I only know to retrieve data (date & time) by the following statement : "select sysdate from ..."
but now I want to make the fields current date and current time separately and put in a adult file with these two fields. how to do it.
how to pull data from a table where date is greater than current time (+24 hours)... my date field is in the following format 15-MAR-2013 20:07:00
I want to do something like this
select * from table_A where date_field > (sys_date_time) +24h
as an example, when I run a query @ 4 PM on March 26, I want to pull data that has date > 4 PM March 27
I have a column where I have time stamp with date and time(8-May-10 10:20:55 Am) from that i will get only time(10:20:55 Am)[query for this mentioned below] Now i need to append the time to current date and insert into a Timestamps column only .
so my result should be 17-May-11 10:20:55 Am(Assuming current Date is 17-May-11) . I tried search it by i found a way in sql server by using DataAdd and DataDiff .
query to get the time is:select to_char(to_date('11-MAY-11 05.00.00 PM', 'DD-Mon-YY HH:MI:SSAM'),'HH24:MI:SS') "Time Now" from dual
What is the difference between the following . In my schema all are giving the same results with some different format
SQL> SELECT sysdate , current_date , current_timestamp , localtimestamp from dual;
SYSDATE CURRENT_DATE CURRENT_TIMESTAMP LOCALTIMESTAMP
----------- ------------ ------------------------------------------------- -------------------------------------------------
5/30/2012 8 5/30/2012 8: 30-MAY-12 08.27.22.037703 AM -04:00 30-MAY-12 08.27.22.037703 AM
I need to verify if the current date is grater than the 15th of the current month. If its grater than the 15th of the current month i need to do an action or if else its lesser than 15th of the current month i need to do an other operation.
View 5 Replies View RelatedWrite a program to declare a date variable and assign it to the current system date. Depending on the day of the month the program should print the following:
If day is 1-10 then print "It is day<day number> of <month name>. It is early in the month".
If day is 11-20 then print "It is day<day number> of <month name>. It is the middle of the month".
If day is 21-31 then print "It is day<day number> of <month name>. It is nearly the end of the month".
For example, if the day is November 30, then print "It is day 30 of November. It is nearly the end of the month".
My below query is working fine with sysdate but when m passing a date it's throwing an error to get the current qtr end date..
select add_months(trunc('20-dec-2012','q'),3) - 1 from dualERROR
ERROR at line 1:
ORA-00932: inconsistent datatypes: expected DATE got NUMBER
even after adding the to_date function between trunc and date.
When I try to extract the date tag value from XML data, the time stored in 20120602153021 format i.e., YYYYMMDD24HHMISS format. The following statement extracts only date as 02-JUN-12 however do not extract the time part.
If I try the same in SQLplus with to_date it works however fails in PL/SQL.
XML data:
<?xml version="1.0"?>
<RECORD>
<REGTIMESTAMP>20120601130010</REGTIMESTAMP>
</RECORD>
PL/SQL Extract:
CURSOR c_xml_record
IS
SELECT extract(value(d), '//ACTIVATIONTS/text()').getStringVal() AS REGTIMESTAMP,
FROM t_xml_data x,
[code].......
I have two tables
table_1
--Emp_id--|--Sup_id--|Sup_name|--Date--|
-------------------------------------------------
--00001--|--00005 --|---ABCD--|01-MARCH-2004
--00002--|--00006 --|---BCDE--|02-MARCH-2004
--00003--|--00007 --|---CDEF--|03-MARCH-2004
--00001--|--00008 --|---DEFG--|04-APRIL-2004
--00003--|--00009 --|---EFGH--|05-APRIL-2004
table_2
--Emp_id--|Emp_name|
--------------------------------
--00001--|--QWER--|
--00002--|--ASDF--|
--00003--|--ZXCV--|
--00004--|--POIU--|
table_1 contain records on employee and the supervisor they are under at a certain date.
As some employee(00001 & 00003) have a different supervisor from different date, I'll like to extract from table_1 the record of each employee in the table that only contain the supervisor info on the most recent date.And from table_2, i'll like to extract the employee's name. These records extracted from both the tables would the be put into a new table,table_3
Example: For employee 00001, only extract record that have the most recent date which is 04-APRIL-2004 and not on 01-MARCH-2004
table_3
Emp_id|Emp_name|Sup_id|Sup_name|Date|
------------------------------------------------
00001 |--QWER--|00008 |--DEFG---|04-APRIL-2004
00002 |--ASDF-- |00006 |--BCDE---|02-MARCH-2004
00003 |--ZXCV-- |00009 |--EFGH---|05-APRIL-2004
How to write an SQL statement to perform this?
How can we create a table with current date in oracle this is to be done daily a job as following today's table name is MYTABLE-2010-07-23
so every day a job is to create a table with tablename-current date
is this possible? and how to
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I have a Employee data as below with EID and DOB
EID DOB
----------------------
1 03/01/1950
2 14/01/1950
3 27/01/1950
4 02/02/1950
5 04/03/1950
6 12/03/1950
7 28/03/1950
8 28/02/1951
9 08/03/1951
10 28/03/1951
I need a query to display the birth date of all emp in such a way that if i run a query today the dob which lies between today & today+15 days data must be displayed.
I need to get the past 12 months from the current month
for example
input:
march2010
output:
apr2009
may2009
june2009
july2009
augest2009
september2009
october2009
november2009
december2009
january2010
february2010
if i make the source for a field is a current date with format dd/mm/rrrr hh:mi:ss and the report published on the application server and the clients from different machines run this report
what the field display on Cline or on DB or On Application Server?
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
Is there any way to display the current date with post fix notation in oracle?
Ex : 2nd ,5th , 3rd , 1st , 8th ,
select to_char(sysdate,'DD') from dual;
How can we insert current date which is present in xml node into a column having date datatype.
View 6 Replies View RelatedI have an attribute in my DB called start_date of type date.I want a query that return the difference between the start_date and the current date.for example if start_date = 2/14/2013 *2*:35:00 PM and the current date = 2/14/2013 *1*:35:00 PM the query returns 1.
I want the result in hours.
I need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I am having problems with the XMLTable function. I cant get it to see the entire date/time value in a date field. This wont work
select x1.* from XMLTABLE('/DOCUMENT' passing xmltype('<DOCUMENT><STR>abc def ghi</STR><NUM>1234</NUM><DT>2013-02-17T04:24:02</DT></DOCUMENT>') columns STR varchar2(25), NUM number, DT date) x1;
However if I change the DT tag to just the date only "2013-02-17" it works. Why wont Oracle see the entire date/time format even if its ISO 8601 compliant?
Oracle DB: 11.2.0.3.0
I have one table with 10 rows and its frequently updated now my question is that, how can it get the latest date of updation of that rows?
View 4 Replies View RelatedI had a database at microsoft access but i had move it to the oracle database.
When i check the datatype at oracle, date column is at DATE datatype. but it only display date. like in oracle. it display:
oracle_date.PNG ( 74.61K )
Number of downloads: 4
But when i link it to microsft access. like i will control the oracle from access. the result is at below:
access_date.PNG ( 136.11K )
Number of downloads: 3
So, my problem is how to display the date and time fully in oracle?
iam having a table A where column ABC is a varchar field with varchar2(50).
currently data stored is like this.
02-27-2009 11:01:33
02-27-2009 11:01:46
03-06-2009 09:07:18
now i want UTC Date time should be in format 2010-02-24T17:08:09Z. in the above format.
is there possible to retrieve date with its time in oracle ,if we didnot provide time while insertion? like hiredate column of emp table can we get hiredate of each emp with its time of joining. i am using "11g Enterprise Edition Release 11.2.0.1.0"
View 3 Replies View RelatedI have a question with Oracle sql developer, i've installed oracle 11g express edition, and i want to insert values 'date' and 'time', but i only got the resultat like this:
Who can tell me how can i do to show just date info in 'date' and same for the 'time'?
T1 = 06-Jun-2011 4:00PM
T2 = 10-Jun-2011 11:AM
Calculation is Required.
If at the end of Day Hours of T1 > 6 hours then it should calculate 1 Day.
same with T2. hours of T2(from begining of Day till end Time (11AM), it should again caculate if >6 hours then 1 Day.
remaining will be date calculation. this is how T2 - T1 should give us 5 Days.
Detail
06-Jun-2011 4:00PM to 06-Jun-2011 12:00AM (8 hours > 6 = 1 Day)
06-Jun-2011 12:00AM to 07-Jun-2011 12:00AM = (1 Day)
07-Jun-2011 12:00AM to 08-Jun-2011 12:00AM = (1 Day)
08-Jun-2011 12:00AM to 09-Jun-2011 12:00AM = (1 Day)
09-Jun-2011 12:00AM to 10-Jun-2011 12:00AM = (1 Day)
10-Jun-2011 12:00AM to 10-Jun-2011 11:00AM (11 hrs > 6 = 1 Day)
this is how 5Days calculation is required.
I am converting data from an old paradox table to a new oracle table, one of the problems im having is incompatibility with date and time formats:
some columns contain times in the format : "00:00:00" eg..... "15:00:00"
some columns have date in the format: "dd/mm/yyyy" eg....... "21/08/2000"
some columns have time and date eg.. "05/09/2000 15:49:39"
Currently I have the data held in tables within an access database, and in CSV format.
eg, I have dates like 03/04/2010 which i need to be 03-APR-10....
how I can get the following into Oracle date formats? there is over 1000 records so manual conversion is out of the question
I have the following piece of
SELECT decode(substr('18900607|000000|20110718112109|23972|002',
17,
14),
'00000000000000',
NULL,
(to_date(substr('18900607|000000|20110718112109|23972|002',
17,
14),
'YYYY/MM/DD HH24:MI:SS')))
FROM dual;
When I run the above code I get an incorrect display ie. "18-JUL-11". when I remove the decode I get the correct display ie."2011/07/18 11:21:09 AM"
Create table time_in (
Emp_id varchar2(6),
at_date date,
time_in varchar2(6),
status varchar2(2)
)
[Code]....
-------------- required restul----------
emp_id at_date time_in at_date time_out
------ ------- ------- -------- --------
00009 16/03/2013 09:47 17/03/2013 09:45
00009 17/03/2013 09:48 17/03/2013 10:43
00009 18/03/2013 09:57
00009 19/03/2013 09:38 19/03/2013 05:22
00009 20/03/2013 09:48 20/03/2013 05:24
status 01 = time in
status 02 = time out
SQL> desc guide;
Name Null? Type
----------------------------------------- -------- ----------
GUIDE_ID NOT NULL NUMBER(20)
CHANNEL_ID NOT NULL NUMBER(5)
SHOW_DATETIME DATE
[code]....
when I run this query it only displays the date but no time.how to display it with the date and time?
