I'm trying to create a new table which has a date field (date of birth) and I want to include a constraint which will not allow me to add values if they are over 21 years old. I'm using SQLPlus .
View 3 RepliesI use Oracle 10.0.2.0.1.If I create a table with constraint key; after that I create an unique index key, I got an error. Does it mean when I create a table with constraint the unique index are automatically created and I could not create index key as I did as below?
create table test_const(ename varchar2(50) not null,
key_num number not null,
descr varchar2(100),
constraint constraint_test_const unique (ename, key_num));
create unique index test_const_idx on test_const
(
"ENAME","KEY_NUM"
)
tablespace tmp_data;
Error report: SQL Error: ORA-01408: such column list already indexed 01408. 00000 - "such column list already indexed" added [pre] tags by Sriram
Why can't we create null constraint on table level?
View 20 Replies View Relatedi'm new to oracle environment.how can i specify NONCLUSTERD INDEX on Primary cloumn during table creation.By default it will create clusterd index but i need non-clusterd index on it.
I'm using following stmt to create normal primary constarint during table creation,
CONSTRAINT PKFORM_PROPS PRIMARY KEY (FORM_PROPS_PK) USING INDEX TABLESPACE DB123_INDEX
how can i change the above query, so that it should create NONCLUSTERED INDEX on Primary key column.
i want to get table name, constraint name, constraint type with join processes in string type. this is what i want: alter table tablename add constraint constraintname constrainttype(columnname)
View 1 Replies View RelatedI have table EMP & DEPT.
Can you give me sample "check" constraint so that when I enter an EMP (with status='active') without matching DEPT entry, the process will fail?
It will allow to enter EMP with status='inactive' only even if no matching DEPT entry. So foreign_key will not apply.
I have a series of SQL scripts which contain SQL statements to create tables, populate them, create functions and stored procedures. Now I would like to execute each sql file against SQLPlus using a batch file so that I can just run this one file and all the configuration work I need to do can get done.
Problem is, when I try to execute the SQL file against SQLPlus, it gets upset with the Create Procedure/Function scripts...
I am using the following command:
sqlplus u/p@<someserver> @<path_to_sqlfile>.sql
this sql file contains create procedure pl/sql code
Is it possible create/compile SP/Functions that are contained within SQL Files using SQLPLus? Or do I have to physically write them out in SQLPLus (or load them in SQLDeveloper) to accomplish this?
, I'd like to create a constraint (when creating a table) that checks to ensure that the 'Year' entered is less than or equal to the current year (based off SYSDATE). Per the code below, I keep getting the same error, "missing right parenthesis". I've spent more than an hour trying different ways to get this to work, but I've been failing miserably. I am using Oracle 11g Express.
CREATE TABLE TEST (Name VARCHAR2(7) PRIMARY KEY, Year NUMBER(4), CONSTRAINT TEST_YEAR_CK CHECK (Year <= (TO_NUMBER(TO_CHAR(SYSDATE, 'YYYY')))FROM DUAL);
*ERROR at line 4:ORA-00907: missing right parenthesis
The way to create a short cut on desktop to have an sql*plus (command line).
i.e. I want to have an short cut on desktop when I click that short cut that would connect me to a specific database with a username and password (which i supply while creating the shortcut-I would provide the database name, username and password)
primary key constraint on transaction_dtl_bk is affecting the insertion of next correct rows.
CREATE OR REPLACE PROCEDURE NP_DB.san_po_nt_wnpg_1 (
dt DATE
)
IS
v_sql_error VARCHAR2 (100); -- added by sanjiv
v_sqlcode VARCHAR2 (100); ---- added by sanjiv added by sanjiv
[code]...
how to i insert a constraint of words into the table example below.I am new to this stuff man.
Create table Orders
(
orderID Number(8) Primary Key,
orderDate Date Not Null,
methPmt Varchar2(10),
custID Number(5),
orderSource Number(2),
Foreign Key(custID) Reference Customer(custID),
Foreign Key(ordersource) Reference OrderSource(ordersource)
);
The catch is I am required to enter a constraint of the methPmt will only take values of "CASH", "CREDIT" or "CHEQUE" only.
How am I suppose to enter this constraint value into the creation of this table?
I want to know constraint name of a particular table if it exists.Here are the queries that i tried to find the constraint name of a particular table but the results were 'no rows selected'.
Queries:
select constraint_name from user_cons_columns where table_name='x';
select constraint_name from user_constraints where table_name='x';
I would like to add a constraint "default value" for a table column, with a name.
I know how to do it for a constraint "not null" : ALTER TABLE tablename MODIFY columnname CONSTRAINT constraintname NOT NULL;
But I don't know how to do it for a constraint "default value".How can I do ?
Can we modifying the existing constraint on table?I have table level UNIQUE constraint on 3 columns of table.I need to modify the UNIQUE constraint to 2 columns? Instead of dropping/recreating the constraint, is there any option to modify the existing constraint
Ex
CREATE TABLE TEST_CONST(NUM1 NUMBER , NUM2 NUMBER , NUM3 NUMBER , UNIQUE (NUM1 ,NUM2,NUM3)); ;
SELECT * FROM USER_CONS_COLUMNS UCC WHERE UCC.TABLE_NAME LIKE 'TEST_CONST';
ALTER TABLE TEST_CONST MODIFY CONSTRAINT SYS_C0025132 UNIQUE(NUM1,NUM2);
ORA-00933: SQL command not properly ended
Third statement is not executing fine .
i have one table HR.employees
SQL> desc hr.employees
Name Null? Type
----------------------------------------- -------- ----------------------------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
EMAIL NOT NULL VARCHAR2(25)
PHONE_NUMBER VARCHAR2(20)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(8,2)
COMMISSION_PCT NUMBER(2,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
SQL>
in this table i want to temporary disable all constraint in this employees table
There was one constraint define on the column of table that the value of column should be in range of 100 to 200. Some one has deleted the constraint. Is it possible to get the exact name of constraint from any system table.
View 7 Replies View RelatedI have a table as below. This table is not partitioned.
create table t1
(
d1 date,
n1 number not null
);
[Code]....
I took an export dump of the above table and after that I renamed the table t1 to t1_old. Then I recreated the table as below with a default constraint on d1 field.
create table t1
(
d1 date default to_date('01/01/1100','DD/MM/YYYY','NLS_CALENDAR=GREGORIAN'),
n1 number not null
[Code]....
But the problem here is the data import is taking too much time than what I expected. I can't afford a maxvalue partition here as of my DBA team mentioned if you add maxvalue partition adding partition later in a stage is difficult on this table
apply in this scenario and make the import faster. I am using oracle 10.2.0.1.0 version.
How to drop an index which has a constraint on the table?
while droping the index on the table wheather i should remove the
constraint or disable the constraint or without droping the
constraint
I am a junior DBA. I want to check how many columns are under PRIMARY KEY constraint.
I used dba_constraints view. Please find below details.
SQL> select OWNER,CONSTRAINT_NAME,CONSTRAINT_TYPE,TABLE_NAME from dba_constraints
2 where TABLE_NAME='DSET_PRODUCT_S';
OWNER CONSTRAINT_NAME C TABLE_NAME
------------------------------ ------------------------------ - ----------------------------------------
SCOTT SYS_C10202456 C EMPLOYEE
SCOTT SYS_C234576 C DEPT
I have created a table below, my TL asked me to create a local unique constraint for the below table.
I went through all sites and could not find the correct solution, how to create LOCAL UNIQUE CONSTRAINT ON SUB PARTITION TABLE and LOCAL UNIQUE INDEX ON PARTITION TABLE. Creating Local Unique constraint should take care of creating local unique index creation.
Unique key columns are DET,GDS,ARRIVE_DT
CREATE TABLE SUB_PAR_TAB
(
ID VARCHAR2(100) NOT NULL,
REGION VARCHAR2(40) NOT NULL,
SOURCE VARCHAR2(80) NOT NULL,
DET VARCHAR2(80) NOT NULL,
GDS VARCHAR2(40) NOT NULL,
ARRIVE_DTDATE,
SYS_SOURCE VARCHAR2(25) ,
[code]........
I used
SELECT USER_CONS_COLUMNS.CONSTRAINT_NAME,
COLUMN_NAME,
CONSTRAINT_TYPE,
[Code]...
to create a parent key table sort of thing, but for some reason there are rows that display multiple times
CONSTRAINT_NAME COLUMN_NAME CONSTRAINT_TYPE R_CONSTRAINT_NAME DELETE_RU
-------------------- -------------------- --------------- ------------------------------ ---------
SYS_C00135225 PATIENT_STATUS C
SYS_C00135226 BALANCE C
SYS_C00135227 PATIENT_STATUS C
PK_PATIENT PATIENT_NUMBER C
[Code] ..........
is it something to do with the join command
I am trying to create snapshot using the following script but I am getting the error
ERROR at line 22:ORA-12014: table 'CDA_FUNCTION' does not contain a primary key constraint
SQL> CREATE SNAPSHOT MEDA.cda_function
PCTFREE 10
PCTUSED 40
MAXTRANS 255
TABLESPACE users
STORAGE (
INITIAL 40960
[code]....
I check in dba_constraint data dictionary table for the constraints in the table CDA_FUNCTION.it is showing as follows
owner constraint_name constraint_type table_name search_condition status deferrable deferred validated generated
WEDA SYS_C0032310 C CDA_FUNCTION (LONG) ENABLED NOT DEFERRABLE IMMEDIATE VALIDATED GENERATED NAME
WEDA SYS_
What is the difference between CREATE EXTERNAL TABLE Vs CREATE TABLE .?
Is CREATE EXTERNAL TABLE included in CREATE TABLE?
I want to find the constraint name from User_Constraints table using the following query:
Select * From User_Constraints Where Table_Name='CHARGECODE' and Constraint_Type='C' And Search_Condition = '"PERCENTAGE" IS NOT NULL';
Then it shows "ORA-00997: illegal use of LONG datatype" error.
Is there any way to compare with long type value.
I have a PIVOT XML query that returns results that I want to display as an HTML report from SQLPlus. Is there a way that this can be done readily? I have searched the net an found references to XML Publisher but in my current situation we do not have the product available.
View 4 Replies View Relatedhow can I reduce the size of ------------- when table is null. I m in sqlplus I typeSelect A,B,C,D,F,G,H from SOMEHERE where B='GOAT1';
if A is 10 char long
B is 50
c is 10
d is 30
e is 10
f is 50
if any of those don't have data it still outputs ----------------------------- (50) for B and tht covers the whole screenhow can I make is to show less if it null
I am trying to execute dynamic SQL in Stored Function and I don't know how to do this.
Explanation:
In the function I am calling pr_createtab is procedure which will create a physical table and return the table name in the out variable v_tbl_nm.
I need to query on this dynamic table and return the result as return result. But i am not able to do it.
Here T_web_loylty_report_table is a type.
CREATE OR REPLACE function CDW_DSS.f_ReturnTable(i_mrkt_id in number, i_cmpgn_year in number)
return T_web_loylty_report_table is
v_tbl_nm varchar2(50);
i_cntry_cd varchar2(20);
v_sql_str varchar2(32567);
[code]......
We have a table in the client database that has two columns - column parent and column child. The whole hierarchy of DB table dependencies is held in this table.If Report 1 is dependent on Table A and Table A in turn is dependent on two tables Table M and Table N. Table N is dependent on table Z it will appear in the db table as,
Hierarchy Table
Parent Child
Report1Table A
Table ATable M
Table ATable N
Table NTable Z
Requirement :
From the above structure, we need to build a table which will hold the complete hierarchy by breaking it into multiple columns.The o/p should look like this
-ParentChild 1Child 2 Child 3
-Report1Table ATable M
-Report1Table ATable N Table Z
Child 1, Child 2, Child 3 ....and so on are columns.The number of tables and the no of hierarchical relationships are dynamic.
SQL Statements to create hierarchy table:
create table hierarchy (parent varchar2(20), child varchar2(20));
insert into hierarchy values ('Report1','Table A');
insert into hierarchy values ('Report1','Table B');
insert into hierarchy values ('Table A','Table M');
insert into hierarchy values ('Table B','Table N');
insert into hierarchy values ('Report2','Table P');
insert into hierarchy values ('Table M','Table X');
insert into hierarchy values ('Table N','Table Y');
insert into hierarchy values ('Report X','Table Z');
Approached already tried :
1) Using indentation : select lpad(' ',20*(level-1)) || to_char(child) P from hierarchy connect_by start with parent='Report1' connect by prior child=parent;
2)Using connect by path function :
select *
from (select parent,child,level,connect_by_isleaf as leaf, sys_connect_by_path(child,'/') as path
from hierarchy start with parent='Report1'
connect by prior child =parent) a where Leaf not in (0);
Both the approaches give the information but the hierarchy data appears in a single column.Ideally we would like data at each level to appear in a different column.
what command is used to create a table by copying the structure of another table including constraints ?
View 2 Replies View RelatedI want to create temp table, for this i am using:
CODEcreate global temporary table help_temp
as
select * from help;
but this is creating only the table structure, not copying the table data.