i would like to know how can i used the OR "|" with REGEXP_SUBSTR
SELECT REGEXP_SUBSTR('500.90 Oracle Parkway, 12-12-2000 78 Redwood Shores, CA','([0-9]{1,2})-([0-9]{1,2})-([0-9]{4})') "REGEXPR_SUBSTR" FROM DUAL;this two condition
([0-9]{1,2}) ([0-9]{1,2}) ([0-9]{4})
or this i did it like this
I would like to use REGEXP_LIKE condition expression with '[:alnum:]' operator in Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 for to check the string is alphanumeric or not.Why do i need: I have xinput field [RAW(24)] which not sure to contains always an alphanumeric string. We should use only when xinput field is an alphanumeric string.
x varchar2(50); x:=rtrim(ltrim(utl_raw.cast_to_varchar2(xinput)));
how should i use REGEXP_LIKE
select 'TRUE' from dual where REGEXP_LIKE( 'True', '[:alnum:]') select 'TRUE' from dual where REGEXP_LIKE( 'False%*^tt123.***', '[:alnum:]')
I am trying to write a pattern that will return multiple numbers when it finds the string "My String" in a Text such as
Text String: My String 5 Test Need a good regExp 34 to test multiple 12334 occurrences of the same 566 search string My String 3 hopefully this time My String 7 with three of these'
Expected Output: 5 3 7
I managed to write Regular expression that returns only for the first match as shown below.
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production PL/SQL Release 11.2.0.3.0 - Production CORE 11.2.0.3.0 Production TNS for HPUX: Version 11.2.0.3.0 - Production NLSRTL Version 11.2.0.3.0 - Production
Can I call a function from a regexp back reference? I would like to call SELECT UTL_ENCODE.TEXT_ENCODE (:mytext, 'WE8ISO8859P1', 1) FROM DUAL; for all text after Password= and before line break WITH t AS (SELECT '[MyDB] Army=@MyDBarmy Navy=@MyDBnavy Airforce=@MyDBairf
Current Output ( ADJ#1-2M1YE2 TYPE 20100524 20100624 1MO/0DY ) ===============================================================================================
1) I would like to alter that code above and substr the back 68 characters only with the 12 spaces padded in front, and the trailing nulls to total 80 characters staying as is. How would I put the below substr into that piece of code above?
2) I also would like the take whatever else there is preceding the 69th character counting it from the back and calling the column ADJ_FIRST_LINE.
Desired Output2 (ADJ#1-2M1YE2 TYPE)
No leading or trailing nulls and This is not a fixed amount of characters. ===============================================================================================
Result would be:
ADJ_FIRST_LINE ----------------- ADJ#1-2M1YE2 TYPE ADJ_SECOND_LINE --------------- 20100524 20100624 1MO/0DY ===============================================================================================
Can we have substr(date) as column name. I am trying to create a query where in I need to achieve something like this select s.xyz Today,s.abcd "6 Months ago" || to_char(add_months(sysdate,-6),'Mon rrrr') ||')'from sales_tab s.
DECLARE var VARCHAR2(4000); BEGIN SELECT DBMS_LOB.SUBSTR(v_clob,4000,1) INTO var FROM test_clob; END; ** v_clob is a CLOB column in test_clob table.
I get the below error:
wrong number or types of arguments in call to 'SUBSTR'"SYS"."DBMS_LOB"."SUBSTR": invalid identifier...I have execute privileges to DBMS_LOB.SUBSTR function.
I would like to have a column heading as follows in double inverted comma. but sqlplus environment returns column heading length equal to output value.
SQL> select substr('The independence day', 5,12) "Example of substr function" 2 from dual;
Example of s ------------ independence
I know that default column heading length is 30 character long.
but my column heading is less than 30 character long (which is 26)
How can i have column heading as Example of substr function?