ASM Kernel Mismatch?
May 5, 2011
I believe I have a problem with the ASM Kernel rpm that I downloaded from Oracle OTN
my Linux OS is
[root@UKEDXDTMTDBS01A u01]# uname -r
2.6.18-194.el5
So I downloaded the x3 ASM files required
[root@UKEDXDTMTDBS01A u01]# ls -ltr *.rpm
-rw-r--r-- 1 oracle oinstall 90858 Apr 12 14:18 oracleasm-support-2.1.4-1.el5.x86_64.rpm
-rw-r--r-- 1 oracle oinstall 14176 May 5 10:10 oracleasmlib-2.0.4-1.el5.x86_64.rpm
-rw-r--r-- 1 oracle oinstall 137486 May 5 10:29 oracleasm-2.6.18-194.el5-2.0.5-1.el5.x86_64.rpm
As you can see the install worked fine
rpm -Uvh oracleasm*.rpm
warning: oracleasm-2.6.18-194.el5-2.0.5-1.el5.x86_64.rpm: Header V3 DSA signature: NOKEY, key ID 1e5e0159
warning: oracleasm-support-2.1.4-1.el5.x86_64.rpm: Header V3 DSA signature: NOKEY, key ID b38a8516
Preparing... ########################################### [100%]
[code]...
So therefore it does not show any disks
[root@UKEDXDTMTDBS01A u01]# /usr/sbin/oracleasm listdisks
[root@UKEDXDTMTDBS01A u01]#
Am I doing something wrong -
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Aug 26, 2011
what is the purpose of kernel parameter while creating database.
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Feb 9, 2013
*10g Oracle installation on OEL*
How Kernel Parameters values calculated in 10g
kernel.shmall = 2097152
kernel.shmmax = 2147483648
kernel.shmmni = 4096
+# semaphores: semmsl, semmns, semopm, semmni+
kernel.sem = 250 32000 100 128
[code].......
Run the following command to change the current kernel parameters
/sbin/sysctl -p
** "/etc/security/limits.conf" **
* soft nproc 2047
* hard nproc 16384
* soft nofile 1024
* hard nofile 65536
My question I think 32 bit or 64 bit OS calculation will be same only. I want know how it was calculated ?
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I have taken the export backup of a table using the following command
userid=system/manager@DBATEST
file=abc.dmp
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feedback=100000
buffer=10000000
[code]......
but on querying the table it shows the number of rows as
select count(*) from X.S_ORG_EXT_X;
COUNT(*)
----------
25656051
Explain why there is a mismatch in the count of the rows in the table.
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We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
CODEemp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
Primary key - emp_id, effective_date..This table is yearly partitioned...I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
CODEWITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]....
For emp_id 1, if we ran this query for 10/31/2011, then it has to compare the 10/31 salary with 10/29 and do the same until the salary mismatches. In this case, salary salary mismatch occurs on 10/20, so the stale salary period is from 10/31 to 10/21 which is 7 days.Below query will give that result:
CODE
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
[code]...
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I've 2 identical tables of 300+ columns each,and each of table is having pk as combination of 2 fields.There are some fields where data is not matching. need a query which will use these two tables and return the following-
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[URL].........
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Also, we had some other observation. It only happens in its 2nd execution and not its first run. Hope there might be some cache problem
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I have created a type of type OBJECT:
CREATE OR REPLACE
TYPE MF_RECORD_TYPE IS OBJECT
(name VARCHAR2(6),
.
.
.
CREATE OR REPLACE
TYPE MF_TABLE_TYPE IS TABLE OF mf_record_type;
Then in my stored procedure:
v_mf_record MF_TABLE_TYPE := MF_TABLE_TYPE();
.
.
OPEN mf_detail;
FETCH mf_detail BULK COLLECT INTO v_mf_record;
CLOSE mf_detail;
[code]....
I am getting the error: PLS-00386: type mismatch found at 'V_MF_RECORD' between FETCH cursor and INTO variables.
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We have employee salary table which will have salary of an employee on daily basis (only working days). Below is the table structure:
emp_salary
----------
emp_id NUMBER(15) NOT NULL
effective_date DATE NOT NULL
salary NUMBER(15) NOT NULL
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This table is yearly partitioned
I have to find out how long the salary is not changed for an employee from given date, and last salary. I am using below query to do this:
WITH salary_tab AS
(SELECT effective_date, salary,
(CASE
WHEN (LAG (salary) OVER (PARTITION BY emp_id ORDER BY effective_date ASC) =
salary
)
THEN 0
ELSE 1
END
) changed_ind
FROM emp_salary
WHERE emp_id = 12345
[code]....
The cost of this query is 1677 and it is taking around 60 msec to complete. When I run this query for around 2000 employees in a loop it is taking around 3 minutes to complete.
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