Server Administration :: Default Partition In Table?
Oct 17, 2011How can i check whether a partition tbale have default partition?
View 9 RepliesHow can i check whether a partition tbale have default partition?
View 9 RepliesWhile trying partition exchange feature of Oracle with 2 hash partitioned tables, I come to know that I can't directly exchange partitions between 2 partitioned tables
I have two hash partitioned tables , so to move partition data from one table to another will include-
1) Exchange from partitioned table to non-partitioned table.
2) exchange from non-partitioned table to new partitioned table.
But I am not sure in which hash partition my data will go in new partitioned table (data need to be moved has single key value on basis of which tables are partitioned),
Any impact is there if is do the following:
ALTER TABLE MY_TABLE TRUNCATE PARTITION P1 UPDATE GLOBAL INDEXES;
will there be any lock on the table during this operation? DML operations will work without any issue or not?
The table tb_hxl_hash have two partitions,when i exchange the second partition,it raise error,why?
SQL> Alter Table tb_hxl_hash
2 Exchange Partition P_HS1 With Table tb_hxl_test;
Table altered.
SQL> Alter Table tb_hxl_hash
2 Exchange Partition P_HS2 With Table tb_hxl_test;
Exchange Partition P_HS2 With Table tb_hxl_test
*
ERROR at line 2:ORA-14099: all rows in table do not qualify for specified partition
splitting a table partition without making its primary key index ar any other indexes unusable.
I think it is possible to do so 10g onwards.
DB Details:
Oracle RDBMS 11.2.0.3, HP-Ux B.11.31, OLTP
As per the bellow the default XML storage has been changed in 11gr2.
docs.oracle.com/cd/E11882_01/appdev.112/e10492/whatsnew.htm
Quote:
Oracle Database 11g Release 2 (11.2.0.2) New Features in Oracle XML DB
The following Oracle XML DB features are new in Oracle Database 11g Release 2 (11.2.0.2).
Default Storage Model for XMLType
The default XMLType storage model is used if you do not specify a storage model when you create an XMLType table or column. Prior to Oracle Database 11g Release 2 (11.2.0.2), unstructured (CLOB) storage was used by default. The default storage model is now binary XML storage.
We have a application which works fine on r1 but not on r2 due to this change, we are going to investigate resolving the issue on the application in the future, in the mean time we need to be able to use the CLOB storage.
Does any one know where we can change this functionality back to the pre 11gR2 change?
how many default users available in oracle 9i version.
View 4 Replies View Related I create a range-list partition table using the subpartition template,and there is a default subpartition p_default,when i insert a row which provcode values is 6 into the table,and it belong to the default subpartition,how can i spilt it into a new subpartition such as p_6, and make the row belong to the subpartition p_6?
create table tb_hxl_user_split
(
statedate date not null,
provcode number not null,
usernumber varchar2(13) not null,
rem1 varchar2(1024),
create_date date,
create_by number,
last_update_date date,
last_update_by number
[code]....
I installed Oracle 11g and created a test database in that the default count should be 4196... but it is 4143.. some packages are missing.. even when i'm creating materialized view it is showing some error that packages are missing. what can i do for that? Is my oracle s/w corrupted ? even when i downloaded from oracle site it also shows the same count.
View 1 Replies View RelatedA question about the WMSYS user that comes with the default installation :
I've locked it because it has the DBA role. The question is :Will this impact the database?
What do you think of this 11.2 parameter? It can give some pretty weird results.
SQL> create tablespace ts1 datafile size 10m;
Tablespace created.
SQL> create table t1 (c1 date) tablespace ts1;
Table created.
SQL> drop tablespace ts1;
Tablespace dropped.
SQL> insert into t1 values(sysdate);
insert into t1 values(sysdate)
[code]...
It cannot use function in partition-key, right?
create table tb_hxl_user_rh
(
statedate number(8),
provcode number not null,
usernumber varchar2(13) not Null
)
partition by range (statedate)
(
partition HXL_USER_20110516 values less than
(to_number(to_char(TO_DATE('2011-05-17 00:00:00', 'YYYY-MM-DD HH24:MI:SS'),'YYYYMMDD')))
);
ORA-14019: partition bound element must be one of: string, datetime or interval literal, number, or MAXVALUE
i want to create tablespace in raw partion on windows.I have added a hard disk and added extended partition to it. Then created 4 logical partitions of 256 MB with diskpart.exe.I have assigned a drive letter to one of them as X:
However, I am having trouble in creating tablespace on it. I referred to [URL]... I get following error,
C:UsersAdministrator>sqlplus
SQL*Plus: Release 11.2.0.1.0 Production on Fri Aug 17 15:32:17 2012
Copyright (c) 1982, 2010, Oracle. All rights reserved.
Enter user-name: SYSTEM
Enter password:
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
With the Partitioning, OLAP, Data Mining and Real Application Testing opti
SQL> create tablespace exampletb datafile '\.X:accounting_1' size 100;
create tablespace exampletb datafile '\.X:accounting_1' size 100
ERROR at line 1:
ORA-03214: File Size specified is smaller than minimum required
SQL> create tablespace exampletb datafile '\.X:accounting_1' size 502;
create tablespace exampletb datafile '\.X:accounting_1' size 502
[code]...
I am using compress partition for a large table.During the process I have used the below command for compress---
1. ALTER TABLE <TABLE_NAME> MODIFY PARTITION P1 COMPRESS;
However I found there are different command as below:-
2. ALTER TABLE <TABLE_NAME> MOVE PARTITION P1 COMPRESS;
What is the basic difference between these two as the compression is happening for both command.
How to move a partition of a table to db_keep_cache ?
View 8 Replies View RelatedHow can i check a partition whether it has been compressed? just as flowing test,i can not get the information about partition P_L1 whether been compressed.
SQL> Select
2 aa.compression,
3 aa.partition_name
4 From dba_tab_partitions aa
5 Where aa.table_name = 'TB_HXL_LIST';
COMPRESS PARTITION_NAME
-------- ------------------------------
DISABLED P_L1
DISABLED P_L2
DISABLED P_L3
DISABLED P_L4
SQL> Alter Table tb_hxl_list compress;
Table altered.
SQL> Alter Table TB_HXL_LIST
2 Move Partition P_L1 compress;
Table altered.
SQL> Select
2 aa.compression,
3 aa.partition_name
4 From dba_tab_partitions aa
5 Where aa.table_name = 'TB_HXL_LIST';
COMPRESS PARTITION_NAME
-------- ------------------------------
ENABLED P_L1
ENABLED P_L2
ENABLED P_L3
ENABLED P_L4
I have a partitioned table - 128 partitions.
If I am not using data of many partitions in any way, will it affect my performance if I am firing select query that uses other/active partitions data.
How can I check when that partitioned was last accessed, also can I brought those inactive partitions offlie? If we can, what will be the advantages or disadvantages of that?
I am not able to exchange partition by following below steps:
drop table manu_tst_hashed_tbl_org;
drop table manu_tst_hashed_tbl_bkp;
drop table manu_tst_smpl_tbl;
CREATE TABLE manu_tst_hashed_tbl_org
[code]...
and getting the below erro:
ORA-14097: column type or size mismatch in ALTER TABLE EXCHANGE PARTITION
14097. 00000 - "column type or size mismatch in ALTER TABLE EXCHANGE PARTITION"
*Cause: The corresponding columns in the tables specified in the ALTER TABLE EXCHANGE PARTITION are of different type or size
*Action: Ensure that the two tables have the same number of columns with the same type and size.
I am using Oracle 10g enterprise edition .
Currently, Partition is enabled in my database.I want to disable it.
SQL> SELECT * FROM V$OPTION WHERE PARAMETER = 'Partitioning';
PARAMETER
----------------------------------------------------------------
VALUE
----------------------------------------------------------------
Partitioning
TRUE
the steps to disable the partition feature.
I have one user CD_APP. I have one partition table CD.T_FCDR_DT. User has got ALTER/INSERT/UPDATE/DELETE/SELECT privileges on the table..
Now when I try to drop a partition, I get error as below:
-------------------------------------
SQL> show user
USER is "CD_APP"
SQL> ALTER TABLE CD.T_FCDR_DT DROP PARTITION D01 UPDATE GLOBAL INDEXES;
ALTER TABLE CD.T_FCDR_DT DROP PARTITION D01 UPDATE GLOBAL INDEXES
*
ERROR at line 1:
ORA-01031: insufficient privileges
--------------------------------------
Do I have to grant some other privileges for this user.
I exchange a partition with into a normal table with UPDATE INDEXES,but i found the index of both table are marked UNUSABLE?
SQL> Create Table tb_hxl_list_part
2 (
3 statedate Number,
4 provcode Number
5 )
6 Partition By List(provcode)
7 (
8 Partition p_1 Values(1)
9 );
Table created.
SQL> Create Unique Index idx_tb_hxl_list_part On tb_hxl_list_part(provcode) Local;
Index created.
SQL> Insert Into tb_hxl_list_part Values(20111101,1);
1 row created.
SQL> commit;
Commit complete.
SQL> Select status From dba_ind_partitions aa
2 Where aa.index_name = 'IDX_TB_HXL_LIST_PART';
STATUS
--------
USABLE
SQL> Create Table tb_hxl_list_part_bak
2 (
3 statedate Number,
4 provcode Number
5 );
Table created.
SQL> Create Unique Index idx_hxl_list_part_bak On tb_hxl_list_part_bak(provcode);
Index created.
SQL> Select status From dba_indexes bb
2 Where bb.index_name = 'IDX_HXL_LIST_PART_BAK';
STATUS
--------
VALID
SQL> Alter Table tb_hxl_list_part
2 Exchange Partition p_1
3 With Table TB_HXL_LIST_PART_bak UPDATE Indexes;
Table altered.
SQL> Select status From dba_ind_partitions aa
2 Where aa.index_name = 'IDX_TB_HXL_LIST_PART';
STATUS
--------
UNUSABLE
SQL> Select status From dba_indexes bb
2 Where bb.index_name = 'IDX_HXL_LIST_PART_BAK';
STATUS
--------
UNUSABLE
Is there a script that it create partitions by auto? who can share it?
View 1 Replies View RelatedWe have a table which is already partitioned by list and now we would like to add a subpartition.
Create table Item_mst
(
ccn varchar2(10),
Flag varchar2(1),
Item varchar2(10),
status varchar2(1)
)
[Code]..
Now I could like to alter the above table for adding a new subpartition on each partition on status.
ALTER TABLE Item_mst
MODIFY PARTITION Item_mst_Test
ADD SUBPARTITION Item_mst_Test_A VALUES ('A');
Above alter gives ORA-14253: table is not partitioned by composite range method.
However dropping and recreating the table with subpartitions is working fine.
But Dropping and recreating the table in production is very cumbersome as it has huge data and many indices.
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
IMPORT PARTITION TABLE Through Data Pump.
I have a table with RANGE PARTITION. I wanted to import this into another server with the same partitions.
But when I imported the table, The table created with the Partition but the data is not inserted in partition wise.
But I could see the Entire table's ROW COUNT.
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies View RelatedCan I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....