I need to return which hour for a given date range had the most calls. I have a query that works but it is inelegant and I'm pretty sure I could do better. I'm pretty new to analytic queries so go easy...
select hour,
calls
from
(
select hour,
calls,
rank() over (ORDER BY calls desc) as ranking
from
(
[Code]....
I created a sample table named as "Student" with following data. table contains two columns only - stdid & marks.
stdid marks
10 75
20 60
30 60
40 45
50 30
I have to find the rank of students based on their marks in descending order.Is there a way to get rank without using RANK function?
I have 3 tables, user_login_event, person and resource_viewed_event. What I want to do have a report for each month, users logged in our application and then show for each month, how many records were created in table person and how many resource views events were logged in resource_viewed_event.
Lets only worry about the timestamp fields in these tables now as I want to use them to join the tables together or at least build correlated subqueries along the months. I have tried several options, all not leading to a desired result:
Left outer join. Works but its incredibly slow:
SELECT
distinct to_char(ule.TIMESTAMP,'YYYY-MM') as "YYYY-MM",
count(distinct ule.id) as "User Logins",
count(distinct ule.user_id) as "Users logged on",
count(distinct p2.id) as "Existing Users",
count(distinct p1.id) as "New Users",
count(distinct r1.id) as "Resources created"
[code]....
Tried the same with left outer joins of temporary tables created through select statements:
select
distinct ule.month as "Month",
count(distinct p1.user_id) as "Users created",
count (ule.id) as "Logins",
count (distinct ule.user_id) as "Users logged in",
count(rv.id) as "Resource Views",
count(distinct rv.resource_id) as "Resources Viewed"
[code]....
Tried the same with left outer joins of temporary tables created through select statements:
select
distinct ule.month as "Month",
count(distinct p1.user_id) as "Users created",
count (ule.id) as "Logins",
count (distinct ule.user_id) as "Users logged in",
count(rv.id) as "Resource Views",
count(distinct rv.resource_id) as "Resources Viewed"
[code]....
another approach is to create my own temporary tables using select statements and create fixed Month values which I can use to directly link the sets together.
select
distinct ule.loginday as "Month",
count(distinct ule.id) as "Logins",
count(distinct ule.user_id) as "Users logged in",
count(distinct p1.user_id) as "Users created",
count(distinct p2.user_id) as "Existing users1"
[code]....
performance is OK with 2 tables but the example above takes forever to execute.
Tried an approach with union but this creates new rows for each table
SELECT DISTINCT p1.MONTH AS "Month",
COUNT(DISTINCT p1.user_id) AS "Users created",
NULL AS "Logins",
NULL AS "Users Logged in",
NULL AS "Resource views",
NULL AS "Resources viewed"
FROM (SELECT To_char(person.created_on_date, 'YYYY-MM') AS MONTH,
[code]....
I certainly know this is possibly but I am trying to do this on the fly and can't seem to work it out:
I have a table A:
ID Name Priority
-------------------
1 Smith 1
1 SSmith 2
1 ASmith 3
1 BSmith 3
2 John 2
3 Ed 1
and I am looking to create the following table from this:
ID Name Sum(Top3Priority)
--------------------------------
1 Smith,SSmith,etc 8
Now, I've got listagg working and everything appears to be going swimmingly but: for every listagg grouping on name I need to only sum the highest top 3 priorities. So in the example above there are four Smiths but I need to only sum the top 3 priorities which are 3,3,2 and ignore the 1 even though I do want all the listagg Smith's (SSmiht, ASmith, etc) in there.
Now I can sum the priority, but don't really know how to sum only the top 3 in any ID ? There can be 1 to n ID's so if there are only 2 ID's I want to sum those 2, if there are 3 all 3 and 4 upwards only the top 3.Here is a snippet of the SQL I am using
SLECT id,
listagg(MN_CR_LOOKUP.f_name, ',') within group (order by Priority)) roadname,
**** sum top 3 here ?****
count(*) "NumI", Sum("Elevation") "CombinedElevation"
FROM jc,
[code]...
I am trying to find out the difference in time between peoples memberships and also the order that these memberships are taken out in. So far I have added in a rank statement to work out the order the memberships were created in, but now want to look at the difference between the dates returned. The SQL I used is:
SELECT owner_party_id,
mem_number,
support_id,
mem_start_date,
RANK() OVER (PARTITION BY owner_party_id ORDER BY mem_start_date ASC) MEMBERSHIP_SEQUENCE
FROM membership_all
WHERE version_type = 'CUR'
AND owner_party_id IN ('65051', '65051', '65348', '65348', '65607', '65607', '65607')
to get:
"OWNER_PARTY_ID"|"MEM_NUMBER"|"SUPPORT_ID"|"MEM_START_DATE"|"MEMBERSHIP_SEQUENCE"
65051|318874751|8014747|01-MAR-10|1
65051|412311060|21502883|15-AUG-12|2
65348|308672459|3526913|01-MAY-10|1
65348|409951130|20950524|18-JUN-12|2
65607|315830192|7510133|17-MAY-10|1
65607|406448110|20024246|16-MAR-12|2
65607|409738130|20903556|14-JUN-12|3
Now I would like to calculate the difference between the start dates of each of the owner_party_id groups, so to get something like this:
OWNER_PARTY_ID|MEM_NUMBER |SUPPORT_ID|MEM_START_DATE |MEMBERSHIP_SEQUENCE|Diff
65051|318874751|8014747|01-Mar-10|1|
65051|412311060|21502883|15-Aug-12|2|898
65348|308672459|3526913|01-May-10|1
65348|409951130|20950524|18-Jun-12|2|779
65607|315830192|7510133|17-May-10|1
65607|406448110|20024246|16-Mar-12|2|669
65607|409738130|20903556|14-Jun-12|3|90
I think that I need to use the Lag function in, but I am not too sure if it can be linked to look at the data within a grouping of owner party id, as it would make no sense to calculate the difference in dates for two different owner party ids.
how do i retrieve only last rank row from table ?
View 7 Replies View RelatedI've below table.
with tmp_tbl as
(select 'H1' as hh_id, 'C1' as cust_id, 2 as f_rnk, 'F' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100203','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C2' as cust_id, 1 as f_rnk, 'M' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100303','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C3' as cust_id, cast(null as number) as f_rnk, 'U' as gender, to_date('20130103','YYYYMMDD') as purch_dt,
[code].....
Now i need to rank each cust_id in each hh_id based on below conditions.
1) If atleaset one cust_id in hh_id has f_rnk then gender 'F' with highest f_rnk (more then one F with same f_rnk then the one with oldest first_dt), if no 'F' then gender 'U' with highest f_rnk ((more then one F with same f_rnk then the one with oldest first_dt)), if no 'F' and 'U' then consider 'M' (more then one M with same f_rnk then the one with oldest first_dt).
2) If the above is not met (no cust_id in hh_id has f_rnk populated) then i've to rank based on purch_dt. Gender 'F' with recent purch_dt (if more than one F in household with same purch_dt then the one with oldest first_dt), if no 'F' then gender 'U' with recent purch_dt (if more than one U in household with same purch_dt then one with oldest first_dt), if no 'F' and 'U' then consider 'M' (more than one M in household with same purch_dt then the one with oldest first_dt).
3) If the above criteria is also not met, then rank based on gender_cd. Gender 'F' will have first preference then 'U' and then 'M'.
My output :
HH_ID CUST_ID F_RNK GENDER PURCH_DT FIRST_DT F_RNK_RANK PURCH_RANK GENDER_ONLY_RANK
----- ------- ---------- ------ ----------- ----------- ------------ ------------ -----------------
H1 C1 2 F 1/2/2013 2/3/2010 1
H1 C2 1 M 1/2/2013 3/3/2010 2
H1 C3 U 1/3/2013 4/3/2010 3
H2 C4 F 4/3/2013 10/2/2009 2
H2 C5 M 5/5/2013 8/8/2010 1
H3 C6 F 5/6/2008 1
H3 C6 M 7/8/2010 2
I've tried below query with one condition, but it's giving f_rnk_rank for all records. How can i include multiple conditions in the rank function.
with tmp_tbl as
(select 'H1' as hh_id, 'C1' as cust_id, 2 as f_rnk, 'F' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100203','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C2' as cust_id, 1 as f_rnk, 'M' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100303','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C3' as cust_id, cast(null as number) as f_rnk, 'U' as gender, to_date('20130103','YYYYMMDD') as purch_dt, s hh_id, 'C5' as cust_id,
[code]....
there is a way when doing the Rank Function in PL/SQL to pass the field that will be ranked as an override.
SELECT rank(p_ColumnAmt) within group (order by p_ColumnNm desc) rank
INTO v_RnkNoAmt
FROM Table_name
WHERE ??????;
p_Column is the amount I am ranking
p_ColumnNm is the actual field name to Rank.
When I pass the field name with an override I do not get the correct rank back. If I run the Select with the actual field name curr_1_mth_amt, I get the correct rank.
I have about 70 different field to Rank and do not want to make a procedure for each field.
the following statement gives each customer owns how many promotions.
Q:) how do i retrieve a customer who has max. promotions?
SELECT C.CUSTOMER_ID,COUNT(P.PROMOTION_ID)
FROM PROMOTIONS P,CUSTOMERS C
WHERE C.CUSTOMER_ID = P.CUSTOMER_ID
GROUP BY C.CUSTOMER_ID
=====================================================
CUSTOMER_ID COUNT(P.PROMOTION_ID)
-------------------------------------
001 | 5
002 | 8
003 | 4
004 | 6
005 | 5
006 | 3
I have a SQL statement that return the following result.
col1
----
a
a
b
b
a
c
c
c
c
What i need is to eliminate the duplication and return the result as the following.
col1
----
a
b
a
c
Using group by or distinct will eliminate the third row "a" and will not return it ordered.My idea is to generate another column that rank the result as following.
col1rank
------------
a1
a1
b2
b2
a3
c4
c4
c4
c4
so using the following SQL query will return the result as needed
select col1, rank
from T
group by col1, rank
order by rank;
col1rank
------------
a1
b2
a3
c4
I have this code which simply gives me the count of term.
SELECT
OUA_ID
,COALESCE (MAX( DECODE( TERM, 0603, TERM_COUNT, NULL ) ), 0 ) "TERM_0603_CNT"
,COALESCE (MAX( DECODE( TERM, 0702, TERM_COUNT, NULL) ), 0 ) "TERM_0702_CNT"
,COALESCE (MAX( DECODE( TERM, 0705, TERM_COUNT, NULL ) ), 0 ) "TERM_0705_CNT"
,COALESCE (MAX( DECODE( TERM, 0707, TERM_COUNT, NULL ) ), 0 ) "TERM_0707_CNT"
FROM(
SELECT DISTINCT
OUA_ID, TERM_COUNT, TERM
FROM(
SELECT OUA_ID, TERM ,PROVIDER_CDE, COUNT(*) TERM_COUNT
FROM TABLE
WHERE PROVIDER_CDE = 'BILL'
GROUP BY OUA_ID, TERM, PROVIDER_CDE)) GROUP BY OUA_ID
Gives:
OUA_IDTERM_0603_CNTTERM_0702_CNTTERM_0705_CNTTERM_0707_CNT
32710 0 3 7 0
45726 2 0 1 0
Is there a way i could used the rank function (with decode) to only display the 1ST (First) and 2nd(Second) most used term per OUA_ID?
So i get this:
OUA_ID1st MOST USED2nd MOST USED
3271 705 702
45726 603 705
I have the following table :
CREATE TABLE A_TEST (A INTEGER, B INTEGER, C INTEGER, D INTEGER, FLAG CHAR(11));
INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
[code].......
I would like to perform an update on the FLAG column by setting to "D" if it is a duplicate record.1,2,3,4);
I would like to use the rank function.
Desired update:
A B C D FLAG
1 2 3 4
2 4 5 8
1 2 3 4 D
2 4 5 8 D
7 2 3 4
9 2 3 4
7 2 3 4 D
1 2 3 4 D
5 4 5 8
2 2 3 9
2 4 5 8
6 2 3 4
1 3 3 4
8 2 8 4
can we create rank on a particular column without using rownum and rank function.
View 9 Replies View RelatedI am trying to use RANK() clause with a window clause...is that possible to use both together?
like
select col1, col2, col3,
RANK() OVER (ORDER BY col3 desc RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) RK
from table t
but getting error in SQL Developer
ORA-00907: missing right parenthesis
00907. 00000 - "missing right parenthesis"
*Cause:
*Action:
Error at Line: 2 Column: 33
The reason why i need to rank in window clause because i have data like this
Name Marks Quiz
Ali 10 1
John 20 1
Sara 30 1
John 40 2
Sara 50 2
Ali 20 2
...
...
and so on
I want to rank them based on their cumulative sum marks after every test..ranking should be in such a way that it should look current row and preceding rows
like this
Name Marks Quiz cumulative_marks rk
Ali 10 1 10 4
John 20 1 20 3
Sara 30 1 30 2
Peter 100 1 100 1
John 40 2 60 3 ==> becuase John has now third most overall cumulative marks (60) after quiz 2.
Sara 50 2 90 2 ==> becuase Sara has now 2nd most overall cumulative marks (90) after quiz 2.
Ali 20 2 30 4 ==> becuase Ali has now fouth most overall cumulative marks (30) after quiz 2.
Here table - tac has
row1
-----
X
X
X
B
[code]...
I want ouptut like using sql query with out using dense_rank function,
row1 row2
X 1
X 1
X 1
B 2
[code]...
I am attempting to user PIVOT and DENSE RANK in a query the following is the query and the record set it returns (condensed and de-identified)
"select * from(
select * from (select dense_rank() over (partition by 1 order by cal.weeksort desc) WEEK_nbr,
u.user_title Manager_Title, replace(hier.manager, '<br>',' - ') Manager,
replace(hier.user_hin, '<br>',' - ') user_name,
to_char(cal.calendar_date_week - 6, 'MM/DD/YYYY') ||' - '|| to_char(cal.calendar_date_week, 'MM/DD/YYYY') Week_of,
upper(substr(cal.day_of_week, 1,3)) DOW, count(distinct Pers_gen_key) cnt from apexim.hrw_member_action act
[code]....
Am working on a workbook to count the number of enrolments and withdrawals in the program. My data looks like this
name semester status year
A 1 enrol 2010
A 2 withdraw 2010
A 3 enrol 2010
B 1 enrol 2010
B 2 withdraw 2010
I want to count their latest status only. It should come up with
Total Enrol - 2
Total Withdrawn - 1
For total Withdrawn, I tried 'rank' and filter to equals 1 but it does not allow me. Is there any way to have this work?
Here's my calculation:(decode((FIRST_VALUE(status) OVER(PARTITION BY year, name ORDER BY semester DESC)),'withdraw', name)) It tells me that 'Aggregation of Analytic function not allowed'
In a pl/sql procedure, when I am doing an update, I need the old value to be returned and stored in a local variable, so that the same can be used for future purpose.
Note : I know the "OLD:" option is present when we use TRIGGER, but in my case , the table I am updating is a old table and I am not permitted to create a trigger for it.
create table testing
( id number (10),
key number (10)
)
insert into testing values (1,10)
insert into testing values (1,10)
insert into testing values (2,10)
insert into testing values (2,20)
insert into testing values (3,10)
My requirement is to return
id key
1 10
1 10
because both their id and key are same
I have the below requirement,
i got a table(deptid, deptname, address,city,zip, state, other columns) i want to write a query to determine any error(records with different values) because i expect all records grouped-by(deptid, deptname, address,city,zip, state) to have the same deptid(pls note that deptid isnt unique),
or a specific deptid should have only one record based on the grouping (deptid, deptname, address,city,zip, state),
I have a table which lists previous jobs, whcih has monthto,yearto, monthfrom and year from fields. I am trying to find the most recent job (of which they might be multiple ending on the same month) Initially, i did the following:
ran a sub query to find the most recent (employee id, max (yearto * 12 + monthto), then another query where I got a list of the most recent jobs, and returned the first one using rownum = 1 (note this may be inconsistent between runs as thee rownum is calculcated before nay ordering clause. This worked, but i figured using the first function might be better as it gives an order
select employee_id from
(select employee_id
,max(NVL(yearto,0) *12 + NVL(monthto,1)) KEEP (DENSE_RANK FIRST ORDER BY emloyer) as latest
from employees
group by employee_id;
but this seems to return more than one entrty:
table date below:
drop table employee_list;
drop table employee_historic;
[code]...
What is the best way to return a single row, if the primary key is not available / applicable.
I have this query to return to me the latest case note, now I would like to add the date prior to the latest case note.
select case_notes.applicant_id,
reg.program_code,
reg.last_name,
[Code].....
I am working on a script in which I want to retrieve multiple rows but I get error ORA-1422.I tried solving it using the following script , but it still gives error.
CREATE OR REPLACE PROCEDURE proc_query
DECLARE
TYPE all_dest IS TABLE OF NUMBER;
destIds all_dest;
BEGIN
SELECT dest_id from sb_packet WHERE src_id = 32;
RETURNING dest_id bulk collect into destIds;
END;
I run following query.
select to_date(sysdate,'DD/MM/YYYY') Dte FROM DUAL
Result is
Dte
--------
01/17/0011
why it is not returning '01-17-2011'?
how to write a function that returns top value if not exists then next top for combination of customer_id and hierarchy.For instance :
If I've got table
customer_id ,hierarchy, function_code
123 |1 | Z1
123 |2 |67
123 |3 |5B
678 |10 |S2
678 |11 |Z2
345 |2 |11
For the customer ID 123 I want to return Z1, for customer 678 I want to return S2 and for customer ID 345 I want 11
Problem is that I'm new to the concept of looping. I know how to write a function that accepts customer_id as a value write a cursor and then check IF hierarchy = 1 the return FUNCTION_CODE IF hierarchy - 2 THEN ...
but I need something more universal as some of the customers may have hierarchy function 1 and that would be the top one for him but others might have function of hierarchy 10 as top and checking all of the possibilities using if would be just stupid. So how to write something universal ? And of course if function did not find any customer_id then return null.
Does the Oracle 11g supports 'RETURNING INTO' clause in MERGE statement? if it was not available is there any alternate to achieve the same ?
View 3 Replies View RelatedI'm trying to query an array where we will have mathnames that have the follow format: variablemathname[00000]
have been digging around for a few days to try and simplify my existing query. As of right now i'm hacking it together to bring back the bracketed array value by using INSTR and SUBSTR. This works and gets me the correct results but I want to clean the code up by using regexp_SUBSTR.
In my reading up on regular expression I've tried to create my pattern by using [.] which I believe to be [any character]. I want it to start at the beginning of the string so I've used [^ and I only want the one occurrence so I've ended my expression with ]
I tried using the escape before my pattern as I know that [ is a metacharacter but I receive the same results.i'm trying to use to get the expression correct.
SELECT REGEXP_SUBSTR('variablemathname[00000]', '[.],[^,],') RESULT
FROM DUAL;
My expectation is it will bring back the following [00000] but the way it is written now is bringing back nothing.
Imagine I have the following scenario:
CREATE TABLE AAA_PLACE
(COD_PLACE NUMBER,
PLACE_NAME VARCHAR2(50 BYTE)
)
insert into AAA_PLACE (COD_PLACE, PLACE_NAME) values (1, 'Munich');
insert into AAA_PLACE (COD_PLACE, PLACE_NAME) values (2, 'Lisbon');
insert into AAA_PLACE (COD_PLACE, PLACE_NAME) values (3, 'Monaco');
insert into AAA_PLACE (COD_PLACE, PLACE_NAME) values (4, 'Madrid');
insert into AAA_PLACE (COD_PLACE, PLACE_NAME) values (5, 'Milan');
Imagine I want to retrieve those records in only 3 distinct rows, like this:
Munich
Madrid
Others
Is there any way I can do this with an simple Statement?
I have following code. It is always returning sysdate even run on Sunday.
declare
vDate date;
begin
if to_char(sysdate,'Day')='Sunday' THEN
vDate := sysdate-3;
[Code]...
if there is something missing or wrong.
I've just started with the Oracle SQL and come from a heavy MS SQL background and I understand that here are some natural differences in the syntax but I'm stumped as to why the following sql represents a problem:
update MASTERMICODES t1
set t1.TEMPTA = ( select t2.TAFCODE
from TA_FEATURES t2
where t2.FCODE = t1.FCODE
)
It returns Error report:
SQL Error: ORA-01427: single-row subquery returns more than one row
01427. 00000 - "single-row subquery returns more than one row"
*Cause:
*Action:
I want it to return more than one row...in fact I want it to make on all rows that have the same fcode between tables.