SQL: SQL Statement ignored
Seems it's not able to identify R.PARTITION_NAME in update statement. Are you aware whether we can partition name like this if we need to update based on partition names in a cursor.
My cursor code is:
DECLARE
CURSOR C_PARTITION IS
SELECT PARTITION_NAME, PARTITION_POSITION FROM ALL_TAB_PARTITIONS
WHERE OWNER = 'FACTS'
AND TABLE_NAME = 'TABLEA'
[code].....
View 1 Replies
ADVERTISEMENT
Oct 14, 2010
We receive hand punches (clock data) every day. Normally a person badges in(hand punch) which creates a row in the clock_tran_processed table. The information from that hand punch is the employee id (emp_id) the date hand punch occurred and a work_summary id (wrks_id). At the end of the day, the employee badges out (hand punch out) and another entry in the clock_tran_processed table is created. The new row will have the emp_id (employee name), date the hand punch occurred and the same work summary id from the morning.
Normally hand punches should occur in pairs. One in, one out... or one in, out for lunch, in for lunch, out for day. I am seeing intervals of three and five. Meaning the employee clocked in twice and out once, or in once and out twice. This shouldn't happen.
I am writing a report that will show number of clocks per for all employees that have three(3) or five(5) clock entries.I wrote a ref cursor that gives all the employees that have a count of 3 or 5 and the employee id (emp_id). I need to pass that employee id to another query that will then get me the dates of the clocks.Here is the ref cursor thus far (I am printing those with a count of 3 and 5).
CODEDECLARE
TYPE ClockTran_Refcur IS REF CURSOR;
ClockTran_cur ClockTran_Refcur;
NumClock_num number :=0;
NumClock_name clock_tran_processed.emp_id%TYPE;
[code]...
How do I pass that variable to the get the clktranpro_time's? I am using "Easy Oracle PL/SQL Programming" but I am not seeing this type of example(pgs 140-148).
View 5 Replies
View Related
May 24, 2011
I would like to know whether a value obtained from one cursor can be passed to the other cursor as a parameter and by passing it i want to retrieve a list of records and print only the records obtained from the second cursor where the value is passed.
View 3 Replies
View Related
Apr 13, 2004
I have a table Student with two columns Rno and Name and i write following PL-Sql, it is working fine, my question is that how can i pass the parameter to cursor in the following query, e.g. if i pass the roll no. 501 then it should display only the particular Name.
declare
��� cursor st_name is
����������� select rno,name from student;
����������� studentnm st_name%ROWTYPE;
begin
�� open st_name;
[code]....
View 6 Replies
View Related
May 6, 2010
I am strugling hard to pass a cursor to my function as in parameter.here is my code
Function migrate_audits (sys_audit_ids SYS_REFCURSOR ) return number;
Function migrate_audits (sys_audit_ids in sys_refcursor ) return number
is
v_return number;
v_sys_audit_id number;
begin
LOOP FETCH sys_audit_ids INTO v_sys_audit_id;
[code]....
passing cursor to a function is not possible in oracle? what other option I have to pass collection to the function ?
View 14 Replies
View Related
Apr 9, 2013
i trying to pass the char varible to the cursor but it is not taking ,,, if i hardcode the values to the cursor it is taking
here is the detailed program ... why this is not taking and tell me how to pass the values through it..
declare
v_name char(6) ;
cursor c1(c_name char) is
select name, parent,child,status from relation
start with name='%'
connect by prior parent=child
union
[Code]...
View 9 Replies
View Related
Apr 15, 2013
in below program,i have to pass column name to cursor at runtime..but this giving error.
DECLARE
TYPE EmpCurTyp IS REF CURSOR;
v_emp_cursor EmpCurTyp;
emp_record hr.employees%rowtYPE;
v_stmt_str VARCHAR2(200);
colname varchar2(10):='Last_name';
BEGIN
[code]....
dbms_output.put_line(emp_record);
*
ERROR at line 13:
ORA-06550: line 13, column 1:
PLS-00306: wrong number or types of arguments in call to 'PUT_LINE'
ORA-06550: line 13, column 1:
PL/SQL: Statement ignored
View 2 Replies
View Related
Aug 8, 2012
How can we pass column index or column name in cursor for loop.
View 3 Replies
View Related
May 24, 2013
I am using the below code to update specific sub-partition data using oracle merge statements.
I am getting the sub-partition name and passing this as a string to the sub-partition clause.
The Merge statement is failing stating that the specified sub-partition does not exist. But the sub-partition do exists for the table.
We are using Oracle 11gr2 database.
Below is the code which I am using to populate the data.
declare
ln_min_batchkey PLS_INTEGER;
ln_max_batchkey PLS_INTEGER;
lv_partition_name VARCHAR2 (32767);
lv_subpartition_name VARCHAR2 (32767);
begin
[code]....
View 2 Replies
View Related
Dec 8, 2010
I need to know how to pass the ref cursor as INOUT parameter to a procedure. I have the following procedure and I need to execute it.
PROCEDURE get_site_setup_detail (
p_study_id IN SITES.study_id%TYPE,
p_proj_act_date IN VARCHAR2,
[code]....
View 2 Replies
View Related
Mar 1, 2012
I am getting the below error with my bulk delete code.
ORA-14403: cursor invalidation detected after getting DML partition lock
declare
Ty_LMRowId is table of rowid;
Tbl_LMRowId Ty_LMRowId := Ty_LMRowId();
v_err_cnt number;
Ex_Dml_Errors Exception;
v_dte date := sysdate;
pragma exception_init(Ex_Dml_Errors, -24381);
[code]....
Record get deleted successfully for the first rowid in the collection, But for the remaining rowids it throws above error.
View 5 Replies
View Related
May 28, 2010
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies
View Related
Mar 17, 2011
I Know we can create dynamic partitions on table in oracle 11g. Is it possible to create normal partition and sub partition both dynamically.I have to create Normal partition range on date and sub partition list on Batch ID (varchar).
View 3 Replies
View Related
Jun 26, 2010
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
View 3 Replies
View Related
Apr 3, 2013
At present we have a non partitioned table.
Can we apply redefinition and create range partition and hash sub partition on it?
View 2 Replies
View Related
Jan 2, 2013
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
View 8 Replies
View Related
Sep 22, 2011
I have two tables Activity and Activity1.
Activity Structure
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
CHILD_REFERENCE_NO VARCHAR2 (19),
USER_ID VARCHAR2 (30) DEFAULT user NOT NULL,
TERMINAL VARCHAR2 (30) DEFAULT userenv ('TERMINAL') NOT NULL )
Activity1 Structure Which I have Done Partitioning When I insert data from Activity to Activity1 it gives that error ORA-14400: inserted partition key does not map to any partition what I am doing wrong
CREATE TABLE ACTIVITY1(
ACTIVITY_TYPE CHAR (1) NOT NULL,
ACTIVITY_DATE DATE DEFAULT sysdate NOT NULL,
ACTIVITY_ON VARCHAR2 (30) NOT NULL,
REFERENCE_NO VARCHAR2 (19),
[code]....
Insert Statement
insert into ACTIVITY1(ACTIVITY_TYPE,
ACTIVITY_DATE,
ACTIVITY_ON,
REFERENCE_NO,
CHILD_REFERENCE_NO,
[code]....
View 2 Replies
View Related
Jun 14, 2011
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
View 15 Replies
View Related
Mar 3, 2011
I have partition based table one the basis of year month. And we have 8 local indexes on this table. Every month we have to create a new partition and load data into this partition and the volume of the data is around 14million and the load process is taking long time due to indexes. Is it possible to drop the indexes from particular partition?
View 8 Replies
View Related
Jul 10, 2012
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
View 2 Replies
View Related
Apr 12, 2010
needed in stored procedure to achieve this...how to get this..(stored procedure)
table:
studentid,sname,partitonid
901,x,null
902,y,null
903,z,null
904,p,null
905,q,null
906,a,null
907,b,null
908,d,null
909,f,null
910,m,null
For the above data set i need to divide into 5 partittions and need to updated the partitonid with the partition number for each partition set,like the below result set
studentid,sname,partitonid
901,x,p1
902,y,p1
903,z,p2
904,p,p2
905,q,p3
906,a,p3
907,b,p4
908,d,p4
909,f,p5
910,m,p5
View 3 Replies
View Related
Mar 28, 2013
write ALTER STATEMENT for adding new partition P1 and SUBPARTITION P1_201001 and P1_201002.
TABLE
=======
CREATE TABLE TEST
(
"REPORT_ID" NUMBER,
"MONTH_ID" NUMBER,
"GROUP_ID" NUMBER,
"AGE_GROUP_ID" NUMBER,
[code]...........
View 4 Replies
View Related
Jun 8, 2011
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies
View Related
Sep 7, 2007
I'm dealing with an ORA-1000 error in a Pro*C application where all the cursors are correctly closed (or so it seems to me).
Here is the code for a simple program which reproduces the problem:
Each cursor is opened in a PL/SQL package:
CREATE OR REPLACE PACKAGE emp_demo_pkg AS
TYPE emp_cur_type IS REF CURSOR;
PROCEDURE open_cur(curs IN OUT emp_cur_type, dept_num IN NUMBER);
END emp_demo_pkg;
[Code]....
While testing the initialization parameter open_cursors is set to 50.
It's my understanding that Oracle doesn't close the cursors until it needs the space for another cursor, which in my test case seems to happen when I enter a value of 50 or bigger for "number of loops". To see how oracle is reusing the cursors, while the test program is running I run SQL*Plus and query v$sesstat for the session that's running the test with the following sentence:
select name, value
from v$sesstat s, v$statname n
where s.statistic# = n.statistic#
and sid = 7
and name like '%cursor%';
Even before I enter a value for number of loops I can see that the session opened 4 cursors and closed 2 of them:
NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 4
opened cursors current 2
Entering a value of 5 for number of loops yields
NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 11 <----- 7+
opened cursors current 8 <----- 6+
With a value of 30
NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 36 <----- 25+ (apparently, Oracle reused at least 5 cursors)
opened cursors current 33 <----- 25+
With a value of 47
NAME VALUE
---------------------------------------------------------------- ----------
opened cursors cumulative 53 <----- 17+
opened cursors current 50 <----- 17+
Now I reached the upper limit set by the initialization parameter open_cursors.
Entering a value of 48, I get the ORA-1000 error.
ORA-01000: maximum open cursors exceeded
ORA-06512: at "SCOTT.EMP_DEMO
Since I open and close the cursor in the same loop iteration, I expect to find in every iterarion 1 explicit cursor and a number of implicit cursors (the PL/SQL call along with the so-called recursive cursors), but I don't expect the sum of all of them to be greater than 50. If my understanding is correct Oracle should be reusing the 50 cursors previously marked as "closeable", not raising the ORA-1000 error.
View 1 Replies
View Related
Feb 25, 2011
Is it possible to:
-define a cursor with bind variables
-get a cursor record from these cursor
-and pass the bind variable in the OPEN clause
Did'nt succeed as shown in the example.
SET SERVEROUTPUT ON SIZE 900000;
DECLARE
--works fine
CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<3;
--doesn't work
--CURSOR c1 IS SELECT * FROM USER_TABLES WHERE rownum<:1;
crec c1%rowtype;
BEGIN
--works fine
OPEN c1;
--isn't possible ?
--OPEN c1 USING 3;
[Code]....
View 3 Replies
View Related
Mar 25, 2011
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
View 11 Replies
View Related
Sep 11, 2011
just looking around to use the new feature available in oracle 11g to convert the dbms_sql numeric cursor to reference cursor, how to do it?
parse and execute the sql string first with dbms_sql and then convert it to ref cursor?
View 1 Replies
View Related
Nov 23, 2011
I want to return ref cursor based on explicit cursors
create table jumbo(id number, name varchar2(20));
insert into jumbo values(1,'jumbo');
create table mumbo(id number, name varchar2(20));
insert into mumbo values(1,'mumbo');
commit;
[Code].....
The above procedure has compilation errors when I am trying to open ref cursor
LINE/COL ERROR
-------- --------------------------------------------------------
20/24 PL/SQL: SQL Statement ignored
20/38 PL/SQL: ORA-00942: table or view does not exist
32/24 PL/SQL: SQL Statement ignored
32/38 PL/SQL: ORA-00942: table or view does not exist
SQL>
View 5 Replies
View Related
Aug 7, 2013
Can i user exist when cursor will using For Cursor .
View 15 Replies
View Related
Jul 17, 2010
I have a partitioned table in which at the first level it is been partitioned based on date column(C1) and within in each partition it is again sub-partitioned based on a column(C1) which is a numeric value now at first level(C1 column level) there are 6 partitions and in the last partition i want to add another partition how can i do that.
View 8 Replies
View Related
