Given the below, how do i get all 3 parameter values (SDI, date_day and value) corresponding to the max(date_day) only the results shown do not included the required associated value
drop table my_r;
create table my_r (
SDI NUMBER(6) NOT NULL
,DATE_DAY DATE NOT NULL
,VALUE NUMBER(8,2) NOT NULL
,CONSTRAINT my_r_pk PRIMARY KEY (sdi,date_day));
[code].......
I'm trying to work out how to take a table like this:
IDDate
12502-Feb-07
12516-Mar-07
12523-May-07
12524-May-07
12525-May-07
33302-Jan-09
33303-Jan-09
33304-Jan-09
33317-Mar-09
And display the data like this:
IDPeriodPeriod StartPeriod End
125102-Feb-0702-Feb-07
125216-Mar-0716-Mar-07
125323-May-0725-May-07
333102-Jan-0904-Jan-09
333217-Mar-0917-Mar-09
As you can see, it's split the entries into date ranges. If there is a 'lone' date, the 'period start' and the 'period end' are the same date.
I have a two date fields in my form; valid from date and expiry date.
Currently my valid from date has an inital value property of $$date$$ which automaitcally brings up todays date.
I need my expiry date to automatically show a date 15 years after this date?
Version : 4.1.1, I have a tabular form on a DB table. One of the columns is a date field. When the user hits the "add Row" button on the tabular form, I want the Date field to be defaulted to sysdate. Here is what I have tried so far,
1. Created a "hidden" item P1_SYSDATE and populated the default value with sysdate. After this, under the DB tabular report date field, I used default type - Item/application on this page and entered P1_sYSDATE
2. Instead of populating the default value of the P1_SYSDATE hidden item, I created a before regions process and added
:P1_SYSDATE := sysdate
and added P1_SYSDATE to default type of the tabular date field with default type as "ITem/application on this page.
I get the error
ORA-01790: expression must have same datatype as corresponding expression
I tried to_Char(sysdate,'dd-mon-yyyy') and then converting it back to to_date. still no luck.
When I run a query form the the Query Window in Visuial Studios 2012 all the date fields truncated to 'mm/dd/yyyy', but i need the full date returned. I am able to get full date from TO_char(MyDateField, 'yyyy-mm-dd hh24:mi:ss'), but if I do TO_DATE(MyDateField, 'yyyy-mm-dd hh24:mi:ss') it only returns 'mm/dd/yyyy'. I'm sure this is a simple setting in Visual studios but I cant find it to save my life. Is there there a way to have the full date returned by default?
View 0 Replies View RelatedI am a novice in oracle
I have 2 columns in my table
->Col1 with experience in years entered as an integer
->Col2 with current date
I need to add another column as a date value adn for that i need to subtract Currentdate-Col1 when i tried currentdate-Col1 it just subtracted the days i need the formula to subtract years and give a date
I have worked in DB2 and all u need to do there was add the keyword years at the end but in oracle the same does not work
I am not able to load complete date along with time in the date column. here is my table desc
DESC STAGE
Name Null Type
----------------------------------
TABLE_NAME NOT NULL VARHCAR(20)
RECORDCOUNT NUMBER
CREATED_DATE NOT NULL DATE
my control file is like this
LOAD DATA
APPEND
INTO TABLE SCOOP.STAGE
FIELDS TERMINATED BY ","
( TABLE_NAME
,RECORDCOUNT
,CREATED_DATE DATE(16) "YYYYMMDDHH:Mi:SS"
)
the data gets loaded, but it appears like this in the table
HIGHSCHOOL3080606-JUN-12
MIDDLESCHOOL8768006-JUN-12
BUT I WANT COMPLETE DATE AND TIME (HH:MI:SS) , HOW CAN I GET IT (THIS IS HOW I WANT 06-JUN-12 11:07:33)
I would like to inquire how do I code my select statement if my user enter a search date range(search startDt: 01/08/2012 and search endDt :30/09/2012) and I will like to retrieve only the 7records out from my table as shown below ?
STARTDT_ ENDDT_
01/08/2012 01/08/2012
01/06/2012 31/12/2012
01/08/2012 01/08/2012
01/09/2012 01/09/2012
01/09/2012 31/12/2012
01/07/2012 01/07/2012->not retrieved out
01/08/2012 01/08/2012
01/01/2012 31/12/2012
Write a program to declare a date variable and assign it to the current system date. Depending on the day of the month the program should print the following:
If day is 1-10 then print "It is day<day number> of <month name>. It is early in the month".
If day is 11-20 then print "It is day<day number> of <month name>. It is the middle of the month".
If day is 21-31 then print "It is day<day number> of <month name>. It is nearly the end of the month".
For example, if the day is November 30, then print "It is day 30 of November. It is nearly the end of the month".
How can we partition a table based on date if it does not have a date column.
Actually I have to compare two tables on daily basis and fetch few rows from those two tables and enter it to a third table.But both these tables does not have a date column.
I am confused if i need to alter those tables and add date column or if there is some way in which i can compare the data from the two tables for that particular day only and not the whole table data.
I have a small prolem thats best described like this....
a table called TONY with a field named VISITED (date as YYYYMMDD).
We want to populate the field TIMESTAMP (Last visited timestamp, 18 digits) using midnight or 00:00:00 on VISITED value.
Something like:
UPDATE TONY SET TIMESTAMP = �(whatever the formula is involving VISITED).
but i cannot figure out the best way to derive the TIMESTAMP value...
it's a date to epoch conversion, and i can find many examples of Epoch to date, but thats the wrong way around for me i'm afraid!
Oracle 11gR2 by the way...
i have a table with the following description
create table gl_periods(period_name varchar2(10),transactions number (2) );
with the data as :
period_name transactions
------------ --------------
JAN-10 12
FEB-10 12
MAR-10 8
APR-10 23
ADJ_TOM-10 25
MAY-10 37
JUN-10 41
JUL-10 10
PHY_JAY-10 6
AUG-10 14
SEP-10 22
My requirment is to find out the period names and transactions which are in valid date formats and are less than sysdate and the non date formats are adjustments made by different users for their transactions
I want to load data from a file using sqlldr.I have a table commissions
(
technician_id char(5)
, tech_name char(30)
, Comm_rcd_date DATE
, Comm_Paid_date DATE
, comm_amt number(10,2)
)
my file is
00001,TIMOTHY TROENDLY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0007,123.56
00002,KENNETH KLEMENZ,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0009,123.56
00003,SHUNDAR ARDERY,2011-03-04T01:45:12+0006,2011-03-04T01:45:12+0005,123.56
write a ctl file to load this data.
I want to get data for month to date. For example, If I pass today or any day date as parameter then i should get data for that month(month of passing date) up to passing(parameter) date. As well as i have to get year to date.For example, If I pass today or any day date as parameter then i should get data for that financial year(year of passing date) up to passing(parameter) date. how to get month to date and year to date data.
View 3 Replies View RelatedA field named xxx_date is a text item which we have to enter manually so as to update a record in that particular date. This is a mandatory field without which we cannot continue the data entry..
I am getting this error while trying to update the record
FRM-40509 :Oracle error :unable to update record
I have kept the enabled = yes
required=no
data type=Date.. in the property pallet
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
select to_date('28-FEB-2013') - TO_DATE('01-FEB-2013') FROM DUAL
gives me 27 days, what should I do to get 28 ? meaning include both the start and end dates in the range ?
I need to convert the type of GMT to Local time, during data entry. I have a source table and a target table.
To make the insert get the most value, I have no problems:
insert into destination (SELECT * FROM WHERE source pointnumber = (SELECT MAX (pointnumber) FROM source));
But since times are different between the tables, I want to convert the data obtained to GMT -4:30 Time (Caracas - Venezuela), before inserting it.
I can use a function?
I have a date field that should be filled everyday with today's date and I need to get the days that were not entered.
i.e. :
CREATE TABLE TRY_F (DAT DATE);
INSERT ALL
INTO TRY_F VALUES (to_date('01/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('02/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('04/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('05/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('06/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('08/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('10/01/2011','DD/MM/YYYY'))
INTO TRY_F VALUES (to_date('14/01/2011','DD/MM/YYYY'))
SELECT * FROM DUAL;
I need a smart way of getting the dates that were missed in DAT.
Lets say the contents of the table are like this -
key dte_start(number) dte_end(number)
1 20010101 20011231
1 20020101 20081231
1 20030601 20071231
1 20100101 20101231
2 20090101 20091231
2 20090401 20101231
2 20101231 20111231
2 20140101 20141231
3 20080101 20091231
3 20070101 20081231
3 20100101 20101231
3 20120101 20120630
I want the query to resolve overlapping dates as well as merge contiguous segment and leave non-contiguous segments as is. The final result of the query should be like this.
key dte_start(number) dte_end(number)
1 20010101 20081231
1 20100101 20101231
2 20090101 20111231
2 20140101 20141231
3 20070101 20101231
3 20120101 20120630
I tried using the lead over partition along with the standard overlap query and case logic to get the results but couldn't get it to work.
I am having problems with the XMLTable function. I cant get it to see the entire date/time value in a date field. This wont work
select x1.* from XMLTABLE('/DOCUMENT' passing xmltype('<DOCUMENT><STR>abc def ghi</STR><NUM>1234</NUM><DT>2013-02-17T04:24:02</DT></DOCUMENT>') columns STR varchar2(25), NUM number, DT date) x1;
However if I change the DT tag to just the date only "2013-02-17" it works. Why wont Oracle see the entire date/time format even if its ISO 8601 compliant?
Oracle DB: 11.2.0.3.0
The oracle table has the following fields,
A_ID, B_ID, CONSUMER_ID, U_DATE, ACTIVE_FLAG.
1 0 111 Jan-02-07 N
1 1 111 Feb-02-07 N
1 2 111 Mar-02-07 Y
1 3 111 Apr-02-07 Y
1 4 111 May-02-07 Y
1 1 222 Feb-06-07 N
1 1 222 Mar-06-07 N
1 1 222 Jun-06-07 Y
1 1 222 Jul-06-07 Y
The table has incorrect data. meaning for each consumer_id we want the ACTIVE_FLAG to be 'Y' only for it's latest record and the rest to be inactive. i.e. we want the data as follows:
A_ID, B_ID, CONSUMER_ID, U_DATE, ACTIVE_FLAG.
A_ID, B_ID, CONSUMER_ID, U_DATE, ACTIVE_FLAG.
1 0 111 Jan-02-07 N
1 1 111 Feb-02-07 N
1 2 111 Mar-02-07 N
1 3 111 Apr-02-07 N
1 4 111 May-02-07 Y
1 1 222 Feb-06-07 N
1 1 222 Mar-06-07 N
1 1 222 Jun-06-07 N
1 1 222 Jul-06-07 Y
I'm trying to run a script that will sum column values from a table using only a certain period of time in example below only January submissions. However, some of those rows have the same date and I want to have the latest time row of that day in the count.
Oracle 10g
sample 'submit' table
pk loan submit_time
1 105000 1/17/2011 08:05:23 AM
2 204954 1/17/2011 07:59:53 AM
3 159000 1/14/2011 05:25:35 PM
4 215000 1/05/2011 01:06:12 PM
5 340415 12/18/2010 4:34:12 PM
How to get the payment date less than the sch date?
example:
1) for 07/24/2012 sch date the nearest payment date is 07/27/2012.
sch date should be less than the payment date.
Sch dates 07/24/2012 and 07/26/2012 are less than payment date 07/27/2012 but we take the least one.
2) sch date 07/27/2012 is less than the payment date 08/08/2012 so 07/27/2012
Below is the scripts and output needed.
create table cust_sch_tbl
(
customer_NUMBER number,
c_CODE char(5),
sch_DATE date
);
[Code]...
Output needed:
cust cust code payment date sch date
4611 c1 7/27/2012 7/24/2012
4611 c1 8/8/2012 16:57 7/27/2012
4611 c1 10/19/2012 16:37 10/11/2012
4611 c1 11/15/2012 10/30/
In my application I show the Date in Hijri using the NLS setting. but the issue that "i face a deference between the real hijri date with oracle hijri date"
Assume that the real hijri date on 18-SEP-2012 was 02/11/1433 in hijri but in oracle was 03/11/1433
when I execute the following query it shows me "1433/11/03", but the actual Hijri date is "1433/11/02"
select to_char(to_date('20120918','YYYYMMDD'),'YYYY/MM/DD', 'NLS_calendar='''||'ARABIC hijrah') FROM DUAL;
I want a hot backup from so and so date to so and so date.. i think its possible through RMAN..
View 2 Replies View RelatedI would like to select the max(date) in a table and then select the next previous max(date) in the same table and then show both dates with the calculated timespan between them.
So it would look like
max(date) next_previous_max(date) timespan_between
I want the max two dates in the table and the time between the two dates.
I need to find the oldest record in a table, and the latest record in the same table.
SQL> SELECT MIN(RECEIVEDDATE) FROM MYREQUEST;
MIN(RECEIVEDDATE)
-----------------
13-APR-0009 00:00
SQL> SELECT MAX(RECEIVEDDATE) FROM MYREQUEST;
MAX(RECEIVEDDATE)
-----------------
02-FEB-5770 11:58
The years shown are not in proper format, how can i get it in proper format
I have two tables; Client and Casenote.
Client contains demographics; ID, Name, Address...
Casenote is 1:M; Client ID, Notes, Location, Date, Volume.
I am trying to write a query to bring back all data from Client and all data from Casenote where the latest casenote was recorded (max date) and is volume number 1. If there is no data in the Casenote table it should still show the client demographics.
This is what I have tried but it doesn't work correctly.
SELECT
a.id,
a.name,
a.address,
b.notes,
b.location,
[Code]....
How to get least date value if my data is like this,
order_id date
121 03-mar-12
232 30-jan-10
343 14-may-11
I want to pic least date value(i.e. 03-mar-12) from the list