I have a function which returns a preformatted SQL but with duplicates as follows
FSI
..FSIL
..FSIL
....IS123
....IS123
....IS345
....IS345
....IS547
....IS547
..FSIR
..FSIR
....IS98777
....IS98777
....IS34567
....IS34567
....IS67799
....IS67799
I have to eliminate the above result set without changing the order. a distinct on the function returns a jumbled result set.
i have a table with a clob column and i have 150 records i want retrieve distinct values from the clob using distinct operator on clob will not work
View 1 Replies View RelatedI need to take the distinct values from VARRAY.. I have wrote following simple example. But it does not work. how to get the distinct value from VARRAY.
declare
type t is varray(10) of varchar2(10);
t1 t;
type r is table of varchar2(10) index by binary_integer;
r1 r;
begin
t1 := t('A','B','A','B','A','B','C');
select distinct * into r1 from table(select * from t1);
END;
i need a Select * from tablename just 1 Row for each distinct ActionMode column value
CREATE TABLE INSTRUCTIONAUDITLOGSS
(
TNUM NUMBER(10) PK NOT NULL,
BATCHTNUM NUMBER(10),
ENTRYTYPE VARCHAR2(8 BYTE),
USERGROUP VARCHAR2(8 BYTE),
USERID VARCHAR2(8 BYTE),
PRODUCT VARCHAR2(8 BYTE),
[code]...
I have following query which gives currency code from two different tables. I would like to get the distinct count of currency codes from these two different columns.
SELECT eb.person_seq_id, eb.bonus_amount, eb.currency_cd, ed.currency_cd_host
FROM fr_emp_bonuses eb, fr_emp_details ed, fr_periods p
WHERE eb.person_seq_id = ed.person_seq_id AND ed.period_seq_id = eb.period_seq_id
AND ed.period_seq_id = p.period_seq_id AND p.period_status = 'CURRENT'
AND eb.bonus_amount >= 0 AND eb.person_seq_id = 3525125;
This query gives following result
3525125240000USDINR
35251250 USDINR
352512560000 USDINR
352512550000 USDINR
There are two distinct currency codes (USD, INR) and total amount is 350000. So I am looking for a query to give me the following result
3525125350000 2
i have a query in this way
select field1,field2,field3 from Table1
union
select field1,field2,field3 from table2
In the query from table2 i am getting duplicate rows, HOW can i retrieve only distinct rows...Using distinct keyword did not work...if i have to post create and insert statements for this one...
I have a table with two columns, like:
123 xxx
456 xxx
789 yyy
987 yyy
And in the output I would like to have:
123 xxx
789 yyy
I tried with distinct and unique on the second column, but it doesn't work.
I need to select multiple columns but only have 2 of them which are distinct. For instance if i have
userid lastname firstname city country time
1 jones tom lon gb 2:25
2 wall paul la usa 2:30
1 jones tom lon gb 2:50
3 smith jane ny usa 2:55
what i would want to do is select all the columns but avoid duplicate lastname-firstname combination rows. The problem is if i use a group by i have to include all the columns and because time is different i will get tom jones twice. a way of getting round this so i can select all the columns but only 1 row of tom jones.
Category Table
Name Null? Type
------------------------- -------- --------------
CAT_ID NOT NULL NUMBER
CAT_NAME VARCHAR2(20)
Qusestion Table
Name Null? Type
--------------------------- -------- -------
QUS_PK NOT NULL NUMBER
CREATED_DATE DATE
VIEW_COUNT NUMBER
CAT_ID NUMBER
select category.cat_id , qus_pk , cat_name , created_date , view_count
from category , qusestion
where category.cat_id = qusestion.cat_id
order by view_count desc
How can I retrieve distinct cat_id here?
I have got the following error while executing below Query.
ORA-01791 'Not a SELECTed expression'
select distinct sgbstdn_levl_code
from sgbstdn,spriden
where spriden_pidm = sgbstdn_pidm
and spriden_id = '200076543'
order by sgbstdn_term_code_eff desc;
The above Query is not working with Distinct & Order By clause are present and by joining two tables. I need the distinct values of levels in Descending order of Terms.
The table creation and Data insertion script is attached with the message.Basically I want to sort all the data based on the order by clause and then remove duplicates from the TSKID column and get distinct TSKIDs in the same order.I have below query to sort data:
SELECT *
FROM piwingetworkitems_vd
ORDER BY profilepriority,
authdptpriority,
returnpriority ASC,
priority DESC,
effdate,
tskid
But when I add a DISTINCT to the query, it does some kind of random sort and doesn't return the data as per above ORDER BY query and ignoring the SORT order.
SELECT DISTINCT tskid
FROM (SELECT *
FROM piwingetworkitems_vd
ORDER BY profilepriority,
authdptpriority,
returnpriority ASC,
priority DESC,
effdate,
tskid)
Is there any way to select the DISTINCT taskids ordered as per requirements?
how can I distinct this query to get just one entry for one day.
this query:
select to_date(to_char(TIMESTAMP, 'YYYY-MON-DD HH24.MI.SS'), 'YYYY-MON-DD HH24.MI.SS') datum from event_table where id=15 ORDER by timestamp
returns:
Datum
01-MAY-09
01-MAY-09
01-MAY-09
..
..
..
02-MAY-09
02-MAY-09
.
.
but i want to have:
Datum
01-MAY-09
02-MAY-09
03-MAY-09
.
.
select * from a (6 column)
where wallet='01710000273'
select * from b (2 column)
where wallet='01710000273'
when I union these two tables it find two row for similar wallet, but i want to show these in one row. How will possible this?
Following on from this answered thread: (xmlagg(xmlelement) - Distinct Values Required..Whereby the last poster recommended the use of
RTRIM (
XMLAGG (
XMLELEMENT (
E,
XMLATTRIBUTES (segment1|| ',' AS "Seg")
)
ORDER BY segment1 ASC
).EXTRACT ('./E[not(@Seg = preceding-sibling::E/@Seg)]/@Seg'),
','
)
To get a distinct list of elements. Works great, but I actually need to use the concept of "distinct immediately preceding".
Sample data:
create table xml_test
(emp_number number, seq number)
insert into xml_test values ('12345',1);
insert into xml_test values ('23456',2);
insert into xml_test values ('44323',3);
insert into xml_test values ('12345',4);
[code]....
I've read so many different pages on this topic but I can't seem to get my query the way it needs to be. Here's the query:
select admitnbr, lastname||', '||firstname||' '||finitial, hphone, mobile, wphone, med_rec, dob
from patients join schedule using (key_patien)
join adtmirro using (key_patien)
where appt_state = 'ON HOLD'
Because patients in my database can have multiple appointments "on hold" there are duplicates in the results. I only need 1 record per patient in order to forward this information into an automated dialer to contact that patient. I do NOT want to call the patient over and over again. Once will suffice. I'm trying to make a distinction on the column 'med_rec'. One row per 'med_rec' will be awesome but I can't find a way to create a distinct on that column.
how to count different characters from a string ....
View 7 Replies View RelatedI had to create a new column in a particular table now i want to insert the values in that column though the other columns are already populated I entered the command (insert into Product(STANDARD_PRICE) values(895.99) when i hit return it says cannot enter null value into (SYSTEM .PRODUCT. PRODUCT_ID) product_id is the PK which is the first column STANDARD_PRICE is the last column in my table...how do i enter the values into that column without receiving this error or having to effect the other columns?
View 3 Replies View RelatedI am little confused applying DISTINCT on a Multiple table Inner join.
Table: Role
=========================
role_id email
1 xxx@abc.com
2 yyy@abc.com
3 zzz@abc.com
Table: notification_role
===========================
id role_id process_id
1 1 p1
2 1 p2
3 1 p3
4 1 p1
5 2 p2
6 2 p2
7 2 p3
8 2 p3
9 3 p4
Table: process
================
process_id proces_name
p1 process1
p2 process2
p3 process3
p4 process4
Expected Result
====================
role.role_id role_email process_process_id process_name
1 xxx@abc.com p1 process1
1 xxx@abc.com p2 process2
1 xxx@abc.com p3 process3
2 yyy@abc.com p2 process2
2 yyy@abc.com p3 process3
3 zzz@abc.com p4 process4
QUERY::
select distinct c.process_id a.role_id,a.email_address,c.process_name
from role a, notification_role b, process c
where a.role_id=b.role_id and b.process_id = c.process_id
I have a collection of objects built in a PL/SQL program.
I want to keep only the distinct elements of this collection for the rest of the program.
I failed to find the correct way to do it
For instance (the actual object is far more complex containing object attributes itself), with the following types:
drop type t1b
/
drop type t1a
/
create or replace type t1a as object (
v1 integer,
v2 integer
)
/
create or replace type t1b as table of t1a
/
I have the following variable:
v t1b := t1b(t1a(1,2),t1a(1,2));
And I want to get only one "t1a(1,2)" in my collection.
My first idea (actually the second one but it does not matter) was to use DISTINCT:
SQL> declare
2 v t1b := t1b(t1a(1,2),t1a(1,2));
3 begin
4 select distinct t1a(v1,v2) bulk collect into v from table(v);
5 dbms_output.put_line(v.count);
6 end;
7 /
declare
*
ERROR at line 1:
ORA-22950: cannot ORDER objects without MAP or ORDER method ORA-06512: at line 4
As I said the object is far more complex and builting a MAP function is quite tedious (but I will do it if there is no other way).
The next idea was to use multiset operators:
SQL> declare
2 v t1b := t1b(t1a(1,2),t1a(1,2));
3 begin
4 select v multiset intersect distinct v into v from dual;
5 dbms_output.put_line(v.count);
6 end;
7 /
1
PL/SQL procedure successfully completed.
This works well but I suspect this is not the correct way and there is one to do it in PL/SQL but currently failed to find it.
Is there a way to export records based on a select distinct into different xls or csv files in oracle? I could be using SQL Developer.
The following will generate 74 unique values which each contain approx 3000 records.
select distinct(telespornr from vingelen2012
I think this is easier than I think but all I want to do is count the distinct rows in a table.
WITH data AS
(SELECT 1 id1, 1 id2, 111 val1
FROM dual
UNION ALL
SELECT 1, 2, 222
FROM dual
UNION ALL
[Code]..
seems to get what I want
ID1VAL1CNT1
111114
212224
321114
422224
but can the count be done in a stand alone query such as??
SELECT DISTINCT id1,
val1,
COUNT(*) over() cnt1,
COUNT(*) over(PARTITION BY id1) cnt2
FROM data
ORDER BY id1, val1
NOT what I want
ID1VAL1CNT1CNT2
1111152
2122252
3211153
4222253
I have 2 tables which contain 1000's of cash and stock transactions and I need to somehow get a list of the distinct clients
select distinct client_id
from pf_cash_txns pct, pf_stock_txns pst
Quote:ORA-00918: column ambiguously defined
can we use distinct keyword with the count and sum analytical functions?
View 5 Replies View RelatedI am trying to work with query to get distinct unique records, following is my scenerio:
DocNo |Title| Revs|UpdateTime|OBID
DOC-101|DESCRIPTION1|1|2/28/2004 11:37|6108-9
DOC-101|DESCRIPTION1|1|2/28/2004 11:36|6106-13
DOC-201|DESCRIPTION2|0|4/24/2005 16:44|7899-1
[code]...
From the above duplicates I would like to get only 1 distinct record based on latest update time (when using distinct on a sub-query since OBID is unique again returning all recds)
I am expecting results like:
DocNo|Title| Revs|UpdateTime|OBID
DOC-101|DESCRIPTION1|1|2/28/2004 11:37|6108-9
DOC-201|DESCRIPTION2|0|4/24/2005 16:47|7900-1
DOC-301|DESCRIPTION3|3|2/21/2007 7:26|6869-4
DOC-304|DESCRIPTION4|3|8/22/2007 9:31| 39208-1
I have a table with 4 columns. The data is stored in an hierarchical format where L1 being the parent and L4 being the lowest child.
L1 L2 L3 L4
1 11 111 1111
2 21 211 2111
2 22 222 2222
[code]...
So each Level(L1 ..L4) has zero or many child levels which further has more levels.With out using PL/SQL how can we write a Select query to give me a distinct of all children, all the way to the lowest level (L4).Example: give me all the children where L1 = 3.Result: 31, 32, 33, 311, 322, 333, 3111, 3222, 3333Is it possible to write such a query or am I asking too much logic out of a select and should go with PL/SQL.
CREATE TABLE TEST_TAB
(
A NUMBER(5),
B VARCHAR2(20)
) ;
INSERT INTO TEST_TAB VALUES ( 1, 'Manoj' ) ;
INSERT INTO TEST_TAB VALUES ( 1, 'Arun' ) ;
INSERT INTO TEST_TAB VALUES ( 1, 'Varun' ) ;
INSERT INTO TEST_TAB VALUES ( 1, 'Suresh' ) ;
[code].....
Query Output :
1Arun,Arun,Manoj,Manoj,Manoj,Suresh,Varun
2Kamlesh,Manoj,Manoj,Manoj,Suresh,Suresh
Expected Output :
1Arun,Manoj,Suresh,Varun
2Kamlesh,Manoj,Suresh
Expectation here is duplicate values should not be repeated.
I have the below SQL code -
SELECT DISTINCT
opr, CAST (distinctcount AS REAL) * 0.02 AS total, distinctcount
FROM ( SELECT DISTINCT opr, COUNT (*) AS distinctcount
FROM out
WHERE code = '22'
AND timestamp LIKE '201303%'
GROUP BY opr)
I would like this value 'distinctcount' to be multiplied with different amount for period January till June and from June to December. For instance for period (January till June) to be multiplied with 0.02, for period (June to December) to be multiplied with 0.03.
SELECT DISTINCT a.emp_id, a.cal_id, TO_CHAR(a.ts_date, 'DD/MM/YYYY') tsdate, a.ts_date, 1 as days
FROM tmsh_timesheet a
INNER JOIN project b ON TO_CHAR(b.proj_id) = a.proj_id
INNER JOIN tmsh_ts_calendar c ON c.cal_id = a.cal_id
INNER JOIN (SELECT a.cal_id, a.emp_id, MAX(a.status) as status, a.create_dt, a.create_by FROM tmsh_stat_hist a
[Code]...
this query results
EMP_IDCAL_IDTSDATE
048283404/10/2010
048283502/11/2010
048283503/11/2010
048283504/11/2010
048283508/11/2010
i need the ts date to be in like this
04/10/2010
02/11/2010 - 04/11/2010
08/11/2010
Oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - 64bit Production
PL/SQL Release 11.1.0.6.0 - Production
"CORE 11.1.0.6.0 Production"
I have a cursor, whose sql is returning seven rows with these values:
9
4
4
9
7
9
4
i open cursor and fetch these values into variable as shown
OPEN id_search FOR l_sql_stmt;
LOOP
FETCH id_search INTO l_eve_id;
if l_eve_id != l_eve_id_prev then
l_eve_id_str := l_eve_id_str || ' , ' ||l_eve_id ;
[code].......
but i want only the distinct values in l_eve_id_str , i.e.,
l_eve_id_str := 9,4,7
What this code is doing is creating a string with all the values
l_eve_id_str := 9,4,4,9,7,9,4
How to remove duplicates from this string?
the below is the csv file data. 1st value is for transaction id, 2nd one is for order id and 3 rd one is category_id
"1","45678","a"
"2","45478","b"
"2","45278","b"
"3","45678","d"
"4","45278","e"
I am reading the above file and need to return the total no. of distinct transaction id from the file . How can i acheive this? In the above case distinct transaction id count is 4
