I need to get the previous Sunday through Saturday from each Sunday. I want to run the report every Sunday and it will compare the previous dates from Sunday to Saturday.
View 3 RepliesSelect to_char(hiredate,'Day'),count(empno)
from empgroup by to_char(hiredate,'Day')order by to_char(hiredate,'Day')
select to_date('25-04-2012', 'DD-MM-YYYY') + rownum -1 dt
from dual
connect by level <= to_date('05-05-2012', 'DD-MM-YYYY') - to_date('25-04-2012', 'DD-MM-YYYY') + 1;
The above query returning the following output,
DT
04/25/2012
04/26/2012
04/27/2012
04/28/2012
04/29/2012
04/30/2012
05/01/2012
05/02/2012
05/03/2012
05/04/2012
05/05/2012
here I need to exclude the Dates which comes on 'saturday' and 'sunday' and also the common holiday..Here it is '01-May-2012' and I need the output like the following,
DT
04/25/2012
04/26/2012
04/27/2012
04/30/2012
05/02/2012
05/03/2012
05/04/2012
I need the common query to calculate between any two dates.
i need to write a function to eliminate SUNDAY AND SATURDAY;
My criteria is
if My date as (5/19/2012 ) and i want to add 10 days to it themn my function should return 06/01/2012
if My date as (5/13/2012 ) and i want to add 12 days to it themn my function should return 05/29/2012
I given the table name,column name,datatype and sample record in the table. I have given the sample record for 01-jan-2008 to 8-Jan-2008, but in the real thing it will be for 30 years.
My Requirement:
For each class_no (202,203..), I need the missing date excluding weekends (sat, sun), I have provided the sample output below.
Table Name : ABC
Column Name : Class_no Data Type : Number
Column Name : Class_DateData Type : Date
Sample Record in the Table :
Class_noClass_Date
202 1-Jan-08
202 2-Jan-08
202 7-Jan-08
202 8-Jan-08
203 1-Jan-08
203 2-Jan-08
203 3-Jan-08
203 7-Jan-08
203 8-Jan-08
OUTPUT:
Class_noClass_Date
202 3-Jan-08
202 4-Jan-08
203 4-Jan-08
I want to schedule a job which will run evry Sunday at 12 P.M IST.I have written the below script.
BEGIN
SYS.DBMS_SCHEDULER.CREATE_JOB
(
job_name => 'SERVICE_SAL_FS.SAL_MESSAGE_BUFFER_PURGE_JOB'
,start_date => SYSTIMESTAMP
[code]...
But the server in US.
SELECT sysdate from Dual;
6/11/2013 3:58:58 AM
--But the time in India is 02:28 PM
How to convert the timezone to IST. how to schedule the job to run evry Sunday at 12 P.M IST.
I have following code. It is always returning sysdate even run on Sunday.
declare
vDate date;
begin
if to_char(sysdate,'Day')='Sunday' THEN
vDate := sysdate-3;
[Code]...
if there is something missing or wrong.
I want to get the week of the year.
Conditions are:
1. Year's first week starts with first Sunday of the year. (6th Jan 2013 will be the starting week (week 1) in Year 2013)
2. 2nd Jan 2013 will be the last week of the previous year i.e. 2012 (either 52th or 53rd week)
At many place I found the below solution:
select to_char(to_date('01-JAN-2008','DD-MON-YYYY')+1,'IW') week_number from dual;
But its not working for the given dates (2nd Jan 2013, which should fall in the last week of 2012, and 6th Jan 2013, which should be the starting week of 2013).
I would like to design a date range query where the beginning of the week is always sunday and the end of the week is always monday.
View 3 Replies View RelatedI need to schedule a script in crontab which needs to be execcuted on every 2nd Sunday of every month.
I used this logic
30 9 8-14 * 0 /$PATH/$FILE_NAME.sh but this is not working only on sunday but on all days of second week.
Any logic to schedule this?
i have one query. i want to Find the list of second and forth Saturday in a particular year.
View 6 Replies View Relatedhow can create function or sql statement to show week of days without Friday and Saturday
View 13 Replies View RelatedThe main condition in SQL is like this.
SELECT TO_DATE (TO_CHAR (doc_date, 'MON-YY'), 'MON-YY') "INV_MTH",
SUM (inv_amt) INV_TOTAL
FROM table_x
WHERE doc_date BETWEEN TRUNC (SYSDATE, 'YYYY')
AND LAST_DAY (
ADD_MONTHS (TRUNC (SYSDATE, 'YYYY'), 11)
);
My Output from if run in JAN as of now 16 Jan.
INV_MTHINV_TOTAL
Jan-136260830.42
I want an sql until previous day of that month for example 15 Jan and another sql until day before previous day of that month for example 14 Jan.
How to get the previous value of row with calling function to add value in SELECT statement for the row value.
Consider the example Table A1 having column a with values 1,NULL,NULL,NULL
SELECT CASE WHEN a IS NULL THEN (prev_row_value+function_return_Value) ELSE a END as A from A1
And my result-set should be like
a
----------------------
1
1+(Return Value Of Function)
Prev_Row_Value+(Return Value Of Function)
Prev_Row_Value+(Return Value Of Function)
Below is sample code but doesn't fulfill my criteria
[code]....
Output is
A A2
---------------------------
1 1
3
3
3
i want to know the all scn number's that are generated yesterday or in any previous day? how can i achieve it?
View 5 Replies View Relatedi need to multiply with previous row value?
my table have about to 100 columns and lakhs of rows
Ex:
date adj
------ -----
8/21/2012 1
1/1/2012 1
12/1/2011 0.5
8/1/2011 0.5
[code]....
My requirement is multiply the existing adj by adj
adj value coming as 0.5
present year always 1
Ex:
date adj
------ -----
8/21/2012 1
1/1/2012 1
.
.
12/1/2011 0.5
8/1/2011 0.5
[code]....
Is it possible for me as a DBA to find IP address of the client who ran a specific transaction or query in past?
Oracle server version I'm using is 11g.
i have tablestructure like this
empno ename sal
1 sam 1000
2 tom 2000
3 ric 3000
4 mac 4000
5 doy 5000
i want TO WRITE SELECT QRY WHICH WILL GO like this
empno ename sal prevemp prevename presale
1 sam 1000 0 0 0
2 tom 2000 1 sam 1000
3 ric 3000 2 tom 2000
4 mac 4000 3 ric 3000
5 doy 5000 4 mac 4000
means when each current row executes it shld show details from previous row also means when details of tom is executing it also shows sam details
Is it possible to get cumulative sum of the same column? I am trying to get a value for COL6... it is dependent on the values of previous row
COL6 Formula:
IF COL2 = 'A' THEN
IF 100 - [SUM_COL6] > COL5 THEN
COL5
ELSE
(TRUNC(100 - [SUM_COL6] / COL4) )* COL4
END IF
[code]....
I need to get data from a table in which dates is equal from previous month. The dates in this table has a formula DD-MMM-YY (CRE_DTTM is the name for date column).
I've already achieve getting data from the previous month by using this formula:
(to_char(CRE_DTTM,'MON')) = UPPER(to_char(add_months(trunc(sysdate,'MONTH'),-1), 'Mon'))
My problem now is what if the current month is for example JAN 2011.. I need to get the data from DEC 2010. How can I query the previous year in this case?
CREATE TABLE F_TIME( PERIOD_ID NUMBER, PERIOD_NAME VARCHAR2(30 CHAR), PERIOD_YEAR NUMBER, PERIOD_TYPE VARCHAR2(30 CHAR), CREATION_DATE DATE, UPDATE_DATE DATE, UPDATE_BY NUMBER); SET DEFINE OFF;Insert into F_TIME (PERIOD_ID, PERIOD_NAME, PERIOD_YEAR, PERIOD_TYPE, CREATION_DATE, UPDATE_DATE) Values (16, 'Q4', 2012, 'q', TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('04/20/2013 17:41:28', 'MM/DD/YYYY HH24:MI:SS'));Insert into F_TIME
[code]...
if i pass 30 then it will return period id=16 data
We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
CODEemp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
Primary key - emp_id, effective_date..This table is yearly partitioned...I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
CODEWITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]....
For emp_id 1, if we ran this query for 10/31/2011, then it has to compare the 10/31 salary with 10/29 and do the same until the salary mismatches. In this case, salary salary mismatch occurs on 10/20, so the stale salary period is from 10/31 to 10/21 which is 7 days.Below query will give that result:
CODE
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]...
I take a select into a cursor and process it record by record.I have to do sum based on a column and display row by row by using dbms_output.put_line .... So the sum has to happen based on a column. Based on the column value i need to display the cumulative sum as well.
Example:-
col1 col2 amount
DL AADD 25
DL BBCC 10
DL BBRR 15
Sum value for DL ----- 50
TX ADED 20
TX EDWW 60
Sum value for TX ----- 80
All the above data should be displayed using DBMS_OUTPUT.PUT_LINE in a pl/sql code. I use cursor to take the values from the table but the problem i face is .... I am not able to display the sum based in the col1 values.
Since i use the cursor .. i took the col1 values in to a variable and checked every time
old_variable = new_variable
if yes then continue the sum
else
display the sum value.
once i get the above check satisfied i am loosing a new col1 row in the check. The next loop only run for the new col1 values -1( which is used in the check loop).So is there any better way to get the solution or is there a facility to store the previous loop values in a cursor ? so that i dont have to loose that one row of data.
I am not able to come up with proper loop so which can identify that the col1 has changed and you have to display the sum value.
How to achieve "Prev_Value" column as shown below without using ORACLE analytic functions
I have records stored in table for various categories and based on ID / Name / Office / Product / Category combination I want to achieve previous value column through efficient SQL query
Test Scripts as below
CREATE TABLE TEST_Prev
(
ID1 NUMBER(3),
Name1 VARCHAR2(10),
OFFICE VARCHAR2(20),
PRODUCT VARCHAR2(20),
Overall VARCHAR2(20),
DATE1 DATE,
VALUE1 NUMBER(1)
);
commit;
[code]......
Expected output as in attached sheet.
What command can be used to take the previous day upto mid night?
For example
TO_DATE('18-MAR-13 23:59:59', 'dd-mon-yy hh24:mi:ss')
Instead of me entering the date any way to take the previous day till mid-night.
I dont think sysdate-1 will work for me because if I enter sysdate-1 it will take from now -1 that means 18-mar-13 15.45.45 but I want till the previous date until mid-night.
I am trying to set the min date if there is no gap between dates.compare previous date2 value with current date1,if they are same then my new date will be min(date1).
source data
date1 iddate2 new_date
1/2/20111234/2/2011
4/2/20111237/2/2011
7/2/201112310/2/2011
10/2/20111231/2/2012
1/2/20121234/2/2012
4/2/20121237/2/2012
12/17/20121233/17/2013
3/17/20131236/17/2013
and I am expecting the out put like this
date1 id date2 new_date
1/2/20111234/2/20111/2/2011
4/2/20111237/2/20111/2/2011
7/2/201112310/2/20111/2/2011
10/2/20111231/2/20121/2/2011
1/2/20121234/2/20121/2/2011
4/2/20121237/2/20121/2/2011
12/17/20121233/17/201312/17/2012
3/17/20131236/17/201312/17/2012
how to achieve this with SQL
i am looking for a SQL query by which i can extract data between 25th of previous month till today .
i tried the below code but no luck
SELECT TO_CHAR(SYSDATE, 'YYMM'), TO_CHAR(SYSDATE, 'YYMM') -1, TO_CHAR(SYSDATE, 'YYMM') -2, TO_CHAR(SYSDATE, 'YYMM') -3
FROM DUAL
I'm making a menu in my form, wherein it has FILE, TRANSACTION and REPORT. Under FILE it has BACK, and LOGOUT. In my back menu item, i want to go back to the previous block or previous module. I used previous_block but it's not working in some of my blocks.
View 8 Replies View RelatedI have a tar.gz file when i issue command like this to untar,
mysql@test ~]$ tar xfvz mysql-advanced-5.5.17-linux2.6-x86_64.tar.gz
output:
mysql-advanced-5.5.17-linux2.6-x86_64/bin/mysql2mysql
mysql-advanced-5.5.17-linux2.6-x86_64/bin/mysqlslap
tar: skipping to next header
tar: Archive contains obsolescent base-64 headers incomplete literal tree
gzip: stdin: invalid compressed data--format violated
tar: Child returned status 1
tar: Error exit delayed from previous errors
But when i check i found the file like below,
mysql@test ~]$ ls
mysql-advanced-5.5.17-linux2.6-x86_64
This means its completly untar the file?Why that error is showing?
I have a stat table that got info like login_date,user_id etc.For a specific user, i have a requirement based on the no of days difference between the current login date and last login date.
For example, Tom logged in on June 4th 2013. His previous login was May 31. So no_of_days_difference is 5 days.How to programmatically get this for each user inside a pl-sql sub block.