Forms :: Ranking Within A Form?

Jul 25, 2013

I have a query find window that allows you to search on various attributes.Also i have a radio button within the query find that allows you to filter the results either as a single record or mulitiple records For example consider the data below.....

Header Table
Record_Id = 1, Record_No = 'Rec1'

Lines Table
Record_Id = 1, Line_desc = 'Line1'
Record_Id = 1, Line_desc = 'Line2'
Record_Id = 1, Line_desc = 'Line3'

I have a View that joins the 2 tables together so for Record_Id = 1 the view returns 3 rows

I would like to have a query find window that allows you to search using:
Record_No
Line_Desc

and has a radio button to allow you to either show the records as a single line or as all detail lines Therefore i would like the following selections:

1) Enter no search criteria but select Single radio option will return 1 record with default line description of Line1
2) Enter no search criteria but select Multiple radio option will return all 3 records
3) Enter Line_Desc = Line1 with Single radio option brings back one record with Line_Desc = Line1
4) Enter Line_Desc = Line2 with Single radio option brings back one record with Line_Desc = Line2
5) Enter Line_Desc = Line3 with Single radio option brings back one record with Line_Desc = Line3
6) Enter Line_Desc = Line1 with Multi radio option brings back one record with Line_Desc = Line1
7) Enter Line_Desc = Line2 with Multi radio option brings back one record with Line_Desc = Line2
7) Enter Line_Desc = Line3 with Multi radio option brings back one record with Line_Desc = Line3

I need the form to select from the view but then perform a rank after it has selected the relavant data. Then the radio button would use the ranking to select either one record or multi records.

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I cann't commit form when new instance form with form status is "NEW".

And then i call:
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PL/SQL :: Ranking Sum Total But Not Overall?

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I'm trying to Rank Username based on the Total Sum of amount waived but I want to avoid Ranking the Overall Total at the bottom, plus I dont want them in Ranking order, I want the order to stay the same as it currently is.

SELECT DECODE(GROUPING(USERNAME),1,'TOTAL',0,UPPER(USERNAME)) as "USERNAME",
       SUM(CASE WHEN TO_CHAR(DATE_PROCESSED,'MON') = 'JAN' THEN AMOUNT_WAIVED ELSE 0 END) AS JAN,
       SUM(CASE WHEN TO_CHAR(DATE_PROCESSED,'MON') = 'FEB' THEN AMOUNT_WAIVED ELSE 0 END) AS FEB,
    
[code]....

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SQL & PL/SQL :: Ranking Non-Consecutive Rows?

Aug 23, 2012

I have a table T with columns

Col1 Col2
1 A
2 B
3 C
4 D

[code]..

I want to do group ranking in desired col3 in such a way that it checks for different values across consecutive rows under col2 and assigns a number to each group. Just when two consecutive rows in col2 have same value then the group ends and the next group starts.

So my desired output is:

Col1 Col2 Col3
1 A 1
2 B 1
3 C 1
4 D 1
5 D 2
6 A 2

[code]...

Here you can see that the first four rows under col2 are unique i.e A,B,C,D so col3 assigns this as group number 1. It ends at row 4 becuase row 5 also has value D under column 2. So in other words, each group must have all unique values and there should not be any repetition. For example, see group 3 (under col3) in above desired output; it starts from row 9 and ends at row 11 because row 12 also has value 'C' and the value 'C' has already occurred in group 3 in row 9.

I want to achieve this SQL. I tried using Dense rank but couldn't go through. I want the shortest possible query to acheive this.

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SQL & PL/SQL :: Ranking Based On A Group?

Jun 29, 2011

I have a table t

CREATE TABLE T
(ID NUMBER(4),
NAME VARCHAR2(40))

INSERT INTO T VALUES (1,'JAMES');
INSERT INTO T VALUES (1,'DOLLY');
INSERT INTO T VALUES (2,'MICHEAL');
INSERT INTO T VALUES (2,'FLASH');
INSERT INTO T VALUES (3,'JAMES');
INSERT INTO T VALUES (3,'MARY');
INSERT INTO T VALUES (4,'JAMES');
INSERT INTO T VALUES (4,'DOLLY');
INSERT INTO T VALUES (5,'JAMES');
INSERT INTO T VALUES (5,'DOLLY');
INSERT INTO T VALUES (6,'JAMES');
INSERT INTO T VALUES (6,'MARY');

SELECT * FROM T ORDER BY 1

ID NAME
1 JAMES
1 DOLLY
2 MICHEAL
2 FLASH
3 JAMES
3 MARY
4 JAMES
4 DOLLY
5 JAMES
5 DOLLY
6 JAMES
6 MARY

each 'ID' has two values always. I want to rank the data based on same pair 'name' in an 'ID'

for example, my desired output is:

ID NAME RANK
1 JAMES 1
1 DOLLY 1
2 MICHEAL 1
2 FLASH 1
3 JAMES 1
3 MARY 1
4 JAMES 2 ---> THAT IS RANK 2 BECAUSE THIS IS THE 2ND TIME JAMES AND DOLLY ARE IN THE SAME 'ID'
4 DOLLY 2 -----> SAME AS ABOVE
5 JAMES 3 ---> THAT IS RANK 2 BECAUSE THIS IS THE 3RD TIME JAMES AND DOLLY ARE IN THE SAME 'ID'
5 DOLLY 3 -----> SAME AS ABOVE
6 JAMES 2 ---> THAT IS RANK 2 BECAUSE THIS IS THE 2ND TIME JAMES AND MARY ARE IN THE SAME 'ID'
6 MARY 2 -----> SAME AS ABOVE

I want the output in exactly above format.

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PL/SQL :: Ranking Partitions - Value Identifier

Jul 4, 2012

Lets say I have a table like the following -

ID--------DATE_TIME-----------------VALUE
101----- 01/01/2012 14:00:00 ---12
101----- 11/01/2012 23:00:00 ---17
101----- 13/01/2012 10:00:00 ---22
101----- 19/03/2012 08:00:00 ---7
101----- 19/03/2012 19:00:00 ---7
101----- 19/03/2012 20:00:00 ---7
101----- 20/03/2012 02:00:00 ---3
101----- 20/03/2012 03:00:00 ---3
101----- 21/03/2012 13:00:00 ---14
101----- 21/03/2012 14:00:00 ---14
101----- 21/03/2012 21:00:00 ---13
101----- 21/03/2012 22:00:00 ---13
101----- 21/03/2012 23:00:00 ---13
101----- 22/03/2012 00:00:00 ---13

I'm looking for a script to partition the data into sections where the VALUE is the same over a constant period of time with no breaks. I'd like to give each partition a value to identify it by.

So the outcome of the script would be the following -

ID--------DATE_TIME-----------------VALUE-----IDENTIFIER
101----- 01/01/2012 14:00:00 ---12----------1
101----- 11/01/2012 23:00:00 ---17----------2
101----- 13/01/2012 10:00:00 ---22----------3
101----- 19/03/2012 08:00:00 ---7------------4
101----- 19/03/2012 19:00:00 ---7------------5
101----- 19/03/2012 20:00:00 ---7------------5
101----- 20/03/2012 02:00:00 ---3------------6
101----- 20/03/2012 03:00:00 ---3------------6
101----- 21/03/2012 13:00:00 ---14----------7
101----- 21/03/2012 14:00:00 ---14----------7
101----- 21/03/2012 21:00:00 ---13----------8
101----- 21/03/2012 22:00:00 ---13----------8
101----- 21/03/2012 23:00:00 ---13----------8
101----- 22/03/2012 00:00:00 ---13----------8

I was trying to do something with trunc(date_time) but that didnt work out right as the blocks of data can carry over several days as seen in the rows with IDENTIFIER = 8.

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SQL & PL/SQL :: Ranking Function And Duplicate Records

Aug 30, 2012

I have the following table :

CREATE TABLE A_TEST (A INTEGER, B INTEGER, C INTEGER, D INTEGER, FLAG CHAR(11));

INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
INSERT INTO A_TEST (A,B,C,D) VALUES(7,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(9,2,3,4);
[code]....

I would like to perform an update on the FLAG column by setting to "D" if it is a duplicate record.1,2,3,4);I would like to use the rank function.

Desired update:

A B C D FLAG
1 2 3 4
2 4 5 8
1 2 3 4 D
2 4 5 8 D
7 2 3 4
9 2 3 4
7 2 3 4 D
1 2 3 4 D
5 4 5 8
2 2 3 9
2 4 5 8
6 2 3 4
1 3 3 4
8 2 8 4

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SQL & PL/SQL :: Analytic Functions And Ranking / Ordering?

Jul 17, 2008

I need to return an ordered list of documents. The documents may belong to a set id (optional) and if so, are either a "master" or a "duplicate" type. For each set there can be only one master but many duplicates. My goal is to group all the sets together such that each master is proceeded by its duplicates.

Table description:
document_master_duplicates
(
documentid,
duplicate_setid,
is_master
)

This needs to join to another table briefcase_documents which contains our set of documents. The briefcase / document relationship is many-to-many.

Table description:
briefcase_documents
(
briefcaseid,
documentid
)

There's also a documents table containing the documentid and among other things a page_count. In the following example I want to sort the documents first by page count but preserving the master/dupe grouping. Any documents which don't belong to a set or are just a duplicate without a master i want at the end of my set but also ordered by page count.

Here's an example set that I would want to order by:

DocumentId Page_Count SetId Is_Master
2002 2 1 0
2003 20 2 0
2008 20 NULL NULL
2010 20 4 0
2012 1 4 1
2001 5 1 1
2004 16 3 1
2011 17 4 0
2014 10 5 0
2009 9 NULL NULL

As you can see I have a little bit of everything here. Docs 2001 and 2002 are the typical set of 1 master and its duplicate. Docs 2010, 2011, and 2012 is the same just a set of 3. Doc 2004 is a master but without any duplicates. Docs 2003 and 2014 are duplicates without a master (these docs have a master in the table but that doc isn't in the set i need to order by). Docs 2008 and 2009 do not belong to a set and as such do not have a master/dupe type.

The result i'm looking to achieve will be ordered as follows:

DocumentId Page_Count SetId Is_Master
2012 1 4 1
2011 17 4 0
2010 20 4 0
2001 5 1 1
2002 2 1 0
2004 16 3 1
2009 9 NULL NULL
2014 10 5 0
2003 20 2 0
2008 20 NULL NULL

As I said above I first want to get the groupings of master/dupes and order ascending on the masters page count. For each duplicate of a master I then want to order the duplicates by page count. After I finished ordering all the master/dupe groups I then want to move on to the rest of the documents which will contain documents that don't belong to a set along with documents which are duplicates but have no master in my set. However, documents which are masters but without duplicates should have been ordered along with the other master/dupes groupings.

With this all in mind I have just been completely overwhelmed as to where to even start. Am I using analytic functions? Hierarchical stuff?

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SQL & PL/SQL :: Ranking Of Consecutive Non-increasing Values In A Column?

Apr 14, 2012

I have a table with numbers like this in a column

sr no. value
1 17
2 0
3 0
4 38
5 32
6 24
7 12
8 51
9 42
10 1
11 1
12 0
13 0
14 1
15 1
.
.
.
so on....

I want to find out consecutive non-increasing sequences of value (2nd column) order by sr. no (first column) in ascending order.

For example, in the 2nd column, 17 is followed by 0 and 0 and then 38 so it means 3 consecutive values (i.e starting from 17 are 0 and 0) are non-increasing and they are ranked by '1' in my desired in third column as shown below. similarly, the 2nd non-increasing sequence starts with 38,32,24 and 12 and this is ranked as '2' in the third column. same is the case with rank '3' for the third non increasing sequence. so bascially i want the third column with "ranks" starting and ending as per above logic. i tried using LEAD function but doesn't get what I want. I need the shortest possible query to get that third column since i have other columns in the original table in a multiple group by query.

my desired output is:

sr no. value Rank
1 17 1
2 0 1
3 0 1
4 38 2
5 32 2
6 24 2
7 12 2
8 51 3
9 42 3
10 1 3
11 1 3
12 0 3
13 0 3
14 1 4
15 1 4
.
.
.

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[Code]....

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