SQL & PL/SQL :: Procedure That Displays Customer ID / Customer Name / Product Name

Dec 7, 2011

I'm trying to write a procedure that displays customerID, customer name, product name, and the total quantity of products the customer purchased, and the total amount the customer paid.Here's the relevant Schema tables:

CREATE TABLE Product (
Product_ID NUMBER(6) NOT NULL,
Description VARCHAR2(30),
Product_Code CHAR(4));
[code]....

Now I'm trying to wrap the above query in procedure code. I believe that I need a cursor, but I don't know what kind of cursor variable to store the result of the SELECT statement in because the query selects columns from several different tables, and I'm not sure how to terminate the FOR loop (but I think probably I can use the EXIT WHEN cursor%NOTFOUND;Here's the procedure code I have written thus far:

CREATE OR REPLACE PROCEDURE find_customer_statistics IS
DECLARE
TYPE cust_stats IS REF CURSOR; weak ref cursor declaration

SELECT sales_order.customer_id, customer.name, product.description, SUM(line_item.quantity),
SUM(line_item.subtotal)
FROM sales_order, customer, product, line_item
WHERE customer.customer_id = sales_order.customer_id
AND line_item.order_id = sales_order.order_id
[code]....

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Nov 3, 2010

i'm working on procedure to send invoices to customer thru mails.

i'm using UTL_Mail package to send html content in a mail , it's working if i'm using my company mail exchange BUT if i put "xxxx@hotmail.com" or "xxxx@yahoo.com" it doesn't work and raise

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May 14, 2011

I am trying to create a procedure that will send in the customer id, password and new password. The procedure will say if it has been updated or not. this is the code i have.

--Patty Carson
--Assignment 3 Question 3
--Description: Allows the user to change a password for a customer
CREATE or REPLACE procedure ChgPwd
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Customer is running on MySql

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Nov 21, 2012

I am writing a query to give me all CustomerID's in the report. I will give you the tables that I am trying to get the query from.

1. Customer table:
Custid (pk)
memberid
fname
lname
bname

2. Cust_cokeid table:
Cokeid (pk, fk)
Custid (pk, fk)

3. Cokeid table:
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[code]....

Here is the query I have wrote:

SELECT customers.custid AS CUSTID,
customers.memberid AS MEMBERID,
customers.bname AS BNAME,
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drpepper_rebate.totalcarb AS TOTALCARB,
drpepper_rebate.totalncb AS TOTALNCB,

[code]....

I have more then 700 customer records in the Customers table, but so far I can only pull 500 records.

Reason I am trying to pull all the records from the customer table is because I want to find out who is missing cokeid and Drpepid.

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Nov 19, 2010

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/
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/
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Nov 25, 2012

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This is not very practical when keeping our reference clean and when deploying/syncing our reference with a customer db: One customer would receive the objects of other customers on a deploy.

Is there a common solution to this problem? We were thinking about having a separate scheme for each customer. That way we would have our standard, untouched scheme with the basic functionality and the customer schemes with the individual content.

To make it a bit more concrete: We have around 100 basic tables that make the most of the content/functionality of the software. Each customer might have between 1 -5 additional tables with "custom" data that is used in conjunction with the standard objects in individual packages, functions etc. The installations will be made on our customers systems. So I have in mind to have schemes 0001, 0002, etc for each customer IN OUR REFERENCE. But we would then deploy only the scheme for that certain user when installing on their system. So for example for customer 0001 I would deploy the STANDARD and 0001 scheme

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i mean i want to fetch only 3rd postion frm the column cstomer_ts and tht should starts with 'Foundation'

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Feb 16, 2012

I am student of Oracle programming(SQL).Has a question on MIN and MAX functions:

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SELECT DISTINCT customers.customer_first_name||' '||customers.customer_last_name AS Customer_name,MAX(order_date) AS "Most recent order", MIN(order_date) AS "Oldest order"
FROM customers
INNER JOIN orders
ON customers.customer_id=orders.customer_id
LEFT JOIN order_details
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LEFT JOIN items
ON order_details.item_id=items.item_id
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Nov 15, 2010

How similar is PL/SQL to SQL? I'm trying to retrieve all data from a customer table and print out each customer information one by one:

DECLARE
CURSOR all_customer IS
SELECT *
FROM customer;
BEGIN
DBMS_OUTPUT.PUT_LINE(all_customer);
END;

but I really don't know the correct syntax. The Powerpoint slides the professor gave is not useful at all.

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Dec 17, 2010

I have got 2 users as user1 and user2.I have used the following statements from user 'user1':

create role GENEVAOBJECTS;
grant select, insert, update, delete on PRODUCT to GENEVAOBJECTS;
grant GENEVAOBJECTS to user2;

In the above statements, product is a table. Now, I could able to access this table from user 'user2'. But however if I write a procedure in user2 schema accessing the table product, then the procedure is not getting compiled.

create or replace procedure test_prc as
v_test number(9);
begin
select product_id into v_test
from PRODUCT where rownum=1;

[code]...

why I cannot access that table from procedure?

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Apr 16, 2012

The view below creates, however displays duplicate rows. Why is this may I ask?

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[Code]....

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Jun 2, 2010

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To do this I add following line into user bash profile in application server:

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...
....
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Feb 23, 2010

I have a table that has three columns.
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By doing the following:

select userid, to_char(creationtimestamp,'YYYY-MM-DD'), count(*)
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I can get the following results
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1 - 2/21/2010 - 8
1 - 2/22/2010 - 3
2 - 2/22/2010 - 2
1 - 2/23/2010 - 1
4 - 2/23/2010 - 6
6 - 2/23/2010 - 1

What I'm trying to get is
2/21/2010 - 1
2/22/2010 - 2
2/22/2010 - 3

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Aug 24, 2012

I recently needed a select list that would allow you to choose from a years worth on Mondays starting with the current week's Monday. It will return the date of that Monday. I thought others might be able to use this too... Plus I wanted to be able to find this in the future.

SELECT DISTINCT
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As of today (Friday, August 24th) the above would return:

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September 3, 2012 03-SEP-12
September 10, 2012 10-SEP-12
September 17, 2012 17-SEP-12

[Code]....

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Jul 29, 2010

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Dec 14, 2011

I am trying to query a Oracle database table that contains sample records like the one below...

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09/12/2011 L1 6 2
09/12/2011 L2 3 7
10/12/2011 L1 4 1
10/12/2011 L2 3 3
11/12/2011 L1 2 2
11/12/2011 L2 2 0
12/12/2011 L1 4 1
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DATE LOC1 LOC2
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Nov 25, 2011

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I am new to PL/SQL environment.. ( USING PL/SQL Oracle)

SELECT TABLE1.PRODUCTID, TABLE1.TYPE , TABLE1.PRODUCT, TABLE2.#SOLD
FROM TR.TABLE1
INNER JOIN
PR.TABLE2
ON (TR. PRODUCTID = PRODUCTID )

Query result.

Product ID     Product          Type          #Sold
1     Fruit          Banana          2
2          Food          Rice          4
3          Food          Sugar          6
4          Fruit          Orange          2
5          Fruit          Apple          10
6          Food          Sugar          12
7          Food          Corn          3
8          Fruit          Apple          5
9          Fruit          Banana          2
10          Food          Sugar          1
11          Fruit          Banana          5
12          Food          Sugar          7

But would like to add Four More Column and group by by PRODUCT.Final Result will look like :

     {Product}     ,     {Type}     ,     {#Sold}     ,     0 to 3     ,     4 to 9     ,     >10          Total Sold     
          ,     {Corn}     ,     3     ,          ,          ,                    
          ,     {Rice}     ,          ,     4     ,          ,                    
          ,     {Sugar}     ,          ,          ,          ,     26               
     {Food}     ,          ,          ,          ,          ,               33     
          ,     {Apple}     ,          ,          ,          ,     15               
          ,     {Banana}     ,          ,          ,     9     ,                    
          ,     {Orange}     ,          ,     2     ,          ,                    
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----- ------ ----
121 ES 03/12
121 NT 30/12
131 ST 03/12
13 WT 04/12
150 ES 05/12
150 ES 06/12
150 ES 07/12
160 MN 05/12
160 ES 06/12
160 ES 07/12
162 NT 08/12

I need a query to display only 150 and 162 as they have purchased only one product.

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Feb 11, 2011

so here is the query : For every state, list the most popular product. Here is the query I have so far :

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Result :
STATE PRODUCT_NAME COUNT(*)
---------- -------------------- ----------
New Jersey Computer 3
Texas Computer 1
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