we can easily find out the locks which are currently active session.
Is any other way to find out locks on particular date and time using data dictionary?
For example, we have to find whether TT_objects occured the lock or not on ON yesterday.
How to find date and time of a column in table ?
say for example there is a column called 'date_txn' in a table .When i select that particular column it display output as 'June 2013'.But i want output "with date and time".
How to find schema stats locked or unlocked?
View 3 Replies View RelatedI am using Forms 6i and developed a Master Detail Oracle Form for Oracle EBS 11i application.
I was asked to write a pl/sql program so that.. When a user updating an existing record at the same time another user query the same record and try to update the same time, the record should be locked and a message should popup saying the record is being updated by another user.
We are experiencing tx row lock wait time over hours. There is no blocking session and it seems that the application hangs. What is funny is that when we gather_stats on the tables, those tx row lock wait are being released.
View 8 Replies View RelatedWhen I try to extract the date tag value from XML data, the time stored in 20120602153021 format i.e., YYYYMMDD24HHMISS format. The following statement extracts only date as 02-JUN-12 however do not extract the time part.
If I try the same in SQLplus with to_date it works however fails in PL/SQL.
XML data:
<?xml version="1.0"?>
<RECORD>
<REGTIMESTAMP>20120601130010</REGTIMESTAMP>
</RECORD>
PL/SQL Extract:
CURSOR c_xml_record
IS
SELECT extract(value(d), '//ACTIVATIONTS/text()').getStringVal() AS REGTIMESTAMP,
FROM t_xml_data x,
[code].......
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
My time zone has the offset of 2 hrs during summer and 1 hr during winter.If I want Oracle to tell me what was offset for particular day for example I want to know the offset for February 01, 2010 and August 01, 2010, is it possible?
View 1 Replies View RelatedI need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I am having problems with the XMLTable function. I cant get it to see the entire date/time value in a date field. This wont work
select x1.* from XMLTABLE('/DOCUMENT' passing xmltype('<DOCUMENT><STR>abc def ghi</STR><NUM>1234</NUM><DT>2013-02-17T04:24:02</DT></DOCUMENT>') columns STR varchar2(25), NUM number, DT date) x1;
However if I change the DT tag to just the date only "2013-02-17" it works. Why wont Oracle see the entire date/time format even if its ISO 8601 compliant?
Oracle DB: 11.2.0.3.0
we know we can see lock mode held in session can be analysed using LM column in v$lock.But i confused in seeing LM column it all shows in numbers from 0 to 6.
eg
0,'None(0)',
1,'Null(1)',
2,'Row Share(2)',
3,'Row Exclu(3)',
4,'Share(4)',
5,'Share Row Ex(5)',
6,'Exclusive(6)')
I wanted to calculate the time variance dynamically as below.I have one table called process_status where we can see the process name, start time, end time and the status .
1. Now i wants to calculate the duration(end_time - start_time) in hh:mi:ss format and i got the output using below query.
select name, start_time, end_time, status, to_char(trunc(sysdate) + (end_time - start_time), 'HH24:MI:SS') duration from process_status ;
I got currect oupput but i am stuggling with the below step.
2). Actually the process expectaiotn time is 2 hours only(fixed time). Now i wants to calculate variance b/w expected time and the duration time(end_time - start_time)
i.e variance = expected_time - (end_time - start_time ) ;
here expected time is 02:00:00(fixed).
I tried using with to_char and to_date function but no luck.
I want to know how I can find which query is taking more time , for example some query's are run from unix, java and from toad,sqlplus. and one query is taking much more time to execute, so how i can get that query and all the details.
View 2 Replies View RelatedI need to query a table to get the time difference based on different dates.
SAMPLE DATA:
JOB ID start_time end_time
1 201008190056 19/08/2010 01:23:12
2 201008190123 19/08/2010 01:50:12
2 201008200045 19/08/2010 01:50:12
3 201008070345 7/08/2010 04:50:12
3 201008070345 7/08/2010 04:50:12
1 201008070003 7/08/2010 00:30:12
in the above, for job 1 ,on 19/08/2010 the time difference should be calculated as
01:23:12-00:56:00 and the difference should be in minutes.
for end_time. i can't take the substring as the length of the date varies for 19 and 7. In case of start date, the time has to be in format, hh:mm:ss, to calculate the difference.
I have a table which is getting populated from a source. I dont have a time-stamp column in the table. Is there anyway to find the time when a record was inserted into the table?
View 3 Replies View RelatedVersion: 11.2 I am not an SQL expert. I am trying to subtract the start time and end time and thereby find the difference between these two times. In the below example , the difference between start_time and end_time is around 52 minutes (6:15 PM to 7:07 PM)I tried some stuff to find the difference below. But it didn't work out .
SQL> create table t (start_time date, end_time date); Table created. SQL> desc t Name Null? Type ----------------------------------------------------------------- -------- --------------------- START_TIME DATE END_TIME DATE SQL> insert into t values (to_date('24/JUN/2013 18:15:42', 'DD/MON/YYYY HH24:MI:SS'), to_date('24/JUN/2013 19:07:54','DD/MON/YYYY HH24:MI:SS')); 1 row created. SQL> commit; Commit complete. SQL>SQL>SQL> select * from t; START_TIME END_TIME-------------------- --------------------24 Jun 2013 18:15:42
[Code] .......
I have one table with 10 rows and its frequently updated now my question is that, how can it get the latest date of updation of that rows?
View 4 Replies View RelatedSQL> select * from emp;
SINO BOOK UPDATION_
---------- ---------- ---------
1 UB 01-MAR-10
2 UB 12-MAR-10
3 SB 12-MAR-10
4 DB 12-MAR-10
4 MB 12-JUN-10
4 MB 31-JUL-10
6 rows selected.
SQL> SELECT sino, book, updation_date
2 FROM emp
3 WHERE updation_date IN (SELECT MAX (updation_date)
4 FROM emp
5 GROUP BY book);
SINO BOOK UPDATION_
---------- ---------- ---------
2 UB 12-MAR-10
3 SB 12-MAR-10
4 DB 12-MAR-10
4 MB 31-JUL-10
I would like to know, how to find out the latest date from above query without using group functions like max, min,order by and group by.
building SQL query to get the result as shown below.
Create Table Temp
CREATE TABLE TEMP
(
CASEID NUMBER,
SATUS VARCHAR2(1 BYTE),
TRANS_DATE DATE
)
Insert data
[Code]...
I want to build a query which should give output as shown below. Basically i want to select those rows which having minimum trans_date for a given CASEID & Status.
OUTPUT:
CASEIDSATUSTRANS_DATE
100A11/02/2010
100B11/07/2010
100A11/12/2010
200A11/02/2010
200B11/07/2010
I have oracle table for Leave
LeaveNo - FromDt - ToDt - Query Retrieve
1 - 01/01/2010 - 31/03/2010 - No
2 - 01/02/2010 - 31/05/2010 - Yes
3 - 01/04/2010 - 30/04/2010 - Yes
4 - 25/04/2010 - 15/05/2010 - Yes
5 - 01/05/2010 - 31/05/2010 - No
6 - 15/03/2010 - 14/04/2010 - Yes
7 - 10/04/2010 - 15/04/2010 - Yes
I want find out who was leave on 01/04/2010 to 30/04/2010. user input parameter may vary like 10/04/2010 to 15/04/2010 or 12/04/2010 to 12/04/2010.
how to write oracle sql?
I am getting daily basis data from third party in excel format which i am converting into CSV format and then uploading into oracle tables using External tables.Now problem is that every time i getting the dates in diff format i.e. sometimes dd-mon-yyyy , dd/mm/yyyy etc.
Now every time i have to open my code and change it there ...to make it as oracle date format. IS there way i can find out format of date and based on format i can do operations with getting errors every time.
I am storing the TP(Excel date) date into varchar columns only and then varchar2 column value i m inserting/updating into date format using to_Date ().
I have two table in the database. I want to find the maximum routine date for a case_id when the lock_date is between 20 jan to 29 jan 2012 .
But I am not getting actual output (Output routine_date should be "28-jan-2012" but I m getting "31-jan-2012")
Master
case_id lock_date
101 23-jan-2012
101 24-jan-2012
102 27-jan-2012
102 29-jan-2012
101 30-jan-2012
101 29-jan-2012
Routine (for routine work)
case_id routine_date
101 23-jan-2012
103 28-jan-2012
102 21-jan-2012
102 29-jan-2012
101 21-jan-2012
101 28-jan-2012
101 31-jan-2012
select m.case_id, r.routine_date from master m, routine r,
(select case_id, max(routine_date) from routine group by case_id) rr
where m.case_id=r.case_id
and m.case_id=rr.case_id
and r.routine_date=rr.routine_date
I have 10 users in my database, I need to find the time at which a query is fired by any of the users in the database. provide the query for this? I think i have to use V$sql,v$sqlarea or v$sql.
View 1 Replies View RelatedI only know to retrieve data (date & time) by the following statement : "select sysdate from ..."
but now I want to make the fields current date and current time separately and put in a adult file with these two fields. how to do it.
I had a database at microsoft access but i had move it to the oracle database.
When i check the datatype at oracle, date column is at DATE datatype. but it only display date. like in oracle. it display:
oracle_date.PNG ( 74.61K )
Number of downloads: 4
But when i link it to microsft access. like i will control the oracle from access. the result is at below:
access_date.PNG ( 136.11K )
Number of downloads: 3
So, my problem is how to display the date and time fully in oracle?
iam having a table A where column ABC is a varchar field with varchar2(50).
currently data stored is like this.
02-27-2009 11:01:33
02-27-2009 11:01:46
03-06-2009 09:07:18
now i want UTC Date time should be in format 2010-02-24T17:08:09Z. in the above format.
is there possible to retrieve date with its time in oracle ,if we didnot provide time while insertion? like hiredate column of emp table can we get hiredate of each emp with its time of joining. i am using "11g Enterprise Edition Release 11.2.0.1.0"
View 3 Replies View RelatedI have a question with Oracle sql developer, i've installed oracle 11g express edition, and i want to insert values 'date' and 'time', but i only got the resultat like this:
Who can tell me how can i do to show just date info in 'date' and same for the 'time'?
T1 = 06-Jun-2011 4:00PM
T2 = 10-Jun-2011 11:AM
Calculation is Required.
If at the end of Day Hours of T1 > 6 hours then it should calculate 1 Day.
same with T2. hours of T2(from begining of Day till end Time (11AM), it should again caculate if >6 hours then 1 Day.
remaining will be date calculation. this is how T2 - T1 should give us 5 Days.
Detail
06-Jun-2011 4:00PM to 06-Jun-2011 12:00AM (8 hours > 6 = 1 Day)
06-Jun-2011 12:00AM to 07-Jun-2011 12:00AM = (1 Day)
07-Jun-2011 12:00AM to 08-Jun-2011 12:00AM = (1 Day)
08-Jun-2011 12:00AM to 09-Jun-2011 12:00AM = (1 Day)
09-Jun-2011 12:00AM to 10-Jun-2011 12:00AM = (1 Day)
10-Jun-2011 12:00AM to 10-Jun-2011 11:00AM (11 hrs > 6 = 1 Day)
this is how 5Days calculation is required.