PL/SQL :: Converting A Row Into Columns Values?

Sep 6, 2012

I have a row which contains 6 columns where I want that data to be shown in the form of columns as shown here:

From:

select item1, item2, item3, amt1, amt2, amt3 from item_table where sno=1; <----- returns 1 row as below

ITEM1 ITEM2 ITEM3 AMT1 AMT2 AMT3
---------- ------------ ------------- ----------- ------------ ----------
AAA BBB CCC 10.00 20.00 15.00

Data explanation: item1's (AAA) price is amt1 (10.00), item2's (BBB) price is amt2 (20.00) and item3's (CCC) price is amt3 (15.00). OK.

Now I want that data to convert into columns as shown here:

To:

ITEMS AMT
--------- ---------
AAA 10.00
BBB 20.00
CCC 30.00

I want a SQL to display this data.

I found one query which converts a row into columns, but this does not serve my requirement: [for your reference only]

SQL> select substr( the_string
, decode( level, 1, 1, instr(the_string,',',1,level-1)+1)
, decode( instr(the_string,',',1,level), 0, length(the_string), instr(the_string,',',1,level) - decode( level, 1, 0, instr(the_string,',',1,level-1))-1)
) the_value
from ( select (select item1||','||item2||','|| item3 from item_table where sno=1) ITEMS
from DUAL)
connect by level <= length(the_string)-length(replace(the_string,','))+1

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Aug 22, 2013

Getting error ORA-00932: inconsistent datatypes: expected NUMBER got CHAR Source row:

NOTE_IDCONTRACT_GRANT_IDPROSPECT_IDPROGRAM_CODE
1 1 1 786
2 2 2 786

Program:

SELECT
CASE
WHEN "PIVOT_ROW_GENERATOR"."ID" = 0 THEN
"PIVOT_SOURCE"."ID_NUMBER"
WHEN "PIVOT_ROW_GENERATOR"."ID" = 1 THEN
"PIVOT_SOURCE"."ID_NUMBER"
[code].........

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Sep 14, 2008

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I need something a little different...I have a query using UNION which goes something along the lines of...

SELECT [get data from one place]
UNION
SELECT [get data from another place]
UNION
SELECT [get data from another place]

this returns the following...
a_val
-----
100
200
300

query to return something like this...
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Oct 20, 2011

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I want to convert rows to columns dynamically..

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i want result like this.

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2 11 23 12
3 11 11 11
4
5
6
7
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123 D 222
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fixing the errors or if there is any new logic that can be implemented.

DECLARE
i_e NUMBER(10);
BEGIN
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Dec 17, 2010

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Step 1)

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------------------------------------------
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Step 2)

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variable 2 table abc col2_abc ----
variable 3 table xyz col1_xyz ----
variable 4 table xyz col2_xyz ----
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for i in 1.2
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After Swapping:

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