PL/SQL :: Attempting To User PIVOT And DENSE RANK In A Query
Oct 22, 2012
I am attempting to user PIVOT and DENSE RANK in a query the following is the query and the record set it returns (condensed and de-identified)
"select * from(
select * from (select dense_rank() over (partition by 1 order by cal.weeksort desc) WEEK_nbr,
u.user_title Manager_Title, replace(hier.manager, '<br>',' - ') Manager,
replace(hier.user_hin, '<br>',' - ') user_name,
to_char(cal.calendar_date_week - 6, 'MM/DD/YYYY') ||' - '|| to_char(cal.calendar_date_week, 'MM/DD/YYYY') Week_of,
upper(substr(cal.day_of_week, 1,3)) DOW, count(distinct Pers_gen_key) cnt from apexim.hrw_member_action act
[code]....
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May 1, 2013
Here table - tac has
row1
-----
X
X
X
B
[code]...
I want ouptut like using sql query with out using dense_rank function,
row1 row2
X 1
X 1
X 1
B 2
[code]...
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Mar 10, 2013
I am trying to find out the difference in time between peoples memberships and also the order that these memberships are taken out in. So far I have added in a rank statement to work out the order the memberships were created in, but now want to look at the difference between the dates returned. The SQL I used is:
SELECT owner_party_id,
mem_number,
support_id,
mem_start_date,
RANK() OVER (PARTITION BY owner_party_id ORDER BY mem_start_date ASC) MEMBERSHIP_SEQUENCE
FROM membership_all
WHERE version_type = 'CUR'
AND owner_party_id IN ('65051', '65051', '65348', '65348', '65607', '65607', '65607')
to get:
"OWNER_PARTY_ID"|"MEM_NUMBER"|"SUPPORT_ID"|"MEM_START_DATE"|"MEMBERSHIP_SEQUENCE"
65051|318874751|8014747|01-MAR-10|1
65051|412311060|21502883|15-AUG-12|2
65348|308672459|3526913|01-MAY-10|1
65348|409951130|20950524|18-JUN-12|2
65607|315830192|7510133|17-MAY-10|1
65607|406448110|20024246|16-MAR-12|2
65607|409738130|20903556|14-JUN-12|3
Now I would like to calculate the difference between the start dates of each of the owner_party_id groups, so to get something like this:
OWNER_PARTY_ID|MEM_NUMBER |SUPPORT_ID|MEM_START_DATE |MEMBERSHIP_SEQUENCE|Diff
65051|318874751|8014747|01-Mar-10|1|
65051|412311060|21502883|15-Aug-12|2|898
65348|308672459|3526913|01-May-10|1
65348|409951130|20950524|18-Jun-12|2|779
65607|315830192|7510133|17-May-10|1
65607|406448110|20024246|16-Mar-12|2|669
65607|409738130|20903556|14-Jun-12|3|90
I think that I need to use the Lag function in, but I am not too sure if it can be linked to look at the data within a grouping of owner party id, as it would make no sense to calculate the difference in dates for two different owner party ids.
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Dec 2, 2010
the following statement gives each customer owns how many promotions.
Q:) how do i retrieve a customer who has max. promotions?
SELECT C.CUSTOMER_ID,COUNT(P.PROMOTION_ID)
FROM PROMOTIONS P,CUSTOMERS C
WHERE C.CUSTOMER_ID = P.CUSTOMER_ID
GROUP BY C.CUSTOMER_ID
=====================================================
CUSTOMER_ID COUNT(P.PROMOTION_ID)
-------------------------------------
001 | 5
002 | 8
003 | 4
004 | 6
005 | 5
006 | 3
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Mar 24, 2013
I created a sample table named as "Student" with following data. table contains two columns only - stdid & marks.
stdid marks
10 75
20 60
30 60
40 45
50 30
I have to find the rank of students based on their marks in descending order.Is there a way to get rank without using RANK function?
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Jan 24, 2011
I have a requirement to write a single sql query where i can generate the pivot report. Found some of the examples in Google search. But here we are hard coding the values if it is limited like month in this example.
i want to write similar query to represent the amount based on product type , i have around 200 types of products. I can't write case/ decode statement those many times.
query which will produce the output in pivot format , dynamically depending the number of values.
select Product,
sum(case when Month=�Jan� then Amount else 0 end) Jan,
sum(case when Month=�Feb� then Amount else 0 end) Feb,
sum(case when Month=�Mar� then Amount else 0 end) Mar
from Sales
group by Product
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Apr 23, 2007
Is there anyway to pivot the results of a query?
so if i have:
SELECT GROUP, count(*)
FROM GROUP
GROUP BY GROUP
And it give the following output:
A 10
B 50
c 24
Is there anyway to put into this format?
A B C
10 50 24
I am doubting that there is and that i am going to have to handle this in my code later, but it never hurts to ask!
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Dec 17, 2011
I've tried for pivot query feature of Oracle 11g, but I'm trying for pivot result on multiple column.
Herewith I'm displaying my try on single column pivot query.
SQL> select * from
2 (select deptno,job,sal
3 --,comm
4 from emp)
5 pivot (sum(sal) as payment for job in('CLERK','SALESMAN','MANAGER'))
6 order by 1;
[code]....
I've tried this one also, but it didn't seems to be working.
SQL> select * from
2 (select deptno,job,sal,comm
3 from emp)
4 pivot (sum(sal) as payment_sal,sum(comm) as payment_comm for job in('CLERK','SALESMAN','MANAGER'))
5 order by 1;
[code]....
I want result like below.
DEPTNO PAYMENT 'CLERK'_PAYMENT 'SALESMAN'_PAYMENT 'MANAGER'_PAYMENT
---------- ------- --------------- ------------------ -----------------
10 SAL1300 2450
20 SAL1900 2975
30 SAL 950 5600 2850
30 COMM 2200
is it possible to have multiple column pivot query.
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May 27, 2011
I'm using pivot query feature of oracle 11g and came across a strange situation where i need to pass a "select statement" in a "in clause" of pivot query.
SQL> CREATE TABLE TEST1
2 (
3 UIN NUMBER(8) NOT NULL,
4 TESTING_ID NUMBER(4),
5 PFA_RESULT VARCHAR2(30 BYTE)
6 );
[code]....
I have tried with pivot xml but it not giving desired output in sql*plus session.It is giving unreadable output.
select * from
(select uin,testing_id,pfa_result from test1)
pivot xml (max(pfa_result) as result
for (testing_id) in (select distinct testing_id from test1));
[code]....
Here actually i want to use "select distinct id from test1" instead of "in (11,12,13,14,15)". Because i don't know how many id's will be there and of which values. e.g. 11 or 21 or 25.
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Jul 20, 2011
me in building a query. I want to show the result of the query just like pivot table.
Test case
CREATE TABLE CPF_YEAR_PAYCODE
(
CPF_NO NUMBER(5),
INC_DATE DATE,
PAYCODE_TYPE CHAR(1 BYTE),
[code]...
I want that my query should look like the format as attached in the xls sheet.
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May 8, 2012
I am having the following pivot query but I am not able to run it is giving error msg
ORA-00937: not a single-group group function
SELECT DISTINCT
C.SHORT_NAME,
MAX (
COUNT (DECODE (TO_CHAR (a.reg_date_cur, 'MON'), 'JAN', A.CAR_NO))
[code]...
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Feb 27, 2013
creating Oracle SQL query to fetch the information using PIVOT option.We are populating audit table using triggers. For every update, there will be two rows into audit table, one row with all OLD values and another with all NEW values. Also every updated is uniquely identified by Sequence No. Example for phone audit is mentioned below :
CREATE TABLE test_audit_phone
(
emplid VARCHAR2(10),
seqno NUMBER,
action VARCHAR2(3),
office NUMBER,
mobile NUMBER
);
Insert some rows into table.
INSERT INTO test_audit_phone VALUES ('100',1,'OLD',1111,9999)
/
INSERT INTO test_audit_phone VALUES ('100',1,'NEW',2222,9999)
/
INSERT INTO test_audit_phone VALUES ('100',2,'OLD',2222,9999)
/
INSERT INTO test_audit_phone VALUES ('100',2,'NEW',2222,8888)
/
Table will look like the following :
SQL> SELECT * FROM sysadm.test_audit_phone ;
EMPLID SEQNO ACT OFFICE MOBILE
---------- ---------- --- ---------- ----------
100 1 OLD 1111 9999
100 1 NEW 2222 9999
100 2 OLD 2222 9999
100 2 NEW 2222 8888
Now we have to present data in different format. For each field, display OLD and NEW values in column format.
EMPLIDFIELDOLDNEW
----- ------ ---- -----
100OFFICE11112222
100MOBILE99998888
Challenges :
1) Make pivoting with old and new values
2) For each field we have to show old and new values
3)if old and new values are same, dont show in report.
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Sep 6, 2010
I'm attempting to write some SQL to delete a record where it doesn't exist in one of three other tables. My SQL is below:
SELECT COUNT(*) FROM GAZETTEER_ADDRESSES
WHERE NOT EXISTS (
SELECT MEDICALS.*, REVIEWS.*, ADDRESS_HISTORIES.*
FROM MEDICALS INNER JOIN REVIEWS
ON MEDICALS.GADDRE_IDENTIFIER = REVIEWS.GADDRE_IDENTIFIER
JOIN ADDRESS_HISTORIES
ON REVIEWS.GADDRE_IDENTIFIER = ADDRESS_HISTORIES.GADDRE_IDENTIFIER
WHERE GAZETTEER_ADDRESSES.IDENTIFIER = MEDICALS.GADDRE_IDENTIFIER);
When I attempt to run this I receive the following error: ORA-00600: internal error code, arguments: [qcopcovm2], [0], [], [], [], [], [], []
I know it's not generally a good idea to delete records but in this case a large number of cases are incorrect and need to be reinserted and this is the quickest way of doing it.
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Jul 26, 2010
I've set up a query that creates 2 columns 'UVLCredit' and 'UVLDebit' and what I'm trying to do is subtract the 'UVLDebit' column from the 'UVLCredit' column and have the resulting value show up in a column called 'UVLTotal.
I'm multiplying 1 column times another to create a new column called UVLCredit, and then doing it again (with a different column) to create a 2nd new column called UVLDebit...the last thing I'm trying to do is to take the results of the 1st new column and subtract the results of the 2nd newly created column to create a 3rd new column called UVLTotal. The error states that the 'UVLDebit' column is an invalid identifier.
See code below....
CODESELECT
T.PO_RELEASE_NBR, T.PO_LINE_STATUS, T.FACILITY,
TI.STATUS_DATE, TI.QTY_ORDERED_UP,
TI.PO_UNIT_PRICE, TI.QTY_REC_TOTAL_UP, TI.QTY_INVOICED_UP,
[b]sum(TI.PO_UNIT_PRICE) * (TI.QTY_REC_TOTAL_UP) as "UVLCredit",
sum(TI.PO_UNIT_PRICE) * (TI.QTY_INVOICED_UP) as "UVLDebit",
[code]........
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Mar 19, 2010
I continue to get compile errors attempting a While Loop. Should I being using a For Loop?
DECLARE
v_item VARCHAR2(20) := &v_item;
v_cost vm_inventory.cost%TYPE;
v_expense CHAR(1) := '$';
loop_count Binary_Integer := 1000;
BEGIN
SELECT item, cost
[code]....
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Jul 22, 2009
I'm trying to do a pivot query in oracle to get the years from a column and make a separate column for each. I found an example of the code to use on the internet and i changed it for my own tables but i'm getting errors. Namely a "FROM keyword not where expected" error at the beginning of the 'avg(...' statements.
I have copied the code used in
select stud_id, 2006, 2007, 2008, 2009
from (
select stud_id,
avg(case when year=2006 then ((present/poss)*100) else null end) 2006,
avg(case when year=2007 then ((present/poss)*100) else null end) 2007,
avg(case when year=2008 then ((present/poss)*100) else null end) 2008,
avg(case when year=2009 then ((present/poss)*100) else null end) 2009
from attendance.vw_all_attendance_perc
group by stud_id
);
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Jul 20, 2010
I certainly know this is possibly but I am trying to do this on the fly and can't seem to work it out:
I have a table A:
ID Name Priority
-------------------
1 Smith 1
1 SSmith 2
1 ASmith 3
1 BSmith 3
2 John 2
3 Ed 1
and I am looking to create the following table from this:
ID Name Sum(Top3Priority)
--------------------------------
1 Smith,SSmith,etc 8
Now, I've got listagg working and everything appears to be going swimmingly but: for every listagg grouping on name I need to only sum the highest top 3 priorities. So in the example above there are four Smiths but I need to only sum the top 3 priorities which are 3,3,2 and ignore the 1 even though I do want all the listagg Smith's (SSmiht, ASmith, etc) in there.
Now I can sum the priority, but don't really know how to sum only the top 3 in any ID ? There can be 1 to n ID's so if there are only 2 ID's I want to sum those 2, if there are 3 all 3 and 4 upwards only the top 3.Here is a snippet of the SQL I am using
SLECT id,
listagg(MN_CR_LOOKUP.f_name, ',') within group (order by Priority)) roadname,
**** sum top 3 here ?****
count(*) "NumI", Sum("Elevation") "CombinedElevation"
FROM jc,
[code]...
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Mar 27, 2013
I need to return which hour for a given date range had the most calls. I have a query that works but it is inelegant and I'm pretty sure I could do better. I'm pretty new to analytic queries so go easy...
select hour,
calls
from
(
select hour,
calls,
rank() over (ORDER BY calls desc) as ranking
from
(
[Code]....
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Dec 2, 2010
how do i retrieve only last rank row from table ?
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Oct 4, 2013
I've below table.
with tmp_tbl as
(select 'H1' as hh_id, 'C1' as cust_id, 2 as f_rnk, 'F' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100203','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C2' as cust_id, 1 as f_rnk, 'M' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100303','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C3' as cust_id, cast(null as number) as f_rnk, 'U' as gender, to_date('20130103','YYYYMMDD') as purch_dt,
[code].....
Now i need to rank each cust_id in each hh_id based on below conditions.
1) If atleaset one cust_id in hh_id has f_rnk then gender 'F' with highest f_rnk (more then one F with same f_rnk then the one with oldest first_dt), if no 'F' then gender 'U' with highest f_rnk ((more then one F with same f_rnk then the one with oldest first_dt)), if no 'F' and 'U' then consider 'M' (more then one M with same f_rnk then the one with oldest first_dt).
2) If the above is not met (no cust_id in hh_id has f_rnk populated) then i've to rank based on purch_dt. Gender 'F' with recent purch_dt (if more than one F in household with same purch_dt then the one with oldest first_dt), if no 'F' then gender 'U' with recent purch_dt (if more than one U in household with same purch_dt then one with oldest first_dt), if no 'F' and 'U' then consider 'M' (more than one M in household with same purch_dt then the one with oldest first_dt).
3) If the above criteria is also not met, then rank based on gender_cd. Gender 'F' will have first preference then 'U' and then 'M'.
My output :
HH_ID CUST_ID F_RNK GENDER PURCH_DT FIRST_DT F_RNK_RANK PURCH_RANK GENDER_ONLY_RANK
----- ------- ---------- ------ ----------- ----------- ------------ ------------ -----------------
H1 C1 2 F 1/2/2013 2/3/2010 1
H1 C2 1 M 1/2/2013 3/3/2010 2
H1 C3 U 1/3/2013 4/3/2010 3
H2 C4 F 4/3/2013 10/2/2009 2
H2 C5 M 5/5/2013 8/8/2010 1
H3 C6 F 5/6/2008 1
H3 C6 M 7/8/2010 2
I've tried below query with one condition, but it's giving f_rnk_rank for all records. How can i include multiple conditions in the rank function.
with tmp_tbl as
(select 'H1' as hh_id, 'C1' as cust_id, 2 as f_rnk, 'F' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100203','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C2' as cust_id, 1 as f_rnk, 'M' as gender, to_date('20130102','YYYYMMDD') as purch_dt, to_date('20100303','YYYYMMDD') first_dt from dual
union
select 'H1' as hh_id, 'C3' as cust_id, cast(null as number) as f_rnk, 'U' as gender, to_date('20130103','YYYYMMDD') as purch_dt, s hh_id, 'C5' as cust_id,
[code]....
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Jul 13, 2011
there is a way when doing the Rank Function in PL/SQL to pass the field that will be ranked as an override.
SELECT rank(p_ColumnAmt) within group (order by p_ColumnNm desc) rank
INTO v_RnkNoAmt
FROM Table_name
WHERE ??????;
p_Column is the amount I am ranking
p_ColumnNm is the actual field name to Rank.
When I pass the field name with an override I do not get the correct rank back. If I run the Select with the actual field name curr_1_mth_amt, I get the correct rank.
I have about 70 different field to Rank and do not want to make a procedure for each field.
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Feb 1, 2012
I have a SQL statement that return the following result.
col1
----
a
a
b
b
a
c
c
c
c
What i need is to eliminate the duplication and return the result as the following.
col1
----
a
b
a
c
Using group by or distinct will eliminate the third row "a" and will not return it ordered.My idea is to generate another column that rank the result as following.
col1rank
------------
a1
a1
b2
b2
a3
c4
c4
c4
c4
so using the following SQL query will return the result as needed
select col1, rank
from T
group by col1, rank
order by rank;
col1rank
------------
a1
b2
a3
c4
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Mar 26, 2012
I have this code which simply gives me the count of term.
SELECT
OUA_ID
,COALESCE (MAX( DECODE( TERM, 0603, TERM_COUNT, NULL ) ), 0 ) "TERM_0603_CNT"
,COALESCE (MAX( DECODE( TERM, 0702, TERM_COUNT, NULL) ), 0 ) "TERM_0702_CNT"
,COALESCE (MAX( DECODE( TERM, 0705, TERM_COUNT, NULL ) ), 0 ) "TERM_0705_CNT"
,COALESCE (MAX( DECODE( TERM, 0707, TERM_COUNT, NULL ) ), 0 ) "TERM_0707_CNT"
FROM(
SELECT DISTINCT
OUA_ID, TERM_COUNT, TERM
FROM(
SELECT OUA_ID, TERM ,PROVIDER_CDE, COUNT(*) TERM_COUNT
FROM TABLE
WHERE PROVIDER_CDE = 'BILL'
GROUP BY OUA_ID, TERM, PROVIDER_CDE)) GROUP BY OUA_ID
Gives:
OUA_IDTERM_0603_CNTTERM_0702_CNTTERM_0705_CNTTERM_0707_CNT
32710 0 3 7 0
45726 2 0 1 0
Is there a way i could used the rank function (with decode) to only display the 1ST (First) and 2nd(Second) most used term per OUA_ID?
So i get this:
OUA_ID1st MOST USED2nd MOST USED
3271 705 702
45726 603 705
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Aug 30, 2012
I have the following table :
CREATE TABLE A_TEST (A INTEGER, B INTEGER, C INTEGER, D INTEGER, FLAG CHAR(11));
INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
INSERT INTO A_TEST (A,B,C,D) VALUES(1,2,3,4);
INSERT INTO A_TEST (A,B,C,D) VALUES(2,4,5,8);
[code].......
I would like to perform an update on the FLAG column by setting to "D" if it is a duplicate record.1,2,3,4);
I would like to use the rank function.
Desired update:
A B C D FLAG
1 2 3 4
2 4 5 8
1 2 3 4 D
2 4 5 8 D
7 2 3 4
9 2 3 4
7 2 3 4 D
1 2 3 4 D
5 4 5 8
2 2 3 9
2 4 5 8
6 2 3 4
1 3 3 4
8 2 8 4
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Mar 17, 2013
can we create rank on a particular column without using rownum and rank function.
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Jan 5, 2012
I am trying to use RANK() clause with a window clause...is that possible to use both together?
like
select col1, col2, col3,
RANK() OVER (ORDER BY col3 desc RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) RK
from table t
but getting error in SQL Developer
ORA-00907: missing right parenthesis
00907. 00000 - "missing right parenthesis"
*Cause:
*Action:
Error at Line: 2 Column: 33
The reason why i need to rank in window clause because i have data like this
Name Marks Quiz
Ali 10 1
John 20 1
Sara 30 1
John 40 2
Sara 50 2
Ali 20 2
...
...
and so on
I want to rank them based on their cumulative sum marks after every test..ranking should be in such a way that it should look current row and preceding rows
like this
Name Marks Quiz cumulative_marks rk
Ali 10 1 10 4
John 20 1 20 3
Sara 30 1 30 2
Peter 100 1 100 1
John 40 2 60 3 ==> becuase John has now third most overall cumulative marks (60) after quiz 2.
Sara 50 2 90 2 ==> becuase Sara has now 2nd most overall cumulative marks (90) after quiz 2.
Ali 20 2 30 4 ==> becuase Ali has now fouth most overall cumulative marks (30) after quiz 2.
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Sep 1, 2010
Am working on a workbook to count the number of enrolments and withdrawals in the program. My data looks like this
name semester status year
A 1 enrol 2010
A 2 withdraw 2010
A 3 enrol 2010
B 1 enrol 2010
B 2 withdraw 2010
I want to count their latest status only. It should come up with
Total Enrol - 2
Total Withdrawn - 1
For total Withdrawn, I tried 'rank' and filter to equals 1 but it does not allow me. Is there any way to have this work?
Here's my calculation:(decode((FIRST_VALUE(status) OVER(PARTITION BY year, name ORDER BY semester DESC)),'withdraw', name)) It tells me that 'Aggregation of Analytic function not allowed'
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Oct 27, 2010
I need query to retrive the default tablespace of the current user, when the user is not a dba, i.e. user doesn't have access to dba_users table.
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Oct 14, 2010
can we use user define value (how to use '&') in nested function of a query ?
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Nov 2, 2012
I have two table APPLICATION_1 and APPLICATION_2, where user's login date is captured.There will be multiple records for each user.Same user may or may not be present in both tables.
The requirement is to find those users who have not logged-in in the last 3 years.
-- Test Case
DROP TABLE application_1;
DROP TABLE application_2;
CREATE TABLE application_1
(
seq NUMBER ,
user_id VARCHAR2(30),
[code].....
Using the below query I'm able to get the desired output.
SELECT user_id, MAX(login_date) last_login_date FROM (
SELECT user_id, MAX(login_date) login_date FROM application_1 GROUP BY user_id
UNION ALL
SELECT user_id, MAX(login_date) login_date FROM application_2 GROUP BY user_id
) GROUP BY user_id
[code].....
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