i want to rename a table that has partitions.
alter table
testora.oldtablename
rename to
testora.newtablename;
ORA-14048: a partition maintenance operation may not be combined with other operations
DDL used to create a table that is partitioned by day, then rolled up to a month using the interval partitioning technique.
View 3 Replies View RelatedI was about to move some tables from one table space to another but it seems it is not possible to move partitioned tables between table spaces of different block sizes.
So far the only option I have is to export and then import back the data.
know if there is any way to move a partitioned table between table spaces of different block size?
While trying partition exchange feature of Oracle with 2 hash partitioned tables, I come to know that I can't directly exchange partitions between 2 partitioned tables
I have two hash partitioned tables , so to move partition data from one table to another will include-
1) Exchange from partitioned table to non-partitioned table.
2) exchange from non-partitioned table to new partitioned table.
But I am not sure in which hash partition my data will go in new partitioned table (data need to be moved has single key value on basis of which tables are partitioned),
that are my biggest tables
Users use front end (called ESS Console) and when they try to open one of those tables they wait very long (really bad performance). Sometimes the GUI even hanging without displaying results.
Does Partitioned Tables feature works for better performance?
I have a Datapump Export File which was created in Schema mode.
I have to import the tabelles in a new database where a have to use the REMAP SCHEMA Parameter.
Additionally I would like to add a prefix to tablenames.
For example:
original tablename: THE_TABLE
Name after import: IMP_THE_TABLE
Is there a way to add a prefix while using Datapump Import?
what is the best way to partitioned a non-partitioned table to partitioned table date wise? I have data from last four year?
View 4 Replies View Relatedi have two tablespaces dictionary managed (SYSTEM,APPLSYSX) i tried to change to locally cause it will cause problem in future when trying to run OATM migration.i did it successfully on APPLSYSX,when i did it on system upon oracle procedure.i have to change all tablespaces to read only when i did that with tablespace APPLSYSD(alter tablespace APPLSYSD read only) i received errors
SQL> alter tablespace APPLSYSD READ ONLY;
alter tablespace APPLSYSD READ ONLY
*
ERROR at line 1:
ORA-01230: cannot make read only - file 636 is offline
ORA-01111: name for data file 636 is unknown - rename to correct file
ORA-01110: data file 636: '/vol5u/oracle/prddb/9.2.0/dbs/MISSING00636'
i have not this file on the OS
I am trying to export a partition of a table and import it to another database. I get the below error when I try to import.
ORA-14400: inserted partition key does not map to any partition
If I export the table(for that particular partition) and import the table(after dropping the table) in destination, the partitions and sub partitions are created without any problem.
The table is Range Partitioned and Sub partitioned in List. So I had to perform the below operation if I want to retain other data in the Destination table.
1. Drop the existing partition
2. Create the partition and sub partition, same as source
3. Execute imp
In fact I had to perform step#2, as if I split the partition also, the sub partition gets replicated in the new partition, which again throws the same error. Is there better way of managing the partitions and subpartition in destination with exp/imp utility, so that I need not perform step#1 and step#2 manually.
RDBMS - 11.1.0.7, I it possible to convert indexes of a non-partitioned table to hash partitioned indexes by retaining table as non-partitioned?
If yes, is this what it is Creating a Hash-Partitioned Global Index - can be created for partitioned and non-partitioned tables?
how to rename table in oracle 8i ?
ALTER TABLE olname RENAME TO nwname;
Above command is not working.
i am not able to rename a column for original table, once i create a new one with Create table as select i can rename the new table column, but not the original one
SQL*Plus: Release 11.2.0.1.0 Production on Tue Feb 14 13:10:10 2012
Copyright (c) 1982, 2010, Oracle. All rights reserved.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
With the Partitioning, Real Application Clusters, OLAP, Data Mining
and Real Application Testing options
SQL> show user
USER is "WEBSYSTEMD6"
SQL> alter table cbe rename column tnum to tnum_old;
alter table cbe rename column tnum to tnum_old
*
ERROR at line 1:
ORA-00900: invalid SQL statement
SQL> create table cbe_test as select * from cbe;
Table created.
SQL> alter table cbe_test rename column tnum to tnum_old;
Table altered.
SQL>
In MS Windows, if I copy a file and paste it into the same folder, I get a copy with the text 'Copy of' in front of the file name. If I paste it again, I get another copy with a different version number.
E.g.
sqlnet.log
Copy of sqlnet.log
Copy (1) of sqlnet.log
Copy (2) of sqlnet.log
I was wondering if I could copy existing rows into a table and do the same thing?
So, for example if I had this table:
create table tst_srch (srch_is varchar(100), user_name varchar(100), srch_name varchar(100));
insert into tst_srch values (1,'USER1','SRCHA');
insert into tst_srch values (2,'USER1','SRCHB');
insert into tst_srch values (3,'USER1','SRCHC');
insert into tst_srch values (4,'USER1','SRCHD');
insert into tst_srch values (5,'USER2','SRCHC');
insert into tst_srch values (6,'USER2','SRCHD');
insert into tst_srch values (7,'USER2','SRCHD_1');
Could I write a procedure like copy_searches('USER1','USER2') that would copy all USER1's searches to USER2 - including renaming any duplicates.
So it would create these new rows:
8,USER2,SRCHA
9,USER2,SRCHB
10,USER2,SRCHC_1
11,USER2,SRCHD_2
I've looked at various insert statements, merge and match statements and exception handling in procedures .
How to know weather table is partitioned or not ? Is there any data dictionary view to know the information about the Partitioned type,keys on table ?
View 4 Replies View RelatedI have a table like this:
CREATE TABLE CARGA_P_RECARGA_NEW1
(
TELE_NUM VARCHAR2(10) NOT NULL,
FECHA DATE NOT NULL,
[Code].....
Then I tried to insert some rows in that table, every insert statement is like this:
INSERT INTO CARGA_P_RECARGA_NEW1
VALUES
('3134769595','20/01/2013 07:22:50','1107','CONFB_20121121_20121122175002 60000000000000000090.TXT',0,16,'8327--7991284',1);
Every insert I executed had the month 01 because I expected to query results only from partittion p_0113 but nevermind how query I execute, the result is always the same. I mean if I excute this statement:
SELECT * FROM CARGA_P_RECARGA_NEW1 P_0113;
I get the same result when I execute any other like this:
SELECT * FROM CARGA_P_RECARGA_NEW1 P_0213
What is the error here ?
We have a partitioned transaction table in our Datawarehouse environment which has the following partition strategy
SCHEME=DATE-HASH
GRAIN=DAILY
SUBGRAIN=NONE
HASH=8
FROM=31/12/2011
We recently had to delete data from the table. This was a simple delete statement with a where clause and without taking into consideration any partition/subpartition clauses. Post committing the delete we have a count mismatch problem with two queries in particular
select count(0) count_without_parallel FROM TRANSACTION_TABLE t;
--THIS RETRIEVES *15774811* ROWS
select /* parallel(t,default) */count(0) count_with_parallel FROM TRANSACTION_TABLE t+
--THIS RETRIEVES *15777617* ROWS WHICH IS THE ACTUAL EXPECTED COUNT.
I also ran the following just to summarize
select (select count_with_parallel from (
select /* parallel(t,default) */count(0) count_with_parallel FROM TRANSACTION_TABLE t))+
-
+(select count_without_parallel from (+
select count(0) count_without_parallel FROM TRANSACTION_TABLE t)) as false_difference
from dual;
The difference in *2806* rows as expected.To re-affirm my counts I ran
select /*+ parallel(t,default) */
'count_on_t',count(*) from TRANSACTION_TABLE t
group by 'count_on_t'
order by 1;
--THIS RETRIEVES *15777617* ROWS
Removing the parallel hint reverts back to the lesser count. Not sure what is wrong but something prevents the query from parsing the whole table and/or partitions and subpartitions.
I have partitioned the table based on field.But when I am selecting by Partition or by the field I am getting Explain plan as Table Access full.I am pasting the sql and Explain Plan here. The table has two partition by BOOKING_DT_WID. One less than 20100801 and other less than 99991231.
CODESELECT * FROM WC_BOOKING_SALESREP_F WHERE BOOKING_DT_WID >= 20100801;
SELECT * FROM WC_BOOKING_SALESREP_F PARTITION(SALESREP_LESS1_99991231);
Here is the Explain Plan for the same.
CODESELECT STATEMENT ALL_ROWSCost: 1,501 Bytes: 293,923,641 Cardinality: 809,707
4 PX COORDINATOR
[code]....
How do I know if the sql is doing partition prune.
A question regarding analyzing behavior of partition table on Oracle -
Is analyzing different sub partitions within a partition is same as analyzing that partition and what about vice-versa?
Attached File(s)
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I created table that is range partitioned:
CODEPARTITION t1p1 VALUES LESS THAN (TO_DATE('2011-11-01', 'YYYY-MM-DD'))
PARTITION t1p2 VALUES LESS THAN (TO_DATE('2011-11-02', 'YYYY-MM-DD'))
....
PARTITION t1p4 VALUES LESS THAN (MAXVALUE)
Every year partitions will be added for next 12 month. The table partition will be dropped every month (I have to have data from last six month so in July I could drop partition t1p1, in August - t1p2....). How many tablespaces should I create for this table and how place partitions in them to have data for last six month and use minimum space on disk?
I was thinking about one tablespace for whole table because space of each dropped partition will be reused, what do you think about that?
I got just confused while looking at the below two create table statements:
CREATE TABLE Test (
TestID integer not null,
Name varchar2(20) not null )
PARTITION BY LIST (TestID)
(
PARTITION testPart1 VALUES (1) TABLESPACE tbspc1,
PARTITION testPart2 VALUES (2) TABLESPACE tbspc2@RemoteServer);
and
CREATE TABLE Test (
TestID integer not null,
Name varchar2(20) not null )
tablespace tbspc1
PARTITION BY LIST (TestID)
(
PARTITION testPart1 VALUES (1) TABLESPACE tbspc1,
PARTITION testPart2 VALUES (2) TABLESPACE tbspc2@RemoteServer);
I have a partitioned table that is streamed to another database. I need to archive data on that table. That is I need to add a partition and remove a partition.
If I make those changes to the source table, will it stream over to the destination table?
If not, can I ...
pause streaming make changes to source table make same changes to destination table sreenable streaming. I know making data changes to the destination table can screw up streams but not sure if that holds for ddl.
I have a partitioned table (one partition per month). Every month there are added about 1GB data. What extent size should I set? 1GB will be ok?
What if data will be greater than 1GB, adding new 1GB extent takes probably a lot of time and clients may see delays while they're inserting in this time? (it's OLTP system)
When new extent is allocated? Exact in time of lacking space in existing extent or before? Partitions are dropped after one year so free space isn't a problem.
I want to add a partition into a ranged partioned table but I receive error:
ALTER TABLE t_log
ADD
PARTITION p897_fft
VALUES
LESS THAN (898);
ORA-14074: partition bound must collate higher than that of the last partition
i check the high value like this:
SELECT partition_name, high_value
FROM dba_tab_partitions
WHERE table_name = 'T_LOG'
AND table_owner = 'PLAT'
[code]........
now, what to do? i dont want to remove Partition P899_MCDW. How to Split?
Facts:
Oracle 10.1.0.5
AIX 5.3
My table, HMTX have 10 partitions each of one have 6 millions of rows (average). We have 7 partitioned LOCAL indexes in that table.
Every month we load data into a new partition (6 million of rows aprox) and drop the oldest partition in table HMTX.
In order to do that we have a script that contain the next statements:
drop of all indexes
drop index n1;
drop index n...;
drop index n7;
[Code]...
create indexes again with tha same storage and degree parameters
CREATE INDEX hmtx_TST_N1 ON hmtx (campo1, campo2, campo3 .... campo8)
TABLESPACE xxxx
PCTFREE 0
INITRANS 2
[Code]....
My problem is in rhe index creation section, despite use parallel with degree 8 and nologging the index was created in :
Elapsed: 02:43:50.85.
In past months that index was created in :
Elapsed: 01:43:36.94
Elapsed: 04:48:31.24
Elapsed: 00:57:16.28
there are another way in order speed the index creation ?? o another way to disable ths index ??
Im having table which is of 45M rows table [Not partitioned], Now I want to compress the old data other than last 3Months data, I should not go for partition compress. Rarely some select queries will be fired on that Old data. Now how can I compress that table without affecting the Indexes , Dependencies proc, pkgs, Functions.
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit ProductionPL/SQL Release 11.2.0.3.0 - Production"CORE 11.2.0.3.0 Production"
I have table with 4 partition by range partition. I am loading the table in bulk mode to latest partition. Before I load , I dropped the index and after Load I will be creating index. So when I am dropping index, it is dropping index from all the partitions and when creating the index, I am creating the index for all partitions. When I am creating index using local, it is telling you have to create local index for all partitions at the same time. because of that I have to drop and recreate all indexes again. Again I have to gather stats for whole table .
I was thinking we can build index for one partition and index should remain as is for old partitions If this is not the case, how do I plan my load for a partitioned table using bulk mode to latest partition.
I have normal tables with hugh Data and would like to increase the performace by following means:
1) Add a new column in each table. Say this column Name is IS_LIVE. This new column have only two value 1 ( LIVE ) OR 0 ( NOT LIVE ).
2) Change the normal tables to Partitioned table. There would be only two partitioned in all the table. The partitioned key column would be IS_LIVE and both partitioend recrods would be in two different tablespace.
3) Added a POLICY function to these partitioned table to Always add a Query Predicate of '1' to all queuries.
I am interested to know that what kind of Indexes ( Global Or local ) would be suitable for these kind of Design.Is there any use of having Local index on IS_LIVE.Please note that Primary Key doesnot have this new column in it.
I have to create primary key using local on a partitioned table.
Since the table is huge it has to be done parallel. Following stmt is giving error
alter table XYZ add CONSTRAINT PKN_XYZ PRIMARY KEY (ID,LogDtTm)
USING INDEX LOCAL parallel 25 INITRANS 5 TABLESPACE OLTP_IDX_TS ;
Is it possible for the DBMS_STATS "LIST STALE" command to show a stale partition but NOT have its table show as stale?
I had a scenario where the table itself AND 1 partition showed as stale. I ran a fnd_stats gather table stats just on that 1 partition. Once it was completed it showed the partition to no longer be stale. it also showed that the table was no longer stale. so I guess I do not need to run stats on the whole table as well?
so if this is the case, when would I need to run stats on the full partitioned table if running it on the partitions themselves removes the staleness of the table?
What is the fastest way to fetch DISTINCT values from partitioned table?
1) DISTINCT/UNIQUE
2) GROUP BY
3) PARTITION BY OVER()
4) MAX(ROWID)
Table Definition
CREATE TABLE STG_SOS_SALES_FACT_STUDY
(
CNTRY_KEY NUMBER,
STUDY_ID NUMBER,
PRD_KEY_YEAR NUMBER,
PRD_KEY_WEEK NUMBER,
DATE_FROM DATE,
[Code]...
-> PARTITION BY RANGE (PRD_KEY_YEAR, PRD_KEY_WEEK)
-> SUBPARTITION BY LIST (CNTRY_KEY)
** Local Partition Indexes
1) CN_SD_CTG_PRD_PRDC_IDX = STG_SOS_SALES_FACT_STUDY (PRD_KEY_YEAR, PRD_KEY_WEEK, CNTRY_KEY, STUDY_ID, CTG_ID, PRDC_KEY)
2) CN_SD_PRD_STR_CTG_IDX = STG_SOS_SALES_FACT_STUDY (PRD_KEY_YEAR, PRD_KEY_WEEK, CNTRY_KEY, STUDY_ID, STR_KEY)#Query:
SELECT DISTINCT PRD_KEY_WEEK, PRD_KEY_YEAR
[Code]...
** Explain Plan:
Plan
SELECT STATEMENT ALL_ROWSCost: 6,235 Bytes: 629 Cardinality: 37
8 HASH UNIQUE Cost: 6,235 Bytes: 629 Cardinality: 37
7 CONCATENATION
3 PARTITION RANGE ITERATOR Cost: 1,985 Bytes: 1,031,900 Cardinality: 60,700 Partition #: 3 Partitions accessed #194 - #207
[Code]...
Partition #: 7 Partitions determined by Key ValuesThe above query is taking around 6-7 minutes to fetch the data.