"ALTER PROFILE profile_name LIMITPASSWORD_LOCK_TIME 1"means the user account will be locked in a period of one day after FAILED_LOGIN_ATTEMPTS has gone over limit.How to set PASSWORD_LOCK_TIME less or more than one day (like not full days)?
View 2 RepliesHow we know a user account locked time in HH:MM:SS format ?
View 1 Replies View Relatedwe have a prod application which use oracle database 11g as backend and .NET technology as front end . There is a user TESTUSER in database.
Issue is that we can login in to the application, but when we try to login in database through toad or Db visualizer then it gives an error of 'user account locked'.
In event of sys account locked and system account is already deleted also no other user is having dba privilege, how to unlock the sys user??
View 5 Replies View RelatedMy Oracle 10G Expression Edition Account locked gets locked, where to raise the request to unlocking my account.as my user name:system
View 4 Replies View RelatedI am getting Oracle odbc ora-28000 account locked error
View 1 Replies View RelatedI am trying to login to the web version of application express [URL]... and get a message that my login is incorrect. I have verified that the ID and workspace are correct, but I do not remember what i set my password to the first time i logged in (account was created by my instructor). There is no "forgot password" or "reset password" link that shows on the page.
View 0 Replies View RelatedWe have the database user called c88888 and is locked yesterday. I came to this with the following query.
select * from dba_users where username like 'C88888';
Due to invalid password the user was locked. Can we track who hit the database with the wrong password?
If the user has locked some row in the database how to find out the row id or the row which is locked by that particular USER.
View 2 Replies View RelatedAn Oracle user account got locked, how do I check, which program or session was the cause for it? how to fetch this details along with details like timestamp, ip address, program name.
Wanted to know for Oracle 11 version running on Solaris machine.
Created user xyz on July 20,2013 with defualt profile (oracle version 11.2.0) and PASSWORD_LIFE_TIME is 180 for default profile. Immediate my friend have assigned new profile APSC to user xyz where profile APSC has PASSWORD_LIFE_TIME = UNLIMITED.
we surprised, user account has expired within a month. How user xyz account can expired within a month????
Note: User account status was open when account created and assigned to profile APSC.
I have altered an user account and set the account status as expired.When I tried to connect with that user, oracle prompted for changing password.
But, after I changed the password, I got an error message as ora-01017 invalid username/password logon denied password unchangedWhat is the cause and solution for it? I am using 11g database and 10g client.
how to find length of the user account password in a database?
View 1 Replies View RelatedWhen i try to change the user account password, i get following error.
alter user bala
identified by Ju4hlsd2;
ERROR at line 1:
ORA-20178: ORA-20176: ORA-28003: password verification for the specified password failed
ORA-20007: Password cannot consist of sequences of 3+ characters from the userid
how to set the password based on the error.
How to find out list of DB_LINKS that uses user account in database ?
View 9 Replies View RelatedFor auditing, I need to insert the user, among other data, into different tables. The thing is, I have an application with DB account authentication, so a real database user is connected, when auditing, the user field inserted is "ANONYMOUS".
Apex 4.2
EPG
Oracle Enterprise Linux 5.5
Database 11.2 EE
Following is the scenario:
CREATE TABLE EMP_VACATION(
EMP_NO NUMBER(3),
VAC_TYPE NUMBER(1),
START_DATE DATE,
END_DATE DATE,
START_PERIOD_DATE DATE,
END_PERIOD_DATE DATE,
PRIMARY KEY (EMP_NO,VAC_TYPE,START_DATE))
[code]....
--How to calculate START_PERIOD_DATE and END_PERIOD_DATE for every time insert reocrd, like for 4 cases?
--I need to check start_date with last period date for same employee.
And based upon calculate START_PERIOD_DATE and END_PERIOD_DATE,,,,,
I'm trying to write a cross tab query but which groups by periods.
Test Case: -
CREATE TABLE COMPANIES
(
"ID" NUMBER(9,0),
"CODE" NUMBER(8,0),
"DESCRIPTION" VARCHAR2(40 CHAR),
CONSTRAINT "PK_COMPANIES" PRIMARY KEY ("ID")
);
[Code]..
The cross tab is to have columns 1 - 31 which sum the quantity of the article sold. Represnting days of the month.
In addition the description of the company.
I would then like to end up with 3 entries in the results for each company, but these are for summing the quantity of articles by the following periods: -
Breakfast: 01:00 - 10:00
Lunch: 11:00 - 14:00
Dinner: 17:00 - 22:30
I hope that makes sense?
i want to find the data which has the more then one rates available for the given date. Here below i've posted a test table. how can find the products for which, there multiple dates/overlapping period is available through sql statement.
SQL> CREATE TABLE STO.TEMP
2 (
3 ID NUMBER(8),
4 ITEM_ID NUMBER(8),
5 RATE NUMBER(5,2),
6 FROMDATE DATE,
7 TODATE DATE
8 );
[code]....
CREATE TABLE CONTRACT
(
EQT VARCHAR2(10 BYTE),
SUBTYP VARCHAR2(3 BYTE),
FROM_DT DATE,
TO_DT DATE
);
[Code]....
The data in contract and lease table show like below.
contract
EQT SUBTYPFROM TO
ABCD100000DRY1/1/20121/7/2012
ABCD100000DCH1/7/20121/21/2012
ABCD100000GAZ1/21/2012
lease
EQT CONTRACTFROM TO
ABCD100000LS11/2/20121/10/2012
ABCD100000LS21/10/20121/17/2012
ABCD100000LS31/17/2012
Now required output should be
EQT SUBTYP CONTRACTFROM TO
ABCD100000DRY 1/1/20121/2/2012
ABCD100000DRYLS11/2/20121/7/2012
ABCD100000DCHLS11/7/20121/10/2012
ABCD100000DCHLS21/10/20121/17/2012
ABCD100000DCHLS31/17/20121/21/2012
ABCD100000GAZLS31/21/2012
The period for contracts should be in sequential order and should not overlap and if contract does not exist for that date period, then it should return NULL.
I need to divide the given time period into weeks from Monday to Sunday .There should not be overlapping of two months, for a week.Every month should start from First day of that month to next Sunday .Same thing can be done by following PL/SQL block . let me know if there is any simple way by using query instead of block .
declare
pid_from_date date := '01-JAN-11';
pid_to_date date := '31-dec-11';
ln_number number := 0;
ld_from_date date;
ld_to_date date;
begin
[Code]....
I need to get the number of rows based on one condition for certain time period. For example, writing a query for 3(any) hrs , i need to get the output as count of rows as hourly basis. Like these:
Date Time Count
12/08/2010 16:00 234
12/08/2010 17:00 345
12/08/2010 18:00 645
I have TableA which has data like below.
ID NAME CRT_DTE
1 AB 03/05/1992
2 EF 15/04/1995
3 CD 20/08/1995
4 GH 01/01/1999
5 UV 08/07/2001
[code]....
I want a query which splits the total time period (from min crt_dte to max crt_dte) into year ranges.For eg, lets say a range of 5 years then I need to get results like below.
start_dte end_dte
---------- ----------
03/05/1992 03/05/1997
03/05/1997 03/05/2002
03/05/2002 03/05/2007
03/05/2007 09/03/2012
how to write this query.
In my production environment, I have a mostly working Oracle 12c Cloud Control environment, managing several database instances. On all of the databases, I am unable to use the Compare period ADDM feature ( Instance > Performance > AWR > Compare Period ADDM).
When I select that menu option, I see the message "To be able to use this feature some PL/SQL packages need to be loaded into the target database's monitoring schema, DBSNMP." I have been searching for further information in the specific packages that need to be loaded per the message, but neither Orafaq, [URL] nor Google seem to have those details.
I am trying to break down a row of data that has nine periods that I want to enter into a table one period at a time. I am trying to use "IF EXISTS ( SELECT * FROM TABLENAME WHERE FIELD1 IS NOT NULL) THEN" through all nine fields. It keeps returning lines that have a null column as well as not null columns. if there is a better way of doing this. Here is an example of what I am trying to do:
IF EXISTS (SELECT * FROM TABLE_NAME WHERE LAST_DT9 IS NOT NULL) THEN
SELECT NUMBER, 1COL9, 2COL9, 3COL9, FIRST_DT9, LAST_DT9, 4COL9
FROM TABLE_NAME;
ELSE IF EXISTS (SELECT * FROM TABLE_NAME WHERE LAST_DT8 IS NOT NULL) THEN
[code]...
i want to select columns of 3 tables in such a way that period column should be in the group by function.
create view allocated_budgets_detail as
select ba.ba_fin_year, ba.ba_start_date, ba.ba_end_date, ba.ba_rev_no,
bh.bh_budget_code,
bd.bd_period,
bb.bb_entered_amount
from budget_header bh, budget_allocation ba, budget_distribution bd, budget_balance bb
where bh.bh_budget_id = ba.ba_budget_id
and ba.ba_line_id = bd.bd_budget_line_id
and ba.ba_line_id = bb.bb_budget_line_id
group by bd.bd_period
session from user U1
C:Documents and Settingsuser>sqlplus u1/u123456@orcl
SQL*Plus: Release 10.2.0.1.0 - Production on Pn Wrz 12 12:56:14 2011
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Po│╣czono z:
Oracle9i Enterprise Edition Release 9.2.0.7.0 - Production
With the Partitioning, OLAP and Oracle Data Mining options
JServer Release 9.2.0.7.0 - Production
SQL> update u1.tab1 set u1.tab1.col1=3 where u1.tab1.col1=1;
1 wiersz zosta│ zmodyfikowany.
SQL>
and now i can check which table is locked
SQL> SELECT lo.session_id, lo.OBJECT_ID, obj.object_name FROM v$locked_object lo
2 INNER JOIN Dba_Objects obj ON obj.object_id = lo.OBJECT_ID;
SESSION_ID OBJECT_ID OBJECT_NAME
---------- ---------- --------------------------------------------------
34 13197 TAB1
but the question is why can i check row id of locked row?
Is it possible to find the locked objects in hierarchical order. Consider the below example
--Connect to scott schema
create table block_session(a NUMBER, b VARCHAR2(100))
/
insert into block_session select rownum,rownum*10 from dual connect by level<=10
/
COMMIT
/
GRANT ALL ON block_session to HR
/
update scott.block_session
SET a=10
where b=10
[code]......
Is it possible to get all locked table details in hierarchical order?
db 10.2.0.4
select * from DBA_2PC_PENDING shows pending transactions in prepared state.
How can I know the resources (e.g. tables) locked by these transactions?
Need to find out what the maximum number of concurrent logins are over a period of 1 month. We need to do this as we may need to buy more licences.
View 4 Replies View Related