I want to convert numbers into hours and minutes.I have two numbers say like first number is 1234 and second number is 1235.4 now i want to find the different between these two numbers. so am subtracting number 2 - number 1
1235.4 - 1234 i will get 1.4 so the result of this 1.4 to be converted as hours and minutes like 1 hr and 40 minutes. How can i convert numbers in hrs and minutes.
I have two varchar variable which has value like this
v_outpunch1:='17:50:00'
and v_Shifttime:='18:00:00'
this both time i am subtracting here and storing in another varchar variable which is like this.
v_EarlyLeaverstimeformat := LPAD((extract(hour from TO_TIMESTAMP (v_ShiftTime,'HH24:mi:ss')) - extract(hour from TO_TIMESTAMP (v_OutPunch1,'HH24:mi:ss'))), 2, '0')||':'|| LPAD((extract(minute from TO_TIMESTAMP (v_ShiftTime,'HH24:mi:ss')) - extract(minute from TO_TIMESTAMP (v_OutPunch1,'HH24:mi:ss'))), 2, '0')||':'|| LPAD((extract(second from TO_TIMESTAMP (v_ShiftTime,'HH24:mi:ss')) - extract(second from TO_TIMESTAMP (v_OutPunch1,'HH24:mi:ss'))), 2, '0');
it's not subtracting value correctly.
I have a query to add two numbers and get results in hours:minutes format.Example I want to add 12.20 and 6.15 and get result in hours and minutes like 18.35 (hours & minutes).if minutes that is after precision exceed more than 60 it should treat as 1 hour.like i want to add
12.35 (number 1) before precision its hour and after its minutes
06.25 (number 2)
04.25 (number 3)
-----
23.25 (23 hours and 25 minutes)
-----
How to get Time Difference between two DateTime Columns in Oracle 10g ?
View 10 Replies View RelatedI need below proc like...
procedure p1
(
i_time_min number -- minutes to be substracted from timestamp
)
is
v_end_timeinstamp timestamp(6);
begin
[code]....
The problem with above procedure is passing parameter is in minutes and i need to substract the same from sys_extract_utc(current_timestamp) and store result in v_end_timeinstamp in timestamp format only... substracting directly will reduce the days and not the minutes.
I currently have a problem where I have two date fields with time stamps. The only bit i am currently interested in in these fields is the time factor. When i display them in their field they have a format of HH24:MI .
I have a start time and end time as well as a duration and duration type. What I am trying to do is the following: when the user inputs the start time, along with the duration say 1 for example and the duration type of say HRS for example I would like to have the end_datetime default to 1 HR from the current start time. This is the code I use on a when validate item trigger to acheive this:
case :blk.duration_type
when 'HRS' then
:blk.end_datetime := :blk.start_datetime + ((1/24)* :blk.duration);
when 'MINS' then
:blk.end_datetime := :blk.start_datetime + ((1/24/60)* :blk.duration);
However, every time it triggers the value put into end_datetime is 0:00 is it something to do with the datatypes im using .
I have a field " Tran_date " with datatype Date . It contains date as well as time . How can I get the time . I tried with it as below :
SELECT TO_CHAR(TRAN_DATE,'DD-MON-YYYY HH24:MI:SS') FROM ABC
WHERE COMP=1 AND
BRANCH=1 AND
LOC_CODE='12' AND
TRAN_DATE='12-JAN-2012' ;
VALUE IS COMING LIKE THIS :
12-JAN-2012 00:00:00
ALTHOUGH THERE IS TIME . Its not zero .
I want to find the hours and minutes between two char field data type.Example I have two char columns one is "start_time" and another one is "end_time".The start time and end time is the machine reading of CNC MACHINE in manufacturing.I want to develope the package to capture the actual machine running time.But I have the start and end time reading in character field.The machine reading format is hour:minutes:seconds only.It will looks like 1234:45:23(the machine ran 1234 hours and 45 minutes and 23 seconds).See the below table to understand my requirements.
start_time end_time result in hours & minutes
---------- -------- -------------------------
345 347 2 hrs
347 350 3 hrs
350 357.20 7 hrs and 20 minutes
If I subtract end_time - start_time I will get the result in char type only not in hours and minutes format.Another example
start_time end_time result in hours & minutes
---------- -------- -------------------------
357.21 360.40 3.19(If subtract end_time - start_time)
SELECT emp.emp_id, emp.ename, TRUNC (attendancedatetime),
TRUNC ( ( 86400
* (MAX (attendancedatetime) - MIN (attendancedatetime))
)
/ 60
)
- 60
[Code]...
Following is the out put:
EMP_IDENAME Date Min Hrs
10013Javed Iqbal09/20/2011 00:00:0036.007.00
10013Javed Iqbal09/21/2011 00:00:0027.007.00
10013Javed Iqbal09/22/2011 00:00:0049.007.00
10013Javed Iqbal09/23/2011 00:00:000.000.00
10013Javed Iqbal09/24/2011 00:00:000.000.00
i need the TOtal sum of Minutes and Hrs e.g 7+7+7=21 and also minutes but if minutes total increase from 60 minutes then it should add to hrs .how to get sum.
I am trying to covert a time shown as 001200 (12 hours) to 720 mins. I have tried the following but get errors when executing:
(MTTD)>=TO_DATE('000000','HH24:MI:SS').
I have also tried .
MTTD = to_date('000000','HH24:MI:SS') =trunc(sysdate,'MM')*24*60; and neither is working.
What am I doing incorrectly?
I want to convert below MS-SQL query in oracle 10g.
for eg:
Select numasdate,
Cast(numasdate / 60 as Varchar) + ' hours ' +
Cast(numasdate % 60 as Varchar) + ' minutes'
as [TotalHoursAndMinutes]
From
#SampleTable
Output:
9436 157 hours 16 minutes
537 8 hours 57 minutes
9323 155 hours 23 minutes
12525 208 hours 45 minutes
i want to convert minutes that is 90 want to convert it in hours and minute that format should come in 01:30 format.
can i get in this format?
Have 2 small tasks for regexp..where we need to extract numbers from the text & multiply & get the result.
Input field varchar2 : 5x a day x 10 days
Output : 5 * 10 = 50
Select regexp_replace('5x a day x 10 days', '[^[:digit:]]' from dual;
The code extracts numbers ..but doesn't multiply & give the result.Have one more scenario as well.
Input field varchar2 : take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days
Output : 2 * 800 * 4 * 6 * 10 = 384000
Select regexp_replace('take 2 tablets (800 mg) by oral route every 4 hours while awake for 10 days', '[^[:digit:]]' from dual;
For the above code, if it's hours ..we need to convert into day by multiplying with the required factor to make it a day.
I Want to make a query to select finished goods product in sales having product code greater than 280 but i have face a problem that order by is not working because products column have character code as well as number. how to sort that column.
View 2 Replies View RelatedI have a table test with column containing dates, characters and numbers. I have to extract the number part and the three characters before the number . My data looks like :
TEST
ID DATA
1 3/12/2007
2 0
3 3/8/2010 ABC 217
4 NONE
5 COLM XYZ 469 6/8/2011
6 LMN 209
My expected results should look like :
ID DATA
1
2
3 ABC 217
4
5 XYZ 469
6 LMN 209
I am trying to write a trigger to reduce 1 day from 4 date fields of a table (order)
table name = order
fields = date_1, date_2, date_11, date_12 and dest_id
for example: the trigger will verify if orders that are dropping is for a specific customer (dest_id). if yes, the trigger will subtract one day from these date fields (by updating them); if no, (the dest_id is not for this customer) the trigger will not update anything in the DB.
I want to substract two dates to get the age of a person. One of the date is sysdate and the other is date of birth. Assuming we remove the time part of the date.
View 16 Replies View RelatedHow to subtract Time_Out - Time_IN
SELECT EMP_CODE, TO_DATE(INTIME,'DD/MM/RR')IN_DATE,
MIN(TO_CHAR(INTIME,'HH24:MI')) TIME_IN,
MAX(TO_CHAR(OUTTIME,'HH24:MI')) TIME_OUT
--MAX(TO_CHAR(OUTTIME,'HH24:MI')) - MIN(TO_CHAR(INTIME,'HH24:MI'))
FROM HCM.einout
WHERE EMP_CODE ='470' AND INTIME >= '01-APR-12' AND INTIME <= '15-APR-12'
GROUP BY EMP_CODE, TO_DATE(INTIME,'DD/MM/RR')
ORDER BY 2 ASC
[code]....
Oracle version:
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
how to subract the timestamp values.
SELECT TO_TIMESTAMP ('10-Sep-02 14:10:10.123000', 'DD-Mon-RR HH24:MI:SS.FF') FROM DUAL;
This is my output.
TO_TIMESTAMP('10-SEP-0214:10:10.123000','DD-MON-RRHH24:MI:SS.FF')
---------------------------------------------------------------------------
10-SEP-02 02.10.10.123000000 PM
Now how to subtract the FF value in sysdate.(ex:10000 this is the input of FF value )
example output like: "18-APR-12 09.46.44.005196 AM"
New to using Oracle and SQL Developer. I am trying to subtract a maximum date from today and adding back 1 to get a field named daysSinceLastActivity....
Syntax I am trying is (date()-max(activity_date))+1 as daysSinceLastActivity
I keep getting a error message of missing expression. After googling, I am not finding anything. This should be a simple calculation.
i'm getting ORA-04091: error when using a trigger to subtract ncopies values of table (rental ; after i insert a NEW record in it ) from cno value of table (copies) to give me the remaining no of copies of a book .
my tables and code is as folllows:
1)COPIES;
CID CNO BOOK
----- ---------- --------------------
A1 5 BOOK1
B1 10 BOOK2
2)rental;
Name Null? Type
------------------------------- ---
RID NOT NULL VARCHAR2(5)
CID VARCHAR2(5)
NCOPIES NUMBER(2)
1 CREATE OR REPLACE TRIGGER NO_COPIES
2 AFTER INSERT ON RENTAL
3 FOR EACH ROW
4 DECLARE
5 K VARCHAR2(5);
[code]....
I am a novice in oracle
I have 2 columns in my table
->Col1 with experience in years entered as an integer
->Col2 with current date
I need to add another column as a date value adn for that i need to subtract Currentdate-Col1 when i tried currentdate-Col1 it just subtracted the days i need the formula to subtract years and give a date
I have worked in DB2 and all u need to do there was add the keyword years at the end but in oracle the same does not work
I want to write a function that gets:
1. event_date (dd/mm/yyyy)
2. event_start_time (??/??/???? HH24:MI)
3. event_end_time (??/??/???? HH24:MI)
I got a table called EVENTS that got 2 fields:
1. event_date (dd/mm/yyyy HH24:MI)
2. event_end_date (??/??/???? HH24:MI)
and want to check if there is an event in my EVENTS table that occurs in the same dd/mm/yyyy as the input, and can disturb the input event times. means:
input.event_start_time is between EVENTS.event_date
and EVENTS.event_end_date
and
input.event_end_time is between EVENTS.event_date
and EVENTS.event_end_date
but to compare only the hours here! (HH24:MI)
because the date (dd/mm/yyyy) is checked before..
I don't know how to cut only the hours out of the date and compare them, and don't know how to write the whole function.
i want one query which return minute between two times which is in this format: 12:00:00 and 06:00:00
so in this it should return 360 minutes.
I have a table which will the following type of data
"COL1""COL2"
1001"27-DEC-2010 02:00:00"
1002"27-DEC-2010 07:00:00"
1003"27-DEC-2010 09:00:00"
1004"27-DEC-2010 02:00:00"
1005"27-DEC-2010 12:00:00"
Here you can see that we have data for 27th Dec 2010 02,07,09 and 12 hours. I want a query which will show the full 24 hours data even if it doenst have any records. like the following,
COL1 COL2
0 2010122701
1001 2010122702
1004 2010122702
0 2010122703
0 2010122704
0 2010122705
0 2010122706
1002 2010122707
I have a field in Customers table called shipeddate....
I wnat to check the number of hours an item which has a shipeddate is in the store room to the current datetime...
But the business hrs of the store room are from 8am-5pm..
So when a shipped date is 4pm on MOnday
and i am checking on 9 am Tuesday the number of hrs shud be 1(4-5 of Monday)+1(8-9 of tuesday) =2hrss..
How can i achieve this...
i am using one query but not getting correct minutes.
here is my query:
v_Interval:= to_timestamp(v_temphrs,'HH24:MI:SS')-to_timestamp(v_outpunch1,'HH24:MI:SS');
v_TotalHrsMin1 := extract(hour from v_interval) * 60 + extract(minute from v_interval);
here v_interval datatype is "interval day to second" and v_temphrs datatype is varchar2 and value is : 12:00:00 and v_outpunch1 datatype is varchar2 and value is: 06:10:00
and v_totalHrsMin1 datatype is number.
here i should get value 370.
but i am getting value 350.
I am using the below sql query to calculate working hours. The problem which i am facing is that query is taking lot of time to calculate the working hours. reduce the execution time of this query or if there is any other way to calculate working hours
The following query take 63.499 sec
SELECT sql_calc_found_rows gstime,
MAX(stoptime) AS mx,
MIN(starttime) AS mn,
[Code].....
I have a table with a date field. This field storage dates with hours like this:
01-08-2012 8:30:00
01-08-2012 8:15:00
01-08-2012 9:30:00
01-08-2012 9:40:00
02-08-2012 8:30:00
02-08-2012 9:30:00
02-08-2012 9:34:00
...
I have to generate a report with the day and the frequency :
__Day_______ Hour Range__CountRecords
WEDNESDAY 8 - 9 2
WEDNESDAY 9 - 10 2
THURSDAY 8 - 9 3
The block of the hour must be 1 hour (8-9,9-10 and so on)
how generate the hours range.
My database oracle version is 8i. (I know that is very old but I can't change because It´s a legacy system).
I am not getting added hours from results.
SELECT audittimestamp + interval (SELECT EXTRACT(TIMEZONE_HOUR
FROM systimestamp) FROM DUAL) hour from tab1I want to add Timezone_hour to my timestamp.
