I need a query to divide the total consumption of an item into parts as it was stored in store on the basis of FIFO. The item that was stored first it will consumed first.
The total consumed against code '012-042C' is 990 for dept_id 19 and we have stored qty 1050.1 against goods receipt no 359 dated 12-jul-12. So have issued the whole qty against no 359 and balance is 0. For item code '012-043D' the total issuance is 1650 and we have issued it against 03 goods receipt nos.
I want to adjust 2900 against certain amount from table on fifo basis.
DROP TABLE ABC CREATE TABLE ABC(ID NUMBER PRIMARY KEY,AMT NUMBER); INSERT INTO ABC VALUES(1,1000); INSERT INTO ABC VALUES(2,2000); INSERT INTO ABC VALUES(3,3000);
Can i do it using SQL. I know that it can be done using PL/SQL but i just wanted to confirm if its possible using SQL.
We have a requirement to update one column as given in the below mentioned pl/sql block.The challenge is to update the a large volume of data every day.Generally this kind of one to one update will takes long time (45 min approxmately) We need a solution that will be able to update 10 million records in few minutes.
begin for i in (select t3.event_id, t1.header_id from table_1 t1, table_2 t2, table_3 t3 where t1.header_id=t2.header_id and t2.entity_id = t3.entity_id) loop update table_1 set event_id = i.event_id where header_id =i.header_id; end loop; commit; end;
1) CREATE TABLE mutu (id NUMBER, text VARCHAR2(20));
2) INSERT INTO mutu SELECT rownum , 'mutu' FROM dual CONNECT BY LEVEL <= 10000;
3) Insert Duplicate row. INSERT INTO mutu VALUES (42, 'DUPLICATE');
4) COMMIT;
5)Create a NON-UNIQUE INDEX's CONSTRAINT as below. ALTER TABLE mutu ADD CONSTRAINT mutu_pk PRIMARY KEY(id) USING INDEX(CREATE INDEX mutu_pk ON mutu(id)) ENABLE NOVALIDATE;
6) Insert Duplicate row. INSERT INTO mutu VALUES (42, 'DUPLICATE');
7) ERROR at line 1: ORA-00001: unique constraint (SYS.ZIGGY_PK) violated
Why it shows the error. Even though I had created a NON-UNIQUE INDEX's Constraint only.
I have 2 tests Oracle instances (a 10g and a 11g) in which somebody added many users (almost 50k), every user having a TEST table with no rows in its schema.
I have to drop these users without recreating the instances, but DROP USER username CASCADE is taking almost 1 minute for each user. This will take me to almost a month.
i got a table and it had 5000 rows of data...ive deleted around 2000 to decrease the db size but i have no success. My harddrive is still showing the same size with no increase in mb.
I've looked at shrink etc methods but some are not compatible with 8i.
I take it the db is still reserving that those deleted rows thinking it may be used again which is the reason for no increase in space.
How to find out the status of the import job(how much work is done, ETA), i have started the job few days back it still running on the server. i am using import not datapump, because i got the dump which took with export. DB version is 11.2.0.2.0
for datapump i know i can use the following queries, but these are not giving any output l think these are only for datapump
select sid, serial#, sofar, totalwork from v$session_longops; select sid, serial# from v$session s, dba_datapump_sessions d where s.saddr = d.saddr;
i have attached the .csv file for gratuity calculation.
In the given criteria you can see if number of years 1 then he can get 1 salary if years 1.5 then 2 salary and so on also we need to take care about the leap year.
create table ex (sno number,ename varchar2(10),job_code char(4),sal number); insert into ex values(101,'John','Java',21000,'IT'); insert into ex values(102,'Michel','BI',25000,'IT'); insert into ex values(103,'Johny','Java',30000,'IT');
and I was wondering if there is a quick method of populating it with calendar data so it would look like the following:
Product Year Month A 2008 Jan A 2008 Feb A 2008 Mar A 2008 Apr A 2008 May A 2008 Jun A 2008 Jul A 2008 Aug A 2008 Sep A 2008 Oct A 2008 Nov A 2008 Dec A 2009 Jan A 2009 Feb Etc.
I have a form of a user feedback with SMS Sending. which I gave to my all clients when ever my any client enter a feedback they press send SMS button so I got SMS if they press the button 2 times I got 2 same sms and if press the button 3 times I got 3 same sms and so on I want to restrict them and allow them to send only 2 sms of that feedback.any method on WHEN-BUTTON-PRESSED Trigger.
Is it possible to solve an equation with the newton-raphson method with sql?
I have an equation f(x)=1-a/x**2, f(x)'= 2a/x**3 and want to solve x for several a's
The newton-raphson methos uses the derivation as next approximation:
xn2 = xn1 - f(x)/f(x)'
The result should be like this:
create table temp_res (a integer, res number); insert into temp_res values(1, 1); insert into temp_res values(2, 1.41421288939285); insert into temp_res values(3, 1.73205078513617); insert into temp_res values(4, 1.99999999999617); insert into temp_res values(5, 2.23606797658102); insert into temp_res values(6, 2.4494897130809); insert into temp_res values(7, 2.64575095945042); insert into temp_res values(8, 2.82842712474403);
DB: 11.2.0.3 & OS: RHEL5 Easy Connect Naming method enhances the host naming method by allowing for a port and service specification. My question is does Oracle 11g support Host naming method?
Our Audit Company has given us a recommendation:"Old DB Link encrypted Passwords: The password of the Oracle databases links are encrypted using DES (password starts with 05). This encryption methord is known and users can decrypt the passwords using a simple SQL query. Please recreate the database links to use the new encryption method (password starts with 06)."What does it mean and how can we perform this recommendation?
I have tested it and it is working as the way I expected: select 'to display week no as column' "Week &week_no" from dual;
The output: Week 16 ---------------------------- to display week no as column ...So how do I display Week 15, Week 17 etc based on the calculation of &week_no e.g. &week_no+1?
I have time fields that have been converted from a 12hr clock to a 24hr clock and these fields hold only the time...no date.
I need to be able to determine the difference between column A and B eg.
Column A: Column B: 11:00 14:00
I can remove the ':' by using the replace command, but as I need to run on a actual 24hr clock I am not sure how to tackle the calculation as it is not the full oracle datetime format.
Is it possible to calculate cumulatively in oracle sql queries, i.e. using the results of the last row for calculating the values in the current row?For example I want my query to return the following:
In col3 above, for feb I want to use the result returned for jan ((100 * 1)*2+200), for mar I am using the result returned for feb((100 * 2 + 200) * 3 + 300) and so on.
i.e. I want to use the previous value of column3 to derive the current value of column3. Like using the LAG function but on the analytically derived column itself.
SELECT FROM_TZ(CAST(TO_DATE('1999-12-01 11:00:00', 'YYYY-MM-DD HH:MI:SS') AS TIMESTAMP), 'gmt') AT TIME ZONE '+05:30' "Time at Time zone" FROM DUAL;
Time at Time zone 01-DEC-99 04.30.00.000000 PM +05:30
My requirement is that
I want to add 2 hours to DateTime i get here i.e. add two hours in result and display the resultant date and tine in time zone '+05:30'. I also want to check that the resultant time falls in business hours (9 am to 6 pm).
for making the query for following data,when we give start and end date then query need to calculate number of years.
if less than one year then return 0 if exact one year then return 1 if exact 1.5 years (18 months) then return 2 if exact 2 years (24 months) then also return 2 if exact 2.5 years (30 months) then return 3 if exact 3 years (36 months) then also return 3 if exact 3.5 years (42 months) then return 4 if exact 4 years (48 months) then also return 4 and so.
also we need to add leap year 1 day if exist in start and end date.
I am developing a form where I need to add Numbers.In fact we have a bag of Cones that contain 24 cones.In normal calculation when I add numbers for example
5.24 Plus 5.24 it will give the result 10.48
I Need the appropriate method to calculate if I add these two numbers it should give the result 5.24 Plus 5.24 the result should be 12
Currently I am working on payroll system where I have to calculate employees working hours/late coming hours/early going hours against its roster which is defined in the beginning of every month/week.
In roster form user define shift of every employee like
Code Name Shift 7 Saad Nafees A - 09:00 17:00 492 Muhammad Nasir Shahzad B - 17:00 01:00 243 Muhammad Tahir C - 01:00 09:00
Roster table structure
code varchar2 name varchar2 Shift date Remarks varchar2
shift table structure
code varchar2 timein date timeout date latetime date Hdaytime date
Oracle stores both date and time information in date data type, suppose today user change shift timings from 17:00 to 17:30 or user change timein/timeout in attendance form then oracle will store current date with user define timings.
Now this is the main problem which I am facing because whenever you calculate difference between timein and timeout or compare with its roster then output comes wrong because oracle returns total no of hours whenever you minus two dates.
We want to calculate Annual leave the scenerio is as follows
1. Employee service more the one year 2. if joining date is 07-04-2008 than on 07-04-2009 completed one year and on 07-04-2010 completed two years and so on. day and month of date must be the same.
so we need YEAR*14. e.g. if 1 year completed then 1*14 if two years completed then 2*14 and so on. by this we will get the opening of Annual leaves.
We have another table where we entered the leave day by day in whole year, if he avail 10 leaves in first year then 4 will be remaining and we can say it is the closing of first year and opening of second year. so on second year he will entitled 14 more leaves so 14 + 4 = 18 should be opening of next year.In year Caclulation Day and Month must be the same for example 07 day, 04 month for every year. 14 Annual leaves are fix for each year
